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JEE • PHYSICS • ELECTRIC FIELDS AND CHARGES

Electric fields and charges practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-270 of 420 questions

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241 Medium
241 of 420
Understanding +4 | -1
Four metal conductors having different shapes
 I. A sphere 
 II. Cylinder
 III. Pear
 IV. Lightning conductor
 are mounted on insulating stands and charged. The one which is best suited to retain the charges for a longer time is
View answer and explanation
Correct option: A
1
Option A (1) is correct because a sphere distributes charge uniformly, minimizing charge concentration and leakage, thus retaining charge longer.
242 Medium
242 of 420
Understanding +4 | -1
The electric field at a distance 2 cm2 \mathrm{~cm} from the centre of a hollow spherical conducting shell of radius 4 cm4 \mathrm{~cm} having a charge of 2×10−3Con2 \times 10^{-3} \mathrm{Con} its surface is
View answer and explanation
Correct option: D
zero
Option D is correct because the electric field inside a hollow charged conducting shell is always zero.
243 Medium
243 of 420
Understanding +4 | -1
A body is negatively charged means
View answer and explanation
Correct option: C
The quantity of negative charge present is more than the quantity positive charge present.
Option C (The quantity of negative charge present is more than the quantity positive charge present) is correct because a negatively charged body has an excess of electrons.
244 Medium
244 of 420
Understanding +4 | -1
Which of the following statements is/are correct?
I. For practical purposes, the earth is used as a reference at zero potential in electrical circuits.
II. The electrical potential of a sphere of radius RR with charge QQ uniformly distributed on the surface is given by Q4πε0R\frac{Q}{4 \pi \varepsilon_0 R}.
III. Work done in carrying a point charge from one point to another in an electrostatic field depends on the path along which the point charge is carried.
View answer and explanation
Correct option: A
I and II only
Option A (I and II only) is correct because the earth is a zero potential reference, and the potential of a charged sphere is given by the formula, but electrostatic fields are conservative.
245 Easy
245 of 420
Understanding +4 | -1
A charge qq is placed on a solid metallic object of irregular shape. Charge qq will distribute itself.
View answer and explanation
Correct option: D
Non uniformly on the surface of metal
Option D (Non uniformly on the surface of metal) is correct because the charge distribution on an irregular metallic object depends on the curvature of the surface.
246 Medium
246 of 420
Understanding +4 | -1
A positively charged insulator is brought near (but does not touch) two metallic sphere that are in contact. The metallic spheres are then separated. The sphere which was initially farthest from the insulator will have:
View answer and explanation
Correct option: C
a positive charge
Option C (a positive charge) is correct because the sphere farthest from the positively charged insulator experiences a deficiency of electrons after separation, resulting in a net positive charge.
247 Medium
247 of 420
Understanding +4 | -1
A charge q\text{q} is fixed. Another charge Q\text{Q} is brought near it and rotated in a circle of radius r\text{r} around it. Work done during rotation is
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because the electrostatic force is conservative, and the work done by a conservative force in a closed path is always zero.
248 Medium
248 of 420
Understanding +4 | -1
Regarding a semiconductor which one of the following statements is wrong?
View answer and explanation
Correct option: A
There are no free electrons at room temperature
Option A (There are no free electrons at room temperature) is wrong because semiconductors do have free electrons at room temperature due to thermal excitation.
249 Medium
249 of 420
Understanding +4 | -1
Suppose a rod is given a negative charge by
rubbing it with wool. Which one of the
following statements is correct in this case?
View answer and explanation
Correct option: D
The negative charges are transferred from
wool to rod
Option D is correct. When a rod is negatively charged by rubbing with wool, negative charges (electrons) are transferred from the wool to the rod.
250 Medium
250 of 420
Application +4 | -1
A surface S=10j^S=10 \hat{{j}} is kept in an electric field E=2i^+4j^+7k^{E}=2 \hat{{i}}+4 \hat{{j}}+7 \hat{{k}}. How much electric flux will come out through this surface?
View answer and explanation
Correct option: A
40 unit
Option A (40 unit) is correct because the electric flux is calculated by taking the dot product of the electric field and the surface area vector.
251 Medium
251 of 420
Application +4 | -1
A particle of mass mm and charge qq is placed at rest in a uniform electric field EE and then released. The kinetic energy attained by the particle after moving a distance yy is
View answer and explanation
Correct option: A
qEyqEy
Option A (qEyqEy) is correct because the kinetic energy gained by the particle is equal to the work done by the electric field on the charge over the distance y.
252 Medium
252 of 420
Understanding +4 | -1
Assertion: The potential difference between any two points in an electric field depends only on initial and final position.

Reason: Electric field is a conservative field so the work done per unit positive charge does not depend on path followed.
View answer and explanation
Correct option: A
Both assertion and reason are true and the reason is the correct explanation of the assertion
Option A (Both assertion and reason are true and the reason is the correct explanation of the assertion) is correct because the electric field is conservative, making the potential difference path-independent.
253 Medium
253 of 420
Understanding +4 | -1
An electric dipole placed in a non-uniform electric field experiences
View answer and explanation
Correct option: A
Both, a torque and a net force
Option A (Both, a torque and a net force) is correct because in a non-uniform electric field, an electric dipole experiences both a torque and a net force.
254 Medium
254 of 420
Analyzing +4 | -1
Assertion: The property that the force with which two charges attract or repel each other are not affected by the presence of a third charge.

Reason: Force on any charge due to a number of other charge is the vector sum of all the forces on that charge due to other charges, taken one at a time.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but
Reason is not the correct explanation of
Assertion
Option B (If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion) is correct because the superposition principle explains the net force, but doesn't directly explain why individual forces are unaffected by other charges.
255 Hard
255 of 420
Analyzing +4 | -1
Given below are two statements:
Statement I An electric diploe is placed at the centre of a hollow sphere. The flux of electric field through the sphere is zero but the electric field is not zero anywhere in the sphere.
Statement II If RR is the radius of a solid metallic sphere and QQ be the total charge on it. The electric field at any point on the spherical surface of radius r(<R)r( < R) is zero but the electric flux passing through this closed spherical surface of radius rr is not zero.
In the light of the above statements, choose the correct answer from the options given below.
View answer and explanation
Correct option: B
Statement I is true but Statement II is false.
Option B is correct. Statement I is true because the net charge of a dipole is zero, resulting in zero flux, but the electric field is non-zero. Statement II is false because the electric field inside a charged solid sphere is not zero.
256 Medium
256 of 420
Analyzing +4 | -1
Assertion: Coulomb force and gravitational force follow the same inverse-square law.
Reason: Both laws are same in all aspects.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C is correct. While both Coulomb and gravitational forces follow the inverse-square law, the reason is false because they differ in nature (attractive vs. attractive/repulsive).
257 Medium
257 of 420
Understanding +4 | -1
In charging by induction,
View answer and explanation
Correct option: C
Body to be charged must be a conductor
Option C (Body to be charged must be a conductor) is correct because charging by induction requires the movement of free charge carriers, which are predominantly found in conductors.
258 Medium
258 of 420
Understanding +4 | -1
The force of repulsion between two electrons at a certain distance is 2F2 F. The force between two protons separated by the same distance is: (mp=1836me)\left(m_p=1836\right.\left.{m}_e\right)
View answer and explanation
Correct option: A
2F2 F
Option A (2F2 F) is correct because the electrostatic force depends on the charges and the distance, which are the same for both electrons and protons.
259 Medium
259 of 420
Understanding +4 | -1
Electric field line at the surface of equipotential surface is
View answer and explanation
Correct option: B
Perpendicular to the surface
Option B is correct because electric field lines are always perpendicular to equipotential surfaces.
260 Medium
260 of 420
Application +4 | -1
If a charged particle (+q,m)(+q, m) is projected along +x+x direction with initial velocity uu and an uniform electric field exist in space along (−-ve) yy-direction then path of partcile is (neglect gravity)
View answer and explanation
Correct option: C
Parabolic
Option C (Parabolic) is correct because the particle experiences constant force in the y-direction and has initial velocity in the x-direction, resulting in parabolic motion.
261 Medium
261 of 420
Understanding +4 | -1
Choose the incorrect statement.
View answer and explanation
Correct option: D
According to Gauss law, if a closed surface encloses no charge, then the electric field must vanish everywhere on the surface
Option D is correct because Gauss's law states that if a closed surface encloses no charge, the electric flux through the surface is zero, but the electric field itself doesn't necessarily vanish everywhere on the surface.
262 Medium
262 of 420
Understanding +4 | -1
The electric field near a conducting surface having a uniform surface charge density σ\sigma is given by
View answer and explanation
Correct option: C
σε0\frac{\sigma }{{{\varepsilon _0}}} and is normal to the surface
Option C (σε0\frac{\sigma }{{\varepsilon _0}} and is normal to the surface) is correct because the electric field near a conductor is perpendicular to the surface and its magnitude is given by the formula.
263 Medium
263 of 420
Application +4 | -1
n identical mercury droplets charged to the same potential VV coalesce to form a single bigger drop. The potential of new drop will be
View answer and explanation
Correct option: D
n2/3V{n^{2/3}}V
Option D (n2/3V{n^{2/3}}V) is correct because the potential of the new drop is proportional to n2/3n^{2/3} times the potential of the small droplets.
264 Medium
264 of 420
Application +4 | -1
Two identical small conducting spheres having unequal positive charges q1q_1 and q2q_2 are separated by a distance rr. If they are now made to touch each other and then separated again to the same distance, the electrostatic force between them in this case will be
View answer and explanation
Correct option: C
more than before
Option A (1.801.80) is correct because it is calculated using the relationship between electric field, magnetic field, and the speed of light in the medium.
265 Medium
265 of 420
Analyzing +4 | -1
A soap bubble of radius RR has uniformly distributed charge QQ on it's surface. It's energy is the self-energy of charges & surface energy due to surface tension. In equilibrium, this energy is minimum. Surface tension is S\mathrm{S}. At equilibrium radius of bubble is R & pressure inside is P\mathrm{P}. Pressure outside is P0\mathrm{P}_0. Then
View answer and explanation
Correct option: A
R=(Q2128π2∈0S)1/3R=\left(\frac{Q^2}{128 \pi^2 \in_0 S}\right)^{1 / 3}
Option A (R=(Q2128π2∈0S)1/3R=\left(\frac{{Q^2}}{{128 \pi^2 \in_0 S}}\right)^{1 / 3}) is correct because it represents the equilibrium radius derived from minimizing the total energy of the bubble.
266 Medium
266 of 420
Analyzing +4 | -1
Two point charges +Q+Q and +q+q are separated by a certain distance. If +Q>+q+Q > +q then in between the charges the electric field is zero at a point:
View answer and explanation
Correct option: B
Closer to +q+q
Option B (Closer to +q+q) is correct because the electric field is zero closer to the smaller charge due to the inverse square relationship.
267 Medium
267 of 420
Understanding +4 | -1
Assertion:- Electric field inside conductor is zero in electrostatics.
Reason:- Charge appears on surface of conductor.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because while both statements are true, the charge appearing on the surface doesn't directly cause the zero electric field inside.
268 Medium
268 of 420
Understanding +4 | -1
Assertion (A): Electric lines of force cross each other.
Reason (R): The resultant electric field at a point is the superimposition of the electric fields at that point.
View answer and explanation
Correct option: D
A is false and R is true
Option D is correct because electric field lines never intersect, and the resultant electric field at a point is indeed the superposition of individual electric fields.
269 Medium
269 of 420
Analyzing +4 | -1
Assertion: A charged particle free to move in an electric field always moves along an electric field line

Reason: The electric field lines diverge from a negative charge and converge at a positive charge.
View answer and explanation
Correct option: D
Assertion is false and Reason is false
Option D (Assertion is false and Reason is false) is correct because a charged particle's motion in an electric field depends on its initial conditions, and electric field lines diverge from positive charges and converge at negative charges.
270 Medium
270 of 420
Application +4 | -1
Two positive point charges are 3 m3 \mathrm{~m} apart and their combined charge is 20μC20 \mu \mathrm{C}. If the force between them is 0.075 N0.075 \mathrm{~N}, then the charges are:
View answer and explanation
Correct option: B
15μC,5μC15 \mu \mathrm{C}, 5 \mu \mathrm{C}
Option B (15μC,5μC15 \mu \mathrm{C}, 5 \mu \mathrm{C}) is correct because these charges satisfy both the combined charge and the force between them as given in the problem.
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