Skip to main content
Back to ELECTRIC FIELDS AND CHARGES

JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

1 Medium
1 of 1
Application +4 | -1
Two insulated charged metallic spheres PP and QQ have their centres separated by a distance of 50 cm50 \mathrm{~cm}. The radii of PP and QQ are negligible compared to the distance of separation. The mutual force of electrostatic repulsion if the charge on each is 3.2×10−7C3.2 \times 10^{-7} \mathrm{C} is:
View answer and explanation
Correct option: A
3.69×10−3 N3.69 \times 10^{-3} \mathrm{~N}
Option A (3.69×10−3 N3.69 \times 10^{-3} \mathrm{~N}) is correct because it calculates the electrostatic force using Coulomb's law with the given charges and separation distance.

More Questions from ELECTRIC FIELDS AND CHARGES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.