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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

1 Hard
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Application +4 | -1
Let there be a spherically symmetric charge distribution with charge density varying as ρ(r)=ρ0[23−2rR]\rho(r)=\rho_0\left[\frac{2}{3}-\frac{2 r}{R}\right] upto r=Rr=R and ρ(r)=0\rho(r)=0 for r>Rr>R, where rr is the distance from origin. The electric field at a distance r(r<R)r(r < R) from the origin is given by:
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Correct option: B
ρ0rε0[29−r2R]\frac{\rho_0 r}{\varepsilon_0}\left[\frac{2}{9}-\frac{r}{2 R}\right]
Option B is correct because the electric field is calculated using Gauss's law by integrating the charge density over a spherical volume and then applying the formula E = Kq/r2.

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