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JEE • PHYSICS • DUAL NATURE OF RADIATION AND MATTER
Dual nature of radiation and matter practice · Medium
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151
Medium
151 of 303
Understanding
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The cathode of a photoelectric cell is changed such that the work function changes from to If the current before and after change are and all other conditions remaining unchanged, then (assuming )
View answer and explanation
Correct option: A
Option A () is correct because the photoelectric current depends on the intensity and frequency of the incident light and the number of photoelectrons emitted, but as long as the photon energy is greater than the work function, changing the work function does not affect the current.
152
Medium
152 of 303
Understanding
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When subjected to a transverse electric field, cathode rays move
View answer and explanation
Correct option: B
Up the potential gradient
Option B is correct because cathode rays, being negatively charged, are attracted towards the positive terminal, moving up the potential gradient.
153
Medium
153 of 303
Application
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One electron and one proton is accelerated by equal potential. Ratio in their de-Broglie wavelength is
View answer and explanation
Correct option: C
Option C () is correct because the de Broglie wavelength is inversely proportional to the square root of the mass for particles accelerated through the same potential.
154
Medium
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Application
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A particle A of mass and charge is accelerated by a potential difference of 50 V. another particle of mass ‘4 m’ and charge is accelerated by a potential difference of 2500 V. The ratio of de-Broglie wavelengths is close to
View answer and explanation
Correct option: D
14.14
Option D (14.14) is correct because the ratio of de-Broglie wavelengths is calculated using the formula .
155
Medium
155 of 303
Understanding
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If intensity of incident light is increased in PEE then which of the following is true
View answer and explanation
Correct option: B
Work function will remain unchanged
Option B (Work function will remain unchanged) is correct because the work function is a property of the metal and is independent of the intensity of incident light.
156
Medium
156 of 303
Application
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The de-Broglie wavelength of a proton (charge =1.6 C, mass=kg) accelerated through a potential difference of 1kV is
View answer and explanation
Correct option: B
0.9 m
Option B (0.9 x 10⁻¹² m) is correct because it is the de-Broglie wavelength calculated using the given parameters and the de-Broglie wavelength formula.
157
Medium
157 of 303
Understanding
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Which of the following statement is not correct?
View answer and explanation
Correct option: D
Infrared photons have more energy than photons of
visible light
visible light
Option D (Infrared photons have more energy than photons of visible light) is correct because infrared photons have less energy than photons of visible light since energy is inversely proportional to wavelength, and infrared light has a longer wavelength than visible light.
158
Medium
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Application
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In a photoelectric effect experiment, the threshold wavelenght of light is 380 nm. If the wavelength of incident light is 260 nm, the maximum kinetic energy of emitted electrons will be
Given, E (in eV)
Given, E (in eV)
View answer and explanation
Correct option: C
Option C () is correct because the maximum kinetic energy is calculated using Einstein's photoelectric equation: , where E is the energy of the incident photon and is the work function.
159
Medium
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Understanding
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Assertion: The number of photons emitted per second by a point source of light is directly proportional to the power of the source and inversely proportional to the energy of each photon.
Reason: The equation relates the number of photons emitted per second to the power of the source , the wavelength of light emitted , and fundamental physical constants ( and ). This equation shows that increasing the power of the source or decreasing the energy of each photon will result in an increase in the number of photons emitted per second.
Reason: The equation relates the number of photons emitted per second to the power of the source , the wavelength of light emitted , and fundamental physical constants ( and ). This equation shows that increasing the power of the source or decreasing the energy of each photon will result in an increase in the number of photons emitted per second.
View answer and explanation
Correct option: A
Both Assertion and Reason are true, and Reason is the correct explanation for Assertion
Option A (Both Assertion and Reason are true, and Reason is the correct explanation for Assertion) is correct because the number of photons emitted per second is directly proportional to the power and inversely proportional to the energy of each photon, as described by the given equation.
160
Medium
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Understanding
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A point source of light is used in a photoelectric effect. If the source is removed farther from the emitting metal, the stopping potential :
View answer and explanation
Correct option: C
Will remain constant
Option C (Will remain constant) is correct because the stopping potential depends on the frequency of the light, not its intensity.
161
Medium
161 of 303
Understanding
+4 | -1
Which one of the following statement is wrong in the context of X-rays generated from X-ray tube?
View answer and explanation
Correct option: B
Cut-off wavelength of the continuous X-rays depends on the atomic number of the target
Option B (Cut-off wavelength of the continuous X-rays depends on the atomic number of the target) is correct because the cut-off wavelength depends on the accelerating voltage, not the target's atomic number.
162
Medium
162 of 303
Understanding
+4 | -1
In photoelectric effect, the electrons are ejected from metals if the incident light has a certain minimum
View answer and explanation
Correct option: B
Frequency
Option B (Frequency) is correct because the photoelectric effect requires the incident light to have a minimum frequency (threshold frequency) to eject electrons.
163
Medium
163 of 303
Understanding
+4 | -1
Which of the following event, support the quantum nature of light?
View answer and explanation
Correct option: D
Photoelectric effect
Option D (Photoelectric effect) is correct because the photoelectric effect demonstrates the particle-like (quantum) nature of light, where energy is transferred in discrete packets (photons).
164
Medium
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Analyzing
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The ratio of de-Broglie wavelength of a -particle to that of a proton being subjected to the same magnetic field so that the radii of their path are equal to each other, assuming the field induction present there is perpendicular to the velocity vectors of the -particle and the proton, is
View answer and explanation
Correct option: C
45689
Option C (01-Feb) is correct because the ratio of de-Broglie wavelengths is inversely proportional to the charge of the particles.
165
Medium
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Application
+4 | -1
When a piece of metal is illuminated by a monochromatic light of wavelength then stopping potential is When same surface is illuminated by light of wavelength , then stopping potential becomes The value of threshold wavelength for photoelectric emission will be
View answer and explanation
Correct option: A
Option A () is correct because it is derived from Einstein's photoelectric equation by setting up two equations based on the given stopping potentials and wavelengths, then solving for the threshold wavelength.
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166
Medium
166 of 303
Analyzing
+4 | -1
The frequency and intensity of a light source are doubled. Consider the following statements
I. Saturation photocurrent remains almost the same.
II. Maximum kinetic energy of the photoelectrons is doubled.
I. Saturation photocurrent remains almost the same.
II. Maximum kinetic energy of the photoelectrons is doubled.
View answer and explanation
Correct option: C
I is false but II is true.
Option C is correct because saturation photocurrent depends on intensity, and maximum kinetic energy depends on frequency.
167
Medium
167 of 303
Remembering
+4 | -1
The magnitude of saturation photoelectric current depends upon
View answer and explanation
Correct option: B
Intensity
Option B (Intensity) is correct because the saturation photoelectric current is directly proportional to the intensity of the incident light.
168
Medium
168 of 303
Understanding
+4 | -1
The stopping potential in the context of photoelectric effect depends on the following property of incident electromagnetic radiation:
View answer and explanation
Correct option: C
Frequency
Option C (Frequency) is correct because the stopping potential in the photoelectric effect is directly related to the frequency of the incident light, as described by Einstein's photoelectric equation.
169
Medium
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Understanding
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Statement 1: Wave nature of particle is not visible in daily life.
Statement 2: In daily life, mass of particle is very high so their de-Broglie wave length is very small.
Statement 2: In daily life, mass of particle is very high so their de-Broglie wave length is very small.
View answer and explanation
Correct option: C
Both the statements are correct
Option C is correct because both statements are true and statement 2 explains why wave nature is not visible in daily life due to the small de-Broglie wavelength.
170
Medium
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Understanding
+4 | -1
The work function of a metal is and is wavelength of incident radiation. There is no emission of photoelectron when
View answer and explanation
Correct option: D
Option D () is correct because for no photoelectron emission, the wavelength of incident radiation must be greater than the threshold wavelength.
171
Medium
171 of 303
Remembering
+4 | -1
The average energy of the Planck oscillator is
View answer and explanation
Correct option: B
Option B () is correct because the average energy of a Planck oscillator is given by this formula, derived from Planck's quantum theory.
172
Medium
172 of 303
Understanding
+4 | -1
Light of frequency falls on material of threshold frequency Maximum kinetic energy of emitted electron is proportional to
View answer and explanation
Correct option: A
Option A () is correct because the maximum kinetic energy is directly proportional to the difference between the incident frequency and the threshold frequency, as described by the photoelectric effect equation.
173
Medium
173 of 303
Understanding
+4 | -1
The momentum of a photon of energy will be
View answer and explanation
Correct option: B
Option B () is correct because the momentum of a photon is related to its energy by the equation .
174
Medium
174 of 303
Application
+4 | -1
When a photon of wavelength 400 nm is incident on a metal surface, the electron emission takes place. The stopping potential to stop electron is 1.5 V. The work function of metal surface is: (given
View answer and explanation
Correct option: B
1.6 eV
Option B (1.6 eV) is correct because it is calculated using the photoelectric effect equation, subtracting the stopping potential energy from the incident photon energy.
175
Medium
175 of 303
Analyzing
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Assertion: An electron cannot be observed without changing its momentum by an indeterminate amount.
Reason: Momentum of an electron is .
Reason: Momentum of an electron is .
View answer and explanation
Correct option: B
Assertion is correct, reason is correct; reason is not a correct explanation for assertion
Option B (Assertion is correct, reason is correct; reason is not a correct explanation for assertion) is correct because the act of observing an electron inevitably alters its momentum, and the de Broglie wavelength relates momentum and wavelength, but doesn't explain the uncertainty.
176
Medium
176 of 303
Application
+4 | -1
If the momentum of an electron is changed by then the de-Broglie wavelength associated with it changes by 0.50%. The initial momentum of the electron will be
View answer and explanation
Correct option: C
Option C () is correct because it is the initial momentum calculated using the relationship between de-Broglie wavelength and momentum.
177
Medium
177 of 303
Application
+4 | -1
In Millikans oil drop experiment, a charged drop of mass is stationary between its plates. The distance between its plates is and potential difference is The number of electrons on the drop is
View answer and explanation
Correct option: C
5
Option C (5) is correct because the number of electrons is calculated by equating the electric force to the gravitational force and solving for the number of electrons.
178
Medium
178 of 303
Application
+4 | -1
The increase in the energy of an electron for changing its de-Broglie wavelength from will be-
View answer and explanation
Correct option: B
0.45 keV
The correct answer is 0.45 keV because the change in energy is calculated from the change in de Broglie wavelength using the kinetic energy formula.
179
Medium
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Application
+4 | -1
A proton moving with one tenth of velocity of light has a certain de Broglie wavelength of . An alpha particle having certain kinetic energy has the same de-Brogle wavelength . The ratio of kinetic energy of proton and that of alpha particle is
View answer and explanation
Correct option: D
Option D () is correct because the ratio of kinetic energies is equal to the inverse ratio of their masses when their de Broglie wavelengths are the same.
180
Medium
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Understanding
+4 | -1
According to photon theory of light which of the following physical quantities associated with a photon do not/does not change as it collides with an electron in vacuum
View answer and explanation
Correct option: C
Speed only
Option C (Speed only) is correct because the speed of a photon in a vacuum is constant () regardless of collisions, while energy and momentum can change.
Revision notes and key takeaways
Review DUAL NATURE OF RADIATION AND MATTER in your textbook or class notes, then use this set to check your understanding.
Showing 151-180 of 303 questions
