Back to DUAL NATURE OF RADIATION AND MATTER

Your Progress

0 / 10 Answered

Correct

Incorrect

Accuracy

JEE • PHYSICS • DUAL NATURE OF RADIATION AND MATTER

Dual nature of radiation and matter practice · Easy

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →

Preparing practice and saved progress…

1 Easy

1 of 10

Understanding +4 | -1

Which of the following phenomena does not explain by wave nature of light.

(A) reflection

\quad

(B) diffraction

(C) photoelectric effect

\quad

(D) interference

\quad

(E) polarization

Choose the most appropriate answer from the options given below :

View answer and explanation

Correct option: B

C only

Option B (C only) is correct because the photoelectric effect demonstrates the particle nature of light, not its wave nature.

2 Easy

2 of 10

Remembering +4 | -1

A photocell works on the principle of

View answer and explanation

Correct option: B

Photoelectric effect

Option B (Photoelectric effect) is correct because a photocell converts light energy into electrical energy based on the photoelectric effect.

3 Easy

3 of 10

Understanding +4 | -1

The wavelength of the waves associated with a proton and a photon are the same. Therefore, the two have equal

View answer and explanation

Correct option: C

Momentum

Option C (Momentum) is correct because, according to de Broglie's hypothesis, wavelength is inversely proportional to momentum, so equal wavelengths imply equal momenta.

4 Easy

4 of 10

Understanding +4 | -1

Which of the following statement is not true about stopping potential

\left(\mathrm{V}_0\right)?

View answer and explanation

Correct option: C

It increases with increase in intensity of the incident light

Option C is correct. Stopping potential does not increase with an increase in the intensity of incident light. It depends on the frequency of incident light and the nature of the emitter material.

5 Easy

5 of 10

Remembering +4 | -1

Kinetic mass of photon is

View answer and explanation

Correct option: B

h v / c^2

Option B (

h v / c^2

) is correct because the kinetic mass of a photon is derived from its energy (

E=hv

) and Einstein's mass-energy equivalence (

E=mc^2

6 Easy

6 of 10

Understanding +4 | -1

c

is the velocity of light in free space, the correct statements about photon among the following are:

A. The energy of a photon is

E=h v

B. The velocity of a photon is

c

C. The momentum of a photon,

p=\frac{h v}{c}

D. In a photon-electron collision, both total energy and total momentum are conserved.

E. Photon possesses positive charge.

Choose the correct answer from the options given below:

View answer and explanation

Correct option: A

A, B, C and D only

Option A is correct. The energy of a photon is

E=hv

, its velocity is

c

, its momentum is

p=\frac{hv}{c}

, and in a photon-electron collision, both total energy and total momentum are conserved.

7 Easy

7 of 10

Application +4 | -1

UV light of

4.13 \mathrm{~eV}

is incident on a photosensitive metal surface having work function

3.13 \mathrm{~eV}

. The maximum kinetic energy of ejected photoelectrons will be :

View answer and explanation

Correct option: B

1 \mathrm{~eV}

Option B (1 eV) is correct because the maximum kinetic energy is the difference between the photon energy and the work function.

8 Easy

8 of 10

Application +4 | -1

de-Broglie wavelength of a proton and an electron is same. The ratio of kinetic energy of electron to that of proton is

View answer and explanation

Correct option: B

1835

Option B (1835) is correct because the ratio of kinetic energies is inversely proportional to the ratio of masses when de-Broglie wavelengths are the same.

9 Easy

9 of 10

Analyzing +4 | -1

Statement-1: If an electron has the same wavelength as a photon, they have the same energy.
Statement-2: By de-Broglie hypothesis,

p=h / \lambda

for both the electron and the photon.

View answer and explanation

Correct option: D

Statement-1 is false, Statement-2 is true

Option D is correct because while both have the same de Broglie wavelength, their energies are different due to their different mass and energy-momentum relationships.

10 Easy

10 of 10

Understanding +4 | -1

Statement-1: Photoelectric effect establishes quantum nature of light.
Statement-2: There is negligible time lag between photon collisions with the material and photoelectron emission irrespective of intensity of incident light. (Assume incident light is of frequency greater than threshold frequency of the material).

View answer and explanation

Correct option: A

Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1

Option A (Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1) is correct because the instantaneous emission of photoelectrons, regardless of intensity, supports the quantum nature of light.

Revision notes and key takeaways

Review DUAL NATURE OF RADIATION AND MATTER in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 10 single-correct-answer MCQs on DUAL NATURE OF RADIATION AND MATTER.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

Your Progress

Dual nature of radiation and matter practice · Easy

Key Takeaways

Continue Your Practice

Your practice