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JEE • PHYSICS • CURRENT ELECTRICITY

Current electricity practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 457 questions
61 Medium
61 of 457
Application +4 | -1
A cell of emf 2 V2 \mathrm{~V} and internal resistance 0.1 Ω0.1 ~\Omega is connected to a 3.9 Ω3.9 ~\Omega external resistance. What will be the p.d. across the terminals of the cell ?
View answer and explanation
Correct option: D
1.95 V1.95 \mathrm{~V}
Option A (E=ma0eE=\frac{m a_0}{e}) is correct because it represents the electric field required to produce the same acceleration on an electron as the acceleration of the rod.
62 Medium
62 of 457
Application +4 | -1
Consider a wire of length 4 m4 \mathrm{~m} and cross-sectional area 1 mm2\mathrm{mm}^2 carrying a current of 2 A2 \mathrm{~A}. If each cubic metre of the material contains 102910^{29} free electrons, find the average time taken by an electron to cross the length of the wire.
View answer and explanation
Correct option: B
3.2×104 sec3.2 \times 10^4\,\mathrm{sec}
Option B (3.2×104 sec3.2 \times 10^4\,\mathrm{sec}) is correct because it is calculated using the drift velocity formula and the relationship between drift velocity, length, and time.
63 Medium
63 of 457
Understanding +4 | -1
Consider the following two statements AA and BB, and identify the correct choice out of given answers

A. Thermo e.m.f.e.\mathrm{m}\mathrm{.f}. is minimum at neutral temperature of a thermocouple

B. When two junctions made of two different metallic wires are maintained at different temperatures, an electric current is generated in the circuit
View answer and explanation
Correct option: A
AA is false and BB is true
Option A is correct because thermo emf is maximum at neutral temperature and an electric current is generated when two junctions of different metallic wires are maintained at different temperatures.
64 Medium
64 of 457
Application +4 | -1
An electric bulb is rated 220  V−100  W\mathrm{220}\,\,\mathrm{V - 100}\,\,\mathrm{W}. The power consumed by it when operated on 110  V\mathrm{110}\,\,\mathrm{V} will be
View answer and explanation
Correct option: C
25  W{\mathrm{25}\,\,\mathrm{W}}
Option C (25 W{\mathrm{25}\,\mathrm{W}}) is correct because the power consumed is proportional to the square of the voltage, and the resistance remains constant.
65 Medium
65 of 457
Understanding +4 | -1
Mobility of free electron in a current carrying conductor is proportional to
View answer and explanation
Correct option: C
Relaxation time
Option C (Relaxation time) is correct because the mobility of free electrons is directly proportional to the relaxation time, which is the average time between collisions.
66 Medium
66 of 457
Understanding +4 | -1
Piece of Aluminium and Silicon both are heated from −10∘C-10^{\circ} {C} to 40∘C40^{\circ} {C}. The resistivity of
View answer and explanation
Correct option: A
AlAl increases and SiSi decreases
Option A (AlAl increases and SiSi decreases) is correct because the resistivity of conductors increases with temperature, while the resistivity of semiconductors decreases.
67 Medium
67 of 457
Understanding +4 | -1
Internal resistance of a cell is independent of
View answer and explanation
Correct option: A
the circuit elements connected to it
Option A is correct because the internal resistance of a cell depends on the properties of the cell itself (electrode area, distance, electrolyte concentration) and not on external circuit elements.
68 Medium
68 of 457
Application +4 | -1
A parallel-plate capacitor has plate area 20 cm220 \mathrm{~cm}^2, plate separation 1.0 mm1.0 \mathrm{~mm} and a dielectric slab of dielectric constant 5.05.0 filling up the space between the plates. This capacitor is joined to a battery of emf 6.0 V6.0 \mathrm{~V} through a 100kΩ100 \mathrm{k} \Omega resistor. Find the energy of the capacitor 8.9μs8.9 \mu \mathrm{s} after the connections are made.
View answer and explanation
Correct option: A
530.97×530.9788.5×2×1012\frac{530.97 \times 530.97}{88.5 \times 2} \times 10^{12}
Option A (530.97×530.9788.5×2×1012\frac{530.97 \times 530.97}{88.5 \times 2} \times 10^{12}) is correct because it is the energy stored in the capacitor calculated using U=12CV2U = \frac{1}{2}CV^2 after considering the charging process through the resistor.
69 Medium
69 of 457
Remembering +4 | -1
Metals have
View answer and explanation
Correct option: C
Low resistivity
Option C (Low resistivity) is correct because metals are good conductors of electricity, which implies they have low resistivity.
70 Medium
70 of 457
Understanding +4 | -1
Point out the right statements about the validity of Kirchhoff's junction rule
View answer and explanation
Correct option: D
All of above.
Option D is correct. Kirchhoff's junction rule is based on the conservation of charge, and it applies regardless of the wire's orientation.
71 Medium
71 of 457
Application +4 | -1
A wire of resistance RR is elongated n−n - fold to make a new uniform wire. The resistance of new wire
View answer and explanation
Correct option: B
n2R{n^2}R
Option B (n2R{n^2}R) is correct because when a wire is elongated n-fold, its length increases by a factor of n and its area decreases by a factor of n, resulting in the resistance increasing by a factor of n2.
72 Medium
72 of 457
Remembering +4 | -1
The speed at which the current travels, in a conductor, is nearly
View answer and explanation
Correct option: D
3  ×  108  ms−13\,\, \times \,\,{10^8}\,\,\mathrm{m}{\mathrm{s}^{ - 1}}
Option D (3×108ms−13 \times {10^8}\mathrm{m}{\mathrm{s}^{ - 1}}) is correct because the current travels at approximately the speed of light in a conductor.
73 Medium
73 of 457
Understanding +4 | -1
The Avogadro’s number is 6  ×  10236\,\, \times \,\,{10^{23}} per gm mole and electronic charge is 1.6  ×  10−19  C1.6\,\, \times \,\,{10^{ - 19}}\,\,C. The Faraday’s number is
View answer and explanation
Correct option: A
6  ×  1023  ×  1.6  ×  10−196\,\, \times \,\,{10^{23}}\,\, \times \,\,1.6\,\, \times \,\,{10^{ - 19}}
Option A (6×1023×1.6×10−196 \times {10^{23}} \times 1.6 \times {10^{ - 19}}) is correct because Faraday's constant is the product of Avogadro's number and the elementary charge.
74 Medium
74 of 457
Understanding +4 | -1
Which of the following statements is correct
View answer and explanation
Correct option: B
Liquids obey partially the ohm's law
Option B (Liquids obey partially the ohm's law) is correct because the V-I graph for liquids is not a straight line, indicating partial obedience to Ohm's law.
75 Medium
75 of 457
Application +4 | -1
The electric resistance of a certain wire of iron is R.R.. If its length and radius are both doubled, then
View answer and explanation
Correct option: B
The resistance will be halved and the specific resistance will remain unchanged
Option B (The resistance will be halved and the specific resistance will remain unchanged) is correct because resistance is inversely proportional to area and specific resistance is a material property.
76 Medium
76 of 457
Understanding +4 | -1
Total emf produced in a thermocouple does not depend on
View answer and explanation
Correct option: D
The duration of time for which the current is passed through thermocouple
Option D (The duration of time for which the current is passed through thermocouple) is correct because the emf produced depends on the metals and the temperature difference, not the duration of current flow.
77 Medium
77 of 457
Understanding +4 | -1
In a metallic conductor, drift velocity vdv_d is related with electric field EE as
View answer and explanation
Correct option: D
Vd∝EV_d \propto E
Option D (Vd∝EV_d \propto E) is correct because drift velocity is directly proportional to the electric field, as shown by the formula Vd=−eE⃗τmV_d=\frac{{-e \vec{{E}}\tau}}{{m}}.
78 Medium
78 of 457
Application +4 | -1
A battery of e.m.f. ₹₹ ', and internal resistance ' rr ', gives a current of 0.5 A0.5 \mathrm{~A} with an external resistor of 12 ohm12 \mathrm{~ohm} and a current of 0.25 A0.25 \mathrm{~A} with an external resistor of 25 ohm25 \mathrm{~ohm}. Calculate (i) internal resistance of the cell and (ii) emf of the cell.
View answer and explanation
Correct option: A
6.5 V6.5 \mathrm{~V}
Option A (6.5 V) is correct because it's the calculated EMF of the cell using the given currents and external resistances, and solving the resulting equations.
79 Medium
79 of 457
Application +4 | -1
Resistance of a wire is 10Ω10 \Omega. Its length is increased 50%50 \% by stretching it. Calculate its new resistance.
View answer and explanation
Correct option: A
12.5 Ω12.5 ~\Omega
Option A (12.5 Ω12.5 ~\Omega) is correct because the change in resistance is proportional to the square of the change in length when the wire is stretched.
80 Medium
80 of 457
Understanding +4 | -1
The resistivity of a wire
View answer and explanation
Correct option: D
None of the above statement is correct
Option D (None of the above statement is correct) is correct because resistivity is a material property and does not depend on the dimensions of the wire.
81 Medium
81 of 457
Application +4 | -1
The masses of the wires of copper are in the ratio 1 : 2 : 3 and their lengths are in the ratio 3 : 2 : 1. The ratio of their electrical resistance
View answer and explanation
Correct option: A
1.129178241
The correct answer is A (27:06:01). The ratio of electrical resistance is inversely proportional to the mass and directly proportional to the square of the length.
82 Medium
82 of 457
Remembering +4 | -1
Ampere hour is the unit of
View answer and explanation
Correct option: A
Quantity of charges
Option A is correct because Ampere-hour is the unit of electric charge (quantity of charge), calculated as current multiplied by time.
83 Medium
83 of 457
Application +4 | -1
A parallel-plate capacitor with plate area 20 cm220 \mathrm{~cm}^2 and plate separation 1.0 mm1.0 \mathrm{~mm} is connected to a battery. The resistance of the circuit is 10kΩ10 \mathrm{k} \Omega. Find the time constant of the circuit.
View answer and explanation
Correct option: D
0.18 μs0.18\,\mu \mathrm{s}
Option D (0.18 μs0.18\,\mu \mathrm{s}) is correct because it's the time constant calculated using the formula τ=RC\tau = RC where C is the capacitance of the parallel plate capacitor.
84 Medium
84 of 457
Understanding +4 | -1
Assertion: A potentiometer is preferred over that of a voltmeter for measurement of emf of a cell.
Reason: Potentiometer does not draw any current from the cell.
View answer and explanation
Correct option: A
Both assertion and reason are true and reason is the correct explanation of assertion
Option A is correct because a potentiometer is preferred for measuring emf as it doesn't draw current from the cell, providing a more accurate measurement than a voltmeter.
85 Medium
85 of 457
Understanding +4 | -1
In a current carrying metallic conductor, current density J⃗\vec{J} and drift velocity vd→\overrightarrow{v_d} will be such that
View answer and explanation
Correct option: A
J→\overrightarrow{{J}} and vd→\overrightarrow{{v}_{{d}}} will have opposite directions
Option A (J→\overrightarrow{{J}} and vd→\overrightarrow{{v}_{{d}}} will have opposite directions) is correct because in metallic conductors, the charge carriers are electrons (negative), so the current density and drift velocity are in opposite directions.
86 Medium
86 of 457
Application +4 | -1
When two identical batteries of internal resistance 1  Ω1\,\,\mathrm{\Omega } each are connected in series across a resistor RR, the rate of heat produced in RR is J1{J_1}. When the same batteries are connected I\mathrm{I} parallel across RR, the rate is J2{J_2}. If J1=2.25  J2{J_1} = 2.25\,\,{J_2} then the value of RR in Ω\mathrm{\Omega } is
View answer and explanation
Correct option: D
5.16
Option D (5.16) is incorrect. The correct answer is R = 4. The solution provided in the original response is incorrect. The correct answer is 4.
87 Medium
87 of 457
Application +4 | -1
A cathode emits 1.8×10141.8 \times {10^{14}} electrons per second. When heated when 400 V is applied to anode all the emitted electrons reach the anode. The charge on electron is 1.6×10−19C1.6 \times {10^{ - 19}}C. The maximum anode current is
View answer and explanation
Correct option: B
29 μA29\,\mu A
Option B (29 μA29\,\mu A) is correct because the current is calculated by multiplying the number of electrons emitted per second by the charge of an electron.
88 Medium
88 of 457
Understanding +4 | -1
A potentiometer is an ideal device of measuring potential difference because
View answer and explanation
Correct option: B
It does not disturb the potential difference it measures
Option B is correct because a potentiometer measures potential difference without drawing current from the circuit being measured, thus not disturbing the potential.
89 Medium
89 of 457
Analyzing +4 | -1
To get the maximum current from a parallel combination of nn identical cells each of internal resistance rr and external resistance RR, when
View answer and explanation
Correct option: B
R  ≪  rR\,\, \ll \,\,r
Option B (R  ≪  rR \, \, \ll \, \, r) is correct because maximum current is obtained when the external resistance is much smaller than the internal resistance in a parallel combination of cells.
90 Medium
90 of 457
Application +4 | -1
Two bulbs of 250  V\mathrm{250}\,\,\mathrm{V} and 100  W\mathrm{100}\,\,\mathrm{W} are first connected in series and then in parallel with a supply of 250  V\mathrm{250}\,\,\mathrm{V}. Total power in each of the case will be respectively
View answer and explanation
Correct option: D
50 W,200 W\begin{array}{llllllllllllllllllll} {\mathrm{50 }\,\mathrm{W, 200 }\,\mathrm{W}} \end{array}
Option D (50 W,200 W\mathrm{50 }\,\mathrm{W, 200 }\,\mathrm{W}) is correct because when bulbs are in series, the power decreases, and when in parallel, the power increases.
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