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JEE • MATHEMATICS • STATISTICS

Statistics practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 312 questions

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91 Easy
91 of 312
Application +4 | -1
The sum of square of deviations for 10 observations taken from mean 50 is 250 . The coefficients of variation is
View answer and explanation
Correct option: B
10
Option B (10) is correct because the coefficient of variation is calculated using the formula CV = (standard deviation / mean) * 100.
92 Easy
92 of 312
Application +4 | -1
The geometric mean of numbers 7,72,73,….,7n7,7^2, 7^3, \ldots ., 7^n is :
View answer and explanation
Correct option: D
7(n+1)/27^{(n+1) / 2}
Option D (7(n+1)27^{{\frac{{(n+1)}}{{2}}}}) is correct because it correctly calculates the geometric mean of the given series using the properties of exponents and arithmetic progression.
93 Easy
93 of 312
Application +4 | -1
The mean of 21 observations (all DIFFERENT) IS 40 . If each observations greater than the median are increases 21 then mean of observations will become
View answer and explanation
Correct option: A
50
Option A (50) is correct because when each of the 10 observations greater than the median is increased by 21, the new mean is calculated to be 50.
94 Easy
94 of 312
Application +4 | -1
The mean and variance of the data 4, 5, 6, 6, 7, 8, x,y,x,y, where x<y,x < y, are 6 and 94\frac{9}{4} respectively. Then x4+y2{x^4} + {y^2} is equal to
View answer and explanation
Correct option: B
320
Option B (320) is correct because after solving for x and y using the given mean and variance, x4+y2{x^4} + {y^2} is calculated to be 320.
95 Easy
95 of 312
Understanding +4 | -1
The best statistical measure used for comparing two series is
View answer and explanation
Correct option: C
coefficient of variation
Option C (coefficient of variation) is correct because it is a relative measure of dispersion, allowing for comparison between datasets with different units or scales.
96 Easy
96 of 312
Understanding +4 | -1
If x,yx, y are independent variables, then Cov⁡(x,y)\operatorname{Cov}(x, y) is
View answer and explanation
Correct option: D
0
Option D (0) is correct because the covariance of two independent variables is always zero.
97 Easy
97 of 312
Understanding +4 | -1
The algebraic sum of deviations of a set of values from the arithmetic mean is
View answer and explanation
Correct option: A
0
Option A (0) is correct because the sum of deviations from the arithmetic mean always equals zero.
98 Easy
98 of 312
Application +4 | -1
If G1G_1 and G2G_2 are geometric means of two series of sizes n1n_1 and n2n_2 and GG is geometric mean of combined series, then log⁡G\log G is
View answer and explanation
Correct option: B
n1log⁡G1+n2log⁡G2n1+n2\frac{n_1 \log G_1+n_2 \log G_2}{n_1+n_2}
Option B (n1log⁡G1+n2log⁡G2n1+n2\frac{{n_1 \log G_1 + n_2 \log G_2}}{{n_1 + n_2}}) is correct because it represents the logarithm of the combined geometric mean.
99 Easy
99 of 312
Understanding +4 | -1
The 70th percentile is equal to
View answer and explanation
Correct option: A
7th decile
Option A (7th decile) is correct because the 70th percentile is equivalent to the 7th decile.
100 Easy
100 of 312
Remembering +4 | -1
Karl Pearson's coefficient of skewness is (M=\left(M=\right. Mean, Me=M_e= Median, Mo=M_{\mathrm{o}}= Mode)
View answer and explanation
Correct option: C
(M−Mo)σ\frac{\left(M-M_{\mathrm{o}}\right)}{\sigma}
Option C ((M−Mo)σ\frac{\left(M-M_{\mathrm{o}}\right)}{\sigma}) is correct because Karl Pearson's coefficient of skewness is defined as (Mean - Mode) / Standard Deviation.
101 Easy
101 of 312
Application +4 | -1
In a test of Mathematics, 15 students got following marks 16,25,35,20,0,12,30,22,5,8,4,38,32,2,116,25,35,20,0,12,30,22,5,8,4,38,32,2,1. The median score of these 15 students is
View answer and explanation
Correct option: D
16
Option D (16) is correct because after arranging the marks in ascending order, the median is the 8th term, which is 16.
102 Easy
102 of 312
Application +4 | -1
The weighed mean of first nn natural numbers whose weights are equal to the squares of corresponding numbers is
View answer and explanation
Correct option: B
3n(n+1)2(2n+1)\frac{3 n(n+1)}{2(2 n+1)}
Option B (3n(n+1)2(2n+1)\frac{3 n(n+1)}{2(2 n+1)}) is correct because it represents the weighted mean calculated by dividing the sum of the product of each number and its weight by the sum of the weights.
103 Easy
103 of 312
Understanding +4 | -1
If xˉ\bar{x} is the mean of x1,x2,…,xnx_1, x_2, \ldots, x_n then mean of x1+a,x2+a,….,xn+ax_1+a, x_2+a, \ldots ., x_n+a where aa is any number positive or negative is-
View answer and explanation
Correct option: A
xˉ+a\bar{x}+a
Option A (xˉ+a\bar{{x}}+a) is correct because adding a constant to each data point shifts the mean by the same constant.
104 Easy
104 of 312
Application +4 | -1
In a class of 100 students there are 70 boys whose average marks in a subject are 75. If the average marks of the complete class is 72, then what is the average of the girls?
View answer and explanation
Correct option: B
65
Option B (65) is correct because it is the calculated average of the girls' marks based on the given class average and boys' average.
105 Easy
105 of 312
Understanding +4 | -1
The value of mean, median and mode coincides, then the distribution is
View answer and explanation
Correct option: B
Symmetrical distribution
Option B (Symmetrical distribution) is correct because when the mean, median, and mode coincide, the distribution is symmetrical.
106 Easy
106 of 312
Application +4 | -1
If ∑i=1n(xi−a)=n\sum\limits_{i = 1}^n {({x_i} - a) = \mathrm{n}} and ∑i=1n(xi−a)2=na,(n,a>1),\sum\limits_{i = 1}^n {{{({x_i} - a)}^2} = \mathrm{n}} a,\mathrm{ }(n,a > 1), then the standard deviation of n observations x1,x2,......,.xn{x_1},{x_2},......,.{x_n} is
View answer and explanation
Correct option: D
a−1\sqrt {a - 1}
Option D (a−1\sqrt {a - 1}) is correct because it represents the standard deviation calculated from the given sums, using the definition of variance and standard deviation.
107 Easy
107 of 312
Application +4 | -1
The AM of n observations isM. If the sum of (n−4)\left( {n - 4} \right) observations is a, then the mean of remains four observations is
View answer and explanation
Correct option: A
nM−a4\frac{{nM - a}}{4}
Option A (nM−a4\frac{{nM - a}}{4}) is correct because it represents the mean of the remaining four observations after subtracting the sum of (n-4) observations from the total sum and dividing by 4.
108 Easy
108 of 312
Application +4 | -1
Lines of regression of yy on xx and xx on yy are respectively y=ax+by=a x+b and x=αy+βx=\alpha y+\beta. If mean of xx and yy series is same, then its value is
View answer and explanation
Correct option: A
b1−a\frac{b}{1-a} or β1−α\frac{\beta}{1-\alpha}
Option A (-0.82) is correct because the correlation coefficient is calculated using the slopes of the two regression lines.
109 Easy
109 of 312
Understanding +4 | -1
The two lines of regression are parallel to the axes if r=r=
View answer and explanation
Correct option: C
0
Option C (0) is correct because the lines of regression are parallel to the axes when the correlation coefficient is 0, indicating no linear relationship between the variables.
110 Easy
110 of 312
Application +4 | -1
If each of n numbers xi=i{x_i} = i is replaced by (i+1)xi,\left( {i + 1} \right){x_i}, then the new mean is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the calculated new mean does not match any of the provided options.
111 Easy
111 of 312
Application +4 | -1
The first of two samples in a group has 100 items with mean 15 and standard deviation 3. If the whole group has 250 items with mean 15.6 and standard deviation 13.44,\sqrt {13.44} , then the standard deviation of the second sample is
View answer and explanation
Correct option: C
4
Option C (4) is correct because it is the standard deviation calculated using the combined mean and standard deviation formulas, accounting for both samples.
112 Easy
112 of 312
Application +4 | -1
The mean and variance of 20 observations are found to be 10 and 4, respectively. On rechecking, it was found that an observation 9 was incorrect and the correct observation was 11. Then the correct variance is
View answer and explanation
Correct option: B
3.99
Option A (1, -1, 1) is correct because it satisfies the equation of the plane found using the midpoint and normal vector.
113 Easy
113 of 312
Understanding +4 | -1
If there exists a linear statistical relationship between two variable x  and  y{x\;and\;y}, then the regression coefficient of y  on    x{y\;on\;\;x} is
View answer and explanation
Correct option: C
cov(x,y)σx2\frac{{cov\left( {x,y} \right)}}{{\sigma _x^2}}
Option C (cov(x,y)σx2\frac{{cov\left( {x,y} \right)}}{{\sigma _x^2}}) is correct because it is the formula for the regression coefficient of y on x.
114 Easy
114 of 312
Understanding +4 | -1
A body is on the point of sliding down an inclined plane under its own weight. If the inclination of the plane to the horizon be 30∘30^{\circ}, the angle of friction will be
View answer and explanation
Correct option: A
30∘30^{\circ}
Option A (30∘30^{\circ}) is correct because when a body is on the point of sliding, the angle of inclination is equal to the angle of friction.
115 Easy
115 of 312
Application +4 | -1
The AM of 2n+1C0,    2n+1C1,  2n+1C2,…,  2n+1Cn^{2n + 1}{C_0},\;{\;^{2n + 1}}{C_1},{\;^{2n + 1}}{C_2}, \ldots ,{\;^{2n + 1}}{C_n} is
View answer and explanation
Correct option: D
22n(n+1)\frac{{{2^{2n}}}}{{\left( {n + 1} \right)}}
Option D (22n(n+1)\frac{{{2^{2n}}}}{{\left( {n + 1} \right)}}) is correct because it represents the arithmetic mean of the given binomial coefficients.
116 Easy
116 of 312
Application +4 | -1
Let a,b∈Ra, b \in {R}. Let the mean and the variance of 6 observations −3,4,7,−6,a,b-3,4,7,-6, a, b be 2 and 23, respectively. The mean deviation about the mean of these 6 observations is:
View answer and explanation
Correct option: A
133\frac{13}{3}
Option A (133\frac{13}{3}) is correct because it calculates the mean deviation about the mean of the given observations after finding the values of a and b.
117 Easy
117 of 312
Understanding +4 | -1
Consider the following statements

(1) Mode can be computed from histogram

(2) Median is not independent of change of scale

(3) Variance is independent of change of origin and scale

Which of these is/are correct?
View answer and explanation
Correct option: C
Only (1) and (2)
Option C (Only (1) and (2)) is correct because mode can be computed from a histogram, and the median is not independent of a change of scale. Variance is dependent on the change of scale.
118 Easy
118 of 312
Analyzing +4 | -1
Suppose values taken by a variable xx are such that a≤xi≤ba \leq x_i \leq b, where xix_i denotes the value of xx in the ii th case for i=1,2,3,…,ni=1,2,3, \ldots, n. Then,
View answer and explanation
Correct option: D
(b−a)2≥Var⁡(x)(b-a)^2 \geq \operatorname{Var}(x)
Option D ((b−a)2≥Var⁡(x)(b-a)^2 \geq \operatorname{{Var}}(x)) is correct because the variance is always less than or equal to the square of the range.
119 Easy
119 of 312
Application +4 | -1
The variance of first n numbers is
View answer and explanation
Correct option: B
n2−112\frac{{{n^2} - 1}}{{12}}
Option B (n2−112\frac{{{n^2} - 1}}{{12}}) is correct because it is the standard formula for the variance of the first n natural numbers.
120 Easy
120 of 312
Understanding +4 | -1
The standard deviation of certain data is 4 . Then, their variance is
View answer and explanation
Correct option: B
16
Option B (16) is correct because variance is the square of the standard deviation, so 42=164^2 = 16.
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