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JEE • MATHEMATICS • STATISTICS

Statistics practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 121-150 of 312 questions

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121 Easy
121 of 312
Application +4 | -1
The standard deviations of two sets containing 10 and 20 members are 2 and 3 , respectively measured from their common mean 5 . The SD for the whole set of 30 members is
View answer and explanation
Correct option: C
223\sqrt{\frac{22}{3}}
Option C (223\sqrt{\frac{22}{3}}) is correct because it is the standard deviation calculated using the formula for combined standard deviation.
122 Easy
122 of 312
Application +4 | -1
The variance of 15 observations was found to be 8 . If each observation is multiplied by 4 , the new variance of the series is
View answer and explanation
Correct option: D
128
Option D (128) is correct because multiplying each observation by a constant multiplies the variance by the square of that constant.
123 Easy
123 of 312
Application +4 | -1
In a class of 50 students, 10 have failed and their average marks are 28. The total marks obtained by the entire class are 2800. The average marks of those who have passed, are
View answer and explanation
Correct option: C
63
The correct answer is C (63) because it is calculated by subtracting the total marks of failed students from the total marks of all students, then dividing by the number of passed students.
124 Easy
124 of 312
Application +4 | -1
If the sum of 11 consecutive natural numbers is 2761, then the middle number is
View answer and explanation
Correct option: C
251
Option C (251) is correct because when the sum of consecutive numbers is known, dividing the sum by the number of terms gives the middle term directly when the number of terms is odd.
125 Easy
125 of 312
Application +4 | -1
If n=10,xˉ=12n=10, \bar{x}=12 and Σx2=1530\Sigma x^2=1530, then coefficient of variation is
View answer and explanation
Correct option: C
25
Option C (25) is correct because the coefficient of variation is calculated using the formula C.V = 100 * (standard deviation / mean).
126 Easy
126 of 312
Understanding +4 | -1
The standard deviation of the wages of 85 employees is ₹ 15.40. After one year, each of them is given an increment of ₹ 25 . The standard deviation of new wages (in ₹ˉ\bar{₹} ) is
View answer and explanation
Correct option: A
15.4
Option A (15.4) is correct because the standard deviation is independent of the change of origin (adding a constant to each value).
127 Easy
127 of 312
Application +4 | -1
The mean deviation from the mean of the series a,  a+d,a+2  d,…,a+2nd,\mathrm{a},\mathrm{\;}a + d,a + 2\;d, \ldots ,a + 2nd, is
View answer and explanation
Correct option: B
n(n+1)d2  n+1\frac{{n\left( {n + 1} \right)d}}{{2\;n + 1}}
Option B (n(n+1)d2;n+1\frac{{n\left( {n + 1} \right)d}}{{2\\;n + 1}}) is correct because it represents the mean deviation from the mean of the given arithmetic series.
128 Easy
128 of 312
Application +4 | -1
Harmonic mean of 2,4,52,4,5 is.....
View answer and explanation
Correct option: B
3.16
Option B (3.16) is correct because it is the result of calculating the harmonic mean of the given numbers 2, 4, and 5.
129 Easy
129 of 312
Application +4 | -1
In a bivariate data Σx=30,  Σy=400,  Σx2=196,  Σxy=850  and  n=10.  \mathrm{\Sigma }x = 30,\;\mathrm{\Sigma }y = 400,\;\mathrm{\Sigma }{x^2} = 196,\;\mathrm{\Sigma }xy = 850\;and\;n = 10.\;. the regression coefficient of y on x is
View answer and explanation
Correct option: C
-3.3
Option -3.3 is correct because the regression coefficient of y on x is calculated using the covariance of x and y, and the variance of x.
130 Easy
130 of 312
Application +4 | -1
The average of the four-digit numbers that can be formed using each of the digits 3, 5, 7 and 9 exactly once in each number, is
View answer and explanation
Correct option: C
6666
The correct answer is C (6666) because it is the average of all possible four-digit numbers formed by the given digits.
131 Easy
131 of 312
Application +4 | -1
If Cov⁡(x,y)=−165,Var⁡(x)=2.89,Var⁡(y)=100\operatorname{Cov}(x, y)=-165, \operatorname{Var}(x)=2.89, \operatorname{Var}(y)=100, then the coefficient of correlation is
View answer and explanation
Correct option: A
-0.97
Option A (-0.97) is correct because the correlation coefficient is calculated by dividing the covariance by the product of the standard deviations.
132 Easy
132 of 312
Remembering +4 | -1
Mode of the data 5,7,2,7,7,4,7,7,6,75,7,2,7,7,4,7,7,6,7 is
View answer and explanation
Correct option: D
7
Option D (7) is correct because the mode is the value that appears most frequently in the data set, and 7 appears 5 times, which is more than any other value.
133 Easy
133 of 312
Analyzing +4 | -1
If a variable xx takes values xi{x_i} such that a≤xi≤ba \le {x_i} \le b, for i=1,  2,  …ni = 1,\;2,\; \ldots n, then
View answer and explanation
Correct option: D
(b−a)2≥var(x){\left( {b - a} \right)^2} \ge \mathrm{var}\left( x \right)
Option D ((b−a)2≥var(x){\left( {b - a} \right)^2} \ge \mathrm{var}\left( x \right)) is correct because the variance is always less than or equal to the square of the range (b-a).
134 Easy
134 of 312
Application +4 | -1
If 25%25 \% of the items are less than 2020 and 25%25 \% are more then 4040 , the quartile deviation is
View answer and explanation
Correct option: D
10
Option D (10) is correct because it correctly calculates the quartile deviation using the given quartiles.
135 Easy
135 of 312
Application +4 | -1
10 is the mean of a set of 7 observations and 5 is the mean of a set of 3 observations. The mean of the combined set is given by
View answer and explanation
Correct option: C
8.5
Option C (8.5) is correct because the combined mean is calculated by weighting the means by the number of observations in each set.
136 Easy
136 of 312
Application +4 | -1
Consider the following data
1,2,3,4,5,6,7,8,9,101,2,3,4,5,6,7,8,9,10
If 1 is added to each number, then variance of the numbers so obtained is
View answer and explanation
Correct option: A
8.25
Option A (8.25) is correct because adding a constant to each data point does not change the variance of the data set.
137 Easy
137 of 312
Application +4 | -1
The median value of observations 83,54,78,64,9083,54,78,64,90, 59,67,72,70,7359,67,72,70,73 is
View answer and explanation
Correct option: B
71
Option B (71) is correct because when the observations are sorted, the median is the average of the 5th and 6th terms, which equals 71.
138 Easy
138 of 312
Application +4 | -1
The weighted AM of first n natural numbers whose weights are equal to the corresponding numbers is equal to
View answer and explanation
Correct option: C
13(2  n+1)\frac{1}{3}\left( {2\;n + 1} \right)
Option C (13(2  n+1)\frac{1}{3}\left( {2\;n + 1} \right)) is correct because the weighted AM is calculated by dividing the sum of the products of the numbers and their weights by the sum of the weights.
139 Easy
139 of 312
Application +4 | -1
Assuming the variance of four numbers a,b,ca , b, c and dd as 9, the variance of 5a,5b,5c5 a, 5 b, 5 c and 5d5 d is
View answer and explanation
Correct option: D
225
Option D (225) is correct because the variance is scaled by the square of the scaling factor.
140 Easy
140 of 312
Application +4 | -1
The mean height of 15 students is 154 cm154 \mathrm{~cm}. It is discovered later on that while calculating the mean the reading 175cm175 \mathrm{cm}. was wrongly read as 145 cm145 \mathrm{~cm}. The correct mean height is
View answer and explanation
Correct option: C
156 cm156 \mathrm{~cm}
Option C (156 cm) is correct because it calculates the correct mean by adjusting the sum of heights based on the error.
141 Easy
141 of 312
Understanding +4 | -1
The arithmetic mean of the series nC0,nC1,nC2,…{ }^n C_0,{ }^n C_1,{ }^n C_2, \ldots, nCn{ }^n C_n is
View answer and explanation
Correct option: A
2n/(n+1)2^n /(n+1)
Option A (2n/(n+1)2^n /(n+1)) is correct because it represents the arithmetic mean of the binomial coefficients nC0,nC1,nC2,…{ }^n C_0,{ }^n C_1,{ }^n C_2, \ldots, nCn{ }^n C_n.
142 Easy
142 of 312
Application +4 | -1
The two lines of regression are given by 3x+2y=26  and  6x+y=31.3x + 2y = 26\;and\;6x + y = 31. The coefficient of correlation between x  and  yx\;and\;y is
View answer and explanation
Correct option: C
−1/2- 1/2
Option C (-1/2) is correct because the correlation coefficient is the negative square root of the product of the regression coefficients when both regression coefficients are negative.
143 Easy
143 of 312
Application +4 | -1
The mean and standard deviation of 20 observations were calculated as 10 and 2.5 respectively. It was found that by mistake one data value was taken as 25 instead of 35. If α\alpha and β\beta are the mean and standard deviation respectively for correct data, then (α, β)\left( {\alpha ,\,\beta } \right) is
View answer and explanation
Correct option: D
(10.5, 26)
Option D (10.5, 26) is correct because after correcting the data, the new mean and standard deviation are calculated, resulting in the given values.
144 Easy
144 of 312
Application +4 | -1
A group of 10 items has arithmetic mean 6. If the arithmetic mean of 4 of these items is 7.5, then the mean of the remaining items is
View answer and explanation
Correct option: D
5.05.0
Option D (5.05.0) is correct because it is the mean of the remaining items calculated using the weighted average formula.
145 Easy
145 of 312
Application +4 | -1
One set containing five members has mean 8 , variance 18 and the second set containing three members has mean 8 and variance 24 . The variance of combined set of numbers is
View answer and explanation
Correct option: B
20.25
Option B (20.25) is correct because it is the variance calculated using the formula for combined variance.
146 Easy
146 of 312
Analyzing +4 | -1
For the arithmetic progression a,(a+d),(a+2d),(a+3d),……,(a+2nd)a,\left( {a + d} \right),\left( {a + 2d} \right),\left( {a + 3d} \right), \ldots \ldots ,\left( {a + 2nd} \right), the mean deviation from mean is
View answer and explanation
Correct option: B
n(n+1)d2n+1\frac{{n\left( {n + 1} \right)d}}{{2n + 1}}
Option B (n(n+1)d2n+1\frac{{n\left( {n + 1} \right)d}}{{2n + 1}}) is correct because the mean deviation from the mean for the given arithmetic progression is calculated to be this value.
147 Easy
147 of 312
Understanding +4 | -1
Angle between two lines of regression is
View answer and explanation
Correct option: B
tan⁡−1(r1r2−1r1+r2)\tan ^{-1}\left(\frac{r_1 r_2-1}{r_1+r_2}\right)
Option B (tan⁡−1(r1r2−1r1+r2)\tan ^{-1}\left(\frac{{r_1 r_2-1}}{{r_1+r_2}}\right)) is correct because it represents the formula for the angle between two lines with slopes derived from the regression coefficients.
148 Easy
148 of 312
Analyzing +4 | -1
Let SS be the set of all values of a1a_1 for which the mean deviation about the mean of 100 consecutive positive integers a1,a2,a3,.....,a100{a_1},{a_2},{a_3},.....,{a_{100}} is 25. Then SS is
View answer and explanation
Correct option: D
N
The correct answer is N because the mean deviation about the mean is independent of the first term of the consecutive integers.
149 Easy
149 of 312
Application +4 | -1
For a given distribution of marks, mean is 35.16 and its standard deviation is 19.76 . The coefficient of variation is
View answer and explanation
Correct option: A
56.2
Option A (56.2) is correct because the coefficient of variation is calculated by dividing the standard deviation by the mean and multiplying by 100.
150 Easy
150 of 312
Application +4 | -1
The mean deviation of any series is 15 , then the value of quartile deviation is
View answer and explanation
Correct option: C
12.5
Option C (12.5) is correct because it is the quartile deviation calculated using the relationship between mean deviation and quartile deviation.
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