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JEE • MATHEMATICS • STATISTICS

Statistics practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 312 questions

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61 Easy
61 of 312
Application +4 | -1
The variance of first 50 even natural numbers is
View answer and explanation
Correct option: B
833
Option B (833) is correct because the variance of the first 50 even natural numbers is calculated using the formula for variance and the sum of squares.
62 Easy
62 of 312
Remembering +4 | -1
The intersecting point of two regression lines is
View answer and explanation
Correct option: D
(xˉ,yˉ)(\bar x,\bar y)
Option D ((xˉ,yˉ)(\bar x,\bar y)) is correct because the point of intersection of the two regression lines is the mean of x and y, represented as (xˉ,yˉ)(\bar x,\bar y).
63 Easy
63 of 312
Application +4 | -1
The AM of the series 1,2,4,8,16,…,2n,1,2,4,8,16, \ldots ,{2^n}, is
View answer and explanation
Correct option: B
2n+1−1n+1\frac{{{2^{n + 1}} - 1}}{{n + 1}}
Option B (2n+1−1n+1\frac{{{2^{n + 1}} - 1}}{{n + 1}}) is correct because it represents the arithmetic mean of a geometric series with the given terms.
64 Easy
64 of 312
Application +4 | -1
The mode of a moderately symmetrical series is 18 and mean is 24 . The median is
View answer and explanation
Correct option: C
22
Option C (22) is correct because it is the median calculated using the empirical relationship between mean, median, and mode for a moderately symmetrical series.
65 Easy
65 of 312
Application +4 | -1
The mean of a set of 30 observations is 75 . If each other observation is multiplied by a non-zero number λ\lambda and then each of them is decreased by 25 , their mean remains the same. The λ\lambda is equal to
View answer and explanation
Correct option: B
43\frac{4}{3}
Option B (43\frac{4}{3}) is correct because setting up the equation for the new mean and solving for λ\lambda gives λ=43\lambda = \frac{4}{3}.
66 Easy
66 of 312
Application +4 | -1
The coefficient of variation of two series are 70 and 90 and their standard deviation are 17.5 and 18 , respectively. The mean of two series are
View answer and explanation
Correct option: A
25,20
Option A (25,20) is correct because the means are calculated by rearranging the coefficient of variation formula.
67 Easy
67 of 312
Application +4 | -1
The mean of the numbers a,  b,  8,  5,  10a,\,\,b,\,\,8,\,\,5,\,\,10 is 6 and their variance is 6.8. If MM is the mean deviation of the numbers about the mean, then 25M25 M is equal to:
View answer and explanation
Correct option: A
60
Option C (5) is correct because it is the remainder when (2021)2023 is divided by 7, calculated using modular arithmetic.
68 Easy
68 of 312
Application +4 | -1
If the two regression coefficients are 0.8 and 0.2 , then the coefficient of correlation is
View answer and explanation
Correct option: A
0.4
Option A (0.4) is correct because the correlation coefficient is the geometric mean of the two regression coefficients.
69 Easy
69 of 312
Application +4 | -1
Mean of 100 observation is 45. If it was later found that two observations 19 and 31 were incorrectly recorded as 91 and 13. The correct mean is
View answer and explanation
Correct option: C
44.46
Option C (44.46) is correct because the correct mean is calculated by subtracting the incorrect observations and adding the correct observations before dividing by the total number of observations.
70 Easy
70 of 312
Application +4 | -1
If mode of a data is 27 and mean is 24 , then median is
View answer and explanation
Correct option: B
25
Option B (25) is correct because the median is calculated correctly using the empirical relationship between mean, median, and mode.
71 Easy
71 of 312
Remembering +4 | -1
Quartile deviation is nearly equal to
View answer and explanation
Correct option: C
2/3σ2 / 3 \sigma
Option C (2/3σ2 / 3 \sigma) is correct because the quartile deviation is approximately 2/3 of the standard deviation.
72 Easy
72 of 312
Application +4 | -1
In a moderately skewed distribution, the values of mean and median are 5 and 6 , respectively. The value of mode for such distribution is
View answer and explanation
Correct option: A
8
Option A (8) is correct because the mode is calculated using the empirical relationship between mean, median, and mode in a moderately skewed distribution.
73 Easy
73 of 312
Application +4 | -1
If the variance of 1, 2, 3, 4, 5, ..., 10 is 9912\frac{{99}}{{12}}, then the standard derivation of 3, 6, 9, 12, ..., 30 is
View answer and explanation
Correct option: B
3233\frac{3}{2}\sqrt {33}
Option B (3233\frac{3}{2}\sqrt {33}) is correct because the standard deviation of the new series is 3 times the standard deviation of the original series.
74 Easy
74 of 312
Application +4 | -1
The coefficient of variation of two series are 58%58 \% and 69%69 \%. If their standard deviations are 21.2 and 15.6 , then their A.Ms are
View answer and explanation
Correct option: A
36.6,22.636.6,22.6
Option A (36.6,22.636.6,22.6) is correct because it accurately calculates the arithmetic means of the two series using their coefficients of variation and standard deviations.
75 Easy
75 of 312
Understanding +4 | -1
Mode of the data 3,2,5,2,3,5,6,6,5,3,5,2,53,2,5,2,3,5,6,6,5,3,5,2,5 is-
View answer and explanation
Correct option: C
5
Option C (5) is correct because 5 appears most frequently in the given data set.
76 Easy
76 of 312
Application +4 | -1
The co-efficient of rank correlation of marks obtained by 10 students in Statistics and Accountancy was found to be 0.2 . It was later discovered that the difference in ranks in the two subjects obtained by one of the students was wrongly taken as 9 instead of 7 . The correct value of co-efficient of rank correlation is
View answer and explanation
Correct option: B
0.39
Option B (0.39) is correct because it correctly adjusts the rank correlation coefficient after correcting the error in the difference of ranks.
77 Easy
77 of 312
Application +4 | -1
Let the mean and the variance of 5 observations x1x_1, x2,x3,x4,x5x_2, x_3, x_4, x_5 be 245\frac{24}{5} and 19425\frac{194}{25} respectively. If the mean and variance of the first 4 observation are 72\frac{7}{2} and a respectively, then (4a+x5)\left(4 a+x_5\right) is equal to
View answer and explanation
Correct option: B
15
Option B (15) is correct because it is the value obtained by using the given mean and variance to find the missing value and then calculating 4a + x_5.
78 Easy
78 of 312
Application +4 | -1
Given the following results for the height (x)(x) and weight (y) in appropriate units of 1000 students: xˉ=68\bar{x}=68, yˉ=150,σx=2.5,σy=20,r=0.60\bar{y}=150, \sigma_x=2.5, \sigma_y=20, r=0.60.
The height of a student A who weights 200 units is
View answer and explanation
Correct option: C
71.75
Option A (68.75) is correct because it uses the regression equation of x on y to predict the height of a student given their weight.
79 Easy
79 of 312
Understanding +4 | -1
If xx and yy are independent variables, then two lines of regression are
View answer and explanation
Correct option: D
x=x= constant, y=y= constant
Option D (x=x= constant, y=y= constant) is correct because when x and y are independent, their regression lines are horizontal and vertical lines respectively, indicating constant values.
80 Easy
80 of 312
Application +4 | -1
If the variables with values 10, 20, 30, 40 have frequencies x,x+2,x−2,x+4x, x+2, x-2, x+4 and the mean is 2.7 then the value of xx is
View answer and explanation
Correct option: B
4
Option B (4) is correct because, by substituting the given values into the mean formula, we can solve for x.
81 Easy
81 of 312
Application +4 | -1
If the mean and variance of six observations 7, 10, 11, 15, aa, bb are 10 and 203\frac{{20}}{3} respectively, then the value of ∣a−b∣\left| {a - b} \right| is equal to
View answer and explanation
Correct option: D
1
Option D (1) is correct because solving the mean and variance equations leads to two possible values for a and b, resulting in |a-b| = 1.
82 Easy
82 of 312
Application +4 | -1
If in a frequency distribution, the mean and median are 25 and 26 , then its mode is approximately.
View answer and explanation
Correct option: A
28
Option A (28) is correct because the mode can be approximated using the empirical relationship: Mode = 3 Median - 2 Mean.
83 Easy
83 of 312
Application +4 | -1
The number of runs scored by 11 players of a cricket team of school are 5,19,425,19,42, 11,50,30,21,0,52,36,2711,50,30,21,0,52,36,27. The median is-
View answer and explanation
Correct option: B
27
Option B (27) is correct because it is the middle value when the data is arranged in ascending order.
84 Easy
84 of 312
Understanding +4 | -1
The values of mean, median and mode coincide, then the distribution is
View answer and explanation
Correct option: B
Symmetric distribution
Option B (Symmetric distribution) is correct because in a symmetric distribution, the mean, median, and mode are equal.
85 Easy
85 of 312
Understanding +4 | -1
If a variate XX is expressed as a linear function of two variates U  and    V{\cal U}\;and\;\;V the form X=a  U+b  V,X = a\;{\cal U} + b\;V, then mean Xˉ  of X\bar X\;of\,X is
View answer and explanation
Correct option: A
aUˉ+bVˉa\bar {\cal U} + b\bar V
Option A (aUˉ+bVˉa\bar {\cal U} + b\bar V) is correct because the mean of a linear combination of variables is the same linear combination of their means.
86 Easy
86 of 312
Application +4 | -1
Let the sum of the first three terms of an A. P, be 39 and the sum of its last four terms be 178 . If the first term of this A.P. is 10 , then the median of the A.P. is :
View answer and explanation
Correct option: C
29.5
The correct answer is C (29.5) because the median of the A.P. is calculated using the given information about the sum of the first three terms and the sum of the last four terms.
87 Easy
87 of 312
Application +4 | -1
If ∑i=118(xi−8)=9\sum\limits_{{i=1}}^{18}\left(x_i-8\right)=9 and ∑i=118(xi−8)2=45\sum\limits_{{i=1}}^{18}\left(x_i-8\right)^2=45 then the standard deviatioin of x1,x2……x18x_1, x_2 \ldots \ldots x_{18} is
View answer and explanation
Correct option: C
32\frac{3}{2}
Option C (32\frac{3}{2}) is correct because it is the standard deviation calculated using the given summation formulas and the properties of variance.
88 Easy
88 of 312
Application +4 | -1
The weighted mean of the first nn natural numbers if their weights are the same as the numbers, is
View answer and explanation
Correct option: B
2n+13\frac{2 n+1}{3}
Option B ((2 n+1)/3) is correct because it calculates the weighted mean using the formula with the numbers as weights.
89 Easy
89 of 312
Application +4 | -1
If the mean and variance of the following data: 6, 10, 7, 13, a, 12, b, 12 are 9 and 374\frac{{37}}{4} respectively, then (a−b)2{(a - b)^2} is equal to
View answer and explanation
Correct option: D
16
Option D (16) is correct because by using the given mean and variance, we can solve for a and b, and then calculate (a-b)2.
90 Easy
90 of 312
Application +4 | -1
The sum of the four arithmetic means between 4 and 40 is
View answer and explanation
Correct option: B
88
Option B (88) is correct because the sum of arithmetic means can be calculated directly using the formula.
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