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JEE MATHEMATICS MCQ: STATISTICS

1 Easy
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Application +4 | -1
Standard deviation of the first 2n+12n + 1 natural numbers is equal to
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Correct option: C
n(n+1)3\sqrt {\frac{{n\left( {n + 1} \right)}}{3}}
The correct answer is C (n(n+1)3\sqrt {\frac{{n\left( {n + 1} \right)}}{3}}) because it is the standard deviation formula for the first 2n+12n+1 natural numbers.

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