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JEE • MATHEMATICS • STATISTICS

Statistics practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 271-300 of 465 questions

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271 Easy
271 of 465
Application +4 | -1
For the data 2,2,3,3,3,4,4,5,6,8,8,8,82,2,3,3,3,4,4,5,6,8,8,8,8, the mean, median and mode are
View answer and explanation
Correct option: D
64/13,4,864 / 13,4,8
Option D (64/13,4,864 / 13,4,8) is correct because the calculated mean is 64/13, the median is 4, and the mode is 8.
272 Easy
272 of 465
Application +4 | -1
In a class of 100 students, the average amount of pocket money is Rs 35 per student. If the average is Rs 25 for girls and Rs 50 for boys, then the number of girls in the class is
View answer and explanation
Correct option: C
60
The correct answer is C (60) because it is calculated by setting up and solving a weighted average equation.
273 Easy
273 of 465
Application +4 | -1
Coefficient of variation of two distribution are 50%50 \% and 60%60 \% and their standard deviation are 10 and 15, respectively. Then, difference of their arithmetic means is
View answer and explanation
Correct option: A
5
Option A (5) is correct because by using the formula for the coefficient of variation, we can find the arithmetic means and then calculate their difference.
274 Easy
274 of 465
Application +4 | -1
If   xˉ=yˉ=0,  ∑xiyi=12,  σX=2,  σY=3  and  n=10,\;\bar x = \bar y = 0,\;\sum {x_i}{y_i} = 12,\;{\sigma _X} = 2,\;{\sigma _Y} = 3\;and\;n = 10, then the coefficient of correlation is
View answer and explanation
Correct option: C
0.2
Option C (0.2) is correct because it is calculated using the formula for the correlation coefficient given the means, sum of products, standard deviations, and number of observations.
275 Easy
275 of 465
Application +4 | -1
The line of regression of yy on xx and xx on yy are respectively y=x+5y=x+5 and 16x−9y=9416 x-9 y=94. If the variance of yy is 16 , then the variance of xx is
View answer and explanation
Correct option: A
9
Option B (0≤K≤140 \leq {K} \leq \frac{{1}}{{4}}) is correct because the product of the regression coefficients must be less than or equal to 1.
276 Easy
276 of 465
Application +4 | -1
If Var(x)=8.25,Var\left( x \right) = 8.25, Var(y)=33.96Var\left( y \right) = 33.96 and cov(x,y)=10.2\mathrm{cov}\left( {x,y} \right) = 10.2 then the correlation coefficient is
View answer and explanation
Correct option: C
0.610.61
Option C (0.610.61) is correct because it is the result of applying the formula for the correlation coefficient using the given variance and covariance values.
277 Easy
277 of 465
Application +4 | -1
If the mean of a set of observations x1,x2,  …x10{x_1},{x_2},\; \ldots {x_{10}} is 20, then the mean of x1+4,  x2+8,  …x10+40{x_1} + 4,\;{x_2} + 8,\; \ldots {x_{10}} + 40 is
View answer and explanation
Correct option: D
42
Option D (42) is correct because it is the new mean calculated by adding the average of the increments to the original mean.
278 Easy
278 of 465
Application +4 | -1
Mean and standard deviation from the following observations of marks of 5 students of a tutorial group (marks out of 25)8, 12, 13, 15, 22 are respectively
View answer and explanation
Correct option: A
14,4.60414,\mathrm{ }4.604
Option A (14,4.60414,\mathrm{ }4.604) is correct because the mean and standard deviation are calculated correctly from the given observations.
279 Medium
279 of 465
Application +4 | -1
If a variate takes values a,ar,ar2,…,arn−1a, a r, a r^2, \ldots, a r^{n-1}, then which of the relation between means bold?
View answer and explanation
Correct option: A
AH=G2A H=G^2
Option A (AH=G2A H=G^2) is correct because the Arithmetic mean (A), Geometric mean (G), and Harmonic mean (H) of a geometric progression satisfy this relationship.
280 Easy
280 of 465
Application +4 | -1
Assertion: The mean deviation of the data 2, 9, 9, 3, 6, 9, 4
from the mean is 2.57.

Reason: For individual observation, Mean  deviation  (Xˉ)=∑∣xi−xˉ∣n{\text{Mean}}\,\,{\text{deviation}}\,\,\left( {\bar X} \right) = \frac{{\sum {\left| {{x_i} - \bar x} \right|} }}{n}
View answer and explanation
Correct option: A
Assertion is correct, reason is correct; reason is a correct
explanation for assertion
Option A is correct because the calculated mean deviation matches the assertion's value, and the reason correctly states the formula for mean deviation.
281 Easy
281 of 465
Application +4 | -1
The correlation between two variables xx and yy is given to be rr. The values of xx and yy change such that Cov⁡(x,y)\operatorname{Cov}(x, y) remains unaltered and Var⁡(x)\operatorname{Var}(x) and Var⁡(y)\operatorname{Var}(y) are changed to four times their original values. The new correlation coefficient is changed to
View answer and explanation
Correct option: B
16r16 \mathrm{r}
Option D (r4\frac{r}{4}) is correct because the new correlation coefficient is the original correlation coefficient divided by 4 due to the change in variances.
282 Easy
282 of 465
Analyzing +4 | -1
The number of values of a∈Na \in N such that the variance of 3,7,12,a,43−a3,7,12, a, 43-a is a natural number is :
View answer and explanation
Correct option: A
0
Option A (0) is correct because the variance calculation results in a non-natural number for all natural number values of 'a'.
283 Easy
283 of 465
Application +4 | -1
Median of 16,10,14,11,9,8,12,6,516,10,14,11,9,8,12,6,5 is
View answer and explanation
Correct option: A
10
Option A (10) is correct because after arranging the data in ascending order, the median is the middle value.
284 Easy
284 of 465
Application +4 | -1
The mean of 100 items is 49 . It was later discovered that three items taken as 40,20,5040,20,50 were actually 60 , 70,80 , respectively. The correct mean is
View answer and explanation
Correct option: C
50
Option C (50) is correct because the correct mean is calculated by adjusting the original sum with the corrected values and then dividing by the number of items.
285 Easy
285 of 465
Application +4 | -1
The marks of some students were listed out of 75. The SD of marks was found to be 9. Subsequently the marks were raised to a maximum of 100 and variance of new marks was calculated. The new variance is
View answer and explanation
Correct option: C
144
Option C (144) is correct because the variance is scaled by the square of the factor by which the marks are raised.
286 Easy
286 of 465
Application +4 | -1
The coefficient of correlation between xx and yy is 0.5 and their covariance is 16 and SD of xx is 4 , then SD of yy is
View answer and explanation
Correct option: B
8
Option B (8) is correct because it is the standard deviation of y calculated using the formula relating correlation coefficient, covariance, and standard deviations.
287 Medium
287 of 465
Application +4 | -1
The mean and variance of 5 observations are 5 and 8 respectively. If 3 observations are 1,3,51,3,5, then the sum of cubes of the remaining two observations is
View answer and explanation
Correct option: D
1072
The correct answer is D (1072) because the sum of cubes of the remaining two observations is calculated using the given mean and variance.
288 Easy
288 of 465
Application +4 | -1
If the lines of regression of Y{Y} on X{X} and X{X} on Y{Y} are respectively y=Kx+4y={K} x+4 and x=4y+5x=4 y+5, then
View answer and explanation
Correct option: B
0≤K≤140 \leq {K} \leq \frac{1}{4}
Option B (0≤K≤140 \leq {K} \leq \frac{1}{4}) is correct because the product of the regression coefficients must be less than or equal to 1, ensuring that the correlation coefficient's square is within the valid range.
289 Easy
289 of 465
Application +4 | -1
If the standard deviation of the numbers −1, 0, 1, k- 1,\,0,\,1,\,k is 5\sqrt 5 where k>0k > 0, then kk is equal to
View answer and explanation
Correct option: B
262\sqrt 6
Option B (262\sqrt 6) is correct because, using the formula for standard deviation and the given values, we can solve for k and find its value to be 262\sqrt 6.
290 Easy
290 of 465
Analyzing +4 | -1
Consider three observations a, ba,\,b and cc such that b = a + cb\, = \,a\, + \,c. If the standard deviation of a + 2, b + 2c, c + 2a\, + \,2,\,b\, + \,2c,\,c\, + \,2 is dd, then which of the following is true?
View answer and explanation
Correct option: B
b2=3(a2+c2)−9d2{b^2} = 3\left( {{a^2} + {c^2}} \right) - 9{d^2}
Option B (b2=3(a2+c2)−9d2{b^2} = 3\left( {{a^2} + {c^2}} \right) - 9{d^2}) is correct because it represents the relationship between the standard deviation and the given condition b = a + c.
291 Medium
291 of 465
Application +4 | -1
The median of 100 observations grouped in classes of equal width is 25 . If the median class interval is 20−3020-30 and the number of observations less than 20 is 45 , then the frequency of median class is
View answer and explanation
Correct option: A
10
Option A (10) is correct. The frequency of the median class is calculated using the median formula for grouped data.
292 Easy
292 of 465
Application +4 | -1
The arithmetic mean of the series 1,2,22,…,2n−11,2,2^2, \ldots, 2^{n-1} is
View answer and explanation
Correct option: B
(2n−1)/n\left(2^n-1\right) / n
Option B (2n−1n\frac{{2^n-1}}{{n}}) is correct because the arithmetic mean of a geometric series is the sum of the series divided by the number of terms.
293 Easy
293 of 465
Application +4 | -1
If the value of mode and mean is 60 and 66 respectively, then the value of median is-
View answer and explanation
Correct option: B
64
Option B (64) is correct because it is calculated using the empirical relationship between mode, median, and mean: Mode = 3 Median - 2 Mean.
294 Easy
294 of 465
Application +4 | -1
If the lines of regression are 3x+12y=19  and  3y+9x=46,  then  rxy3x + 12y = 19\;\mathrm{and}\;3y + 9x = 46,\;\mathrm{then}\;{r_{xy}}, will be
View answer and explanation
Correct option: B
−0.289- 0.289
Option B (−0.289-0.289) is correct because it is the result of calculating the correlation coefficient from the given regression lines, ensuring the correct sign.
295 Medium
295 of 465
Application +4 | -1
The average marks of boys in a class is 52 and that of girls is 42. The average marks of boys and girls combined is 50. The percentage of boys in the class is
View answer and explanation
Correct option: C
80%80\%
Option C (80%80\%) is correct because it is the percentage of boys calculated using the weighted average of the marks.
296 Medium
296 of 465
Application +4 | -1
The quartile deviation of daily wages (in ₹) of 11 persons given below, is
140,145,130,165,160,125,150,170,175,120,180140,145,130,165,160,125,150,170,175,120,180
View answer and explanation
Correct option: C
20
Option C (20) is correct because the quartile deviation is calculated as half the difference between the third and first quartiles.
297 Medium
297 of 465
Application +4 | -1
Given the following frequency distribution with some missing frequencies.
ClassFrequency10−2018020−30−−30−403440−5018050−6013660−70−−70−8050\begin{array}{cccccccccccccccccccc} {{\text{Class}}}&{{\text{Frequency}}} \\ {10 - 20}&{180} \\ {20 - 30}&{ - - } \\ {30 - 40}&{34} \\ {40 - 50}&{180} \\ {50 - 60}&{136} \\ {60 - 70}&{ - - } \\ {70 - 80}&{50} \end{array}

If the total frequency is 685 and median is 42.6 then the missing frequencies are
View answer and explanation
Correct option: C
82, 23
Option C (82, 23) is correct because solving the equations for the total frequency and median yields these missing frequencies.
298 Medium
298 of 465
Application +4 | -1
The mean and s.d. of a sample of size 10 were found
to be 9.5 and 2.5 respectively. Later on, an additional
observation 15 was added to the original data. The
s.d. of 11 observation is
View answer and explanation
Correct option: C
2.86
Option C (2.86) is correct because it is the standard deviation calculated after adding the additional observation and correcting the mean and variance.
299 Medium
299 of 465
Application +4 | -1
If mean and variance of observations 60,60,44,58,68,56,α,β60,60,44,58,68,56, \alpha, \beta are 58 and 66.2 respectively then α2+β2\alpha^2+\beta^2 is equal to
View answer and explanation
Correct option: B
7181.6
The correct answer is B; 7181.6. The problem involves using the formulas for mean and variance to find the values of α\alpha and β\beta, and then calculating α2+β2\alpha^2 + \beta^2.
300 Medium
300 of 465
Analyzing +4 | -1
Let r be the range and S2=1n−1∑i=1n(xi−xˉ)2{S^2} = \frac{1}{{n - 1}}\sum \limits_{i = 1}^n {\left( {{x_i} - \bar x} \right)^2} be the S.D. of a set observations x1,x2,…,xn,{x_1},{x_2}, \ldots ,{x_n}, then
View answer and explanation
Correct option: A
S≤rnn−1S \le r\sqrt {\frac{n}{{n - 1}}}
Option A (S≤rnn−1S \le r\sqrt {\frac{n}{{n - 1}}}) is correct because it represents the relationship between the standard deviation (S) and the range (r) of a set of observations.
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