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JEE • MATHEMATICS • STATISTICS

Statistics practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 301-330 of 465 questions

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301 Medium
301 of 465
Analyzing +4 | -1
Let the mean and variance of 12 observations be 92\frac{9}{2} and 4 respectively. Later on, it was observed that two observations were considered as 9 and 10 instead of 7 and 14 respectively. If the correct variance is mn\frac{m}{n}, where mm and nn are coprime, then m+nm+n are coprime, then m+nm+n is equal to
View answer and explanation
Correct option: D
317
Option D, 317, is the correct value of m+nm+n where the corrected variance is mn\frac{m}{n} and mm and nn are coprime. This is calculated by first finding the correct mean and then the correct variance after adjusting for the incorrect observations.
302 Easy
302 of 465
Understanding +4 | -1
The point that lies on both the lines of regression for a bivariate distribution, is
View answer and explanation
Correct option: B
(xˉ,yˉ)(\bar{x}, \bar{y})
Option B is correct because the point of intersection of the two regression lines is always the means of the x and y variables, represented as (xˉ,yˉ)(\bar{x}, \bar{y}).
303 Easy
303 of 465
Understanding +4 | -1
Median is based on the
View answer and explanation
Correct option: D
middle 50%50 \% of items
Option D (middle 50% of items) is correct because the median represents the central value, dividing the data set into two equal halves, effectively encompassing the middle 50%.
304 Easy
304 of 465
Application +4 | -1
In a test of Statistics, marks were awarded out of 40 . The average of 15 students was 38 . Later, it was decided to give marks out of 50 . The new average marks will be
View answer and explanation
Correct option: B
47.5
Option B (47.5) is correct because the new average is calculated by multiplying the original average by the ratio of the new maximum marks to the old maximum marks.
305 Easy
305 of 465
Application +4 | -1
The mean of two samples of sizes 200 and 300 were found to be 25 and 10 respectively, their standard deviations were 3 and 4 respectively the variance of combined sample size of 500 is
View answer and explanation
Correct option: C
67.2
Option C (67.2) is correct because the combined variance is calculated using the formula σ2=n1(σ12+d12)+n2(σ22+d22)n1+n2\sigma^{2} = \frac{{n_{{1}}(\sigma_{{1}}^{{2}}+d_{{1}}^{{2}})+n_{{2}}(\sigma_{{2}}^{{2}}+d_{{2}}^{{2}})}}{{n_{{1}}+n_{{2}}}}, where did_i is the difference between the individual mean and the combined mean.
306 Easy
306 of 465
Understanding +4 | -1
The mode of the series 3,4,2,6,1,7,6,7,6,8,9,5 is
View answer and explanation
Correct option: B
6
Option B (6) is correct because the mode is the value that appears most frequently in the series, and 6 appears three times, which is more than any other number.
307 Medium
307 of 465
Application +4 | -1
The mean and variance of a set of 15 numbers are 12 and 14 respectively. The mean and variance of another set of 15 numbers are 14 and σ2\sigma^{2} respectively. If the variance of all the 30 numbers in the two sets is 13 , then σ2\sigma^{2} is equal to
View answer and explanation
Correct option: A
10
Option A (10) is correct because it is the variance of the second set of numbers, calculated using the combined variance formula.
308 Easy
308 of 465
Application +4 | -1
The variance of the first nn natural numbers is
View answer and explanation
Correct option: A
(n2−112)\left( {\frac{{{n^2} - 1}}{{12}}} \right)
Option A ((n2−112)\left( {\frac{{{{{n^2} - 1}}}}{{{{12}}}}} \right)) is correct because it is the formula for the variance of the first n natural numbers.
309 Easy
309 of 465
Application +4 | -1
The mean of data 55,155,255,35555,155,255,355, 455 and 555 is
View answer and explanation
Correct option: B
305
Option B (305) is correct because the mean is calculated by summing the data points and dividing by the number of points.
310 Easy
310 of 465
Remembering +4 | -1
For a symmetrical distribution, the coefficient of skewness is
View answer and explanation
Correct option: B
0
Option B (0) is correct because in a symmetrical distribution, the mean, median, and mode are equal, resulting in a skewness coefficient of 0.
311 Medium
311 of 465
Application +4 | -1
If the mean and the standard deviation of the data 3, 5, 7, aa, bb are 5 and 2 respectively, then aa and bb are the roots of the equation
View answer and explanation
Correct option: C
x2−10x+19=0{x^2} - 10x + 19 = 0
Option C (x2−10x+19=0{x^2} - 10x + 19 = 0) is correct because the equation is formed using the calculated sum and product of the roots aa and bb from the given mean and standard deviation.
312 Easy
312 of 465
Application +4 | -1
The algebraic sum of the deviation of 20 observations measured from 30 is 2. Then, mean of observations is
View answer and explanation
Correct option: B
30.130.1
Option B (30.130.1) is correct because it is the mean of the observations calculated using the given algebraic sum of deviations.
313 Easy
313 of 465
Application +4 | -1
The mean marks of students of a school is 56 . The mean marks of girls is 60 and that of boys is 50. If number of boys and girls are nn and mm respectively, then 9nm\frac{9 n}{m} equals
View answer and explanation
Correct option: D
6
Option D (6) is correct because it is derived from setting up a weighted average equation for the mean marks of the school and solving for the ratio n/m.
314 Easy
314 of 465
Application +4 | -1
If in a moderately skewed distribution the values of mode and mean are 6  λ  and  9λ6\;\lambda \;and\;9\lambda respectively, then the value of the median is
View answer and explanation
Correct option: A
8  λ8\;\lambda
Option A (8;λ8\\;\lambda) is correct because the median is calculated using the relationship between mean, median, and mode in a moderately skewed distribution.
315 Easy
315 of 465
Application +4 | -1
The mean of the series x1,x2,…,xn{x_1},{x_2}, \ldots ,{x_n} is Xˉ.\bar X. If x2{x_2} is replaced by λ\lambda, then the new mean is
View answer and explanation
Correct option: D
n  Xˉ−x2+λn\frac{{n\;\bar X - {x_2} + \lambda }}{n}
Option D (n  Xˉ−x2+λn\frac{{n\;\bar X - {x_2} + \lambda }}{n}) is correct because it represents the new mean after replacing one of the values in the series.
316 Medium
316 of 465
Application +4 | -1
The mean and standard deviation of a sample of size 20 are found 10 and 2 respectively. If one item 8 is replaced by 12 then
View answer and explanation
Correct option: B
Standard deviation decreases
Option B (Standard deviation decreases) is correct because replacing 8 with 12 increases the mean by a small amount, but the overall spread of the data decreases, leading to a lower standard deviation.
317 Easy
317 of 465
Application +4 | -1
The mean and SD of the marks of 200 candidates were found to be 40 and 15 , respectively. Later, it was discovered that a score of 40 was wrongly read as 50 . The correct mean and SD\mathrm{SD} are respectively
View answer and explanation
Correct option: B
39.95,14.9839.95,14.98
Option B (39.95,14.9839.95,14.98) is correct because the corrected mean is 39.95 and the corrected standard deviation is approximately 14.98.
318 Easy
318 of 465
Application +4 | -1
In a set of 2n2 n distinct observations, each of the observations below the median of all the observations is increased by 5 and each of the remaining observations is decreased by 3 . Then the mean of the new set of observations:
View answer and explanation
Correct option: A
increases by 1
Option A (increases by 1) is correct because increasing the lower half by 5 and decreasing the upper half by 3 results in a net increase of 2 per observation, which averages to 1.
319 Easy
319 of 465
Application +4 | -1
If a variable takes the discrete values α+4,α−72,α−52,α−3,α−2,α+12,α−12\alpha+4, \alpha-\frac{7}{2}, \alpha-\frac{5}{2}, \alpha-3, \alpha-2, \alpha+\frac{1}{2}, \alpha-\frac{1}{2}, α+5(α>0)\alpha+5(\alpha > 0), then the median is
View answer and explanation
Correct option: A
α−54\alpha-\frac{5}{4}
Option A (α−54\alpha-\frac{5}{4}) is correct because it is the median of the given discrete values after arranging them in ascending order.
320 Easy
320 of 465
Application +4 | -1
The mean and variance of 7 observations are 8 and 16 respectively. If two observations are 6 and 8, then the variance of the remaining 5 observations is
View answer and explanation
Correct option: C
53625\frac{{536}}{25}
Option C (53625\frac{{536}}{{25}}) is correct because it is the variance calculated after removing the two observations and adjusting for the new mean.
321 Hard
321 of 465
Application +4 | -1
If a variable X takes values 0,1,2,…,n0,1,2, \ldots ,n with frequencies proportional to the binomial coefficients nC0,  nC1,  nC2,…,  nCn,^n{C_0},{\;^n}{C_1},{\;^n}{C_2}, \ldots ,{\;^n}{C_n}, then the Var  (X)\mathrm{Var\;}\left( X \right) is
View answer and explanation
Correct option: C
n4\frac{n}{4}
Option C (n4\frac{n}{4}) is correct because the variance of a binomial distribution with frequencies proportional to binomial coefficients is n4\frac{n}{4}.
322 Easy
322 of 465
Application +4 | -1
The two lines of regression are 13x−10y+11=013 x-10 y+11=0 and 2x−y−1=02 x-y-1=0, then mean of xx and yy series are
View answer and explanation
Correct option: B
3,5
Option C (4) is correct because the standard deviation of y is calculated using the regression coefficients and the variance of x.
323 Medium
323 of 465
Application +4 | -1
If the average of the numbers 148, 146, 144, 142, ... in AP, be 125, then the total numbers in the series will be
View answer and explanation
Correct option: B
24
Option B (24) is correct because the total number of terms in the AP series is calculated using the average and the properties of arithmetic progressions.
324 Medium
324 of 465
Understanding +4 | -1
The mean and variance for first n{n} natural numbers are respectively
View answer and explanation
Correct option: A
Mean =n+12=\frac{n+1}{2}, variance =n2−112=\frac{n^2-1}{12}
Option A (Mean =n+12\frac{{n+1}}{{2}}, variance =n2−112\frac{{n^2-1}}{{12}}) is correct because it uses the standard formulas for the mean and variance of the first n natural numbers.
325 Easy
325 of 465
Remembering +4 | -1
The sum of absolute deviations about median is
View answer and explanation
Correct option: A
Least
Option A (Least) is correct because the sum of absolute deviations is minimized when taken about the median.
326 Easy
326 of 465
Application +4 | -1
For a symmetrical distribution Q1=20Q_1=20 and Q3=40Q_3=40. The value of 50 th percentile is
View answer and explanation
Correct option: B
30
Option B (30) is correct because for a symmetrical distribution, the 50th percentile (median) is the average of the first and third quartiles.
327 Medium
327 of 465
Application +4 | -1
The mean square deviation of nn observations x1,x2,…,xnx_1, x_2, \ldots, x_n about -2 and 2 are 18 and 10 respectively. Then S.D. of the given set is
View answer and explanation
Correct option: C
3
Option C (3) is correct because the standard deviation is calculated correctly using the given mean square deviations.
328 Easy
328 of 465
Application +4 | -1
The variance of first n natural numbers is
View answer and explanation
Correct option: B
n2−112\frac{{{n^2} - 1}}{{12}}
Option B (n2−112\frac{{{n^2} - 1}}{{12}}) is correct because it is the standard formula for the variance of the first n natural numbers.
329 Easy
329 of 465
Application +4 | -1
If the co-efficient of variation of a distribution is 60 and its standard deviation is 24, then its arithmetic mean is ____.
View answer and explanation
Correct option: A
40
Option A (40) is correct because the arithmetic mean is calculated using the coefficient of variation formula.
330 Easy
330 of 465
Application +4 | -1
If the mean deviation about median for the number 3,5,7,2k,12,16,21,243,5,7,2 k, 12,16,21,24 arranged in the ascending order, is 6 then the median is
View answer and explanation
Correct option: D
11
Option B (10) is correct because by using the given functional equation and the value of f(8), we can find f(14).
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