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JEE • MATHEMATICS • STATISTICS

Statistics practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-270 of 465 questions

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241 Medium
241 of 465
Application +4 | -1
If the resultant of two forces of magnitude PP and 2P2 P is perpendicular to PP, then the angle between the forces is
View answer and explanation
Correct option: A
2π/32 \pi / 3
Option A, 2π3\frac{2 \pi}{3}, is correct because it is the angle between the forces that satisfies the condition that the resultant is perpendicular to P.
242 Easy
242 of 465
Application +4 | -1
The mean deviation of any series is 15 , then the value of quartile deviation is
View answer and explanation
Correct option: C
12.5
Option C (12.5) is correct because it is the quartile deviation calculated using the relationship between mean deviation and quartile deviation.
243 Easy
243 of 465
Application +4 | -1
The average weight of 25 boys was calculated to be 78.4 kg78.4 \mathrm{~kg}. It was later discovered that one weight was misread as 69 kg69 \mathrm{~kg} instead of 96 kg96 \mathrm{~kg}. The correct average is
View answer and explanation
Correct option: B
79.48 kg79.48 \mathrm{~kg}
Option B (79.48 kg) is correct because it represents the corrected average weight after accounting for the misread weight.
244 Easy
244 of 465
Application +4 | -1
The mean of nn observations is xˉ\bar x. If one observation xn+1{x_{n + 1}} is added, then the mean remains same. The value of xn+1{x_{n + 1}} is
View answer and explanation
Correct option: D
xˉ\bar x
Option D (xˉ\bar x) is correct because if adding a new observation doesn't change the mean, the new observation must be equal to the original mean.
245 Easy
245 of 465
Remembering +4 | -1
Mode of data 3,2,5,2,3,5,6,6,5,3,5,2,53,2,5,2,3,5,6,6,5,3,5,2,5 is
View answer and explanation
Correct option: C
5
Option C (5) is correct because the mode is the value that appears most frequently in the data set, and 5 appears 5 times, which is more than any other value.
246 Medium
246 of 465
Application +4 | -1
If the standard deviation of a variable xx is σ\sigma, then the standard deviation of another variable ax+bc\frac{{ax + b}}{c} is
View answer and explanation
Correct option: B
σac\frac{{\sigma a}}{c}
The correct answer is B (σac\frac{{\sigma a}}{c}) because standard deviation is affected by scaling but not by translation.
247 Easy
247 of 465
Application +4 | -1
The mean of the n observations x1,x2,x3,…,  xn{x_1},{x_2},{x_3}, \ldots ,\;{x_n} be xˉ{\bar x}. Then , the mean of n observations 2x1+3,  2x2+3,  2x3+3,  …,  2xn+32{x_1} + 3,\;2{x_2} + 3,\;2{x_3} + 3,\; \ldots ,\;2{x_n} + 3 is
View answer and explanation
Correct option: B
2xˉ+32\bar x + 3
Option B (\2xˉ+3\2\bar x + 3) is correct because multiplying each observation by 2 multiplies the mean by 2, and adding 3 to each observation adds 3 to the mean.
248 Easy
248 of 465
Application +4 | -1
The two regression lines for a bivariate data are x+y+50=0x+y+50=0 and 2x+3y+k=02 x+3 y+k=0. If xˉ=0\bar{x}=0, then yˉ\bar{y} is
View answer and explanation
Correct option: C
-50
Option C (-50) is correct because the regression lines pass through the mean values (xˉ,yˉ\bar{x}, \bar{y}), and given xˉ=0\bar{x}=0, we can solve for yˉ\bar{y} from the first equation.
249 Easy
249 of 465
Understanding +4 | -1
If mean and mode of a frequency distribution have same value, then coefficient of skewness is
View answer and explanation
Correct option: A
zero
Option A (zero) is correct because the coefficient of skewness measures the asymmetry of a distribution, and if the mean and mode are equal, the distribution is symmetric, resulting in zero skewness.
250 Easy
250 of 465
Application +4 | -1
If a variable takes values 0,  1,  2,  …,n0,\;1,\;2,\; \ldots ,n with frequencies 1,    nC1,  nC2,…,  nCn,1,\;{\;^n}{C_1},{\;^n}{C_2}, \ldots ,{\;^n}{C_n}, then the AM is
View answer and explanation
Correct option: D
n2\frac{n}{2}
Option D (n/2) is correct because the weighted average simplifies to n/2 using binomial coefficient properties.
251 Easy
251 of 465
Application +4 | -1
Variance of the data 2,4,5,6,8,172,4,5,6,8,17 is 23.33. Then, variance of 4,8,10,12,16,344,8,10,12,16,34 will be
View answer and explanation
Correct option: A
93.32
Option A (93.32) is correct because when each data point is multiplied by a constant, the variance is multiplied by the square of that constant.
252 Medium
252 of 465
Analyzing +4 | -1
Let the mean and standard deviation of marks of class AA of 100 students be respectively 40 and α\alpha (>0)(> 0), and the mean and standard deviation of marks of class BB of nn students be respectively 55 and 30−α30-\alpha. If the mean and variance of the marks of the combined class of 100+n100+n students are respectively 50 and 350, then the sum of variances of classes AA and BB is:
View answer and explanation
Correct option: D
500
Option D (500) is correct because, after setting up equations for the means and variances of the two classes and the combined class, solving for the unknowns yields the sum of the variances of classes A and B as 500.
253 Easy
253 of 465
Application +4 | -1
The points scored by a basketball team in a series of matches are as follows:

15,3,8,10,22,5,27,11,12,19,18,21,13,1415,3,8,10,22,5,27,11,12,19,18,21,13,14
Its median is
View answer and explanation
Correct option: C
13.5
Option C (13.5) is correct because the median is the average of the two middle values when the data is arranged in ascending order.
254 Easy
254 of 465
Analyzing +4 | -1
Out of two lines of regression given by x+2y=4x+2 y=4 and 2x−3y−5=02 x-3 y-5=0, the regression of xx on yy is
View answer and explanation
Correct option: C
they are not lines of regression
The correct answer is "they are not lines of regression" because the product of the regression coefficients is negative, which is impossible.
255 Medium
255 of 465
Analyzing +4 | -1
If r1r_1 and r2r_2 are regression coefficients of yy on xx and xx on yy respectively, then
View answer and explanation
Correct option: C
r1+r2≥2rr_1+r_2 \geq 2 r
Option C (r1+r2≥2rr_1+r_2 \geq 2 r) is correct because the arithmetic mean of the regression coefficients is greater than or equal to the correlation coefficient.
256 Easy
256 of 465
Application +4 | -1
The mean deviation from the mean of the set of observations, -1, 0, 4 is
View answer and explanation
Correct option: D
2
Option D (2) is correct because the mean deviation from the mean is calculated by finding the average of the absolute differences between each observation and the mean.
257 Easy
257 of 465
Analyzing +4 | -1
For the frequency distribution
Variate (x):x1 x2 x3.... x15(x):{x_1}\,{x_2}\,{x_3}....\,{x_{15}}
Frequency (f):  f1 f2 f3...... f15(f):\,\,{f_1}\,{f_2}\,{f_3}......\,{f_{15}}
Where 0<x1<x2<x3<.....<x15=100 < {x_1} < {x_2} < {x_3} < ..... < {x_{15}} = 10 and ∑i=115fi>0,\sum\limits_{i = 1}^{15} {{f_i}} > 0, the standard deviation cannot be
View answer and explanation
Correct option: C
6
Option C 6 is correct because the standard deviation cannot exceed a certain limit based on the range of the variate, and 6 falls outside this limit.
258 Easy
258 of 465
Application +4 | -1
Coefficient of skewness for the values

Median =18.8,  Q1=14.6,  Q3=25.2= 18.8,\;{Q_1} = 14.6,\;{Q_3} = 25.2 is
View answer and explanation
Correct option: A
0.20.2
Option A (0.20.2) is correct because it is calculated using the formula for the coefficient of skewness based on quartiles and median.
259 Easy
259 of 465
Understanding +4 | -1
The arithmetic mean of the first nn natural numbers is
View answer and explanation
Correct option: A
(n+1)/2(n+1) / 2
Option A ((n+1)/2(n+1) / 2) is correct because the sum of the first nn natural numbers is n(n+1)/2n(n+1)/2, and dividing by nn gives the arithmetic mean.
260 Easy
260 of 465
Application +4 | -1
Given 5 sample measurement of a part of machine as 6.33,6.37,6.36,6.326.33,6.37,6.36,6.32 and 6.37 . The sample variance is
View answer and explanation
Correct option: C
0.0004
Option C (0.0004) is correct because the sample variance is calculated using the formula and given measurements, resulting in approximately 0.0004.
261 Easy
261 of 465
Application +4 | -1
The weighted mean of first nn natural number if their weight are the same as the number is-
View answer and explanation
Correct option: C
2n+13\frac{2 n+1}{3}
Option C (2n+13\frac{{2n+1}}{{3}}) is correct because the weighted mean is calculated using the formula ∑wx∑w\frac{{\sum wx}}{{\sum w}}, where w is the weight and x is the value.
262 Easy
262 of 465
Application +4 | -1
A school has four sections of chemistry in class XII having
40, 35, 45 and 42 students. The mean marks obtained in
chemistry test are 50, 60, 55 and 45 respectively for the
four sections, the over all average of marks per students is
View answer and explanation
Correct option: D
52.25
Option D (52.25) is correct because it is the weighted average of the marks obtained by all students.
263 Hard
263 of 465
Application +4 | -1
If Z=aX+bYZ = aX + bY and rr be the correlation coefficient between X  and  YX\;and\;Y, then σZ2\sigma _Z^2 is equal to
View answer and explanation
Correct option: A
a2σX2+b2σY2+2abrσXσY{a^2}\sigma _X^2 + {b^2}\sigma _Y^2 + 2abr{\sigma _X}{\sigma _Y}
The correct answer is A (a2σX2+b2σY2+2abrσXσY{a^2}\sigma _X^2 + {b^2}\sigma _Y^2 + 2abr{\sigma _X}{\sigma _Y}) because it represents the variance of a linear combination of two random variables, considering their correlation.
264 Easy
264 of 465
Application +4 | -1
If G1,G2{{G_1},{G_2}} are the geometric means of two series of observations and GG is the GM of the ratios of the corresponding observations then G is equal to
View answer and explanation
Correct option: A
G1G2\frac{{{G_1}}}{{{G_2}}}
Option A (G1G2\frac{{{{{G_1}}}}}{{{{G_2}}}}) is correct because the geometric mean of ratios is the ratio of the geometric means.
265 Easy
265 of 465
Remembering +4 | -1
If r is Karl Pearson’s coefficient of correlation between two sets of variates, then
View answer and explanation
Correct option: D
∣r∣≤1\left| r \right| \le 1
Option D (∣r∣≤1\left| r \right| \le 1) is correct because Karl Pearson's coefficient of correlation, r, always lies between -1 and +1, inclusive.
266 Easy
266 of 465
Application +4 | -1
The mean income of a group of persons is ₹400₹ 400. Another group of persons has mean income ₹480.₹ 480. If the mean income of all the persons in the two groups together is ₹430₹ 430, then ratio of the number of persons in the groups is
View answer and explanation
Correct option: A
n1n2=53\frac{n_1}{n_2}=\frac{5}{3}
Option A (n1/n2 = 5/3) is correct because it is derived by setting up a weighted average equation for the combined mean income and solving for the ratio of the number of persons in each group.
267 Easy
267 of 465
Application +4 | -1
The mean of the values 0,  1,  2,  3,  ...  n0,\;1,\;2,\;3,\;...\;n with the corresponding weights nC0,  nC1,…,  nCn^n{C_0},{\;^n}{C_1}, \ldots ,{\;^n}{C_n} respectively is
View answer and explanation
Correct option: D
n2\frac{n}{2}
Option D (n/2) is correct because the weighted average simplifies to n/2 using binomial coefficient properties.
268 Hard
268 of 465
Application +4 | -1
If ∑i=15(xi−10)=5\sum\limits_{{i=1}}^5\left(x_i-10\right)=5 and ∑i=15(xi−10)2=25\sum\limits_{{i=1}}^5\left(x_i-10\right)^2=25 then standard deviation of observations 2x1+72 x_1+7, 2x2+7,2x3+7,2x4+72 x_2+7,2 x_3+7,2 x_4+7 and 2x5+72 x_5+7 is equal to:
View answer and explanation
Correct option: C
4
Option C (4) is correct because the standard deviation of 2xi+72x_i + 7 is twice the standard deviation of xix_i, and the standard deviation is not affected by the change of origin.
269 Hard
269 of 465
Application +4 | -1
If the mean deviation about the median of the numbers aa, 2a,……,50a2 a, \ldots \ldots, 50 a is 50 , then ∣a∣|a| equals
View answer and explanation
Correct option: B
4
Option B (4) is correct. The mean deviation about the median is calculated using the given information.
270 Medium
270 of 465
Application +4 | -1
Let 9=x1<x2<…<x79=x_{1} < x_{2} < \ldots < x_{7} be in an A.P. with common difference dd. If the standard deviation of x1,x2…x7x_{1}, x_{2} \ldots x_{7} is 4 and the mean is xˉ\bar{x}, then xˉ+x6\bar{x}+x_{6} is equal to:
View answer and explanation
Correct option: B
34
Option B (34) is correct because it is the sum of the mean and the 6th term of the A.P., calculated using the given standard deviation.
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