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JEE • MATHEMATICS • SET THEORY

Set theory practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 194 questions

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91 Easy
91 of 194
Analyzing +4 | -1
Let S={θ∈[0,2π]:82sin⁡2θ+82cos⁡2θ=16}.S = \left\{ {\theta \in [0,2\pi ]:{8^{2{{\sin }^2}}}\theta + {8^{2{{\cos }^2}\theta }} = 16} \right\}. Then n(S)+n(S)+ ∑θ∈S(sec⁡(π4+2θ)cos⁡ec(π4+2θ))\sum\limits_{\theta \in S} {\left( {\sec \left( {\frac{\pi }{4} + 2\theta } \right)\cos ec\left( {\frac{\pi }{4} + 2\theta } \right)} \right)} is equal to :
View answer and explanation
Correct option: C
−4-4
Option C (-4) is correct because after finding the values of θ\theta that satisfy the given equation and substituting them into the expression, the result is -4.
92 Easy
92 of 194
Understanding +4 | -1
If the number of elements in AA is mm and number of element in BB is nn then the number of elements in the power set of A×BA \times B is
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Correct option: C
2mn2^{m n}
Option C is correct because the number of elements in A × B is m*n, and the number of elements in the power set of A × B is 2(m*n).
93 Easy
93 of 194
Application +4 | -1
If A={1,2,3},B={3,4,5},A=\{1,2,3\}, B=\{3,4,5\}, then (A∩B)×A(A \cap B) \times A is
View answer and explanation
Correct option: B
{(3,1),(3,2),(3,3)}\{(3,1),(3,2),(3,3)\}
Option B ({(3,1),(3,2),(3,3)}\{(3,1),(3,2),(3,3)\}) is correct because it represents the Cartesian product of the intersection of A and B with A.
94 Easy
94 of 194
Application +4 | -1
Given the sets A={1,2,3},B={3,4},C={4,5,6}A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}, then: A∪(B∩C)A \cup(B \cap C) is
View answer and explanation
Correct option: B
{1,2,3,4}\{1,2,3,4\}
Option B ({1,2,3,4}\{1,2,3,4\}) is correct because it represents the union of set A with the intersection of sets B and C.
95 Easy
95 of 194
Analyzing +4 | -1
If XX and YY are two sets, then X∩(Y∩X)′X \cap(Y \cap X)^{\prime} equals
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the expression simplifies to X∩Y′X \cap Y', which is equivalent to X−(X∩Y)X - (X \cap Y).
96 Easy
96 of 194
Application +4 | -1
Let U\mathcal{U} be the universal set for sets A and B such that n(A)=200,n(B)=300n\left( A \right) = 200,n\left( B \right) = 300 and n(A∩B)=100.n\left( {A \cap B} \right) = 100. Then, n(A′∩B′)n\left( {A' \cap B'} \right) is equal to 300, provided that n(U)n\left( \mathcal{U} \right) is equal to
View answer and explanation
Correct option: B
700
The correct answer is B (700) because it is found by using De Morgan's law and the formula for the number of elements in the union of two sets.
97 Easy
97 of 194
Application +4 | -1
Two finite sets have mm and nn elements. The total number of subsets of the first set is 56 more than the total number of subsets of the second set. The values of mm and nn are
View answer and explanation
Correct option: B
m=6,n=3m = 6,n = 3
Option B (m = 6, n = 3) is correct because it satisfies the equation 2^m - 2^n = 56, where m and n are the number of elements in the two sets.
98 Easy
98 of 194
Application +4 | -1
If A={1,  2,  3},  B{3,  4},  C{4,  5,  6}A = \left\{ {1,\;2,\;3} \right\},\;B\left\{ {3,\;4} \right\},\;C\left\{ {4,\;5,\;6} \right\}. Then, A∪(B∩C)A \cup \left( {B \cap C} \right) is
View answer and explanation
Correct option: D
{1,2,3,4}\left\{ {1,2,3,4} \right\}
The correct answer is D ( {1,2,3,4} ) because it is the union of set A with the intersection of sets B and C.
99 Easy
99 of 194
Understanding +4 | -1
The value of n{P[P(ϕ)]}n\{P[P(\phi)]\} is equal to
View answer and explanation
Correct option: A
4
Option A (4) is correct because the power set of the power set of the null set has 4 elements.
100 Easy
100 of 194
Understanding +4 | -1
For any two sets AA and BB, A−(A−B)A - \left( {A - B} \right) equals
View answer and explanation
Correct option: C
A∩BA \cap B
Option C (A∩BA \cap B) is correct because A−(A−B)A - (A - B) simplifies to the intersection of A and B.
101 Easy
101 of 194
Understanding +4 | -1
If AA and BB are two given sets, then A∩(A∩B)cA \cap {\left( {A \cap B} \right)^c} is equal to
View answer and explanation
Correct option: D
A∩BcA \cap {B^c}
Option D (A∩BcA \cap {B^c}) is correct because using De Morgan's law and set identities, A∩(A∩B)cA \cap (A \cap B)^c simplifies to A∩BcA \cap B^c.
102 Easy
102 of 194
Understanding +4 | -1
The set (A\B)∪(B\A)(A \backslash B) \cup(B \backslash A) is equal to
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Correct option: B
(A∪B)\(A∩B)(A \cup B) \backslash(A \cap B)
Option B ((A∪B)\(A∩B)(A \cup B) \backslash(A \cap B)) is correct because it represents the symmetric difference between A and B, which includes elements in A or B but not both.
103 Easy
103 of 194
Understanding +4 | -1
If A={x,  y}A = \left\{ {x,\;y} \right\}, then the power set of AA is
View answer and explanation
Correct option: D
{ϕ,  {x},  {y},  {x,  y}}\left\{ {\phi ,\;\left\{ x \right\},\;\left\{ y \right\},\;\left\{ {x,\;y} \right\}} \right\}
Option D ({ϕ,;x,;y,;x,;y}\{ {\phi ,\\;\\{ x \\} ,\\;\\{ y \\} ,\\;\\{ x,\\;y \\} } \}) is correct because it lists all possible subsets of the set A = {x, y}, including the empty set and the set itself.
104 Easy
104 of 194
Analyzing +4 | -1
If A,BA,B and CC are three sets such that A∩B=A∩CA \cap B = A \cap C and A∪B=A∪CA \cup B = A \cup C, then
View answer and explanation
Correct option: B
B=CB = C
Option B (B = C) is correct because given the conditions A ∩ B = A ∩ C and A ∪ B = A ∪ C, it can be proven that B must equal C.
105 Easy
105 of 194
Understanding +4 | -1
Statement-I: The set {x\left\{x\right. : xx is a real number and x2−1=0}\left.x^2-1=0\right\} is the empty set.

Statement-II: The set A={x:x∈R,x2=16{A}=\left\{{x}: {x} \in {R}, {x}^2=16\right. and 2x=6}\left.2 {x}=6\right\} is an empty set.
View answer and explanation
Correct option: B
Statement II is true
Statement II is true because the set A is empty since there is no real number that satisfies both conditions x2=16x^2 = 16 and 2x=62x = 6 simultaneously.
106 Easy
106 of 194
Analyzing +4 | -1
Let f(x)=(x+1)2−1,(x≥−1)f(x)=(x+1)^2-1,(x \geq-1). Then, the set S={x:f(x)=f−1(x)}S=\left\{x: f(x)=f^{-1}(x)\right\} is
View answer and explanation
Correct option: C
{0,−1}\{0,-1\}
Option C ({0,−1}\{0,-1\}) is correct because these are the points where f(x)=xf(x) = x, which are the intersection points of f(x)f(x) and f−1(x)f^{-1}(x).
107 Easy
107 of 194
Understanding +4 | -1
If AA and BB are two sets, then (A−B)∪(B−A)∪(A∩B)(A-B) \cup(B-A) \cup(A \cap B) is equal to
View answer and explanation
Correct option: A
A∪BA \cup B
Option A (A∪BA \cup B) is correct because (A−B)∪(B−A)∪(A∩B)(A-B) \cup (B-A) \cup (A \cap B) combines the elements unique to A, unique to B, and common to both, resulting in the union of A and B.
108 Easy
108 of 194
Remembering +4 | -1
The number of elements of the power set of a set containing nn elements is
View answer and explanation
Correct option: B
2n2^n
Option B (2n2^n) is correct because the power set of a set with n elements contains 2n2^n elements.
109 Easy
109 of 194
Understanding +4 | -1
If A={1,2,5}A=\{1,2,5\} and B={3,4,5,9}B=\{3,4,5,9\}, then AΔBA \Delta B is equal to
View answer and explanation
Correct option: B
{1,2,3,4,9}\{1,2,3,4,9\}
Option B ({1,2,3,4,9}) is correct because the symmetric difference A Δ B consists of elements that are in A or B, but not in both.
110 Easy
110 of 194
Understanding +4 | -1
Which one of the following is (A−B)∪(B−A)(A-B) \cup(B-A) ?
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Correct option: C
(A∪B)−(A∩B)(A \cup B)-(A \cap B)
Option C ((A∪B)−(A∩B)(A \cup B)-(A \cap B)) is correct because (A−B)∪(B−A)(A-B) \cup (B-A) represents the elements that are in A or B but not in both, which is the same as the union minus the intersection.
111 Easy
111 of 194
Application +4 | -1
In a rehabilitation programme, a group of 50 families were assured new houses and compensation by the government. Number of families who got both is equal to the number of families who got neither of the two. The number of families who got new houses is 6 greater than the number of families who got compensation. How many families got houses?
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Correct option: B
28
Option B (28) is correct because it is the number of families who got new houses, derived from the given relationships between the families who received houses, compensation, or neither.
112 Easy
112 of 194
Understanding +4 | -1
If A={2,3,4,8,10},B={3,4,5,10,12}A=\{2,3,4,8,10\}, B=\{3,4,5,10,12\} and C={4,5,6,12,14}C=\{4, 5,6,12,14\}, then (A∩B)∪(A∩C)(A \cap B) \cup(A \cap C) is equal to
View answer and explanation
Correct option: A
{3,4,10}\{3,4,10\}
Option A ({3,4,10}\{3,4,10\}) is correct because it represents the union of the intersection of A and B, and A and C.
113 Easy
113 of 194
Application +4 | -1
The finite sets AA and BB have m and n elements respectively. if the total number of subsets of AA is 112 more than the total number of subsets of BB, then the volume of mm is
View answer and explanation
Correct option: A
7
The correct answer is A (7) because solving the equation 2^m - 2^n = 112 yields m = 7 and n = 4.
114 Easy
114 of 194
Understanding +4 | -1
If A={1,2,3}A=\{1,2,3\} and B={3,8}B=\{3,8\}, then (A∪B)×(A∩B)(A \cup B) \times(A \cap B) is
View answer and explanation
Correct option: B
{(1,3),(2,3),(3,3),(8,3)}\{(1,3),(2,3),(3,3),(8,3)\}
Option B ({ (1,3),(2,3),(3,3),(8,3)}) is correct because it represents the Cartesian product of (A ∪ B) and (A ∩ B).
115 Easy
115 of 194
Remembering +4 | -1
If a set A={a,b,c}A=\{a, b, c\} then the number of subsets of the set AA is
View answer and explanation
Correct option: A
8
Option A (8) is correct because a set with 3 elements has 23=82^3 = 8 subsets.
116 Easy
116 of 194
Application +4 | -1
Let AA and BB be two finite sets with mm and nn elements respectively. The total number of subsets of the set AA is 56 more than the total number of subsets of B.B. Then the distance of the point P(m,n)P(m, n) from the point Q(−2,−3)Q(-2,-3) is:
View answer and explanation
Correct option: C
10
Option C (10) is correct because solving the equation relating the number of subsets of A and B gives m=6 and n=3, and the distance between P(6,3) and Q(-2,-3) is 10.
117 Easy
117 of 194
Understanding +4 | -1
If AA and BB are any two sets, then A∪(A∩B)A \cup(A \cap B) is equal to:
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Correct option: A
AA
Option A (AA) is correct because A∩BA \cap B is a subset of AA, so the union of AA and A∩BA \cap B is simply AA.
118 Easy
118 of 194
Understanding +4 | -1
If U={1,2,3}{U}=\{1,2,3\} and A={1,2}{A}=\{1,2\} then [P(A)]′=[{P}({A})]^{\prime}=
View answer and explanation
Correct option: B
{{3},{2,3},{1,3},{1,2,3}}\{\{3\},\{2,3\},\{1,3\},\{1,2,3\}\}
Option B is correct because [P(A)]' is the complement of P(A) with respect to P(U), where U={1,2,3} and A={1,2}.
119 Easy
119 of 194
Analyzing +4 | -1
Out of all the patients in a hospital 89% are found to be suffering from heart ailment and 98% are suffering from lungs infection. If KK% of them are suffering from both ailments, then KK cannot belong to the set
View answer and explanation
Correct option: C
{79, 81, 83, 85}
The correct answer is C ({79, 81, 83, 85}) because the percentage of patients suffering from both ailments must lie within a specific range, and this set falls outside that range.
120 Easy
120 of 194
Understanding +4 | -1
Let AA and BB have 3 and 6 elements respectively. What can be the minimum number of elements in A∪B?A \cup B?
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Correct option: B
6
Option B (6) is correct because the minimum number of elements in A∪BA \cup B occurs when A⊂BA \subset B, in which case A∪B=BA \cup B = B, and n(B)=6n(B) = 6.
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