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JEE MATHEMATICS MCQ: SET THEORY

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Analyzing +4 | -1
Let A={x:∣x∣<2}A=\{x:|x|<2\} and B={x:∣x−2∣≥3}B=\{x:|x-2| \geq 3\}. Then
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Correct option: D
B−A=R−(−2,5)B-A=R-(-2,5)
Option D (B−A=R−(−2,5)B-A=R-(-2,5)) is the correct answer because it accurately represents the set of elements in B but not in A.

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