Back to SET THEORY
Your Progress
0 / 273 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • SET THEORY
Set theory practice · Mixed difficulty
Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.
Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
Take a chapter quiz →
Showing 61-90 of 273 questions
Preparing practice and saved progress…
61
Easy
61 of 273
Application
+4 | -1
A class has 175 students. The following data shows the number of students opting one or more subjects. Mathematics 100; Physics 70; Chemistry 40; Mathematics and Physics 30; Mathematics and Chemistry 28; Physics and Chemistry 23; Mathematics, Physics and Chemistry 18. Hoe many students have offered Mathematics alone?
View answer and explanation
Correct option: C
60
The correct answer is C (60) because it is calculated by using the principle of inclusion-exclusion and subtracting the number of students taking combined subjects from the total number of students taking mathematics.
62
Easy
62 of 273
Analyzing
+4 | -1
Let and be two sets. The
View answer and explanation
Correct option: A
Option A () is correct because the expression simplifies to the complement of set A using De Morgan's laws and set identities.
63
Medium
63 of 273
Analyzing
+4 | -1
If and then number of elements in is
View answer and explanation
Correct option: A
7
Option A (7) is correct because it correctly identifies the number of elements in the intersection of A and B that are odd multiples of 15 and less than or equal to 50*15.
64
Easy
64 of 273
Understanding
+4 | -1
Let be the set of real numbers, If is defined by , then is
View answer and explanation
Correct option: B
Injective but not surjective
Option B (Injective but not surjective) is correct because the exponential function is one-to-one but its range is only positive real numbers.
65
Easy
65 of 273
Understanding
+4 | -1
Which of the following is true?
View answer and explanation
Correct option: B
Option B () is correct because the intersection of any set A with the empty set is always the empty set.
66
Easy
66 of 273
Analyzing
+4 | -1
Let and . Then
View answer and explanation
Correct option: D
Option D () is the correct answer because it accurately represents the set of elements in B but not in A.
67
Medium
67 of 273
Application
+4 | -1
Let and be the sets of all positive divisors of 400 and 1000 respectively (including 1 and the number). Then, is equal to
View answer and explanation
Correct option: D
12
Option D (12) is correct because the intersection of the sets of divisors of 400 and 1000 is the set of divisors of their greatest common divisor (GCD), which is 200, and 200 has 12 divisors.
68
Medium
68 of 273
Analyzing
+4 | -1
Which of the following is not correct?
View answer and explanation
Correct option: C
If , then
The statement \"If , then \" (Option C) is not always correct, making it the correct answer.
69
Easy
69 of 273
Analyzing
+4 | -1
If and is the universal set, then is
View answer and explanation
Correct option: B
Option B (N) is correct because the expression simplifies to A' ∪ A, which by definition equals the universal set N.
70
Medium
70 of 273
Application
+4 | -1
Let , then is equal to
View answer and explanation
Correct option: C
300
Option C (300) is correct because it is calculated using De Morgan's law and the formula for the number of elements in the union of two sets.
71
Easy
71 of 273
Application
+4 | -1
In a city, three daily newspapers are published. of the people in that city read , read and read C. read and read and ; read and do not read any of the three newspapers. The percentage of persons who read all the three papers is
View answer and explanation
Correct option: A
Option A () is correct because it uses the principle of inclusion-exclusion for three sets to find the percentage of people who read all three newspapers.
72
Easy
72 of 273
Understanding
+4 | -1
Let be 100 sets such that and then contains… elements
View answer and explanation
Correct option: C
101
Option D (101) is correct because the union of nested sets is the largest set, and n(A_100) = 100 + 1 = 101.
73
Medium
73 of 273
Analyzing
+4 | -1
In a certain town, of the families own a phone and own a car; families own neither a phone nor a car and 2,000 families own both a car and a phone. Consider the following three statements:
(A) families own both a car and a phone
(B) families own either a car or a phone
(C) 40,000 families live in the town
Then,
(A) families own both a car and a phone
(B) families own either a car or a phone
(C) 40,000 families live in the town
Then,
View answer and explanation
Correct option: C
All (A), (B) and (C) are correct.
Option C (All (A), (B) and (C) are correct) is correct because the calculations based on the given percentages and the number of families owning both a car and a phone confirm all three statements.
74
Easy
74 of 273
Understanding
+4 | -1
If and , then
View answer and explanation
Correct option: B
Option B (Z) is correct because the union of the set of odd integers and the set of even integers is the set of all integers.
75
Easy
75 of 273
Analyzing
+4 | -1
If and then:
View answer and explanation
Correct option: A
Option A () is correct because every element in X is also an element in Y, meaning X is a subset of Y.
Explore Other Chapters in MATHEMATICS
View All →
76
Easy
76 of 273
Application
+4 | -1
In a group of 70 people, 37 like coffee, 52 like tea and each person likes at least one of the two drinks. How many persons like both coffee and tea?
View answer and explanation
Correct option: A
19
Option A (19) is correct because it is the number of people who like both coffee and tea, calculated using the principle of inclusion-exclusion.
77
Medium
77 of 273
Understanding
+4 | -1
If and are three sets such that then
View answer and explanation
Correct option: C
Option C () is correct because given , and , so the expression simplifies to .
78
Medium
78 of 273
Analyzing
+4 | -1
From 50 students taking examinations in Mathematics, Physics and Chemistry, 37 passed Mathematics, 24 Physics and 43 Chemistry. At most 19 passed Mathematics and Physics, at most 29 passed Mathematics and Chemistry and at most 20 passed Physics and Chemistry. The largest possible number that could have passed all three examinations is
View answer and explanation
Correct option: D
14
Option D (14) is correct because it represents the largest possible number of students who could have passed all three examinations, derived from the given constraints on the number of students passing in pairs of subjects.
79
Easy
79 of 273
Understanding
+4 | -1
Let be a set of squares, be set of parallelograms, be a set of quadrilaterals and be a set of rectangles. Consider the following:
I. II. III. IV.
Which of the above are correct?
I. II. III. IV.
Which of the above are correct?
View answer and explanation
Correct option: B
I, III and IV
Option B (I, III and IV) is correct because squares are parallelograms and rectangles, and rectangles are quadrilaterals.
80
Medium
80 of 273
Analyzing
+4 | -1
Let and be two sets, then is equal to
View answer and explanation
Correct option: A
Option A () is correct because the expression simplifies to the complement of set A using set theory rules.
81
Easy
81 of 273
Understanding
+4 | -1
If and are symmetric relations (not disjoint) on a set , then the relation is
View answer and explanation
Correct option: B
Symmetric
Option B (Symmetric) is correct because the intersection of two symmetric relations is also symmetric.
82
Medium
82 of 273
Application
+4 | -1
If denotes the power set of and is the void set, then what is number of elements in
View answer and explanation
Correct option: D
16
Option D (16) is correct because the power set of the power set is calculated iteratively, doubling the number of elements at each step.
83
Easy
83 of 273
Application
+4 | -1
and are two sets such that has 40 elements, has 60 elements and has 10 elements, then number of elements has
View answer and explanation
Correct option: C
30
Option C (30) is correct because it uses the principle of inclusion-exclusion to find the number of elements in set Y.
84
Medium
84 of 273
Application
+4 | -1
If there are three atheletic teams in a school, 21 are in the basketball team, 26 in hockey team and 29 in the football team. 14 play hockey and basketball, 15 play hockey and football, 12 play football and basketball and 8 play all the games. The total number of members is
View answer and explanation
Correct option: B
43
Option B (43) is correct because it is calculated using the principle of inclusion-exclusion to find the total number of members in all three teams.
85
Easy
85 of 273
Understanding
+4 | -1
If and are two sets, then is equal to
View answer and explanation
Correct option: B
Option B () is correct because the expression represents all elements in A, all elements in B, and the intersection of A and B, which is the union of A and B.
86
Medium
86 of 273
Understanding
+4 | -1
Let be the set of prime numbers and is a prime\}. Then,
View answer and explanation
Correct option: A
Option A () is correct because if is prime, then t must be prime, but not all prime numbers t will result in being prime. Therefore, S is a subset of P.
87
Easy
87 of 273
Application
+4 | -1
Out of 800 boys in a school 224 played cricket, 240 played hockey and 336 played basketball. Of the total, 64 played both basketball and hockey; 80 played cricket and basketball and 40 played cricket and hockey; 24 played all the three games. The number of boys who did not play any game is
View answer and explanation
Correct option: A
160
Option A (160) is correct because it is calculated by subtracting the number of boys who played at least one game from the total number of boys.
88
Easy
88 of 273
Understanding
+4 | -1
Let denote the set of integers, then
View answer and explanation
Correct option: C
Option C () is correct because it represents the intersection of two sets of integers defined by absolute value inequalities.
89
Easy
89 of 273
Application
+4 | -1
Suppose are thirty sets each with 5 elements and are n sets. Each with three elements such that . If each element of belongs to exactly 10 of the 's and exactly 9 of the 's, then the value of is
View answer and explanation
Correct option: C
45
Option C (45) is correct because it is derived from equating the total number of elements in S calculated using the information from sets A_i and B_j.
90
Easy
90 of 273
Understanding
+4 | -1
Let and , then is
View answer and explanation
Correct option: B
Option B ({1,2,3,4}) is correct because it represents the union of set A with the intersection of sets B and C.
Revision notes and key takeaways
Review SET THEORY in your textbook or class notes, then use this set to check your understanding.
Showing 61-90 of 273 questions
