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JEE • MATHEMATICS • RELATIONS

Relations practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 121-150 of 238 questions

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121 Medium
121 of 238
Application +4 | -1
Let A={1,2,3,4,5};B={2,3,6,7}A=\{1,2,3,4,5\} ; B=\{2,3,6,7\}. Then the number of elements in (A×B)∩(B×A)(A \times B) \cap(B \times A) is :
View answer and explanation
Correct option: D
4
Option D (4) is correct because there are 4 elements that are present in both A x B and B x A, which are (2,2), (2,3), (3,2), and (3,3).
122 Easy
122 of 238
Understanding +4 | -1
If the number of elements in A\mathrm{A} is m\mathrm{m} and number of element in B\mathrm{B} is n\mathrm{n} then the number of elements in the power set of A×BA \times B is
View answer and explanation
Correct option: C
2mn2^{\mathrm{mn}}
Option C (2mn2^{\mathrm{mn}}) is correct because the power set of a set with mn elements has 2mn2^{\mathrm{mn}} elements.
123 Easy
123 of 238
Analyzing +4 | -1
Let RR be the set of real numbers.
Statement-1: A={(x,y)∈R×R:y−xA=\{(x, y) \in R \times R: y-x is an integer }\} is an equivalence relation on RR.

Statement-2: B={(x,y)∈R×R:x=αyB=\{(x, y) \in R \times R: x=\alpha y for some rational number α\alpha } is an equivalence relation on RR.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1
Option A (Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1) is correct because both statements define equivalence relations, but the second statement doesn't explain the first.
124 Easy
124 of 238
Application +4 | -1
Let A={1,2,3,4}{A}=\{1,2,3,4\}. Then the total no.of symmetric relations from A→AA \rightarrow A is
View answer and explanation
Correct option: A
1024
Option A (1024) is correct because it is the total number of symmetric relations from A to A, calculated using the formula 2n(n+1)22^{\frac{n(n+1)}{2}}.
125 Easy
125 of 238
Understanding +4 | -1
If A={2,4,5},B={7,8,9}A = \left\{ {2,4,5} \right\},B = \left\{ {7,8,9} \right\}, then n(A×B)n\left( {A \times B} \right) is equal to:
View answer and explanation
Correct option: B
9
The correct answer is 9 because the number of elements in the Cartesian product A×BA \times B is the product of the number of elements in AA and BB.
126 Medium
126 of 238
Analyzing +4 | -1
Let R1{R_1} be a relation defined by
R1={(a,b)|a⩾b,a,b∈R}.{R_1} = \left\{ {\left( {a,b} \right){\text{|}}a \geqslant b,a,b \in R} \right\}. Then, R1{R_1} is
View answer and explanation
Correct option: B
Reflexive, transitive but not symmetric
Option B (Reflexive, transitive but not symmetric) is correct because the relation satisfies the reflexive and transitive properties but fails to be symmetric.
127 Easy
127 of 238
Understanding +4 | -1
The relation R={(1,1),(2,2),(3,3),(1,2),(2,3),(1,3)}R = \left\{ {\left( {1,1} \right),\left( {2,2} \right),\left( {3,3} \right),\left( {1,2} \right),\left( {2,3} \right),\left( {1,3} \right)} \right\} on set A={1,2,3}A = \left\{ {1,2,3} \right\} is
View answer and explanation
Correct option: A
Reflexive but not symmetric
Option A (Reflexive but not symmetric) is correct because the relation contains (1,1), (2,2), and (3,3), making it reflexive, but it lacks (2,1), making it not symmetric.
128 Easy
128 of 238
Analyzing +4 | -1
Let RR be a relation on the set AA of ordered pairs of positive integers defined by (x,y)R(u,v)(x, y) R(u, v), if and only if xv=yu\mathrm{xv}=\mathrm{yu}. Then, R\mathrm{R} is
View answer and explanation
Correct option: D
an equivalence relation
Option D (an equivalence relation) is correct because the relation R is reflexive, symmetric, and transitive, thus satisfying the definition of an equivalence relation.
129 Medium
129 of 238
Application +4 | -1
Let xx denote the total number of one-one functions from a set AA with 3 elements to a set BB with 5 elements and yy denote the total number of one-one functions from the set AA to the set A×BA \times B. Then,
View answer and explanation
Correct option: A
2y=91x2y = 91x
The correct answer is A (2y=91x2y = 91x) because it correctly calculates the number of one-one functions and establishes the relationship between x and y.
130 Easy
130 of 238
Understanding +4 | -1
Let R1\mathrm{R}_1 be a relation defined by R1={(a,b)∣a≥b;a,b∈R}\mathrm{R}_1=\{(\mathrm{a}, \mathrm{b}) \mid \mathrm{a} \geq \mathrm{b} ; \mathrm{a}, \mathrm{b} \in \mathrm{R}\}. Then R1\mathrm{R}_1 is
View answer and explanation
Correct option: B
Reflexive, transitive but not symmetric
Option B (Reflexive, transitive but not symmetric) is correct because the given relation satisfies the reflexive and transitive properties but fails to be symmetric.
131 Medium
131 of 238
Understanding +4 | -1
If A={a,b,c,d},B={1,2,3}A=\{a, b, c, d\}, B=\{1,2,3\}, which of the following sets of ordered pairs are not relations from AA to BB ?
View answer and explanation
Correct option: C
{(a,2),(b,3),(3,b)}\{(a, 2),(b, 3),(3, b)\}
Option C is correct because (3, b) is not an element of A x B since 3 is not in A and b is not in B.
132 Easy
132 of 238
Analyzing +4 | -1
Which one of the following is not an equivalence relation?
View answer and explanation
Correct option: B
R2R_2 on RR defined by a R2 b⇔1+ab>0a \,R_2 \,b \Leftrightarrow 1+a b>0 for all a,b∈R.a, b \in R.
Option B is the correct answer because R2R_2 is not transitive, and therefore not an equivalence relation. An equivalence relation must be reflexive, symmetric, and transitive.
133 Easy
133 of 238
Understanding +4 | -1
Define a relation RR over a class of n×nn \times n real matrices AA and BB as "ARBARB, if there exists a non-singular matrix PP such that PAP−1=BPA{P^{ - 1}} = B”. Then which of the following is true?
View answer and explanation
Correct option: C
RR is an equivalence relation
Option C (RR is an equivalence relation) is correct because the relation is reflexive, symmetric, and transitive.
134 Easy
134 of 238
Analyzing +4 | -1
If A={x,y,z},A = \left\{ {x,y,z} \right\}, then the relation
R={(x,x),(y,y),(z,z),(z,x),(z,y)}R = \left\{ {\left( {x,x} \right),\left( {y,y} \right),\left( {z,z} \right),\left( {z,x} \right),\left( {z,y} \right)} \right\} is
View answer and explanation
Correct option: D
Both (1) and (2)
Option C is correct because the given relation R is transitive.
135 Easy
135 of 238
Understanding +4 | -1
On the set of human beings a relation RR is defined as follows:
"aRbaRb iff aa and bb have the same brother". Then RR is
View answer and explanation
Correct option: D
Equivalence
Option D (Equivalence) is correct because the relation R satisfies reflexive, symmetric, and transitive properties, making it an equivalence relation.
136 Easy
136 of 238
Analyzing +4 | -1
If R={(a,b):∣a+b∣=a+b}R = \left\{ {\left( {a,b} \right):\left| {a + b} \right| = a + b} \right\} is a relation defined on a set {−1,  0,  1},\left\{ { - 1,\;0,\;1} \right\}, then RR is
View answer and explanation
Correct option: B
Symmetric
Option B (Symmetric) is correct because if ∣a+b∣=a+b|a + b| = a + b, then ∣b+a∣=b+a|b + a| = b + a, implying that if (a, b) is in R, then (b, a) is also in R.
137 Medium
137 of 238
Application +4 | -1
If RR is the smallest equivalence relation on the set {1,2,3,4}\{1,2,3,4\} such that {(1,2),(1,3)}⊂R\{(1,2),(1,3)\} \subset R, then the number of elements in RR is
View answer and explanation
Correct option: B
10
The correct answer is B (10) because it represents the minimum number of ordered pairs required to satisfy the properties of an equivalence relation given the initial conditions.
138 Easy
138 of 238
Understanding +4 | -1
Let RR be the relation on the set R of all real numbers defined by aRb  if  ∣a−b∣≤1aRb\;if\;\left| {a - b} \right| \le 1, then RR is
View answer and explanation
Correct option: A
Reflexive and symmetric
Option A (Reflexive and symmetric) is correct because |a-a| <= 1 and |a-b| <= 1 implies |b-a| <= 1.
139 Medium
139 of 238
Understanding +4 | -1
Total number of equivalence relations defined in the set S={a,b,c}S=\{a, b, c\} is
View answer and explanation
Correct option: A
5
Option A (5) is correct because the number of equivalence relations on a set is equivalent to the number of partitions of the set, which is 5 for a set with 3 elements.
140 Easy
140 of 238
Analyzing +4 | -1
Let A={1,2,3}\mathrm{A}=\{1,2,3\} and R={(1,2)\mathrm{R}=\{(1,2), (2,3)}(2,3)\} be a relation in AA. Then, the minimum number of ordered pairs may be added, so that R\mathrm{R} becomes an equivalence relation. Is
View answer and explanation
Correct option: A
7
Option A (7) is correct because to make R an equivalence relation, we need to add (1,1), (2,2), (3,3), (2,1), (3,2), (1,3), and (3,1).
141 Easy
141 of 238
Remembering +4 | -1
Let X={1,2,3,4,5}X=\{1,2,3,4,5\}. Then, the number of elements in XX are
View answer and explanation
Correct option: A
5
Option A (5) is correct because the set X contains five distinct elements: 1, 2, 3, 4, and 5.
142 Medium
142 of 238
Understanding +4 | -1
Let N\mathrm{N} denote the set of all natural numbers. Define two binary relations on NN as R1={(x,y)∈N×N:2x+y=10}R_{1}=\{(x, y) \in N \times N: 2 x+y=10\} and R2={(x,y)∈N×N:x+2y=10}R_{2}=\{(x, y) \in N \times N: x+2 y=10\}. Then
View answer and explanation
Correct option: C
Range of R2R_{2} is {1,2,3,4}\{1,2,3,4\}
Option C is correct because the range of R2, defined by x + 2y = 10, with x and y being natural numbers, is {1, 2, 3, 4}.
143 Easy
143 of 238
Analyzing +4 | -1
Let R={(1,3),(4,2),(2,4),(2,3),(3,1)}R=\{(1,3),(4,2),(2,4),(2,3),(3,1)\} be a relation on the set A={1,2,3,4}.A=\{1,2,3,4\}. The relation RR is
View answer and explanation
Correct option: C
Not symmetric
The correct answer is C. The relation RR is not symmetric because (2,3)∈R(2,3) \in R but (3,2)∉R(3,2) \notin R.
144 Easy
144 of 238
Analyzing +4 | -1
The probability that a relation RR from {x,y}\{x, y\} to {x,y}\{x, y\} is both symmetric and transitive, is equal to
View answer and explanation
Correct option: A
516\frac{5}{16}
Option A (516\frac{5}{16}) is correct because there are 5 relations that are both symmetric and transitive out of a total of 16 possible relations.
145 Easy
145 of 238
Understanding +4 | -1
Let AA be the set of first ten natural numbers and let RR be a relation on AA defined by (x,y)∈R⇔x+2y=10(x, y) \in R \Leftrightarrow x+2 y=10 i.e., R={(x,y):x∈A,y∈AR=\{(x, y): x \in A, y \in A and x+2y=10}x+2 y=10\}. Then domains of R−1R^{-1}
View answer and explanation
Correct option: B
{4,3,2,1}\{4,3,2,1\}
Option B ({4,3,2,1}\{4,3,2,1\}) is correct because it represents the domain of the inverse relation, which is the range of the original relation.
146 Hard
146 of 238
Understanding +4 | -1
If R⊆A×BR \subseteq A \times B and S⊆B×CS \subseteq B \times C be two relations, then (S∘R)−1(S \circ R)^{-1} is equal to
View answer and explanation
Correct option: C
R−1∘S−1R^{-1} \circ S^{-1}
Option C (R−1∘S−1R^{-1} \circ S^{-1}) is correct because the inverse of the composition of two relations is the composition of their inverses in reverse order.
147 Easy
147 of 238
Understanding +4 | -1
Let RR be a relation on a set AA such that R=R−1,R = {R^{ - 1}}, then RR is
View answer and explanation
Correct option: B
Symmetric
Option B (Symmetric) is correct because if R = R⁻¹, then for every (a, b) in R, (b, a) is also in R, which is the definition of a symmetric relation.
148 Easy
148 of 238
Understanding +4 | -1
If relation RR is defined as :
aRbaRb if ′′a''a is the father of b′′b''. Then, RR is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the relation "a is the father of b" is neither reflexive, symmetric, nor transitive.
149 Medium
149 of 238
Application +4 | -1
If A={x∈z+:x<10A=\left\{x \in z^{+}: x<10\right. and xx is a multiple of 3 or 4}\}, where z+z^{+}is the set of positive integers, then the total number of symmetric relations on AA is
View answer and explanation
Correct option: B
2152^{15}
The correct answer is B (215) because it correctly determines the number of symmetric relations on set A by considering the pairs and their reverses.
150 Easy
150 of 238
Analyzing +4 | -1
For α∈N\alpha \in \mathbf{N}, consider a relation RR on N\mathbf{N} given by R={(x,y):3x+αyR=\{(x, y): 3 x+\alpha y is a multiple of 7}\}. The relation RR is an equivalence relation if and only if
View answer and explanation
Correct option: D
4 is the remainder when α\alpha is divided by 7
Option D (4 is the remainder when α is divided by 7) is correct because it satisfies the conditions for reflexivity, symmetry, and transitivity, making R an equivalence relation.
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