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JEE • MATHEMATICS • PROBABILITY

Probability practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 331-360 of 822 questions

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331 Easy
331 of 822
Application +4 | -1
If the mean of a binomial distribution with 9 trials is 6, then its variance is
View answer and explanation
Correct option: A
2
Option A (2) is correct because the variance of a binomial distribution is calculated as np(1-p), where n is the number of trials and p is the probability of success.
332 Easy
332 of 822
Analyzing +4 | -1
A box ' AA ' contanis 2 white, 3 red and 2 black balls. Another box ' BB ' contains 4 white, 2 red and 3 black balls. If two balls are drawn at random, without replacement, from a randomly selected box and one ball turns out to be white while the other ball turns out to be red, then the probability that both balls are drawn from box ' BB ' is
View answer and explanation
Correct option: A
716\frac{7}{16}
Option A (716\frac{7}{16}) is correct because it represents the conditional probability of drawing from box B given that a white and a red ball were drawn.
333 Easy
333 of 822
Application +4 | -1
A bag contains 4 brown and 5 white balls. A man pulls two balls at random without replacement. The probability that the man gets both the balls of the same colour is
View answer and explanation
Correct option: D
49\frac{4}{9}
Option D (4/9) is correct because it calculates the probability of drawing two balls of the same color by considering both cases: two brown balls or two white balls.
334 Easy
334 of 822
Application +4 | -1
If 14(1+4p),14(1−p)\frac{1}{4}(1+4 p), \frac{1}{4}(1-p) and 12(1−2p)\frac{1}{2}(1-2 p) are the probabilities of three mutually exclusive events, then 2p2 p is
View answer and explanation
Correct option: A
1
Option A (1) is correct because, given the probabilities of three mutually exclusive events, solving for p yields 2p = 1.
335 Easy
335 of 822
Analyzing +4 | -1
If AA and BB are two events. The probability that at most one of A,BA, B occurs, is
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Correct option: D
all the above
Option D (all the above) is correct because all the given expressions are equivalent representations of the probability that at most one of A, B occurs.
336 Easy
336 of 822
Application +4 | -1
The probability of choosing a number divisible by 6 or 8 from among 1 to 90 is
View answer and explanation
Correct option: D
2390\frac{{23}}{{90}}
Option D (2390\frac{{23}}{{90}}) is correct because it's the probability calculated by counting the numbers divisible by 6 or 8 between 1 and 90, using inclusion-exclusion.
337 Easy
337 of 822
Application +4 | -1
An urn contains 3 red and 5 blue balls. The probability that two balls are drawn in which 2nd ball drawn is blue without replacement, is
View answer and explanation
Correct option: C
58\frac{5}{8}
Option C (5/8) is correct as it calculates the probability of the second ball being blue by considering both cases: the first ball being red or blue.
338 Easy
338 of 822
Application +4 | -1
A box contains 3 white and 2 red balls. If we draw one ball and without replacing the first ball, the probability of drawing red ball in the second draw is
View answer and explanation
Correct option: B
25\frac{2}{5}
Option B (25\frac{2}{5}) is correct because it considers both cases: drawing a white ball first and drawing a red ball first, then calculating the probability of drawing a red ball in the second draw.
339 Easy
339 of 822
Application +4 | -1
In a binomial distribution, the mean is 4 and variance is 3. Then, its mode is
View answer and explanation
Correct option: C
4
Option C (4) is correct because the mode of a binomial distribution is the integer x that satisfies np+p>x>np−qnp + p > x > np - q, given mean np=4np = 4 and variance npq=3npq = 3.
340 Easy
340 of 822
Application +4 | -1
The probability of obtaining an even prime number on each die when a pair of dice is rolled is
View answer and explanation
Correct option: D
1/361 / 36
Option D (136\frac{1}{36}) is correct because it is the probability of getting an even prime number (2) on both dice.
341 Easy
341 of 822
Analyzing +4 | -1
An urn contains 6 white and 4 black balls. A fair die is rolled and that number of balls are chosen from the urn. The probability that the balls selected are white is
View answer and explanation
Correct option: A
1/51/5
Option A, 1/51/5, is correct because it represents the probability of selecting only white balls after rolling a die and choosing that many balls from the urn.
342 Easy
342 of 822
Application +4 | -1
If three integers are chosen at random from the set of first 20 natural numbers, the chance that their product is a multiple of 3 , is
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Correct option: D
194285\frac{194}{285}
Option D (194285\frac{194}{285}) is correct because it calculates the probability of the product of three integers being a multiple of 3 by finding the complement (none of the integers are multiples of 3) and subtracting from 1.
343 Easy
343 of 822
Application +4 | -1
On a Saturday night 20%20 \% of all drives in U.S.A. are under the influence of alcohol. The probability that a driver under the influence of alcohol will have an accident is 0.001.0.001. The probability that a sober driver will have an accident is 0.0001.0.0001. If a car on a Saturday night smashed into a tree, the probability that the driver was under the influence of alcohol is
View answer and explanation
Correct option: C
57\frac{5}{7}
Option C (5/7) is correct because it is the probability calculated using Bayes' theorem considering the probabilities of accidents with and without alcohol influence.
344 Easy
344 of 822
Application +4 | -1
In a party 23 persons take their seats at a round table. The odds against two particular persons sitting together are:
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Correct option: A
10:110: 1
Option A (10:110: 1) is correct because it's the odds against two particular persons sitting together, calculated using probability.
345 Easy
345 of 822
Application +4 | -1
A man is known to speak truth in 75% cases. If he throws an unbiased die and tells his friend that it is a six, then the probability that it is actually a six, is
View answer and explanation
Correct option: D
3/83/8
Option D (3/8) is correct because it is the result of applying Bayes' theorem to calculate the probability that it was actually a six given that the man reported it was a six.
346 Easy
346 of 822
Application +4 | -1
Seven white balls and three black balls are randomly placed in a row. The probability that no two black balls are placed adjacently equals
View answer and explanation
Correct option: B
715\frac{7}{15}
Option B (7/15) is correct because it represents the probability of arranging the balls such that no two black balls are adjacent, calculated using combinations.
347 Easy
347 of 822
Application +4 | -1
An article manufactured by a company consists of two parts X{X} and Y{Y}. In the process of manufacture of part X{X}, 9 out of 104 parts may be defective. Similarly, 5 out of 100 are likely to be defective in the manufacture of the part YY. The probability that the assembled product will not be defective, is
View answer and explanation
Correct option: B
361416\frac{361}{416}
Option B (361416\frac{361}{416}) is correct because it represents the probability of both parts X and Y not being defective when assembled.
348 Easy
348 of 822
Application +4 | -1
AA and BB are two events such that P(A∪B)=34P(A \cup B)=\frac{3}{4}, P(A∩B)=14,P(Aˉ)=23P(A \cap B)=\frac{1}{4}, P(\bar{A})=\frac{2}{3}, then P(Aˉ∩B)=P(\bar{A} \cap B)=
View answer and explanation
Correct option: A
512\frac{5}{12}
Option A (512\frac{5}{12}) is correct because it calculates the probability of the event (Aˉ∩B\bar{A} \cap B) using the given probabilities of (A ∪ B), (A ∩ B), and (Aˉ\bar{A}).
349 Easy
349 of 822
Application +4 | -1
A pack of cards contains 4 aces, 4 kings, 4 queens and 4 jacks. Two cards are drawn at random. The probability that atleast one of them is an ace is
View answer and explanation
Correct option: C
920\frac{9}{20}
Option C (920\frac{{9}}{{20}}) is correct because it is the probability of at least one ace being drawn, calculated by considering both cases: both cards are aces, or only one is an ace.
350 Easy
350 of 822
Analyzing +4 | -1
Box-I contains 30 cards numbered 1 to 30 and Box - II contains cards numbered 31 to 50 . A box is selected at random and a card is drawn from it. The number on the card is found to be a non-prime number. The probability that the card was drawn from Box - I is
View answer and explanation
Correct option: C
817\frac{8}{17}
Option C (817\frac{8}{17}) is correct because it uses Bayes' theorem to find the probability that the card was drawn from Box-I given that it's a non-prime number.
351 Easy
351 of 822
Application +4 | -1
In a binomial distribution B(n,p)B(n, p), the sum and the product of the mean and the variance are 5 and 6 respectively, then 6(n+p−q)6(n+p-q) is equal to
View answer and explanation
Correct option: A
52
Option A (52) is correct because it is the value obtained by solving the equations derived from the given sum and product of the mean and variance of the binomial distribution.
352 Easy
352 of 822
Application +4 | -1
If XX follows a binomial distribution with parameters n=6n = 6 and p.p. If 4(P(X=4))=P(X=2),4\left( {P\left( {X = 4} \right)} \right) = P\left( {X = 2} \right), then p=p =
View answer and explanation
Correct option: D
1/31/3
Option D (1/3) is correct because solving the equation 4P(X=4)=P(X=2)4P(X=4) = P(X=2) for a binomial distribution with n=6 yields p=1/3.
353 Easy
353 of 822
Application +4 | -1
The digits 1,2,3,4,5,6,7,81,2,3,4,5,6,7,8 and 9 are written in random order to form a nine digit number. The probability that this number is divisible by 4, is
View answer and explanation
Correct option: C
29\frac{2}{9}
Option C (29\frac{2}{9}) is correct because it calculates the probability of a nine-digit number formed by the digits 1-9 being divisible by 4 by considering the possible combinations of the last two digits.
354 Easy
354 of 822
Application +4 | -1
Out of 40 consecutive natural numbers, two are chosen at random. Probability that the sum of the numbers is odd, is
View answer and explanation
Correct option: B
2039\frac{{20}}{{39}}
Option B (20/39) is correct because the sum is odd only when one number is odd and the other is even, and this probability is calculated using combinations.
355 Easy
355 of 822
Application +4 | -1
For an initial screening of an admission test, a candidate is given fifty problems to solve. If the probability that the candidate can solve any problem is 45\frac{4}{5}, then the probability that he is unable to solve less than two problem is
View answer and explanation
Correct option: C
545(45)49\frac{{54}}{5}{\left( {\frac{4}{5}} \right)^{49}}
Option C (545(45)49\frac{{54}}{5}{\left( {\frac{4}{5}} \right)^{49}}) is correct because it is the probability that the candidate is unable to solve less than two problems, calculated using the binomial distribution.
356 Easy
356 of 822
Application +4 | -1
In a game two players AA and BB take turns in throwing a pair of fair dice starting with player AA and total of scores on the two dice, in each throw is noted. AA wins the game if he throws a total of 6 before BB throws a total of 7 and BB wins the game if he throws a total of 7 before AA throws a total of six. The game stops as soon as either of the players wins. The probability of AA winning the game is
View answer and explanation
Correct option: B
3061\frac{{30}}{{61}}
The correct answer is B (3061\frac{{30}}{{61}}) because it represents the probability of player A winning the game, calculated by considering the probabilities of throwing a 6 or 7 and using an infinite geometric series.
357 Easy
357 of 822
Application +4 | -1
A bag contains 4 red and 4 blue balls. Four balls are drawn one by one from the bag, then find the probability that the drawn balls are in alternate colour.
View answer and explanation
Correct option: D
635\frac{6}{35}
Option D (635\frac{{6}}{{35}}) is correct because it calculates the probability of drawing balls in alternating colors by considering both red-blue and blue-red sequences.
358 Easy
358 of 822
Application +4 | -1
In a book of 500 pages, it is found that there are 250 typing errors. Assume that poisson law holds for the number of errors per page. Then, the probability that a random sample of 2 pages will contain no error, is
View answer and explanation
Correct option: C
e−1{e^{ - 1}}
Option C (e−1{e^{ - 1}}) is correct because it applies the Poisson distribution to calculate the probability of no errors on a random sample of 2 pages.
359 Easy
359 of 822
Application +4 | -1
Three persons A,BA, B and CC are to speak at a function along with 7 other persons. The probability that A,BA, B, and CC speak together
View answer and explanation
Correct option: B
115\frac{1}{15}
Option B (115\frac{1}{15}) is correct because it represents the probability that A, B, and C speak together in a function with 7 other people.
360 Easy
360 of 822
Application +4 | -1
A box contain NN coins, mm of which are fair and rest are biased. The probability of getting a head when a fair coin is tossed is 1/21 / 2, while it is 2/32 / 3 when a biased coin is tossed. A coin is drawn from the box at random and is tossed twice. The first time it shows head and the second time it shows tail. The probability that the coin drawn is fair is
View answer and explanation
Correct option: C
9m8N+m\frac{9 m}{8 N+m}
Option C (9m8N+m\frac{{9 m}}{{8 N+m}}) is correct because it represents the probability that the coin drawn is fair, given the observed sequence of head and tail, using Bayes' theorem.
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