JEE MATHEMATICS MCQ: PROBABILITY

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10 different vectors are lying on a plane out of which four are parallel with respect to each other. Probability that three vectors chosen from them will satisfy the equation

\lambda_1 \mathbf{a}+\lambda_2 \mathbf{b}+\lambda_3 \mathbf{c}=0

, where

\lambda_1, \lambda_2

and

\lambda_3 \neq 0

View answer and explanation

Correct option: D

\frac{\left({ }^6 C_2+{ }^4 C_1\right)+\left({ }^6 C_2 \times{ }^4 C_1\right)}{{ }^{10} C_3}

Option D (

\frac{\left({ }^6 C_2+{ }^4 C_1\right)+\left({ }^6 C_2 \times{ }^4 C_1\right)}{{ }^{10} C_3}

) is correct because it considers all possible combinations of vectors from the parallel and non-parallel sets that satisfy the given equation.

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