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JEE • MATHEMATICS • PROBABILITY
Probability practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 271-300 of 1130 questions
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271
Easy
271 of 1130
Application
+4 | -1
If follows a binomial distribution with parameters and , then is maximum when is equal to
View answer and explanation
Correct option: C
33
Option C is correct because the maximum probability occurs at r = floor((n+1)p), which is 33 in this case.
272
Medium
272 of 1130
Application
+4 | -1
Suppose that a die (with faces marked 1 to 6) is loaded in such a manner that for the probability of the face marked turning up when die is tossed is proportional to . The probability of the event that the outcome of a toss of the die will be an even number, is equal to
View answer and explanation
Correct option: A
Option A, is correct because when the probability is proportional to K, the probability of an even number is simply the sum of probabilities of even numbers divided by the sum of probabilities of all numbers.
273
Medium
273 of 1130
Application
+4 | -1
An integer is chosen at random from the integers . The probability that the chosen integer is a multiple of atleast one of 4,6 and 7 is
View answer and explanation
Correct option: C
The correct answer is C (21/50) because it represents the probability calculated using the principle of inclusion-exclusion for multiples of 4, 6, and 7.
274
Easy
274 of 1130
Application
+4 | -1
A die is thrown twice and the sum of the numbers appearing is observed to be 6 . The conditional probability that the number 4 has appeared at least once, is
View answer and explanation
Correct option: B
Option B () is correct because it calculates the conditional probability of the number 4 appearing at least once, given that the sum of the numbers is 6.
275
Easy
275 of 1130
Application
+4 | -1
Two dice are thrown together. If the numbers appearing on the two dice are different, then what is the probability that the sum is 6?
View answer and explanation
Correct option: C
Option C () is correct because it calculates the conditional probability of the sum being 6 given that the numbers on the two dice are different.
276
Easy
276 of 1130
Application
+4 | -1
A coin is tossed times the probability of getting head at least once is greater than 0.8. Then the least value of such is
View answer and explanation
Correct option: B
3
Option B (3) is correct because it is the smallest integer value of n for which the probability of getting at least one head is greater than 0.8.
277
Medium
277 of 1130
Analyzing
+4 | -1
If is a binomial variate with parameters and , where such that is independent of and , then equals
View answer and explanation
Correct option: A
Option A () is correct because the condition being independent of and implies that must be equal to .
278
Easy
278 of 1130
Understanding
+4 | -1
Let be the sample space and be an event.
Given below are two statements:
(S1) : If , then
(S2) : If , then
Then
Given below are two statements:
(S1) : If , then
(S2) : If , then
Then
View answer and explanation
Correct option: D
Both (S1) and (S2) are true
Option D is correct. If P(A) = 0, A is almost surely empty, and if P(A) = 1, A is almost surely the entire sample space.
279
Medium
279 of 1130
Application
+4 | -1
If follows a binomial distribution with parameters and , find for which is maximum
View answer and explanation
Correct option: C
33
Option C (33) is correct because the value of r for which P(X=r) is maximum is the mode of the binomial distribution, which is the integer part of (n+1)p = (100+1)(1/3) = 33.67, hence r=33.
280
Easy
280 of 1130
Application
+4 | -1
A bag contains 4 tickets numbered 1, 2, 3, 4 and another bag contains 6 tickets numbered 2, 4, 6, 7, 8, 9. One bag is chosen and a ticket is drawn. The probability that the ticket bears the number 4 is
View answer and explanation
Correct option: C
May-24
Option D (May-24) is correct because the probability is calculated by considering both bags and the chance of drawing a 4 from each.
281
Easy
281 of 1130
Application
+4 | -1
If and are mutually exclusive events with , then
View answer and explanation
Correct option: D
Option D (P(A)/(1-P(B))) is correct because it applies the conditional probability formula and uses the fact that A and B are mutually exclusive.
282
Medium
282 of 1130
Application
+4 | -1
An urn contains 6 white and 9 black balls. Two successive draws of 4 balls are made without replacement. The probability that the first draw gives all white balls and second draw gives all black balls is
View answer and explanation
Correct option: D
Option D () is correct because the probability of drawing 4 white balls then 4 black balls without replacement is calculated as .
283
Hard
283 of 1130
Understanding
+4 | -1
If and are independent events such that then
View answer and explanation
Correct option: D
Option D () is correct because represents the sum of conditional probabilities of an event and its complement given B, which always equals 1.
284
Easy
284 of 1130
Application
+4 | -1
and are two events such that odds against are odds in favour of are . If , then the ordered pair is
View answer and explanation
Correct option: A
Option A () is correct because it determines the range of P(B) based on the given probabilities and the properties of probability.
285
Easy
285 of 1130
Application
+4 | -1
A coin is tossed times. The chance that the number of times one gets head is not equal to the number of times one gets tail, is
View answer and explanation
Correct option: C
The correct answer is because it represents 1 minus the probability of getting an equal number of heads and tails.
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286
Easy
286 of 1130
Analyzing
+4 | -1
is a set containing elements. A subset of is chosen at random. The set is reconstructed by replacing the elements of . A subset is again chosen at random. The probability that and have equal number of elements, is
View answer and explanation
Correct option: B
Option B () is correct because it represents the probability that P and Q have an equal number of elements, considering all possible choices for sets P and Q.
287
Easy
287 of 1130
Application
+4 | -1
A company has two plants A and B to manufacture motorcycles. motorcycles are manufactured at plant A and the remaining are manufactured at plant B. of the motorcycles manufactured at plant A are rated of the standard quality, while of the motorcycles manufactured at plant B are rated of the standard quality. A motorcycle picked up randomly from the total production is found to be of the standard quality. If p is the probability that it was manufactured at plant B, then is
View answer and explanation
Correct option: A
54
Option A (54) is correct because it is the value of 126p, where p is the probability that the motorcycle was manufactured at plant B given that it is of standard quality, calculated using Bayes' theorem.
288
Easy
288 of 1130
Application
+4 | -1
It is against a person who is now 40 years old living till he is 70 and against a person now 50 living till he is 80 . The probability that at least one of these persons will be alive 30 years hence, is
View answer and explanation
Correct option: C
Option A () is correct because it calculates the probability that the vowels occupy only odd positions when arranging the letters of the word 'longest'.
289
Easy
289 of 1130
Application
+4 | -1
Three coins are tossed together, then the probability of getting at least one head is
View answer and explanation
Correct option: D
Option D () is correct because it represents the probability of getting at least one head, which is the complement of getting all tails.
290
Medium
290 of 1130
Analyzing
+4 | -1
For any two independent events and
View answer and explanation
Correct option: A
Option A () is correct because the expression simplifies to 0, which is less than or equal to 1/4.
291
Easy
291 of 1130
Analyzing
+4 | -1
Out of consecutive integers, three are selected at random. Find the probability that their sum is divisible by 3 , is
View answer and explanation
Correct option: C
Option C () is correct because it represents the probability calculated by dividing the number of ways to choose three integers whose sum is divisible by 3 by the total number of ways to choose three integers.
292
Easy
292 of 1130
Application
+4 | -1
Two events and are such that and . The probability of occurrence of at least one of event is
View answer and explanation
Correct option: A
0.7
Option A (0.7) is correct because it calculates the probability of at least one of the events occurring using the formula P(A∪B) = P(AB') + P(B).
293
Easy
293 of 1130
Application
+4 | -1
A bag contains 3 red and 7 black balls. Two balls are selected at random without replacement. If the second selected ball is given to be red, the Probability that the first selected ball is also red, is
View answer and explanation
Correct option: B
Option B () is correct because it represents the conditional probability that the first ball is red, given that the second ball is red.
294
Easy
294 of 1130
Application
+4 | -1
A fair die is tossed repeatedly until a six is obtained. Let denote the number of tosses required. Then, the probability that equals
View answer and explanation
Correct option: A
Option A (25/216) is correct because it represents the probability of not getting a six in the first two tosses and then getting a six on the third toss.
295
Medium
295 of 1130
Application
+4 | -1
A bag contains 5 white and 3 black balls and 4 balls are successively drawn out and not replaced. The probability that they are alternately of different colours, is
View answer and explanation
Correct option: C
Option C (1/7) is correct because it calculates the probability of alternately drawing white and black balls without replacement.
296
Easy
296 of 1130
Application
+4 | -1
A bag contains 5 red and 3 bluc balls. If 3 balls are drawn at random without replacement, then the probability of getting exactly one red ball is
View answer and explanation
Correct option: C
Option C () is correct because it is the probability of drawing exactly one red ball out of three, calculated using combinations.
297
Easy
297 of 1130
Application
+4 | -1
100 Students appeared for two examinations, 60 passed the first, 50 passed the second and 30 passed both. The Probability that a student selected at random has failed in both examinations, is
View answer and explanation
Correct option: B
0.2
Option B (0.2) is correct because it calculates the probability of a student failing both exams by subtracting the probability of passing at least one exam from 1.
298
Medium
298 of 1130
Application
+4 | -1
Two integers and are drawn one at a time without replacement from the set . If , then is if .
View answer and explanation
Correct option: A
1
Option A (1) is correct because given the condition p_k = P(r <= k | s <= k), and n=25, k=7, then 4p_7 = 1.
299
Medium
299 of 1130
Application
+4 | -1
Bag A contains 4 green and 3 red balls and Bag contains 4 red and 3 green balls. One bag is taken at random and a ball is noted it is green. The probability that it comes from is -
View answer and explanation
Correct option: C
Option C () is correct because the probability is calculated using Bayes' theorem, considering the probabilities of drawing a green ball from each bag.
300
Easy
300 of 1130
Application
+4 | -1
A number is chosen at random among the first 120 natural numbers. The probability of the number chosen being a multiple of 5 or 15 is
View answer and explanation
Correct option: B
Option B () is correct because it calculates the probability of a number chosen from the first 120 natural numbers being a multiple of 5 or 15.
Revision notes and key takeaways
Review PROBABILITY in your textbook or class notes, then use this set to check your understanding.
Showing 271-300 of 1130 questions
