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JEE • MATHEMATICS • PROBABILITY

Probability practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 301-330 of 1130 questions

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301 Easy
301 of 1130
Analyzing +4 | -1
In a convex hexagon two diagonals are drawn at random. The probability that the diagonals intersect at an interior point of the hexagon is
View answer and explanation
Correct option: A
5/125 / 12
Option A (512\frac{5}{12}) is correct because it accurately calculates the probability of two randomly drawn diagonals intersecting inside the hexagon.
302 Easy
302 of 1130
Application +4 | -1
A perfect die is thrown twice. The expected value of the product of the number of points obtained in two throws is
View answer and explanation
Correct option: C
49/449 / 4
Option C (49/4) is correct because the expected value of the product is the product of the expected values of each throw, given the independence of the throws.
303 Easy
303 of 1130
Understanding +4 | -1
A card is selected from a pack of 52 cards.

I. The probability that card is an ace of spades, is 252\frac{2}{52}.

II. The probability that the card is black card, is 2652\frac{26}{52}.
View answer and explanation
Correct option: A
Only I is false
Option A (Only I is false) is correct because the probability of drawing an ace of spades is 1/52, not 2/52, while the probability of drawing a black card is indeed 26/52.
304 Easy
304 of 1130
Application +4 | -1
The probability that a leap year selected at random contains either 53 Sundays or 53 Mondays, is
View answer and explanation
Correct option: C
37\frac{3}{7}
Option C (37\frac{3}{7}) is correct because it calculates the probability of a leap year containing either 53 Sundays or 53 Mondays by considering the possible combinations of the two extra days in a leap year.
305 Medium
305 of 1130
Application +4 | -1
Let 0.8 the probability that a man aged 90 years will die in a year. If pp is the probability that out of 4 men A1,A2,A3A_1, A_2, A_3 and A4A_4 each aged 90,A190, A_1 will die in a year and will be the first to die, find 10000p−249010000 p-2490 is
View answer and explanation
Correct option: D
6
Option D (6) is correct because it is calculated by finding the probability that A1 dies first and then subtracting 2490 from 10000 times that probability.
306 Easy
306 of 1130
Application +4 | -1
A five digit number is chosen at random. The probability that all the digit are distinct and digits at odd places are odd and digits at even place are even, is
View answer and explanation
Correct option: D
175\frac{1}{{75}}
Option D (1/75) is correct because the probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
307 Easy
307 of 1130
Application +4 | -1
Let A={1,3,5,7,9}A=\{1,3,5,7,9\} and B={2,4,6,8}B=\{2,4,6,8\}. An element (a,b)(a, b) of their cartesian product A×BA \times B is chosen at random. The probability that a+b=9a+b=9, is
View answer and explanation
Correct option: A
1/51 / 5
Option A (1/5) is correct because there are 4 favorable outcomes (a+b=9) out of a total of 20 possible outcomes in the Cartesian product A x B.
308 Medium
308 of 1130
Application +4 | -1
A bag contains 8 red and 7 black balls. Two balls are drawn at random. The probability that both the balls are of the same colour, is
View answer and explanation
Correct option: C
715\frac{7}{{15}}
Option C (715\frac{7}{{15}}) is correct because it represents the probability of drawing two balls of the same color, calculated by summing the probabilities of drawing two red balls and drawing two black balls.
309 Easy
309 of 1130
Analyzing +4 | -1
A pack of cards has one card missing. Two cards are drawn randomly and are found to be spades. The probability that the missing card is not a spade is:
View answer and explanation
Correct option: C
3950\frac{{39}}{{50}}
Option C (3950\frac{{39}}{{50}}) is correct because it is the calculated probability that the missing card is not a spade, given that two drawn cards are spades.
310 Easy
310 of 1130
Application +4 | -1
You are given a box with 20 cards in it. 10 of these cards have the letter II printed on them. The other ten have the letter T{T} printed on them. If you pick up 3 cards at random and keep them in the same order, the probability of making the word IITIIT is
View answer and explanation
Correct option: D
538\frac{5}{38}
Option D (538\frac{5}{38}) is correct because it represents the probability of drawing an I, then another I, and then a T in that specific order.
311 Easy
311 of 1130
Understanding +4 | -1
If AA and BB are two given events, then P(A∩B)P(A \cap B) is
View answer and explanation
Correct option: A
not less than P(A)+P(B)−1P(A)+P(B)-1
Option A is correct because P(A∩B)P(A \cap B) is always greater than or equal to P(A)+P(B)−1P(A) + P(B) - 1 due to the properties of probability.
312 Easy
312 of 1130
Application +4 | -1
A coin is tossed 4 times. The probability that atleast one head turn up, is
View answer and explanation
Correct option: D
1516\frac{15}{16}
Option D (15/16) is correct because it calculates the probability of at least one head by subtracting the probability of all tails from 1.
313 Medium
313 of 1130
Application +4 | -1
Two dice are rolled. If the probability of getting different numbers on the these dice is pq\frac{p}{q} where p,qp, q are relatively prime then q−pq-p is
View answer and explanation
Correct option: C
1
Option B (2-4a) is correct because applying L'Hopital's rule to the limit yields the result 2-4a.
314 Easy
314 of 1130
Understanding +4 | -1
If AA and BB are two independent events, then AA and Bˉ\bar B are
View answer and explanation
Correct option: B
Also independent
Option B (Also independent) is correct because if A and B are independent, then A and the complement of B are also independent.
315 Easy
315 of 1130
Analyzing +4 | -1
Five boys and three girls are seated at random in a row. The probability that no boy sits between two girls is
View answer and explanation
Correct option: C
3/283/28
Option C (3/283/28) is correct because it represents the probability of five boys and three girls sitting in a row with no boy between two girls, calculated by considering the girls as one unit.
316 Easy
316 of 1130
Application +4 | -1
5 persons A,B,C,DA, B, C, D and EE are in 9 queue of a shop. The probability that AA and EE always together is
View answer and explanation
Correct option: C
25\frac{2}{5}
Option C (2/5) is correct because it calculates the probability of A and E being together by considering them as a single unit.
317 Easy
317 of 1130
Analyzing +4 | -1
The probability of the product of 3 numbers chosen from the set A={1,2,3,4,……20}\mathrm{A}=\{1,2,3,4, \ldots \ldots 20\} is divisible by 4 is equal to
View answer and explanation
Correct option: B
5376\frac{53}{76}
Option B (5376\frac{53}{76}) is correct because it calculates the probability of the product being divisible by 4 by finding the complement (not divisible by 4) and subtracting from 1.
318 Easy
318 of 1130
Application +4 | -1
AA and BB are two independent events such that P(A∪B′)=0.8P\left( {A \cup B'} \right) = 0.8 and P(A)=0.3.P\left( A \right) = 0.3. Then, P(B)P\left( B \right) is
View answer and explanation
Correct option: A
27\frac{2}{7}
Option A (2/7) is correct because it correctly uses the independence of events A and B to find P(B) from the given probabilities.
319 Medium
319 of 1130
Application +4 | -1
One percent of the population suffers from a certain disease. There is blood test for this disease, and it is 99%99 \% accurate, in other words, the probability that it gives the correct answer is 0.99 , regardless of whether the person is sick or healthy. A person takes the blood test, and the result says that he has the disease. The probability that he actually has the disease, is
View answer and explanation
Correct option: C
50%50 \%
Option C (50 %) is correct because the probability is calculated using Bayes' theorem, considering the prior probability of having the disease and the accuracy of the test.
320 Easy
320 of 1130
Application +4 | -1
A man is known to speak the truth 3 out of 4 times. He throws a die and reports that it is six. The probability that it is actually a six, is
View answer and explanation
Correct option: A
38\frac{3}{8}
Option A (38\frac{3}{8}) is correct because it is calculated using Bayes' theorem, considering the probability of the man speaking the truth and the probability of him lying.
321 Easy
321 of 1130
Application +4 | -1
The probability that a student is not a swimmer is 1/51 / 5. The probability that out of 5 students exactly 4 are swimmer is
View answer and explanation
Correct option: B
(45)4\left(\frac{4}{5}\right)^4
Option B ((45)4\left(\frac{{4}}{{5}}\right)^4) is correct because it represents the probability of exactly 4 swimmers out of 5 students, accounting for the combination and probability of success.
322 Medium
322 of 1130
Application +4 | -1
A bag contains 50 tickets numbered 1, 2, 3, …, 50 of which five are drawn at random and arranged in ascending order of magnitude (x1<x2<x3<x4<x5).\left( {{x_1} < {x_2} < {x_3} < {x_4} < {x_5}} \right). The probability that x3=30,{x_3} = 30, is
View answer and explanation
Correct option: C
  20C2×  29C2  50C5\frac{{{\;^{20}}{C_2} \times {\;^{29}}{C_2}}}{{{\;^{50}}{C_5}}}
Option C (  20C2×  29C2  50C5\frac{{{\;^{20}}{C_2} \times {\;^{29}}{C_2}}}{{\;^{50}}{C_5}}) is correct because it represents the probability of having x3 = 30, with two numbers less than 30 and two numbers greater than 30.
323 Easy
323 of 1130
Application +4 | -1
A box contains 20 cards of these 10 have letter I printed on them and the remaining 10 have T printed on them. 3 cards are drawn from the box, the probability that we can write IIT with these cards is
View answer and explanation
Correct option: D
1538\frac{15}{38}
Option D (1538\frac{{15}}{{38}}) is correct because it is calculated by finding the number of ways to choose 2 'I's and 1 'T' and dividing it by the total number of ways to choose 3 cards.
324 Easy
324 of 1130
Application +4 | -1
Two numbers aa and bb are selected at random from 1,2,….,1001,2, \ldots ., 100 and are multiplied. The probability that the product aba b is divisible by 3 , is
View answer and explanation
Correct option: B
83150\frac{83}{150}
Option B (83150\frac{83}{150}) is correct because it calculates the probability that the product of two randomly selected numbers is divisible by 3 by considering the complement event (neither number is divisible by 3).
325 Easy
325 of 1130
Application +4 | -1
Two dice are rolled one after the other. The probability that the number on the first is smaller than the number on the second is
View answer and explanation
Correct option: D
512\frac{5}{{12}}
Option D (512\frac{5}{{12}}) is correct because it calculates the probability of the first die showing a smaller number than the second die.
326 Easy
326 of 1130
Application +4 | -1
A die is tossed thrice. If event of getting an even number is a success, then the probability of getting at least two successes is
View answer and explanation
Correct option: D
1/21 / 2
The correct answer is 1/21 / 2 because it calculates the probability of getting at least two successes when tossing a die thrice.
327 Easy
327 of 1130
Application +4 | -1
An elevator starts with mm passengers and stops at nn floors (m≤n)(m \leq n). The probability that no two passengers alight at the same floor is
View answer and explanation
Correct option: B
nPmnm\frac{{ }^n P_m}{n^m}
Option B (nPmnm\frac{{ }^n P_m}{n^m}) is correct because it represents the probability that no two passengers alight at the same floor when m passengers start in an elevator and stop at n floors.
328 Medium
328 of 1130
Application +4 | -1
Three letters are written to there different persons and addresses on the three envelopes are also written. Without looking at the addresses, the letters are kept in these envelopes. The probability that all the letters are not placed into their right envelopes is
View answer and explanation
Correct option: B
13\frac{1}{3}
Option B (1/3) is correct because it calculates the probability that all letters are not placed into their right envelopes using derangements.
329 Easy
329 of 1130
Application +4 | -1
Three six faced dice are tossed together, then the probability that exactly two of the three numbers are equal is
View answer and explanation
Correct option: D
90/216
Option D (90/216) is correct because it represents the probability of exactly two dice showing the same number when three dice are tossed.
330 Medium
330 of 1130
Understanding +4 | -1
If AA and BB are independent events and P(C)=0,P\left( C \right) = 0, then
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because if P(C) = 0, then A and C, B and C, and A, B, and C are all independent events.
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