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JEE • MATHEMATICS • PERMUTATION AND COMBINATION
Permutation and combination practice · Easy
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 151-180 of 485 questions
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151
Easy
151 of 485
Application
+4 | -1
The exponent of 3 in 100 !, is
View answer and explanation
Correct option: C
48
Option A (72) is correct because it calculates the number of words formed with at least one vowel.
152
Easy
152 of 485
Understanding
+4 | -1
There are 10 true-false questions. The number of ways, in which they can be answered is
View answer and explanation
Correct option: B
Option B () is correct because each of the 10 questions can be answered in 2 ways (true or false), leading to total possibilities.
153
Easy
153 of 485
Understanding
+4 | -1
The value of , when numerator and denominator takes their greatest value, is
View answer and explanation
Correct option: A
Option A () is correct because it is the simplified ratio of the two binomial coefficients.
154
Easy
154 of 485
Application
+4 | -1
If all permutations of the letters of the word PENCIL are arranged as in a dictionary, then 413th word is
View answer and explanation
Correct option: D
LICPEN
Option D (LICPEN) is correct because after arranging the permutations of the letters in the word PENCIL in dictionary order, the 413th word is LICPEN.
155
Easy
155 of 485
Application
+4 | -1
A seven-digit numbers divisible by 9 is to be formed by using 7 out of numbers . The number of ways in which this can be done, is
View answer and explanation
Correct option: D
Option D () is correct because there are 4 pairs of digits that can be excluded to make the sum of the remaining 7 digits divisible by 9, and each set of 7 digits can be arranged in 7! ways.
156
Easy
156 of 485
Application
+4 | -1
How many four digit numbers can be formed using the digits 1, 2, 3, 4, 5 such that at least one of the digit is repeated?
View answer and explanation
Correct option: D
Option D () is correct because it subtracts the number of four-digit numbers with no repetition from the total number of four-digit numbers that can be formed.
157
Easy
157 of 485
Application
+4 | -1
A dictionary is printed consisting of 7 letters words only that can be made with a letters of the word CRICKET. If the words are printed at the alphabetical order as in an ordinary dictionary, then the number of words before the word CRICKET is
View answer and explanation
Correct option: A
530
Option A (530) is correct because it calculates the number of words before \"CRICKET\" by considering alphabetical order and accounting for repeated letters.
158
Easy
158 of 485
Application
+4 | -1
The number of six-digit numbers that can be formed from the digits 1, 2, 3, 4, 5, 6 and 7, so that digits do not repeat and the terminal digits are even, is
View answer and explanation
Correct option: D
720
The correct answer is D (720) because it correctly calculates the number of six-digit numbers with even terminal digits from the given digits without repetition.
159
Easy
159 of 485
Application
+4 | -1
The number of ways in which positive and negative signs may be placed in a row so that no two negative signs shall be together is
View answer and explanation
Correct option: A
Option A () is correct because it represents the number of ways to place negative signs such that no two are together.
160
Easy
160 of 485
Analyzing
+4 | -1
The number of 6 digits numbers that can be formed using the digits 0, 1, 2, 5, 7 and 9 which are divisible by 11 and no digit is repeated, is
View answer and explanation
Correct option: A
60
Option A (60) is correct because it is the total number of 6-digit numbers that can be formed using the given digits, divisible by 11, with no repetition.
161
Easy
161 of 485
Understanding
+4 | -1
Let be the set of all functions from the set to the set . If , then is
View answer and explanation
Correct option: B
Option B () is correct because each of the k elements in A can be mapped to any of the k elements in A.
162
Easy
162 of 485
Application
+4 | -1
If then is equal to
View answer and explanation
Correct option: C
8, 9, 10
Option C (8, 9, 10) is correct because these values of r satisfy the inequality after simplification.
163
Easy
163 of 485
Application
+4 | -1
If and , then is equal to
View answer and explanation
Correct option: A
6
Option A (6) is correct because solving the given ratio of permutations leads to the equation 2x-1=11, which gives x=6.
164
Easy
164 of 485
Application
+4 | -1
A basket ball team consists of 12 pairs of twin brothers. On the first day of training, all 24 players stand in a circle in such a way that all pairs of twin brothers are neighbours. Number of ways this can be done is :
View answer and explanation
Correct option: B
Option B () is correct because there are 11! ways to arrange the 12 pairs in a circle, and each pair can be arranged in 2 ways.
165
Easy
165 of 485
Analyzing
+4 | -1
Consider the following statement:
1.The number of ways of arranging m different things taken all at a time in which perticular things are never together is
2. A pack of 52 cards can be divided equally among four players in order in ways
Which of these is/are correct?
1.The number of ways of arranging m different things taken all at a time in which perticular things are never together is
2. A pack of 52 cards can be divided equally among four players in order in ways
Which of these is/are correct?
View answer and explanation
Correct option: C
Both of these
Both statements are correct. Statement 1 correctly describes the number of arrangements where p particular things are never together, and statement 2 accurately represents the number of ways to divide a deck of cards equally among four players.
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166
Easy
166 of 485
Application
+4 | -1
The number of ways distributing 8 identical balls in 3 distinct boxes so that none of the boxes is empty is
View answer and explanation
Correct option: B
21
Option B (21) is correct because it represents the number of ways to distribute 8 identical balls into 3 distinct boxes with no box empty, which is calculated using the stars and bars method.
167
Easy
167 of 485
Analyzing
+4 | -1
A man has three friends. The number of ways he can invite one friend everyday for dinner on six successive nights, so that no friend is invited more than three times, is
View answer and explanation
Correct option: D
510
The correct answer is D (510) because it accounts for all possible ways the man can invite his friends, considering the constraint that no friend is invited more than three times.
168
Easy
168 of 485
Application
+4 | -1
The number of arrangements which can be made out of the letters of the word ALGEBRA, without changing the relative order (positions) of vowels and consonants, is
View answer and explanation
Correct option: A
72
Option A (72) is correct because it accounts for arranging vowels and consonants separately while considering repeated vowels.
169
Easy
169 of 485
Application
+4 | -1
Eleven books consisting of 5 Mathematics, 4 physics and 2 Chemistry are places on a shelf. The number of possible ways of arranging them on the assumption that the books of the same subject are all together, is
View answer and explanation
Correct option: C
Option C () is correct because it accounts for arranging the books within each subject and then arranging the subjects themselves.
170
Easy
170 of 485
Application
+4 | -1
If the letters of the word ‘SACHIN’ are arranged in all possible ways and these words are written out as in dictionary, then the word ‘SACHIN’ appears at serial number
View answer and explanation
Correct option: D
601
Option D (601) is correct because it represents the position of the word 'SACHIN' when all permutations are arranged alphabetically.
171
Easy
171 of 485
Application
+4 | -1
The number of ways in which things of which are alike, can be arranged in a circular order, is
View answer and explanation
Correct option: B
Option B (48) is correct because we calculate the total permutations of 5-digit numbers and subtract those that start with 3 to ensure the number is greater than 50,000.
172
Easy
172 of 485
Application
+4 | -1
Four married couples are to be seated in a row having 8 chairs. The number of ways so that spouses are seated next to each other, is
View answer and explanation
Correct option: C
384
Option C (384) is correct because it accounts for arranging the couples and then arranging the spouses within each couple.
173
Easy
173 of 485
Understanding
+4 | -1
The value of is
View answer and explanation
Correct option: B
Option B () is correct because the given summation is equivalent to the binomial expansion of excluding the first term.
174
Easy
174 of 485
Application
+4 | -1
A man has 6 friends. In how many ways he can invite one or more of them at dinner?
View answer and explanation
Correct option: C
63
Option C (63) is correct because each friend can either be invited or not, leading to possibilities, but we subtract 1 for the case where no friends are invited.
175
Easy
175 of 485
Application
+4 | -1
Find the number of ways of arranging the letters of the word ENGINEERING
View answer and explanation
Correct option: D
Option D () is correct because it accounts for the repetitions of the letters E, N, G, and I in the word ENGINEERING.
176
Easy
176 of 485
Application
+4 | -1
From 7 gentlemen and 4 ladies, a committee of 5 is to be formed. The number of ways in which this can be done so as to include atleast one lady is
View answer and explanation
Correct option: A
805
Option A (805) is correct because it sums the number of ways to form the committee with at least one lady.
177
Easy
177 of 485
Application
+4 | -1
If one test (on screening paper basis) was conducted on Batch A, maximum number of marks is students get the marks lower than 80 . Coaching institute decide to inform their guardians, that is why their result card were sent to their home. The number of ways, in which all the letters were put in wrong envelopes, is
View answer and explanation
Correct option: A
9
Option A (9) is correct because the number of ways to put all 4 letters in the wrong envelopes is calculated using the derangement formula, which results in 9.
178
Easy
178 of 485
Application
+4 | -1
How many 10 digit numbers can be written by using the digits 1 and 2?
View answer and explanation
Correct option: B
Option B () is correct because each of the 10 digits can be either 1 or 2, resulting in 2 options for each digit.
179
Easy
179 of 485
Application
+4 | -1
If 20 lines are drawn in a plane such that no two of them are parallel and no three are concurrent. The number of points in which they intersect each other is
View answer and explanation
Correct option: B
190
Option B (190) is correct because it calculates the number of intersection points formed by 20 lines, where no two are parallel and no three are concurrent.
180
Easy
180 of 485
Application
+4 | -1
The number of ways 12 different books can be distributed equally among 4 persons, is
View answer and explanation
Correct option: C
Option C () is correct because it represents the number of ways to distribute 12 distinct books equally among 4 people.
Revision notes and key takeaways
Review PERMUTATION AND COMBINATION in your textbook or class notes, then use this set to check your understanding.
Showing 151-180 of 485 questions
