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JEE MATHEMATICS MCQ: PERMUTATIONS

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Application +4 | -1
Out of 10 consonants four vowels, the number of words that can be formed using six consonants and three vowels
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Correct option: C
  10C6×  4C3×9!{\;^{10}}{C_6} \times {\;^4}{C_3} \times 9!
Option C (  10C6×  4C3×9!{\;^{10}}{C_6} \times {\;^4}{C_3} \times 9!) is correct because it selects 6 consonants out of 10, 3 vowels out of 4, and then arranges the 9 selected letters.

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