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JEE MATHEMATICS MCQ: PERMUTATIONS

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Analyzing +4 | -1
There are 6 gentlemen and 3 ladies to dine at a round table. In how many ways can they seat themselves so that two particular ladies refuse to sit beside a particular gentleman?
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Correct option: B
8!−2!×6!8 !-2 ! \times 6 !
Option B (8!−2!×6!8 !-2 ! \times 6 !) is correct because it calculates the total possible arrangements minus the arrangements where the two ladies sit beside the gentleman.

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