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JEE • MATHEMATICS • PERMUTATION AND COMBINATION

Permutation and combination practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 541-570 of 742 questions

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541 Easy
541 of 742
Application +4 | -1
If the permutations of a,b,c,da, b, c, d and ee taken all together are written down in alphabetical order as in dictionary and numbered, the rank of the permutation debac is
View answer and explanation
Correct option: D
93
Option D (93) is correct because it determines the rank of the given permutation in alphabetical order.
542 Easy
542 of 742
Application +4 | -1
Find the number of ways in which 8 different flowers can be strung to form a garland so that 4 particular flowers are never separated
View answer and explanation
Correct option: B
288
Option B (288) is correct because the 4 particular flowers are treated as one unit, and the garland can be flipped, so we divide by 2.
543 Easy
543 of 742
Application +4 | -1
If (m+n)P2=90{ }^{(m+n)} P_2=90 and (m−n)P2=30^{(m-n)} P_2=30, then (m,n)(m, n) is
View answer and explanation
Correct option: D
(8,2)(8,2)
Option D ((8,2)) is the correct answer because it satisfies both permutation equations, (m+n)P2=90{ }^{(m+n)} P_2=90 and (m−n)P2=30{ }^{(m-n)} P_2=30.
544 Easy
544 of 742
Application +4 | -1
If 0<r<s≤n0 < r < s \leq n and nPr=nPs{ }^n P_r={ }^n P_s, then value of r+sr+s is
View answer and explanation
Correct option: B
2n−12 n-1
Option B (2n−12n-1) is correct because the equality of permutations nPr=nPs{}^nP_r = {}^nP_s with r<sr < s implies that rr and ss must be n−1n-1 and nn respectively.
545 Easy
545 of 742
Understanding +4 | -1
(8C1−8C2+8C3−8C4+8C5−8C6+8C7−8C8)\left({ }^8 {C}_1-{ }^8 {C}_2+{ }^8 {C}_3-{ }^8 {C}_4+{ }^8 {C}_5-{ }^8 {C}_6+{ }^8 {C}_7-{ }^8 {C}_8\right) equals:
View answer and explanation
Correct option: A
1
Option A (1) is correct because the given expression simplifies to 1 using binomial coefficient properties.
546 Easy
546 of 742
Analyzing +4 | -1
If nC3+nC4>n+1C3{ }^n C_3+{ }^n C_4 > { }^{n+1} C_3, then
View answer and explanation
Correct option: A
n>6n > 6
Option A (n > 6) is correct because simplifying the inequality nC3+nC4>n+1C3{ }^n C_3+{ }^n C_4 > { }^{n+1} C_3 leads to the condition n > 6.
547 Medium
547 of 742
Application +4 | -1
The number of proper divisors of 2520 is
View answer and explanation
Correct option: A
46
Option A (46) is correct because it represents the number of proper divisors of 2520.
548 Easy
548 of 742
Understanding +4 | -1
The number of ways of putting 5 identical balls in 10 identical boxes, if not more than one can go in a box is
View answer and explanation
Correct option: D
1
Option D (1) is correct because there is only one way to put 5 identical balls in 10 identical boxes with at most one ball per box.
549 Easy
549 of 742
Application +4 | -1
There are 10 true-false questions in an examination. Then, these questions can be answered in
View answer and explanation
Correct option: C
1024 ways
Option C (1024 ways) is correct because each question has 2 choices (True or False), and there are 10 questions, so the total number of ways is 210.
550 Easy
550 of 742
Understanding +4 | -1
The products of any rr consecutive natural numbers is always divisible by
View answer and explanation
Correct option: A
r!r!
Option A (r!r!) is correct because the product of any r consecutive natural numbers is always divisible by r!.
551 Easy
551 of 742
Analyzing +4 | -1
The value of (2.1P0−3.2P1+43P2......upto  51th  term)+(1!−2!+3!...upto  51th  term)\left( {{{2.}^1}{P_0} - {{3.}^2}{P_1} + {4^3}{P_2}......\mathrm{upto}{\mkern 1mu} {\mkern 1mu} \mathrm{51th}{\mkern 1mu} {\mkern 1mu} \mathrm{term}} \right)\mathrm{ + }\left( {\mathrm{1}! - \mathrm{2}!\mathrm{ + 3}!...\mathrm{upto}{\mkern 1mu} {\mkern 1mu} \mathrm{51th}{\mkern 1mu} {\mkern 1mu} \mathrm{term}} \right) is equal to
View answer and explanation
Correct option: C
1+(52)!1 + (52)!
Option C (1+(52)!1 + (52)!) is correct because by simplifying the expression using properties of permutations and factorials, the result is 1+(52)!1 + (52)!.
552 Medium
552 of 742
Application +4 | -1
The number of integral points that lie exactly in the interior of the triangle with vertices (0,0),(0,21),(21,0)(0,0),(0,21),(21,0), is
View answer and explanation
Correct option: B
190
Option B (190) is correct because it sums the number of integral points on each line parallel to the y-axis within the triangle's interior.
553 Medium
553 of 742
Analyzing +4 | -1
If number of ways of arranging letters aaaabbbbccdd in a line so that there should be at least one b in between two a&rsquo;s is k,k, then the value of ∣15000−k∣\left| {15000 - k} \right| is
View answer and explanation
Correct option: A
150
Option A (150) is correct because the number of arrangements is calculated by considering the possible arrangements with at least one 'b' between two 'a's and then subtracting from the total arrangements.
554 Easy
554 of 742
Application +4 | -1
Four boys picked up 30 mangoes. The number of ways in which they can divide them if all mangoes be identical, is
View answer and explanation
Correct option: A
5456
Option A (5456) is correct because it represents the number of ways to distribute 30 identical mangoes among 4 boys, allowing each boy to receive any number of mangoes.
555 Easy
555 of 742
Application +4 | -1
Assuming the balls to be identical except for difference in colours, the number of ways in which one or more balls can be selected from 10 white, 9 green and 7 black balls, is
View answer and explanation
Correct option: B
879
Option B (879) is correct because it calculates the total number of ways to select one or more balls by considering all possible combinations of white, green, and black balls and then subtracting the case where no balls are selected.
556 Medium
556 of 742
Application +4 | -1
If nn objects are arranged in a row, then the number of ways of selecting three objects, so that no two of them are next to each other, is
View answer and explanation
Correct option: B
n−2C3{ }^{n-2} C_3
Option B (n−2C3{ }^{n-2} C_3) is correct because it represents the number of ways to select three non-adjacent objects from n objects arranged in a row.
557 Easy
557 of 742
Application +4 | -1
If n+2C3=n+3P2−20{ }^{{n}+2} C_3={ }^{{n}+3} P_2-20, then nn is equal to:
View answer and explanation
Correct option: D
3
Option D (3) is correct because substituting n=3 into the given equation satisfies the equality after simplifying the combinations and permutations.
558 Easy
558 of 742
Application +4 | -1
The number of ways in which 3 boys and 3 girls (all are of different heights) can be arranged in a line, so that boys as well as girls among themselves are in decreasing order of height from left to right, is
View answer and explanation
Correct option: C
20
Option D (766) is correct because it is the total count of numbers less than 2⋅1082 \cdot 10^8 formed using only 1 and 2.
559 Easy
559 of 742
Analyzing +4 | -1
Number of positive integer nn less than 17, for which n!+(n+1)!+(n+2)!n !+(n+1) !+(n+2)! is an integral multiple of 49, is
View answer and explanation
Correct option: C
5
Option C (5) is the correct answer because there are five values of n less than 17 for which the given expression is divisible by 49.
560 Medium
560 of 742
Application +4 | -1
If 2  n+1Pn−1:  2  n−1Pn=3  :5,2{\;^{n + 1}}{P_{n - 1}}:{\;^{2\;n - 1}}{P_n} = 3\;:5, then nn is equal to
View answer and explanation
Correct option: A
4
Option A (4) is correct because solving the given ratio of permutations leads to n = 4.
561 Easy
561 of 742
Application +4 | -1
If l=LCM⁡l=\operatorname{LCM} of 8 !, 10 ! and 12 ! and h=HCF⁡h=\operatorname{HCF} of 8 !, 10 ! and 12 !, then lh\frac{l}{h} is equal to
View answer and explanation
Correct option: C
11880
Option C (11880) is correct because it calculates the ratio of the LCM and HCF of the given factorials.
562 Medium
562 of 742
Analyzing +4 | -1
Let n=1!+4!+7!+⋯+400n=1 !+4 !+7 !+\cdots+400 !. Then ten's digit of nn is
View answer and explanation
Correct option: B
6
Option B (6) is correct because after calculating the sum of factorials, the tens digit is determined to be 6.
563 Easy
563 of 742
Application +4 | -1
The total number of factors (excluding 1) of 2160 is
View answer and explanation
Correct option: B
39
Option B (39) is correct because it calculates the total number of factors (including 1 and 2160) and then subtracts 1 to exclude the factor 1.
564 Medium
564 of 742
Application +4 | -1
Number of 6 digit numbers which can be formed if the sum of their digits has to be 51 , is
View answer and explanation
Correct option: A
56
Option A (56) is correct because it represents the total number of 6-digit numbers that can be formed where the sum of their digits is 51. The possible combinations are derived by considering the minimum digit value of 6.
565 Medium
565 of 742
Application +4 | -1
The sum of all that can be formed with the digits 2,3,4,5 taken all at a time is
View answer and explanation
Correct option: A
93324
Option A (93324) is correct because the sum of all numbers formed is calculated using the formula (sum of digits) * (n-1)! * (1111... n times).
566 Medium
566 of 742
Analyzing +4 | -1
The number of distinct rational numbers xx such that 0<x<10 < x < 1 and x=pqx=\frac{p}{q}, where p,q∈{1,2,3,4,5,6}p, q \in\{1,2,3,4,5,6\} is
View answer and explanation
Correct option: D
11
Option D (11) is correct because it represents the number of distinct rational numbers between 0 and 1 that can be formed using the given set of numbers, after removing duplicates.
567 Easy
567 of 742
Application +4 | -1
If aa denotes the number of permutations of x+2x + 2 things taken all at a time, bb the number of permutations of xx things taken 11 at a time and cc the number of permutations of x−11x - 11 things taken all at a time such that a=182  bca = 182\;bc, then the value of xx is
View answer and explanation
Correct option: B
12
Option A (12) is correct because it is the value of x that satisfies the given permutation equation after simplification and solving the quadratic equation.
568 Easy
568 of 742
Application +4 | -1
Total number of positive integral solutions of x1⋅x2⋅x3=60x_1 \cdot x_2 \cdot x_3=60 is equal to
View answer and explanation
Correct option: B
54
Option B (54) is correct because it accurately calculates the number of positive integral solutions by considering the distribution of prime factors of 60 among the three variables.
569 Medium
569 of 742
Application +4 | -1
A class has nn students. We have to form a team of the students including atleast two students and also excluding atleast two students. The number of ways of forming the team is
View answer and explanation
Correct option: B
2n−2n−22^n-2 n-2
Option C (2n−2n−42^n-2 n-4) is correct because it represents the total number of subsets minus the subsets with fewer than two students and the subsets with fewer than two students excluded.
570 Medium
570 of 742
Application +4 | -1
The total number of flags with three horizontal strips, in order that can be formed using 2 identical red, 2 identical green and 2 identical white strips, is equal to
View answer and explanation
Correct option: A
4!
Option A (4!) is correct because the total number of flags is calculated by considering all possible arrangements of the colored strips.
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