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JEE • MATHEMATICS • PERMUTATION AND COMBINATION

Permutation and combination practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 571-600 of 742 questions

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571 Easy
571 of 742
Analyzing +4 | -1
The number of bijective functions f:{1,3,5,7,…f:\{1,3,5,7, \ldots, 99}→{2,4,6,8,……,100}99\} \rightarrow\{2,4,6,8, \ldots \ldots, 100\} such that f(3)≥f(9)≥f(15)≥f(21)≥…≥f(99)f(3) \geq f(9) \geq f(15) \geq f(21) \geq \ldots \geq f(99), is _____.
View answer and explanation
Correct option: B
50P33{ }^{50} P_{33}
Option B (50P33{ }^{50} P_{33}) is correct because we choose 17 elements out of 50 for the decreasing sequence and arrange the remaining 33 elements.
572 Medium
572 of 742
Application +4 | -1
Letter of the word 'WATER' is arranged in all possible ways and written as dictionary then rank of the word 'WATER' is
View answer and explanation
Correct option: C
101
Option C (101) is correct because it calculates the number of words preceding 'WATER' in the dictionary by considering the alphabetical order of the letters.
573 Medium
573 of 742
Application +4 | -1
A boat is to be managed by eight men of whom 2 can only row on bow side and 3 can only row on stroke side, the number of ways in which the crew can be arranged, is
View answer and explanation
Correct option: B
5760
Option B (5760) is correct because it calculates the number of ways to arrange the crew, considering the restrictions on who can row on the bow and stroke sides.
574 Easy
574 of 742
Application +4 | -1
An examination paper contains 8 question of which 4 has 3 possible answers, 3 have 2 possible answers each and the remaining one question has 5 possible answers. The total number of possible answers to all the questions is
View answer and explanation
Correct option: D
3240
Option D (3240) is correct because it calculates the total number of possible answer combinations by multiplying the number of choices for each question.
575 Easy
575 of 742
Application +4 | -1
There are three copies, each of 4 different books. The number of ways in which they can be arranged on a shelf, is
View answer and explanation
Correct option: A
12!(3!)4\frac{12 !}{(3 !)^4}
Option A (12!(3!)4\frac{{12 !}}{{(3 !)^4}}) is correct because it accounts for the repetitions of the 4 different books.
576 Easy
576 of 742
Application +4 | -1
12 boys and 2 girls are to be seated in a row such that there are atleast 3 boys between the 2 girls. The number of ways this can be done is λ×12!\lambda \times 12 ! ! the value of λ\lambda is
View answer and explanation
Correct option: B
110
Option B (110) is correct because it calculates the number of arrangements where at least 3 boys are between the two girls.
577 Easy
577 of 742
Application +4 | -1
The number of squares that we can find on a chess board is
View answer and explanation
Correct option: D
204
Option D (204) is correct because the total number of squares is the sum of squares of integers from 1 to 8.
578 Easy
578 of 742
Application +4 | -1
The total number of proper factors of 7875 is
View answer and explanation
Correct option: C
22
Option C (22) is correct because it calculates the total number of factors and then subtracts 1 to exclude the number itself, giving the number of proper factors.
579 Easy
579 of 742
Analyzing +4 | -1
The number of positive terms in the sequence xn=1954nPn−n+3P3n+1Pn+1,n∈Nx_n=\frac{195}{4{ }^n P_n}-\frac{{ }^{n+3} P_3}{{ }^{n+1} P_{n+1}}, n \in N is
View answer and explanation
Correct option: C
4
Option A (3) is correct because by substituting the limit of f(x) and simplifying, the logarithm evaluates to 3.
580 Medium
580 of 742
Application +4 | -1
Five digit number divisible by 3 is formed using 0,1,2,3,40,1,2,3,4, 6 and 7 without repetition. Total number of such numbers are
View answer and explanation
Correct option: D
216
The correct answer is D (216) because it calculates the total number of 5-digit numbers divisible by 3 formed using the given digits without repetition.
581 Easy
581 of 742
Application +4 | -1
The number of ways in which 5 boys and 5 girls can sit in a row so that all girls sit together is
View answer and explanation
Correct option: C
86400
Option C (86400) is correct because it calculates the arrangements of boys and girls with all girls sitting together.
582 Easy
582 of 742
Understanding +4 | -1
The no. of dissimilar terms in the expansion of (a+b+c)10(a+b+c)^{10} is
View answer and explanation
Correct option: A
66
Option A (66) is correct because the number of dissimilar terms in the expansion of (a+b+c)10(a+b+c)^{10} is calculated using the formula for combinations with repetition.
583 Easy
583 of 742
Application +4 | -1
The total number of selections of at least one red ball from a bag containing 4 red balls and 3 green balls, balls of the same colour being identical, is
View answer and explanation
Correct option: C
16
Option C (16) is correct because it represents the total number of selections with at least one red ball.
584 Easy
584 of 742
Application +4 | -1
The number of even proper divisors of 1008 is
View answer and explanation
Correct option: A
23
Option A (23) is correct because it is the number of even proper divisors of 1008, calculated by considering the prime factorization and excluding the number itself.
585 Easy
585 of 742
Application +4 | -1
From 3 mangoes, 4 apples and 2 oranges. The number of selections of fruits that can be made, taking at least one of each kind is
View answer and explanation
Correct option: A
24
Option A (24) is correct because it represents the number of selections with at least one of each kind of fruit.
586 Medium
586 of 742
Application +4 | -1
The sum of all four digit numbers that can be med using the digits 1,2,3,41,2,3,4, when repetition of digits is not allowed, is
View answer and explanation
Correct option: D
66660
Option D (66660) is correct because the sum is calculated by summing the digits, multiplying by (n-1)!, and then multiplying by (10^n - 1)/9.
587 Medium
587 of 742
Understanding +4 | -1
The value of (2n)!n!\frac{(2 n) !}{n !} is
View answer and explanation
Correct option: A
{1⋅3⋅5…(2n−1)}2n\{1 \cdot 3 \cdot 5 \ldots(2 n-1)\} 2^n
Option A ({1 · 3 · 5 …(2 n-1)} 2^n) is correct because it correctly represents the simplification of the given factorial expression.
588 Easy
588 of 742
Application +4 | -1
If   56Pr+6:  54Pr+3=30800  :1,{\;^{56}}{P_{r + 6}}:{\;^{54}}{P_{r + 3}} = 30800\;:1, then the value of rr is
View answer and explanation
Correct option: B
41
Option B (41) is correct because substituting r = 41 into the given permutation equation satisfies the condition.
589 Easy
589 of 742
Application +4 | -1
The number of 3 letters words, with or without meaning which can be formed out of the letters of the word 'NUMBER'.

Statement I: When repetition of letters is not allowed is 120.

Statement II: When repetition of letters is allowed is 216.

Choose the correct option.
View answer and explanation
Correct option: C
Both I and II are correct
Option C (Both I and II are correct) is correct because the number of 3-letter words without repetition is 120 and with repetition is 216.
590 Medium
590 of 742
Application +4 | -1
An nn-digit number is a positive number with exactly nn digits. Nine hundred distinct nn-digit numbers are to be formed using only the three digits 2, 5 and 7. The smallest value of nn for which this is possible, is
View answer and explanation
Correct option: B
7
Option B (7) is correct because it is the smallest number of digits needed to form at least 900 distinct numbers using only the digits 2, 5, and 7.
591 Medium
591 of 742
Application +4 | -1
Two teams are to play a series of 5 matches between them. A match ends in a win or loss or draw for a team. A number of people forecast the result of each match and no two people make the same forecast for the series of matches. The smallest group of people in which one person forecasts correctly for all the matches will contain nn people, where nn is
View answer and explanation
Correct option: B
243
Option B (243) is correct because the total number of possible forecasts is calculated as 3 raised to the power of the number of matches (5), resulting in 243.
592 Easy
592 of 742
Analyzing +4 | -1
We are required to form different words with the help of the letters of the word INTEGER. Let m1m_1 be the number of words in which I and N are never together and m2m_2 be the number of words which begin with I and end with R, then m1m2\frac{m_1}{m_2} is given by
View answer and explanation
Correct option: B
30
Option B (30) is correct because the ratio of the number of words with I and N not together to the number of words starting with I and ending with R is 1800/60 = 30.
593 Easy
593 of 742
Application +4 | -1
The number of five digit numbers that can be formed by using digits 1, 2, 3 only, such that three digits of the formed number are identical, is
View answer and explanation
Correct option: C
120
The correct answer is C (120) because it accounts for the cases where exactly three digits are identical and the remaining two are different, and where three digits are identical and the remaining two are also identical.
594 Medium
594 of 742
Application +4 | -1
The number of arrangements that can be formed out of GANESHPURI so that "The vowels are always together is
View answer and explanation
Correct option: C
7!4!7 ! 4 !
Option C (7!4!7 ! 4 !) is correct because the vowels are treated as a single unit, and then arranged with the consonants, followed by arranging the vowels within their unit.
595 Easy
595 of 742
Application +4 | -1
The number of words that can be formed from the letters a,b,c,d,e,fa, b, c, d, e, f, taken 3 at a time, each word containing at least one vowel is
View answer and explanation
Correct option: A
96
Option A (96) is correct because it represents the number of 3-letter words formed with at least one vowel from the given letters.
596 Medium
596 of 742
Application +4 | -1
The number of integers, greater than 7000 that can
be formed, using the digits 3, 5, 6, 7, 8 without
repetition, is
View answer and explanation
Correct option: B
168
Option B (168) is correct because it involves counting permutations of numbers greater than 7000 using the given digits.
597 Easy
597 of 742
Application +4 | -1
The range of the function f(x)=7−xPx−3f(x) = {}^{7-x} P_{x-3} is
View answer and explanation
Correct option: A
{1,2,3}\left\{ {1,2,3} \right\}
Option A ({1,2,3}\{ {1,2,3} \}) is correct because the range is found by determining the valid domain of x and then evaluating the function at those points.
598 Medium
598 of 742
Application +4 | -1
If n=210032n=2^{100} 3^2 and {d1,d2,…dk}\left\{d_1, d_2, \ldots d_k\right\} is the set of all divisors of nn, then ∑j=1k1dj\sum\limits_{{j=1}}^k \frac{1}{d_j} equals
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the sum of reciprocals of divisors is calculated using the formula and the result doesn't match any of the given options.
599 Easy
599 of 742
Analyzing +4 | -1
The number of divisors of n=27⋅35⋅53n=2^7 \cdot 3^5 \cdot 5^3, which are of the form 4t+1(t∈N)4 t+1(t \in N), is
View answer and explanation
Correct option: C
11
Option C (11) is correct because it accurately counts the number of divisors of the given form 4t+1.
600 Medium
600 of 742
Application +4 | -1
The total number of four-digit numbers having all different digits is equal to
View answer and explanation
Correct option: A
4536
Option A (4536) is correct because it calculates the number of four-digit numbers with all different digits.
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