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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy
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Application +4 | -1
If 33!33 ! is divisible by 2n2^n, then the maximum value of nn is equal to
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Correct option: B
31
Option B (31) is correct because it represents the highest power of 2 that divides 33!, calculated by summing the quotients of successive divisions by 2.

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