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JEE • MATHEMATICS • MATRICES

Matrices practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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811 Easy
811 of 922
Analyzing +4 | -1
If ω\omega is imaginary root of unity, then the value of ∣abω2aωbωcbω2cω2aωc∣\left| {\begin{array}{cccccccccccccccccccc} a&{b{\omega ^2}}&{a\omega }\\ {b\omega }&c&{b{\omega ^2}}\\ {c{\omega ^2}}&{a\omega }&c \end{array}} \right| is
View answer and explanation
Correct option: C
0
Option C (0) is correct because the determinant simplifies to zero after applying column operations, indicating linear dependence between columns.
812 Easy
812 of 922
Analyzing +4 | -1
For the system of equations

7x+6y−2z=03x+4y+2z=0x−2y−6z=0\begin{aligned} &7 x+6 y-2 z=0 \\ &3 x+4 y+2 z=0 \\ &x-2 y-6 z=0 \end{aligned}

which of the following is correct?
View answer and explanation
Correct option: C
Has infinitely many non-trivial solutions for x=2zx=2 z
The correct answer is C (Has infinitely many non-trivial solutions for x=2zx=2z) because the determinant of the coefficient matrix is zero, indicating non-trivial solutions, and the relationship x=2zx=2z can be derived from the equations.
813 Easy
813 of 922
Analyzing +4 | -1
Let AA be a n×nn \times n matrix such that An=αA,A^n=\alpha A, where α\alpha is a real number different from 1 and −1.-1. The matrix A+InA+I_n is
View answer and explanation
Correct option: B
Invertible
Option B (Invertible) is correct because the given condition and subsequent algebraic manipulation show that A+I has an inverse.
814 Easy
814 of 922
Analyzing +4 | -1
If ∣111abca3b3c3∣=(a−b)(b−c)(c−a)(a+b+c)\left|\begin{array}{ccc}1 & 1 & 1 \\ a & b & c \\ a^3 & b^3 & c^3\end{array}\right|=(a-b)(b-c)(c-a)(a+b+c), where a,ba, b and cc are all different, then the determinant
∣111(x−a)2(x−b)2(x−c)2(x−b)(x−c)(x−c)(x−a)(x−a)(x−b)∣\left|\begin{array}{ccc}1 & 1 & 1 \\ (x-a)^2 & (x-b)^2 & (x-c)^2 \\ (x-b)(x-c) & (x-c)(x-a) & (x-a)(x-b)\end{array}\right| vanishes when
View answer and explanation
Correct option: B
x=13(a+b+c)x=\frac{1}{3}(a+b+c)
Option B (x=13(a+b+c)x=\frac{1}{3}(a+b+c)) is correct because the determinant vanishes when x=13(a+b+c)x=\frac{1}{3}(a+b+c).
815 Easy
815 of 922
Remembering +4 | -1
A=[aij]m×n\mathrm{A}=\left[a_{i j}\right]_{m \times n} is a square matrix, if
View answer and explanation
Correct option: C
m=nm=n
Option C (m=nm=n) is correct because a square matrix is defined as a matrix with an equal number of rows and columns.
816 Easy
816 of 922
Application +4 | -1
Let P=[1004101641]P=\left[\begin{array}{ccc}1 & 0 & 0 \\ 4 & 1 & 0 \\ 16 & 4 & 1\end{array}\right] and II be the identity matrix of order 3. If Q=[qij]Q=\left[q_{i j}\right] is a matrix such that P50−Q=IP^{50}-Q=I, then q31+q32q21\frac{q_{31}+q_{32}}{q_{21}} equals
View answer and explanation
Correct option: B
103
Option B (103) is correct because after calculating P50 and subtracting I, the ratio (q31 + q32) / q21 equals 103.
817 Easy
817 of 922
Analyzing +4 | -1
The determinant ∣4+x2−6−2−69+x23−231+x2∣\left| {\begin{array}{cccccccccccccccccccc} {4 + {x^2}}&{ - 6}&{ - 2}\\ { - 6}&{9 + {x^2}}&3\\ { - 2}&3&{1 + {x^2}} \end{array}} \right| is not divisible by
View answer and explanation
Correct option: D
x5{x^5}
Option D (x5{x^5}) is correct because the determinant simplifies to x4(x2+14){x^4}({x^2} + 14), which is not divisible by x5{x^5}.
818 Easy
818 of 922
Analyzing +4 | -1
If the system of homogeneous equations 2x−y+z=0,x−2y+z=0  ,  λx−y+2z=0  2x - y + z = 0,x - 2y + z = 0\;,\;\lambda x - y + 2z = 0\; has infinitely many solutions, then
View answer and explanation
Correct option: A
λ=5\lambda = 5
Option A (λ=5\lambda = 5) is correct because when λ=5\lambda = 5, the determinant of the coefficient matrix is zero, leading to infinitely many solutions for the homogeneous system.
819 Easy
819 of 922
Application +4 | -1
Let A be a 3×33 \times 3 matrix such that det⁡(A)=−2\operatorname{det}(A)=-2. Then det⁡(−2A−1)+2det⁡(A)\operatorname{det}\left(-2 A^{-1}\right)+2 \operatorname{det}(A) is equal to
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the calculated value is 0, which is not among the given options.
820 Easy
820 of 922
Application +4 | -1
If A=[1    23    4]A = \left[ {\begin{array}{cccccccccccccccccccc} {1\;\;2}\\ {3\;\;4} \end{array}} \right], then A−1{A^{ - 1}} is equal to
View answer and explanation
Correct option: A
−12[4−2−31]- \frac{1}{2}\left[ {\begin{array}{cccccccccccccccccccc} 4&{ - 2}\\ { - 3}&1 \end{array}} \right]
Option A (- \frac{1}{2}\left[ {\begin{{array}}{{{*{20}{c}}}} 4&{ - 2}\\ { - 3}&1 \end{{array}}} \right]- \frac{1}{2}\left[ {\begin{{array}}{{{*{20}{c}}}} 4&{ - 2}\\ { - 3}&1 \end{{array}}} \right]) is correct because it is the correct inverse matrix calculated using the formula for a 2x2 matrix inverse.
821 Easy
821 of 922
Application +4 | -1
If A=[1−2202−33−24]\mathrm{A}=\left[\begin{array}{ccc}1 & -2 & 2 \\ 0 & 2 & -3 \\ 3 & -2 & 4\end{array}\right], then Aadj⁡(A)\mathrm{A} \operatorname{adj}(\mathrm{A}) is equal to
View answer and explanation
Correct option: C
[800080008]\left[\begin{array}{lll}8 & 0 & 0 \\ 0 & 8 & 0 \\ 0 & 0 & 8\end{array}\right]
Option C [800080008]\left[\begin{array}{lll}8 & 0 & 0 \\0 & 8 & 0 \\0 & 0 & 8\end{array}\right] is correct because A(Adj⁡A)=∣A∣IA(\operatorname{Adj} A) = |A|I, and in this case, ∣A∣=8|A| = 8.
822 Easy
822 of 922
Analyzing +4 | -1
The system of equations x+2y−3z=a,x+2 y-3 z=a,
2x+6y−11z=b,x−2y+7z=c2 x+6 y-11 z=b, x-2 y+7 z=c has
View answer and explanation
Correct option: C
Infinite solution for 5a=2b+c5 a=2 b+c
Option D (none of these) is correct. The determinant simplifies to 0, which is not equal to any of the given options.
823 Easy
823 of 922
Application +4 | -1
If AA and BB are square matrices of order 3×33 \times 3 such that AA is an orthogonal matrix and BB is a skew-symmetric matrix, then which of the following statements is true?
View answer and explanation
Correct option: B
∣AB∣=0|A B|=0
Option B (∣AB∣=0|A B|=0) is correct because the determinant of a skew-symmetric matrix of odd order is always 0, and ∣AB∣=∣A∣∣B∣|A B|=|A||B|. Since ∣B∣=0|B|=0, ∣AB∣=0|A B|=0.
824 Easy
824 of 922
Analyzing +4 | -1
Let a,b,ca, b, c be such that b(a+c)≠0b(a+c) \neq 0. If ∣aa+1a−1−bb+1b−1cc−1c+1∣+∣a+1b+1c−1a−1b−1c+1(−1)n+2a(−1)n+1b(−1)nc∣=0,\left| {\begin{array}{cccccccccccccccccccc} a&{a + 1}&{a - 1} \\ { - b}&{b + 1}&{b - 1} \\ c&{c - 1}&{c + 1} \end{array}} \right| + \left| {\begin{array}{cccccccccccccccccccc} {a + 1}&{b + 1}&{c - 1} \\ {a - 1}&{b - 1}&{c + 1} \\ {{{( - 1)}^{n + 2}}a}&{{{( - 1)}^{n + 1}}b}&{{{( - 1)}^n}c} \end{array}} \right| = 0, then the value of nn is
View answer and explanation
Correct option: D
any odd integer
Option D (any odd integer) is correct because the equation simplifies to 2∣aa+1a−1−bb+1b−1cc−1c+1∣=02\left| {\begin{array}{cccccccccccccccccccc} a&{a + 1}&{a - 1} \\ { - b}&{b + 1}&{b - 1} \\ c&{c - 1}&{c + 1} \end{array}} \right| = 0 when n is odd.
825 Easy
825 of 922
Application +4 | -1
If A=[0110],A = \left[ {\begin{array}{cccccccccccccccccccc} 0&1\\ 1&0 \end{array}} \right], then A4={A^4} =
View answer and explanation
Correct option: A
[1001]\left[ {\begin{array}{cccccccccccccccccccc} 1&0\\ 0&1 \end{array}} \right]
Option A ([1001]\begin{bmatrix} 1&0\\0&1 \end{bmatrix}) is correct because A2{A^2} equals the identity matrix, and therefore A4{A^4} also equals the identity matrix.
826 Easy
826 of 922
Understanding +4 | -1
Which is true about matrix multiplication?
View answer and explanation
Correct option: B
It is associative
Option B (It is associative) is correct because matrix multiplication is associative, meaning (AB)C = A(BC).
827 Easy
827 of 922
Understanding +4 | -1
Choose the correct answer
View answer and explanation
Correct option: A
Every identify matrix is a scalar matrix
Option A (Every identity matrix is a scalar matrix) is correct because an identity matrix is a special case of a scalar matrix where the scalar is 1.
828 Easy
828 of 922
Application +4 | -1
If [ ] denotes the greatest integer less than or equal to the real number under consideration and −1≤x<0;  0≤y<1;  1≤z<2,- 1 \le x < 0;\,\,0 \le y < 1;\,\,1 \le z < 2, then the value of the determinant ∣[x]+1[y][z][x][y]+1[z][x][y][z]+1∣\left| {\begin{array}{cccccccccccccccccccc} {\left[ x \right] + 1}&{\left[ y \right]}&{\left[ z \right]}\\ {\left[ x \right]}&{\left[ y \right] + 1}&{\left[ z \right]}\\ {\left[ x \right]}&{\left[ y \right]}&{\left[ z \right] + 1} \end{array}} \right| is
View answer and explanation
Correct option: C
[z]\left[ z \right]
Option C ([z]) is correct because substituting the greatest integer values for x, y, and z into the determinant results in a value of 1, which equals [z].
829 Easy
829 of 922
Analyzing +4 | -1
Let matrix A=[xy−z123112]A=\left[\begin{array}{rrr}{x} & {y} & -{z} \\ 1 & 2 & 3 \\ 1 & 1 & 2\end{array}\right], where x,y,z∈Nx, y, z \in N. If ∣adj⁡∣adj⁡∣adj⁡∣adj⁡A∣∥∣=48⋅516|\operatorname{adj}| \operatorname{adj}|\operatorname{adj}| \operatorname{adj} A|\||=4^8 \cdot 5^{16}, then the number of such matrices A{A} is equal to (where, ∣M∣|M| represents determinant of a matrix MM)
View answer and explanation
Correct option: D
36
Option D, 36, is correct because the number of such matrices A is equal to the number of positive integer solutions to x + y + z = 10, which is given by 9C2=36^{9}C_2 = 36.
830 Easy
830 of 922
Analyzing +4 | -1
If S={x∈[0,2π]:∣0cos⁡x−sin⁡xsin⁡x0cos⁡xcos⁡xsin⁡x0∣=0}S=\left\{x \in[0,2 \pi]:\left|\begin{array}{ccc}0 & \cos x & -\sin x \\ \sin x & 0 & \cos x \\ \cos x & \sin x & 0\end{array}\right|=0\right\}, then ∑x∈Stan⁡(π3+x)\sum_{x \in S} \tan \left(\frac{\pi}{3}+x\right) is equal to
View answer and explanation
Correct option: C
−2−3-2-\sqrt{3}
Option C (-2-3\sqrt{3}) is correct because solving the determinant equation leads to tan(x) = 1, and substituting into the expression yields -2-3\sqrt{3}.
831 Easy
831 of 922
Application +4 | -1
The rank of the matrix [−1252−4a−41−2a+1]\left[\begin{array}{rrr}-1 & 2 & 5 \\ 2 & -4 & a-4 \\ 1 & -2 & a+1\end{array}\right] is (where a=−6)a=-6)
View answer and explanation
Correct option: A
1
Option A (1) is correct because after row operations, the matrix reduces to a single non-zero row, indicating a rank of 1.
832 Easy
832 of 922
Application +4 | -1
The value of the determinant Δ=∣(a+1)(a+2)a+21(a+2)(a+3)a+31(a+3)(a+4)a+41∣\Delta=\left|\begin{array}{lll}(a+1)(a+2) & a+2 & 1 \\ (a+2)(a+3) & a+3 & 1 \\ (a+3)(a+4) & a+4 & 1\end{array}\right| is equal to
View answer and explanation
Correct option: A
−2-2
Option A (-2) is correct because after applying row operations R2 -> R2 - R1 and R3 -> R3 - R1 and expanding along C3, the determinant simplifies to -2.
833 Easy
833 of 922
Application +4 | -1
If A=[2−34],B=[321],X=[023]\text{A}=\left[\begin{array}{ll}2 & -3 & 4\end{array}\right], \text{B}=\left[\begin{array}{l}3 \\ 2 \\ 1\end{array}\right], \text{X}=\left[\begin{array}{lll}0 & 2 & 3\end{array}\right] and Y=[224]\mathrm{Y}=\left[\begin{array}{l}2 \\ 2 \\ 4\end{array}\right], then AB+XY=\mathrm{AB}+\mathrm{XY}=
View answer and explanation
Correct option: A
[20][20]
Option B is correct. The inverse of a diagonal matrix is a diagonal matrix with the reciprocals of the original diagonal elements, and their sum is 11/6.
834 Easy
834 of 922
Analyzing +4 | -1
If ∣xnxn+2xn+3ynyn+2yn+3znzn+2zn+3∣=(y−z)(z−x)(x−y)\left| {\begin{array}{cccccccccccccccccccc} {{x^n}}&{{x^{n + 2}}}&{{x^{n + 3}}}\\ {{y^n}}&{{y^{n + 2}}}&{{y^{n + 3}}}\\ {{z^n}}&{{z^{n + 2}}}&{{z^{n + 3}}} \end{array}} \right| = \left( {y - z} \right)\left( {z - x} \right)\left( {x - y} \right) (1x+1y+1z),\left( {\frac{1}{x} + \frac{1}{y} + \frac{1}{z}} \right), then nn is equal to
View answer and explanation
Correct option: C
−1- 1
Option C (-1) is correct because by comparing the degree of the determinant and the RHS, we find that n = -1.
835 Easy
835 of 922
Application +4 | -1
The matrix A=[a224]A = \left[ {\begin{array}{cccccccccccccccccccc} a&2\\ 2&4 \end{array}} \right] is singular, if
View answer and explanation
Correct option: B
a=1a = 1
Option B (a=1a = 1) is correct because a matrix is singular if its determinant is zero, and setting the determinant of the given matrix to zero yields a=1a = 1.
836 Easy
836 of 922
Analyzing +4 | -1
Let AA and BB be any two 3×33 \times 3 symmetric and skew symmetric matrices respectively. Then Which of the following is NOT true?
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Correct option: C
B5−A5B^5-A^5 is a skew-symmetric matrix
Option C (B5−A5B^5-A^5 is a skew-symmetric matrix) is NOT true because the transpose of B5−A5B^5 - A^5 is not equal to its negative, hence it is not skew-symmetric.
837 Easy
837 of 922
Understanding +4 | -1
If AA is an invertible matrix, then det  (A−1)\mathrm{det\;}\left( {{A^{ - 1}}} \right) is equal to
View answer and explanation
Correct option: B
1det  (A)\frac{1}{{\mathrm{det\;}\left( A \right)}}
Option B (1det;(A)\frac{{1}}{{\mathrm{det\\;}\left( A \right)}}) is correct because the determinant of the inverse of a matrix is the reciprocal of the determinant of the original matrix.
838 Easy
838 of 922
Understanding +4 | -1
If AA and BB are two 3×33 \times 3 matrices and ∣A∣≠0|A| \neq 0, then which of the following are not true?
View answer and explanation
Correct option: D
∣A+A∣=2∣A∣|A+A|=2|A|
Option D (∣A+A∣=2∣A∣|A+A|=2|A|) is correct because ∣A+A∣=∣2A∣=23∣A∣=8∣A∣|A+A| = |2A| = 2^3|A| = 8|A| for a 3x3 matrix A, not 2∣A∣2|A|.
839 Easy
839 of 922
Application +4 | -1
If ω\omega is a complex cube root of unity, and A=[ω00ω],A = \left[ {\begin{array}{cccccccccccccccccccc} \omega &0 \\ 0&\omega \end{array}} \right], then A100{A^{100}} is equal to
View answer and explanation
Correct option: A
AA
Option A (AA) is correct because A=ωI2A = \omega I_2, and since ω3=1\omega^3 = 1, A100=(ω100)I2=ωI2=AA^{100} = (\omega^{100})I_2 = \omega I_2 = A.
840 Easy
840 of 922
Application +4 | -1
If ω\omega is a complex cube root of unity, then a root of the equation
∣x+1ωω2ωx+ω21ω21x+ω∣=0,\left|\begin{array}{ccc}x+1 & \omega & \omega^2 \\ \omega & x+\omega^2 & 1 \\ \omega^2 & 1 & x+\omega\end{array}\right|=0, is
View answer and explanation
Correct option: D
x=0x=0
Option D (x=0x=0) is correct because x=0x=0 satisfies the given determinant equation after simplification using properties of cube roots of unity.
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