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JEE • MATHEMATICS • MATRICES

Matrices practice · Easy

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661 Easy
661 of 922
Application +4 | -1
If square matrix AA is such that 3A3+2A2+3 A^3+2 A^2+ 5A+I=O5 A+I=O, then A−1A^{-1} is equal to
View answer and explanation
Correct option: B
−(3A2+2A+5I)-\left(3 A^2+2 A+5 I\right)
Option B (−(3A2+2A+5I)-\left(3 A^2+2 A+5 I\right)) is correct because it is derived by multiplying the given equation by A−1A^{-1} and rearranging to solve for A−1A^{-1}.
662 Easy
662 of 922
Analyzing +4 | -1
If the system of equations x+ky−z=0,3x−ky−z=0x + ky - z = 0,3x - ky - z = 0 and x−3y+z=0x - 3y + z = 0 has non-zero solution then kk is equal to
View answer and explanation
Correct option: C
1
The correct answer is C (1). For the system to have a non-zero solution, the determinant of the coefficient matrix must be zero, which leads to k = 1.
663 Easy
663 of 922
Analyzing +4 | -1
The number of values of kk for which the system of equations: (k+1)x+8y=4k,kx+(k+3)y=3k−1(k + 1)x + 8y = 4k,kx + (k + 3)y = 3k - 1 has solution is
View answer and explanation
Correct option: B
1
Option B is correct because there is only one value of k (k=3) for which the system of equations has a solution.
664 Easy
664 of 922
Analyzing +4 | -1
Consider the system of equations in x,y,zx, y, z as
xsin⁡3θ−y+z=0x \sin 3 \theta-y+z=0

xcos⁡2θ+4y+3z=0x \cos 2 \theta+4 y+3 z=0

2x+7y+7z=02 x+7 y+7 z=0
If this system has a non-trivial solution, then for any integer nn, values of θ\theta are given
View answer and explanation
Correct option: C
(n+(−1)n6)π\left(n+\frac{(-1)^n}{6}\right) \pi
The correct answer is (n+(−1)n6)π\left(n+\frac{{(-1)^n}}{{6}}\right) \pi because solving the determinant equation leads to θ=nπ\theta = n\pi or θ=nπ+(−1)nπ6\theta = n\pi + (-1)^n \frac{{\pi}}{{6}}.
665 Easy
665 of 922
Application +4 | -1
If A=[1000110−24]A=\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & 1 & 1 \\ 0 & -2 & 4\end{array}\right] and I=[100010001]I=\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right] and A−1=16(A2+cA+dI)A^{-1}=\frac{1}{6}\left(A^2+c A+d I\right) then, the value of c+d=c+d=
View answer and explanation
Correct option: A
5
Option A (5) is correct because using the characteristic equation and Cayley-Hamilton theorem, we find c = -6 and d = 11, so c+d = 5.
666 Easy
666 of 922
Analyzing +4 | -1
There are two possible values of AA in the solution of the matrix equation [2A+1−5−4A]−1[A−5B2A−2C]=[14DEF],\left[\begin{array}{rr}2 A+1 & -5 \\ -4 & A\end{array}\right]^{-1}\left[\begin{array}{rr}A-5 & B \\ 2 A-2 & C\end{array}\right]=\left[\begin{array}{rr}14 & D \\ E & F\end{array}\right], where A,B,C,D,E,FA, B, C, D, E, F are real numbers. The absolute value of the difference of these two solutions, is
View answer and explanation
Correct option: D
193\frac{19}{3}
Option D (193\frac{{19}}{{3}}) is correct because solving the matrix equation leads to a quadratic in A, and the absolute difference of the roots is 193\frac{{19}}{{3}}.
667 Easy
667 of 922
Understanding +4 | -1
Consider the following statements

I. If AB{AB} and BA{BA} are both defined, then they must be equal i.e., AB=BAA B=B A.

II. If AB{AB} and BA{BA} are both defined, it is not necessary that AB=BA{AB}={BA}.

Choose the correct option.
View answer and explanation
Correct option: B
Only II is true
Option B (Only II is true) is correct because matrix multiplication is not always commutative, meaning AB is not necessarily equal to BA.
668 Easy
668 of 922
Application +4 | -1
If AA is a square matrix of order 3 such that A2=A^2= 2A2 A, then ∣A∣2|A|^2 is equal to
View answer and explanation
Correct option: B
8∣A∣8|A|
Option B (8∣A∣8|A|) is correct because from the given condition, we can deduce that ∣A∣2=8∣A∣|A|^2 = 8|A|.
669 Easy
669 of 922
Application +4 | -1
If A=[1              xx2      4y]A = \left[ {\begin{array}{cccccccccccccccccccc} {1\;\;\;\;\;\;\;x}\\ {{x^2}\;\;\;4y} \end{array}} \right] and   B=[−3          11            0],  adj  A+B=[1        00          1]\;B = \left[ {\begin{array}{cccccccccccccccccccc} { - 3\;\;\;\;\;1}\\ {1\;\;\;\;\;\;0} \end{array}} \right],\;\mathrm{adj}\;A + B = \left[ {\begin{array}{cccccccccccccccccccc} {1\;\;\;\;0}\\ {0\;\;\;\;\;1} \end{array}} \right], Then values of xx and yy are
View answer and explanation
Correct option: A
1,11,1
Option A (1,11,1) is correct because substituting x=1x = 1 and y=1y = 1 into the equation adjA+B=Iadj A + B = I satisfies the matrix equality.
670 Easy
670 of 922
Application +4 | -1
Let A=[12−51]and  A−1=xA+yIA = \left[ {\begin{array}{cccccccccccccccccccc} 1&2\\ { - 5}&1 \end{array}} \right]\mathrm{and}\;{A^{ - 1}} = xA + yI, then the value of xx and yy are
View answer and explanation
Correct option: A
x=−111,  y=211x = \frac{{ - 1}}{{11}},\;y = \frac{2}{{11}}
Option A (x=−111,  y=211x = \frac{{ - 1}}{{11}},\;y = \frac{2}{{11}}) is correct because these values satisfy the equation A−1=xA+yI{A^{ - 1}} = xA + yI.
671 Easy
671 of 922
Application +4 | -1
If A\mathrm{A} is a square matrix of order 3 such that ∣adj⁡A∣=64|\operatorname{adj} \mathrm{A}|=64, then ∣AT∣=|\mathrm{A^T}|=
View answer and explanation
Correct option: D
±8\pm 8
Option D (±8\pm 8) is correct because ∣adj⁡A∣=∣A∣n−1|\operatorname{adj} A| = |A|^{n-1} where n is the order of the matrix, and ∣AT∣=∣A∣|A^T| = |A|.
672 Easy
672 of 922
Understanding +4 | -1
Let for any matrix M,  M−1  M,\;{M^{ - 1}}\; exist which of the following is not true?
View answer and explanation
Correct option: B
(M2)−1=(  M−1)2{\left( {{M^2}} \right)^{ - 1}} = {\left( {\;{M^{ - 1}}} \right)^2}
The correct answer is B. The inverse of M squared is the inverse of M raised to the power of -2, not 2.
673 Easy
673 of 922
Application +4 | -1
If xayb=em,xcyd=en,Δ1=∣mbnd∣,x^a y^b=e^m, x^c y^d=e^n, \Delta_1=\left|\begin{array}{ll}m & b \\ n & d\end{array}\right|, Δ2=∣amcn∣\Delta_2=\left|\begin{array}{ll}a & m \\ c & n\end{array}\right| and Δ3=∣abcd∣,\Delta_3=\left|\begin{array}{ll}a & b \\ c & d\end{array}\right|, then the values of xx and yy are
View answer and explanation
Correct option: D
eΔ1/Δ3e^{\Delta_1 / \Delta_3} and eΔ2/Δ3e^{\Delta_2 / \Delta_3}
Option D (eΔ1/Δ3e^{\Delta_1 / \Delta_3} and eΔ2/Δ3e^{\Delta_2 / \Delta_3}) is correct because it follows from applying Cramer's rule to solve the system of equations after taking logarithms.
674 Easy
674 of 922
Application +4 | -1
If AA is a square matrix such that A3=OA^3=O, then I+A+A2I+A+A^2 (II is the corresponding unit matrix) is
View answer and explanation
Correct option: D
(I−A)−1(I-A)^{-1}
Option D is correct. Since A3 = O, we can show that (I-A)(I+A+A2) = I, which means I+A+A2 is the inverse of (I-A).
675 Easy
675 of 922
Analyzing +4 | -1
The system of equations kx + y+ z = 1, x+ ky + z = k and x +y +zk = k2{k^2} has no solution, If k is equal to
View answer and explanation
Correct option: D
-2
Option D (-2) is correct because when k = -2, the system of equations has no solution, as the determinant is zero and the equations are inconsistent.
676 Easy
676 of 922
Understanding +4 | -1
The inverse of a skew-symmetric matrix (if it exists) is
View answer and explanation
Correct option: B
A skew-symmetric matrix
Option B (A skew-symmetric matrix) is correct because the inverse of a skew-symmetric matrix, if it exists, is also skew-symmetric.
677 Easy
677 of 922
Application +4 | -1
Let A=(aij)3×3A=\left(a_{i j}\right)_{3 \times 3} be a matrix with aij∈Ca_{i j} \in {C}. Let BB be a matrix obtained by interchanging two columns of A.A. Then det⁡(A+B)\operatorname{det}(A+B) is equal to
View answer and explanation
Correct option: B
0
Option C (A is non-singular matrix) is correct because the given equation can be rearranged to show that A has an inverse, implying it is non-singular.
678 Easy
678 of 922
Understanding +4 | -1
If AA is a square matrix then which one of the following is not a symmetric matrix
View answer and explanation
Correct option: D
A−A′A-A^{\prime}
Option D (A−A′A-A^{\prime}) is correct because A−A′A-A^{\prime} is a skew-symmetric matrix, not a symmetric matrix.
679 Easy
679 of 922
Understanding +4 | -1
If AA is an invertible matrix of order nn, then the determinant of adj(A)adj\left( A \right) is equal to
View answer and explanation
Correct option: C
∣A  ∣n−1  |A\;{\left. \right|^{n - 1}}\;
Option C (∣A∣n−1|A|^{n-1}) is correct because the determinant of the adjugate of a matrix A is equal to the determinant of A raised to the power of (n-1), where n is the order of the matrix.
680 Easy
680 of 922
Analyzing +4 | -1
If the trivial solution is the only solution of the system of equations x−ky+z=0,  kx+3y−kz=0,   3x+y−z=0x - ky + z = 0,\,\,kx + 3y - kz = 0,\,\,\,3x + y - z = 0 Then, the set of values of kk is
View answer and explanation
Correct option: B
R−{2,−3}R-\{2,-3\}
Option B (R−{2,−3}R-\left\{2,-3\right\}) is correct because the trivial solution is the only solution when the determinant of the coefficient matrix is non-zero, which means kk cannot be 2 or -3.
681 Easy
681 of 922
Understanding +4 | -1
If AA is a singular matrix, then adj AA is
View answer and explanation
Correct option: B
singular
Option B (singular) is correct because if A is singular, |A| = 0, and |adj A| = |A|^(n-1) = 0, which means adj A is also singular.
682 Easy
682 of 922
Application +4 | -1
If ∣xyz−xyzx−yz∣=kxyz,\left| {\begin{array}{cccccccccccccccccccc} x&y&z\\ { - x}&y&z\\ x&{ - y}&z \end{array}} \right| = kxyz, then kk is equal to
View answer and explanation
Correct option: C
4
Option C (4) is correct because the determinant simplifies to 4xyz4xyz after applying row operations, thus k=4k=4.
683 Easy
683 of 922
Application +4 | -1
If ω\omega is a complex cube root of unity, then the value of ∣x+1ωω2ωx+ω21ω21x+ω∣\left| {\begin{array}{cccccccccccccccccccc} {x + 1}&\omega &{{\omega ^2}}\\ \omega &{x + {\omega ^2}}&1\\ {{\omega ^2}}&1&{x + \omega } \end{array}} \right| is
View answer and explanation
Correct option: D
None of these
The correct answer is D (None of these) because the determinant simplifies to x2, which is not among the provided options.
684 Easy
684 of 922
Application +4 | -1
If A=[0110]A=\left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right], then A2A^2 is equal to
View answer and explanation
Correct option: D
[1001]\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]
Option D (\left[\begin{{array}}{{ll}} 1 & 0 \\ 0 & 1 \end{{array}}\right]\left[\begin{{array}}{{ll}} 1 & 0 \\ 0 & 1 \end{{array}}\right]) is correct because the matrix multiplication of A by itself results in the identity matrix.
685 Easy
685 of 922
Analyzing +4 | -1
The value of Δ=∣(ax+a−x)2(ax−a−x)21(ay+a−y)2(ay−a−y)21(az+a−z)2(az−a−z)21∣,\Delta=\left|\begin{array}{lll}\left(a^x+a^{-x}\right)^2 & \left(a^x-a^{-x}\right)^2 & 1 \\ \left(a^y+a^{-y}\right)^2 & \left(a^y-a^{-y}\right)^2 & 1 \\ \left(a^z+a^{-z}\right)^2 & \left(a^z-a^{-z}\right)^2 & 1\end{array}\right|, is
View answer and explanation
Correct option: C
0
Option C (0) is correct because after applying a column operation, two columns become identical, resulting in a zero determinant.
686 Easy
686 of 922
Analyzing +4 | -1
Let SS be the set of all λ∈R\lambda \in R for which the system of linear equations

2x−y+2z=2x−2y+λz=−4x+λy+z=4\begin{aligned} &2 x-y+2 z=2 \\ &x-2 y+\lambda z=-4 \\ &x+\lambda y+z=4 \end{aligned}

has no solution, than the set SS
View answer and explanation
Correct option: B
Contains exactly two elements
Option B (Contains exactly two elements) is correct because the set S contains two values of lambda for which the system has no solution.
687 Easy
687 of 922
Application +4 | -1
In a square matrix AA of order 3 the elements aiia_{i i} 's are the sum of the roots of the equation x2−(a+b)x+ab=0;x^2-(a+b) x+a b=0; ai, i+1a_{i, \,i+1} 's are the product of the roots, ai, i−1a_{i, \,i-1} 's are all unity and the rest of the elements are all zero.

The value of the det⁡(A)\operatorname{det}(A) is equal to
View answer and explanation
Correct option: D
(a2+b2)(a+b)\left(a^2+b^2\right)(a+b)
The correct answer is D, (a2+b2)(a+b)\left(a^2+b^2\right)(a+b), which is the determinant of the given matrix A after expanding and simplifying the expression.
688 Easy
688 of 922
Application +4 | -1
Suppose a∈Ra \in {R}. Let f(x)=∣x+axxxx+axxxx+a∣f(x)=\left|\begin{array}{ccc} x+a & x & x \\ x & x+a & x \\ x & x & x+a \end{array}\right| Then f(2x)−f(x)f(2 x)-f(x) is equal to
View answer and explanation
Correct option: A
3xa23 x a^2
The correct answer is A (3xa23 x a^2) because after evaluating f(x) and f(2x), the difference f(2x) - f(x) simplifies to 3xa23 x a^2.
689 Easy
689 of 922
Application +4 | -1
If AA and BB are two square matrices such that B=−A−1BA,B=-A^{-1} B A, then (A+B)2(A+B)^2 is equal to
View answer and explanation
Correct option: B
A2+B2A^2+B^2
Option B (A2+B2) is correct because given B = -A-1BA, it implies AB = -BA, which simplifies the expansion of (A+B)2.
690 Easy
690 of 922
Understanding +4 | -1
Let A,BA,B and CC be n×nn \times n matrices. Which one of the following is a correct statements?
View answer and explanation
Correct option: B
If A3+2A2+3A+5I=O;then  A  is  invertible{A^3} + 2{A^2} + 3A + 5I = O;\mathrm{then}\;A\;\mathrm{is\;invertible}
Option B (If A3+2A2+3A+5I=O;then  A  is  invertible{A^3} + 2{A^2} + 3A + 5I = O;\mathrm{then}\;A\;\mathrm{is\;invertible}) is correct because the equation can be rearranged to show that A has an inverse.
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