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JEE • MATHEMATICS • MATHEMATICAL REASONING

Mathematical reasoning practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-171 of 171 questions
151 Easy
151 of 171
Understanding +4 | -1
The Boolean expression ∼(p⇒(∼q))\sim \left( {p \Rightarrow \left( { \sim q} \right)} \right) is equivalent to
View answer and explanation
Correct option: A
p∧qp \wedge q
Option A (p∧qp \wedge q) is correct because the given Boolean expression simplifies to p∧qp \wedge q using logical equivalences.
152 Easy
152 of 171
Understanding +4 | -1
The negation of the statement ' 72 is divisible by 2 and 3 ' is
View answer and explanation
Correct option: A
72 is not divisible by 2 of 72 is not divisible by 3
The correct answer is '72 is not divisible by 2 or 72 is not divisible by 3' because it is the logical negation of the original statement using De Morgan's Law.
153 Easy
153 of 171
Analyzing +4 | -1
Consider the following two statements.

Statement pp :

The value of sin⁡120∘\sin 120^{\circ} can be divided by taking θ=240∘\theta=240^{\circ} in the equation 2sin⁡θ2=1+sin⁡θ−1−sin⁡θ2 \sin \frac{\theta}{2}=\sqrt{1+\sin \theta}-\sqrt{1-\sin \theta}.

Statement q:q:

The angles A,B,CA, B, C and DD of any quadrilateral ABCDA B C D satisfy the equation cos⁡(12(A+C))+cos⁡(12(B+D))=0\cos \left(\frac{1}{2}(A+C)\right)+\cos \left(\frac{1}{2}(B+D)\right)=0
Then the truth values of pp and qq are respectively.
View answer and explanation
Correct option: A
F,T\mathrm{F}, \mathrm{T}
Option A (F, T) is correct because statement p is false when θ=240∘\theta = 240^\circ, and statement q is true because the sum of angles in a quadrilateral is 2π2\pi.
154 Easy
154 of 171
Analyzing +4 | -1
Let p,q,rp, q, r be three statements such that the truth value of ∼(∼p∨∼q)→(∼q∨r)\sim(\sim p \vee \sim q) \rightarrow(\sim q \vee r) is FF. Then the truth values of p,q,rp, q, r are respectively:
View answer and explanation
Correct option: D
T, T, F
The correct answer is D (T, T, F) because when p and q are true and r is false, the given expression evaluates to false, satisfying the condition.
155 Easy
155 of 171
Analyzing +4 | -1
Negation of the Boolean statement (p∨q)⇒((∼r)∨p)(p \vee q) \Rightarrow((\sim r) \vee p) is equivalent to
View answer and explanation
Correct option: C
(∼p)∧q∧r(\sim p) \wedge q \wedge r
Option C ((∼p)∧q∧r\sim p) \wedge q \wedge r) is correct because it represents the negation of the given Boolean statement after applying De Morgan's laws and logical equivalences.
156 Easy
156 of 171
Understanding +4 | -1
The contrapositive of the statement "I go to school if it does not rain" is
View answer and explanation
Correct option: B
If I do not go to school, it rains.
Option B (If I do not go to school, it rains) is correct because it is the contrapositive of the given statement.
157 Easy
157 of 171
Analyzing +4 | -1
Consider the following statements :

P : Suman is brilliant

Q: Suman is rich.

R\mathrm{R} : Suman is honest

the negation of the statement

"Suman is brilliant and dishonest if and only if suman is rich" can be equivalently expressed as :
View answer and explanation
Correct option: D
∼Q↔P∧∼R\sim \mathrm{Q} \leftrightarrow \mathrm{P} \wedge \sim \mathrm{R}
Option D (∼Q↔P∧∼R\sim Q \leftrightarrow P \wedge \sim R) is correct because the negation of "Suman is brilliant and dishonest if and only if Suman is rich" is equivalent to ∼Q↔P∧∼R\sim Q \leftrightarrow P \wedge \sim R.
158 Easy
158 of 171
Understanding +4 | -1
Contrapositive of the statement “If two numbers are not equal, then their squares are not equal” is
View answer and explanation
Correct option: B
If the squares of two numbers are equal, then the numbers are equal.
Option B (If the squares of two numbers are equal, then the numbers are equal) is correct because it is the contrapositive of the given statement.
159 Easy
159 of 171
Analyzing +4 | -1
Let Δ∈{∧,∨,⇒,⇔}\Delta \in\{\wedge, \vee, \Rightarrow, \Leftrightarrow\} \quad be such that (p∧q)Δ((p∨q)⇒q)(p \wedge q) \Delta((p \vee q) \Rightarrow q) is a tautology. Then Δ\Delta is equal to :
View answer and explanation
Correct option: C
⇒\Rightarrow
Option C (⇒\Rightarrow) is correct because the truth table for (p∧q)⇒((p∨q)⇒q)(p \wedge q) \Rightarrow ((p \vee q) \Rightarrow q) results in all true values, indicating that it is a tautology.
160 Easy
160 of 171
Application +4 | -1
   −[p∧(q⇒∼r)]=……\,\,\,-[p \wedge(q \Rightarrow \sim r)]=\ldots \ldots
View answer and explanation
Correct option: B
∼p∨(q∧r)\sim p \vee(q \wedge r)
Option B (∼p∨(q∧r)\sim p \vee (q \wedge r)) is correct because by applying logical equivalences and De Morgan's law, the given expression simplifies to this form.
161 Easy
161 of 171
Analyzing +4 | -1
For any two statements pp and qq, ∼(p∨q)∨(∼p∧q)\sim \left( {p \vee q} \right) \vee \left( { \sim p \wedge q} \right) is logically equivalent to
View answer and explanation
Correct option: B
∼p\sim p
Option B (∼p\sim p) is correct because the given expression simplifies to ∼p\sim p using logical equivalences.
162 Easy
162 of 171
Understanding +4 | -1
If p: Nidhi is intelligent; q\mathrm{q} : Nidhi will pass, then the statement Nidhi is intelligent but will not pass is written in symbols as
View answer and explanation
Correct option: C
p∧∼qp\wedge \sim q
Option C (p∧∼qp\wedge \sim q) is correct because it accurately represents "Nidhi is intelligent but will not pass" in symbolic form.
163 Easy
163 of 171
Understanding +4 | -1
The statement p∧∼q→rp \wedge \sim q \rightarrow r is logically equivalent to
View answer and explanation
Correct option: A
∼p∨q∨r\sim p \vee q \vee r
Option A (∼p∨q∨r\sim p \vee q \vee r) is correct because it is logically equivalent to the given statement p∧∼q→rp \wedge \sim q \rightarrow r after applying logical equivalences.
164 Easy
164 of 171
Analyzing +4 | -1
Which of the following Boolean expression is a tautology?
View answer and explanation
Correct option: D
(p∧q)→(p→q)(p \wedge q) \to (p \to q)
The correct answer is D ((p∧q)→(p→q)(p \wedge q) \to (p \to q)) because its truth table always results in true, making it a tautology.
165 Easy
165 of 171
Understanding +4 | -1
The statement p⇔qp \Leftrightarrow q is equal to -
View answer and explanation
Correct option: C
(∼p∨q)∧(p∨∼q)(\sim p \vee q) \wedge(p \vee \sim q)
Option C ((∼p∨q)∧(p∨∼q)\sim p \vee q) \wedge(p \vee \sim q)) is correct because p⇔qp \Leftrightarrow q is equivalent to (p→q)∧(q→p)(p \rightarrow q) \wedge (q \rightarrow p), which expands to the given expression.
166 Easy
166 of 171
Understanding +4 | -1
the contrapositive of "If two triangles are identical, then these are similar" is
View answer and explanation
Correct option: A
If two triangles are not similar, then these are not identical
Option A (If two triangles are not similar, then these are not identical) is correct because it is the contrapositive of the given conditional statement.
167 Easy
167 of 171
Analyzing +4 | -1
The proposition ∼(p∨∼q)∨∼(p∨q)\sim(p \vee \sim q) \vee \sim(p \vee q) is logically equivalent to
View answer and explanation
Correct option: C
∼p\sim p
Option C (∼p\sim p) is correct because by applying De Morgan's laws and simplification, the expression reduces to ∼p\sim p.
168 Easy
168 of 171
Understanding +4 | -1
p∧(q∧r)p \wedge \left( {q \wedge r} \right) is logically equivalent to
View answer and explanation
Correct option: B
(p∧q)∧r\left( {p \wedge q} \right) \wedge r
Option B ((p∧q)∧r\left( {p \wedge q} \right) \wedge r) is correct because the conjunction is associative.
169 Easy
169 of 171
Understanding +4 | -1
The contrapositive of p→(∼q→∼r)p \rightarrow(\sim q \rightarrow \sim r) is
View answer and explanation
Correct option: A
(∼q∧r)→∼p(\sim q \wedge r) \rightarrow \sim p
Option A is correct because it accurately represents the contrapositive of the given logical statement, derived by negating and reversing the implication.
170 Easy
170 of 171
Understanding +4 | -1
Which of the following statement has the truth value 'F'?
View answer and explanation
Correct option: A
A quadratic equation has always a real root
Option A is correct because a quadratic equation can have complex roots, thus not always a real root.
171 Easy
171 of 171
Understanding +4 | -1
The negation of the Boolean expression x↔ ∼yx \leftrightarrow \, \sim y is equivalent to
View answer and explanation
Correct option: B
(x∧y)∨(∼x∧∼y)(x \wedge y) \vee ( \sim x \wedge \sim y)
Option B ((x∧y)∨(∼x∧∼y)(x \wedge y) \vee (\sim x \wedge \sim y)) is correct because it represents the negation of the biconditional statement using logical equivalences.
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