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JEE • MATHEMATICS • INDEFINITE INTEGRATION

Indefinite integration practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 691-720 of 746 questions
691 Easy
691 of 746
Analyzing +4 | -1
If ∫(x2+1)ex(x+1)2dx=f(x)ex+C,\int {\frac{{({x^2} + 1){e^x}}}{{{{(x + 1)}^2}}}dx = f(x){e^x} + C,} where C is a constant then d3fdx3\frac{{{d^3}f}}{{d{x^3}}} at x=1x = 1 is equal to:
View answer and explanation
Correct option: B
34\frac{3}{4}
Option B (34\frac{3}{4}) is correct because after finding f(x) and its derivatives, substituting x=1 into the third derivative gives 34\frac{3}{4}.
692 Easy
692 of 746
Application +4 | -1
∫x2−2x3x2−1dx\int \frac{x^2-2}{x^3 \sqrt{x^2-1}} d x equals
View answer and explanation
Correct option: A
−x2−1x2+c\frac{-\sqrt{x^2-1}}{x^2}+c
Option A is correct because the integral is solved using substitution, where x2-1 = t2, simplifying the integral to a rational function.
693 Easy
693 of 746
Understanding +4 | -1
∫cosec⁡xlog⁡tan⁡x2dx=\int \frac{\operatorname{cosec} x}{\log \tan \frac{x}{2}} d x=
View answer and explanation
Correct option: A
log⁡(log⁡tan⁡x2)+c\log \left(\log \tan \frac{x}{2}\right)+c
Option A (log⁡(log⁡tan⁡x2)+c\log \left(\log \tan \frac{x}{2}\right)+c) is correct because the derivative of the inner function log⁡tan⁡x2\log \tan \frac{x}{2} is a constant multiple of cosec⁡x\operatorname{cosec} x.
694 Easy
694 of 746
Application +4 | -1
If ∫21/xx2dx=a 21/x+C\int \frac{2^{1 / x}}{x^2} d x=a\, 2^{1 / x}+C, then a=a=
View answer and explanation
Correct option: A
−log⁡2e-\log _2 e
Option A (−log⁡2e- \log _2 e) is correct because, after simplifying the integral, the coefficient of 21/x2^{1/x} is −log⁡2e-\log_2 e.
695 Easy
695 of 746
Application +4 | -1
∫cos⁡  (log⁡e  x) dx\int \cos \,\,({\log _e}\,\,x)\,dx is equal to
View answer and explanation
Correct option: A
12  x [cos⁡  (log⁡e  x)  +  sin⁡  (log⁡e  x)]\frac{1}{2}\,\,x\,[\cos \,\,({\log _e}\,\,x)\,\, + \,\,\sin \,\,({\log _e}\,\,x)]
Option A (12 x[cos⁡ (log⁡e x) + sin⁡ (log⁡e x)]\frac{1}{2}\,x[\cos \,({\log _e}\,x)\, + \,\sin \,({\log _e}\,x)] ) is correct because it is the result of applying integration by parts twice.
696 Easy
696 of 746
Application +4 | -1
The equation of a curve passing through the point (0,1)(0,1) be given by y=∫x2⋅ex3dxy=\int x^2 \cdot e^{x^3} d x. If the equation of the curve be written in the form x=f(y)x=f(y), then f(y)=f(y)=
View answer and explanation
Correct option: B
log⁡e(3y−2)3\sqrt[3]{\log _e(3 y-2)}
Option B is correct because it involves solving the integral, applying the initial condition, and then finding the inverse function.
697 Easy
697 of 746
Application +4 | -1
If ∫g(x)dx=g(x)\int g(x) d x=g(x), then the value of the integral ∫f(x)g(x){f(x)+2f′(x)}dx\int f(x) g(x)\left\{f(x)+2 f^{\prime}(x)\right\} d x, is
View answer and explanation
Correct option: B
{f(x)}2g(x)+C\{f(x)\}^2 g(x)+C
The correct answer is B ({f(x)}2g(x)+C\{f(x)\}^2 g(x)+C) because it results from integrating by parts and using the given condition ∫g(x)dx=g(x)\int g(x) dx = g(x).
698 Easy
698 of 746
Application +4 | -1
If the integral ∫5tan⁡xtan⁡x−2dx=x+\int \frac{5 \tan x}{\tan x-2} d x=x+ alog⁡∣sin⁡x−2cos⁡x∣+Ka \log |\sin x-2 \cos x|+K, then aa is equal to
View answer and explanation
Correct option: C
2
Option C is correct because the integral can be solved by rewriting the integrand and using logarithmic integration.
699 Easy
699 of 746
Application +4 | -1
∫1x(1+x3)2dx\int \frac{1}{x(1+\sqrt[3]{x})^2} d x is equal to
View answer and explanation
Correct option: A
3{log⁡(x1/31+x1/3)+11+x3}+C3\left\{\log \left(\frac{x^{1 / 3}}{1+x^{1 / 3}}\right)+\frac{1}{1+\sqrt[3]{x}}\right\}+C
Option A, 3\left{\log \left(\frac{x^{1 / 3}}{1+x^{1 / 3}}\right)+\frac{1}{1+\sqrt[3]{x}}\right\}+C3\left{\log \left(\frac{x^{1 / 3}}{1+x^{1 / 3}}\right)+\frac{1}{1+\sqrt[3]{x}}\right\}+C, is correct because it is the result of integrating the given expression after a suitable substitution and partial fraction decomposition.
700 Easy
700 of 746
Application +4 | -1
The value of ∫ex(x5+  5x4+  1)dx\int {e^x}\left( {{x^5} + \,\,5{x^4} + \,\,1} \right)dx is
View answer and explanation
Correct option: B
ex  .  x5  +  ex+  c{e^x}\,\,.\,\,{x^5}\,\, + \,\,{e^x} + \,\,c
Option B (ex . x5 + ex+ c{e^x}\,.\,{x^5}\, + \,{e^x} + \,c) is the correct result of integrating the given expression using integration by parts.
701 Easy
701 of 746
Application +4 | -1
∫dx2x−x2=\int \frac{d x}{\sqrt{2 x-x^2}}=
View answer and explanation
Correct option: B
sin⁡−1(x−1)+c\sin ^{-1}(x-1)+c
Option B is correct because the integral can be rewritten and solved using a trigonometric substitution, resulting in sin⁡−1(x−1)+c\sin^{-1}(x-1)+c.
702 Easy
702 of 746
Application +4 | -1
If ∫  dxx2+2x+2=f (x)+c\int \,\,\frac{{dx}}{{{x^2} + 2x + 2}} = f\,\left( x \right) + c, then f(x)f\left( x \right) is equal to
View answer and explanation
Correct option: A
tan⁡−1  (x+1){\tan ^{ - 1}}\,\,\left( {x + 1} \right)
Option A (tan⁡−1  (x+1){\tan ^{ - 1}}\,\,\left( {x + 1} \right)) is correct because completing the square and using the standard integral formula for arctangent yields this result.
703 Easy
703 of 746
Application +4 | -1
∫dxxln⁡xln⁡(ln⁡x)\int {\frac{{dx}}{{x\ln x\ln \left( {\ln x} \right)}}} is equal to
View answer and explanation
Correct option: A
ln⁡∣(ln⁡(ln⁡x))∣+c\ln \left| {\left( {\ln \left( {\ln x} \right)} \right)} \right| + c
Option A (ln⁡∣(ln⁡(ln⁡x))∣+c\ln \left| {\left( {\ln \left( {\ln x} \right)} \right)} \right| + c) is correct because after two successive substitutions, the integral simplifies to this logarithmic expression.
704 Easy
704 of 746
Understanding +4 | -1
∫  ∣ x ∣  dx\int \,\,\left| {\,x\,} \right|\,\,dx is equal to
View answer and explanation
Correct option: D
12  x  ∣ x ∣  +  c\frac{1}{2}\,\,x\,\,\left| {\,x\,} \right|\,\, + \,\,c
Option D (\frac{1}{2}\,x\,\left| {\,x\} \right|\, + \,c\frac{1}{2}\,x\,\left| {\,x\} \right|\, + \,c) is correct because the integral of ∣x∣|x| is 12x∣x∣+c\frac{1}{2}x|x| + c.
705 Easy
705 of 746
Application +4 | -1
∫(2x+1)ex(2x+3)2dx\int \frac{(2 x+1) e^x}{(2 x+3)^2} d x is equal to
View answer and explanation
Correct option: D
ex2x+3+c\frac{e^x}{2 x+3}+c
Option D is correct because the integral can be rewritten in the form ∫ex[f(x)+f′(x)]dx\int e^x [f(x) + f'(x)] dx, which simplifies to exf(x)+ce^x f(x) + c.
706 Easy
706 of 746
Understanding +4 | -1
If polynomials PP and QQ satisfies
∫((3x−1)cos⁡x+(1−2x)sin⁡x)dx\int((3 x-1) \cos x+(1-2 x) \sin x) d x
=Pcos⁡x+Qsin⁡x=P \cos x+Q \sin x
(ignoring the constant of integration) then
View answer and explanation
Correct option: D
Q=3(x−1)Q=3(x-1)
Option D (Q=3(x−1)Q=3(x-1)) is correct because after integrating by parts and comparing coefficients, Q is found to be 3(x-1).
707 Easy
707 of 746
Application +4 | -1
The value of ∫(x+1x)3/2(x2−1x2)dx\int\left(x+\frac{1}{x}\right)^{3 / 2}\left(\frac{x^2-1}{x^2}\right) d x, is
View answer and explanation
Correct option: B
25(x+1x)5/2+C\frac{2}{5}\left(x+\frac{1}{x}\right)^{5 / 2}+C
Option B is correct because the integral simplifies to (2/5)(x + 1/x)(5/2) + C after recognizing the derivative pattern.
708 Easy
708 of 746
Understanding +4 | -1
If ∫dxx  log⁡  x=f(x)+\int \frac{{dx}}{{x\,\,\log \,\,x}} = f\left( x \right) + constant, then f(x)f\left( x \right) is equal to
View answer and explanation
Correct option: C
log⁡  log⁡  x\log \,\,\log \,\,x
Option C (log⁡ log⁡ x\log \, \log \, x) is correct because the integral of 1x log⁡x\frac{1}{x \, \log x} is log⁡(log⁡x)\log(\log x).
709 Easy
709 of 746
Application +4 | -1
∫cos⁡xdx=\int \cos \sqrt{x} d x=
View answer and explanation
Correct option: A
2[xsin⁡x+cos⁡x]+c2[\sqrt{x} \sin \sqrt{x}+\cos \sqrt{x}]+c
Option A (2[xsin⁡x+cos⁡x]+c2[\sqrt{x} \sin \sqrt{x}+\cos \sqrt{x}]+c) is correct because it is the result of integrating the given expression using substitution and integration by parts.
710 Easy
710 of 746
Application +4 | -1
∫  tan⁡  xsin⁡  x  cos⁡  x  dx\int \,\,\frac{{\sqrt {\tan \,\,x} }}{{\sin \,\,x\,\,\cos \,\,x}}\,\,dx is equal to
View answer and explanation
Correct option: A
2 tan⁡  x  +  C2\,\sqrt {\tan \,\,x} \,\, + \,\,C
Option A (2 tan⁡ x + C2\,\sqrt {\tan \,x} \, + \,C) is correct because it is the result of a direct u-substitution and integration.
711 Easy
711 of 746
Analyzing +4 | -1
∫sin⁡4xsin⁡4x+cos⁡4xdx\int \frac{\sin ^4 x}{\sin ^4 x+\cos ^4 x} d x is equal to
View answer and explanation
Correct option: C
12{x−122log⁡∣2+sin⁡2x2−sin⁡2x∣}+C\frac{1}{2}\left\{x-\frac{1}{2 \sqrt{2}} \log \left|\frac{\sqrt{2}+\sin 2 x}{\sqrt{2}-\sin 2 x}\right|\right\}+C
The correct answer is C (12{x−122log⁡∣2+sin⁡2x2−sin⁡2x∣}+C\frac{1}{2}\left\{x-\frac{1}{2 \sqrt{2}} \log \left|\frac{\sqrt{2}+\sin 2 x}{\sqrt{2}-\sin 2 x}\right|\right\}+C) because after applying trigonometric identities and simplification, the integral can be evaluated.
712 Easy
712 of 746
Application +4 | -1
If ∫dx4−3cos⁡2x+5sin⁡2x=13f(3tan⁡x)+C\int \frac{\mathrm{d} x}{4-3 \cos ^2 x+5 \sin ^2 x}=\frac{1}{3} f(3 \tan x)+C, then f(x)f(x) is equal to
View answer and explanation
Correct option: D
tan⁡−1x\tan ^{-1} x
Option D (\tan-1 x\\) is correct. Dividing by \cos2 x and substituting \t=tan⁡xt = \tan x simplifies the integral to a standard arctangent form.
713 Easy
713 of 746
Analyzing +4 | -1
If ∫1(sin⁡  x  +  4) (sin⁡  x−1)  dx\int \frac{1}{{(\sin \,\,x\,\, + \,\,4)\,(\sin \,\,x - 1)}}\,\,dx
=A1tan⁡  x2−1+Btan⁡−1(f(x))+C= A\frac{1}{{\tan \,\,\frac{x}{2} - 1}} + B{\tan ^{ - 1}}\left( {f\left( x \right)} \right) + C, then
View answer and explanation
Correct option: D
A=25,   B=− 25 15,   f(x)=4tan⁡  x/2+115A = \frac{2}{5},\;\,B = \frac{{ - \,2}}{{5\,\sqrt {15} }},\;\,f\left( x \right) = \frac{{4\tan \,\,x/2 + 1}}{{\sqrt {15} }}
Option D (A=25,;B=−,25;15,; f(x)=4tan⁡,x2+,115A = \frac{2}{5},\\;B = \frac{{ - \\,2}}{{5\\;\sqrt {15} }},\\;\,f\left( x \right) = \frac{{4\tan \\,\frac{x}{2}\\ + \\,1}}{{\sqrt {15} }}) is correct because it represents the correct partial fraction decomposition and integration of the given expression.
714 Easy
714 of 746
Application +4 | -1
Let ∫  ex  (f  (x)−f′(x))  dx=ϕ  (x)\int \,\,{e^x}\,\,\left( {f\,\,\left( x \right) - f'\left( x \right)} \right)\,\,dx = \phi \,\,\left( x \right)

Then, ∫  ex f(x)  dx\int \,\,{e^x}\,f\left( x \right)\,\,dx is equal to
View answer and explanation
Correct option: C
12  [ϕ(x)  +  exf  (x)]\frac{1}{2}\,\,\left[ {\phi \left( x \right)\,\, + \,\,{e^x}f\,\,\left( x \right)} \right]
Option C (12 [ϕ(x) + exf  (x)]\frac{1}{2}\,\left[ {\phi \left( x \right)\, + \,{e^x}f\,\,\left( x \right)} \right]) is correct because it is derived from integration by parts and the given equation.
715 Easy
715 of 746
Application +4 | -1
The integral ∫2x12+5x9(x5+x3+1)3dx\int {\frac{{2{x^{12}} + 5{x^9}}}{{{{\left( {{x^5} + {x^3} + 1} \right)}^3}}}dx} is equl to
View answer and explanation
Correct option: B
x102(x5+x3+1)2+C\frac{{{x^{10}}}}{{2{{\left( {{x^5} + {x^3} + 1} \right)}^2}}} + C
Option B is correct because the integral simplifies to a form that can be solved by substitution, resulting in the given expression.
716 Easy
716 of 746
Analyzing +4 | -1
Integral of 1+2cot⁡x(cot⁡x+cosec⁡x)\sqrt{1+2 \cot x(\cot x+\operatorname{cosec} x)} w.r.t. xx, is
View answer and explanation
Correct option: B
2ln⁡sin⁡x2+C2 \ln \sin \frac{x}{2}+C
Option B (2ln⁡sin⁡x2+C2 \ln \sin \frac{x}{2}+C) is correct because simplifying the expression inside the square root leads to an integral that can be directly evaluated to this result.
717 Easy
717 of 746
Application +4 | -1
If f(x)=x21+x2f(x)=\frac{x^2}{1+x^2} and g(x)=sin⁡xg(x)=\sin x then ∫fog(x)cos⁡x dx\int f o g(x) \cos x \mathrm{~d} x is
View answer and explanation
Correct option: A
sin⁡x−tan⁡−1(sin⁡x)+C\sin x-\tan ^{-1}(\sin x)+C
Option A (\sin x - \tan-1(\sin x) + C\\) is correct. By substituting \t=sin⁡xt = \sin x, the integral simplifies to \∫t21+t2dt\int \frac{t^2}{1+t^2} dt, which can be easily integrated.
718 Easy
718 of 746
Application +4 | -1
∫  1  +  x1  +  x3  dx\int \,\,\frac{{1\,\, + \,\,x}}{{1\,\, + \,\,\sqrt[3]{x}}}\,\,dx is equal to
View answer and explanation
Correct option: A
35  x5/3  −  34x4/3  +  x  +  C\frac{3}{5}\,\,{x^{5/3}}\,\, - \,\,\frac{3}{4}{x^{4/3}}\,\, + \,\,x\,\, + \,\,C
Option A (35⋅x5/3−34x4/3+x+C\frac{3}{5}\cdot{x^{5/3}}\\ - \frac{3}{4}{x^{4/3}}\\ + \\ x\\ + \\ C) is correct because after integrating the simplified expression, we obtain this result.
719 Easy
719 of 746
Application +4 | -1
∫sec⁡  xsec⁡  x  +  tan⁡x    dx\int \frac{{\sec \,\,x}}{{\sec \,\,x\,\, + \,\,\tan x}}\,\,\;dx
is equal to
View answer and explanation
Correct option: A
tan⁡  x−sec⁡  x+c\tan \,\,x - \sec \,\,x + c
Option A (tan⁡ x−sec⁡ x+c\tan \,x - \sec \,x + c) is correct because it is obtained by multiplying the numerator and denominator by (sec⁡x−tan⁡x)(\sec x - \tan x) and then integrating the resulting expression.
720 Easy
720 of 746
Application +4 | -1
The integral ∫dxx+x23\int \frac{d x}{\sqrt{x}+\sqrt[3]{x^2}} represents the function
View answer and explanation
Correct option: B
3x3−6x6+6log⁡∣1+x6∣+c3 \sqrt[3]{x}-6 \sqrt[6]{x}+6 \log |1+\sqrt[6]{x}|+c
Option B (3x3−6x6+6log⁡∣1+x6∣+c3 \sqrt[3]{x}-6 \sqrt[6]{x}+6 \log |1+\sqrt[6]{x}|+c) is correct because it is the result of integrating the given expression using substitution.
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