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JEE • MATHEMATICS • INDEFINITE INTEGRATION

Indefinite integration practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 411 questions
1 Medium
1 of 411
Application +4 | -1
If f(x)f(x) is differentibale and ∫0t2xf(x)dx=25t5\int\limits_{0}^{t^2} x f(x) d x=\frac{2}{5} t^5 then f(425)f\left(\frac{4}{25}\right) equals
View answer and explanation
Correct option: A
2/52 / 5
Option A (2 / 5) is correct because it is the value of f(4/25) obtained after differentiating both sides of the given equation and substituting t=2/5.
2 Medium
2 of 411
Application +4 | -1
If ∫ex2(2−1x2)de=ex2f(x)+C\int {e}^{{x}^2}\left(2-\frac{1}{{x}^2}\right) {de}={e}^{{x}^2} {f}({x})+{C} and f(12)=2{f}\left(\frac{1}{2}\right)=2, then f(1)f(1) is equal to (where C{C} is an arbitrary constant)
View answer and explanation
Correct option: A
1
Option A (1) is correct because after integrating and comparing with the given form, f(x) is found to be 1/x, and f(1) equals 1.
3 Medium
3 of 411
Application +4 | -1
The value of ∫1+x+x21+x2etan⁡−1xdx\int {\frac{{1 + x + {x^2}}}{{1 + {x^2}}}{e^{{{\tan }^{ - 1}}x}}dx} is equal to
View answer and explanation
Correct option: C
xetan⁡−1x+cx{e^{{{\tan }^{ - 1}}x}} + c
Option C (xetan⁡−1x+cx{e^{{{\tan }^{ - 1}}x}} + c) is correct because after substituting t=tan⁡−1xt = \tan^{-1}x and integrating by parts, the integral evaluates to this expression.
4 Medium
4 of 411
Application +4 | -1
The value of ∫0π/2  sin⁡3  x  cos⁡  xsin⁡4  x  +  cos⁡4  x  dx\int \limits_0^{\pi /2} \,\,\frac{{{{\sin }^3}\,\,x\,\,\cos \,\,x}}{{{{\sin }^4}\,\,x\,\, + \,\,{{\cos }^4}\,\,x}}\,\,dx, is
View answer and explanation
Correct option: A
π/8\pi /8
Option A (π/8) is correct because by using the property of definite integrals and trigonometric identities, the integral simplifies to π/8.
5 Medium
5 of 411
Analyzing +4 | -1
If y(x−y)2=xy(x-y)^2=x, then ∫dx(x−3y)=mnln⁡[(x−y)2−1]\int \frac{d x}{(x-3 y)}=\frac{m}{n} \ln \left[(x-y)^2-1\right]. Then (m+2n)(m+2 n) is equal to
View answer and explanation
Correct option: C
5
Option C is correct because after solving the differential equation and substituting back, the value of (m+2n) is found to be 5.
6 Medium
6 of 411
Application +4 | -1
If I=∫−20[x3+3x2+3x+(x+1)cos⁡(x+1)]dx\mathrm{I}=\int_{-2}^0\left[\mathrm{x}^3+3 \mathrm{x}^2+3 \mathrm{x}+(\mathrm{x}+1) \cos (\mathrm{x}+1)\right] \mathrm{dx}, then I\mathrm{I} equals:
View answer and explanation
Correct option: C
-2
Option A is incorrect. The correct answer should be c3c^3 but the provided solution and explanation are flawed and do not lead to the correct conclusion. The problem involves arithmetic progressions and their sums.
7 Medium
7 of 411
Analyzing +4 | -1
If ∫cos⁡4xsin⁡2xdx=Acot⁡x+Bsin⁡2x+C2x+D\int \frac{\cos ^4 x}{\sin ^2 x} d x=A \cot x+B \sin 2 x+\frac{C}{2} x+D, then
View answer and explanation
Correct option: B
B=−1/4,C=−3B=-1 / 4, C=-3
Option B is correct because after evaluating the integral, we find that B=−14B = -\frac{1}{4} and C=−3C = -3.
8 Medium
8 of 411
Application +4 | -1
∫sin⁡51x(sin⁡x)49dx=\int \sin 51 x(\sin x)^{49} d x=
View answer and explanation
Correct option: A
sin⁡50x(sin⁡x)5050+c\frac{\sin 50 x(\sin x)^{50}}{50}+c
Option A (sin⁡50x(sin⁡x)5050+c\frac{{\sin 50 x(\sin x)^{{50}}}}{{50}}+c) is correct because the integral simplifies to this form after applying trigonometric identities and integration by parts.
9 Medium
9 of 411
Analyzing +4 | -1
The value of ∫cos⁡xsin⁡2x(sin⁡x+cos⁡x)dx\int \frac{\cos x}{\sin ^2 x(\sin x+\cos x)} d x is equal to
View answer and explanation
Correct option: A
log⁡∣1+tan⁡xtan⁡x∣−cot⁡x+C\log \left|\frac{1+\tan x}{\tan x}\right|-\cot x+C
Option A (log⁡∣1+tan⁡xtan⁡x∣−cot⁡x+C\log \left|\frac{{1+\tan x}}{{\tan x}}\right|-\cot x+C) is correct because the integral can be solved by dividing the numerator and denominator by cos3(x) and using partial fractions after substituting tan(x) = t.
10 Medium
10 of 411
Application +4 | -1
∫e−2xsin⁡3xdx=\int e^{-2 x} \sin 3 x d x=
View answer and explanation
Correct option: D
−113e−2x[2sin⁡3x+3cos⁡3x]+c-\frac{1}{13} e^{-2 x}[2 \sin 3 x+3 \cos 3 x]+c
Option D (−113e−2x[2sin⁡3x+3cos⁡3x]+c-\frac{{1}}{{13}} e^{-2 x}[2 \sin 3 x+3 \cos 3 x]+c) is correct because it is the result of integrating the given expression using integration by parts twice.
11 Medium
11 of 411
Application +4 | -1
The value of ∫dxsin⁡x⋅sin⁡(x+α)\int \frac{d x}{\sin x \cdot \sin (x+\alpha)} is equal to
View answer and explanation
Correct option: A
cosec⁡α ℓn∣sin⁡xsin⁡(x+α)∣+C\operatorname{cosec} \alpha \,\ell n \left|\frac{\sin x}{\sin (x+\alpha)}\right|+C
Option A (cosec⁡α ℓn∣sin⁡xsin⁡(x+α)∣+C\operatorname{cosec} \alpha \,\ell n \left|\frac{{\sin x}}{{\sin (x+\alpha)}}\right|+C) is correct because it results from using trigonometric identities and properties of logarithms.
12 Medium
12 of 411
Application +4 | -1
If ∫dxx(1+x4)10=a(1+x4)−8+b(1+x4)−9\int \frac{d x}{\sqrt{x}(1+\sqrt[4]{x})^{10}}=a(1+\sqrt[4]{x})^{-8}+b(1+\sqrt[4]{x})^{-9} then a+ba+b is
View answer and explanation
Correct option: B
−118-\frac{1}{18}
Option B (−118-\frac{1}{18}) is correct because after evaluating the integral and comparing coefficients, a+ba+b equals this value.
13 Medium
13 of 411
Application +4 | -1
∫1  +  xx  +  e−x    dx\int \frac{{1\,\, + \,\,x}}{{x\,\, + \,\,{e^{ - x}}}}\,\,\;dx is equal to
View answer and explanation
Correct option: C
log⁡  ∣ (1  +  xex) ∣+c\log \,\,\left| {\,\left( {1\,\, + \,\,x{e^x}} \right)\,} \right| + c
Option C (log⁡ ∣ (1+xex) ∣+c\log \,|\,(1 + x{e^x})\,| + c) is correct because by using substitution, the integral simplifies to this logarithmic form.
14 Medium
14 of 411
Application +4 | -1
∫sin⁡2xcos⁡3xdx=\int \sin 2 x \cos 3 x d x=
View answer and explanation
Correct option: B
12(cos⁡x−15cos⁡5x)+c\frac{1}{2}\left(\cos x-\frac{1}{5} \cos 5 x\right)+c
Option B is correct because the integral of sin⁡2xcos⁡3x\sin 2x \cos 3x is solved using the product-to-sum trigonometric identities.
15 Medium
15 of 411
Application +4 | -1
∫xx4−1dx=\int \frac{x}{x^4-1} d x=
View answer and explanation
Correct option: A
14log⁡[x2−1x2+1]+c\frac{1}{4} \log \left[\frac{x^2-1}{x^2+1}\right]+c
Option A is correct because the integral is solved by substituting t=x2t = x^2 and using partial fraction decomposition.
16 Medium
16 of 411
Application +4 | -1
3a  ∫01  (ax−1a−1)2dx3a\,\,\int \nolimits_0^1 \,\,{\left( {\frac{{ax - 1}}{{a - 1}}} \right)^2}dx is equal to
View answer and explanation
Correct option: A
a−1+(a−1)−2a - 1 + {\left( {a - 1} \right)^{ - 2}}
Option A is correct because the integral evaluates to the given expression after simplification, matching the form in option A.
17 Medium
17 of 411
Application +4 | -1
∫  (sec⁡2  x  −  7)sin⁡7  x    dx\int \,\,\frac{{({{\sec }^2}\,\,x\,\, - \,\,7)}}{{{{\sin }^7}\,\,x}}\,\,\;dxis equal to
View answer and explanation
Correct option: A
tan⁡  xsin⁡7  x  +  c\frac{{\tan \,\,x}}{{{{\sin }^7}\,\,x}}\,\, + \,\,c
Option A is correct because the given integral simplifies to the derivative of (tan x) / (sin7 x), making the solution (tan x) / (sin7 x) + c.
18 Medium
18 of 411
Application +4 | -1
∫  dxx(x7+1)\int \,\,\frac{{dx}}{{x\left( {{x^7} + 1} \right)}} is equal to
View answer and explanation
Correct option: B
17  log⁡  (x7x7+1)+c\frac{1}{7}\,\,\log \,\,\left( {\frac{{{x^7}}}{{{x^7} + 1}}} \right) + c
Option B (17 log⁡ (x7x7+1)+c\frac{1}{7}\,\log \,\left( {\frac{{{x^7}}}{{{x^7} + 1}}} \right) + c) is correct because after substitution and partial fraction decomposition, the integral evaluates to this expression.
19 Medium
19 of 411
Analyzing +4 | -1
The value of ∫dxx  +  x  −  1\int \frac{{dx}}{{x\,\, + \,\,\sqrt {x\,\, - \,\,1} }} is
View answer and explanation
Correct option: C
log⁡  (x  +  x−1)−  23  tan⁡−1  (2 x  −  1+  13)  +  c\log \,\,\left( {x\,\, + \,\,\sqrt {x - 1} } \right) - \,\,\frac{2}{{\sqrt 3 }}\,\,{\tan ^{ - 1}}\,\,\left( {\frac{{2\,\sqrt {x\,\, - \,\,1} + \,\,1}}{{\sqrt 3 }}} \right)\,\, + \,\,c
Option C (log⁡  (x + x−1)−  23 tan⁡−1  (2 x − 1+ 13) + c\log \,\,\left( {x\, + \,\sqrt {x - 1} } \right) - \,\,\frac{2}{{\sqrt 3 }}\,{\tan ^{ - 1}}\,\,\left( {\frac{{2\,\sqrt {x\, - \,1} + \,1}}{{\sqrt 3 }}} \right)\, + \,c) is correct because after substitution and integration, the integral evaluates to the given expression.
20 Medium
20 of 411
Analyzing +4 | -1
∫777x⋅77x⋅7xdx\int 7^{7^{7^x}} \cdot 7^{7^x} \cdot 7^x d x is equal to
View answer and explanation
Correct option: A
777x(log⁡e7)3+C\frac{7^{7^{7^x}}}{\left(\log _e 7\right)^3}+C
Option A is correct because the integral can be solved by recognizing the pattern and using substitution, leading to the given result.
21 Medium
21 of 411
Application +4 | -1
If ∫ex−1ex+1dx=f(x)+C\int \frac{e^x-1}{e^x+1} d x=f(x)+C, then f(x)=f(x)=
View answer and explanation
Correct option: C
2log⁡(ex+1)−x+C2 \log \left(e^x+1\right)-x+C
Option C is correct because the integral simplifies to 2log(e^x + 1) - x + C after algebraic manipulation and integration.
22 Medium
22 of 411
Analyzing +4 | -1
If f2(x)=tan⁡−1(sec⁡x+tan⁡x),−π2<x<π2,  and  f(0)=0,  then  f(1)f2(x) = {\tan ^{ - 1}}(\sec x + \tan x), - \frac{\pi }{2} < x < \frac{\pi }{2},\,\,{\text{and}}\,\,f(0) = 0,\,\,{\text{then}}\,\,f(1) is equal to:
View answer and explanation
Correct option: A
π+14\frac{\pi+1}{4}
Option A (π+14\frac{{\pi+1}}{{4}}) is correct because it is the value of f(1) obtained after integrating f'(x) and applying the initial condition f(0) = 0.
23 Medium
23 of 411
Application +4 | -1
∫dx(x−a)(b−x)=\int \frac{d x}{\sqrt{(x-a)(b-x)}}=
View answer and explanation
Correct option: A
2sin⁡−1(x−ab−a)+c2 \sin ^{-1} \sqrt{\left(\frac{x-a}{b-a}\right)}+c
Option A is correct because the integral can be solved by using a suitable trigonometric substitution.
24 Medium
24 of 411
Analyzing +4 | -1
If ∫  4ex+  6e−x9ex−  4e−x  dx=Ax+B  log⁡  (9e2x−  4)+C\int \,\,\frac{{4{e^x} + \,\,6{e^{ - x}}}}{{9{e^x} - \,\,4{e^{ - x}}}}\,\,dx = Ax + B\,\,\log \,\,\left( {9{e^{2x}} - \,\,4} \right) + C, then
View answer and explanation
Correct option: C
A=−  32,    B=3536,    C∈RA = - \,\,\frac{3}{2},\;\,\,B = \frac{{35}}{{36}},\;\,\,C \in R
Option C (A=− 32,   B=3536,   C∈RA = - \,\frac{3}{2},\,\;B = \frac{{35}}{{36}},\,\;C \in R) is correct because after integrating the given function and comparing with the given form, we find the values of A and B.
25 Medium
25 of 411
Application +4 | -1
∫  tan⁡−1  x  dx=...  +c\int \,\,{\tan ^{ - 1}}\,\,x\,\,dx = ...\,\, + c
View answer and explanation
Correct option: D
x  tan⁡−1  x  −  12  log⁡  ∣1  +  x2∣x\,\,{\tan ^{ - 1}}\,\,x\,\, - \,\,\frac{1}{2}\,\,\log \,\,\left| {1\,\, + \,\,{x^2}} \right|
Option D (x tan⁡−1 x − 12 log⁡ ∣1 + x2∣x\,\tan ^{ - 1}\,x\, - \,\frac{1}{2}\,\log \,\left| {1\, + \,{x^2}} \right|) is correct because it is the result of integrating tan⁡−1x\tan^{-1}x using integration by parts.
26 Medium
26 of 411
Application +4 | -1
∫(sin⁡x)−3/2(cos⁡x)−5/2dx=\int(\sin x)^{-3 / 2}(\cos x)^{-5 / 2} d x=
View answer and explanation
Correct option: C
−2cot⁡x+23tan⁡3x+c-2 \sqrt{\cot x}+\frac{2}{3} \sqrt{\tan ^3 x}+c
Option C (−2cot⁡x+23tan⁡3x+c-2 \sqrt{{\cot x}}+\frac{{2}}{{3}} \sqrt{{\tan ^3 x}}+c) is correct because it is the result of integrating the given expression after trigonometric manipulation and substitution.
27 Medium
27 of 411
Application +4 | -1
∫cos⁡(ln⁡xa)dx\int \cos \left(\ln \frac{x}{a}\right) d x is equal to
View answer and explanation
Correct option: B
x2(cos⁡(ln⁡xa)+sin⁡(ln⁡xa))+c\frac{x}{2}\left(\cos \left(\ln \frac{x}{a}\right)+\sin \left(\ln \frac{x}{a}\right)\right)+c
Option B (x2(cos⁡(ln⁡xa)+sin⁡(ln⁡xa)))+c\frac{x}{2}(\cos(\ln \frac{x}{a})+\sin(\ln \frac{x}{a}))) + c) is correct because it is the result of integrating cos⁡(ln⁡xa)\cos(\ln \frac{x}{a}) using integration by parts.
28 Medium
28 of 411
Application +4 | -1
∫(xx)x(2xlog⁡ex+x)dx\int\left(x^x\right)^x\left(2 x \log _e x+x\right) d x is equal to
View answer and explanation
Correct option: B
(xx)x+C\left(x^x\right)^x+C
Option B ((xx)x+C)((x^x)^x+C) is correct because the integral simplifies to the derivative of xx2x^{x^2}, making the solution (xx)x+C(x^x)^x+C.
29 Medium
29 of 411
Analyzing +4 | -1
If ∫1−5sin⁡2xcos⁡5xsin⁡2xdx=f(x)cos⁡5x+C\int \frac{1-5 \sin ^2 x}{\cos ^5 x \sin ^2 x} d x=\frac{f(x)}{\cos ^5 x}+C, then f(x)f(x) is
View answer and explanation
Correct option: D
cot⁡x\cot x
Option D (cot⁡x\cot x) is correct because by rewriting the integrand and integrating, f(x)f(x) is found to be cot⁡x\cot x.
30 Medium
30 of 411
Application +4 | -1
∫x6a8+x8dx=\int \sqrt{\frac{x^6}{a^8+x^8}} d x=
View answer and explanation
Correct option: B
14ln⁡∣x4+a8+x8∣+c\frac{1}{4} \ln \left|x^4+\sqrt{a^8+x^8}\right|+c
Option B (14ln⁡∣x4+a8+x8∣+c\frac{{1}}{{4}} \ln |x^4+\sqrt{{a^8+x^8}}|+c) is correct because the integral is solved using substitution and the standard integral formula for ∫dxx2+a2\int \frac{{dx}}{{\sqrt{{x^2+a^2}}}}
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