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JEE • MATHEMATICS • INDEFINITE INTEGRATION

Indefinite integration practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 661-690 of 746 questions

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661 Easy
661 of 746
Application +4 | -1
∫x1+x2+(1+x2)3dx\int \frac{x}{\sqrt{1+x^2+\sqrt{\left(1+x^2\right)^3}}} d x is equal to
View answer and explanation
Correct option: D
21+1+x2+C2 \sqrt{1+\sqrt{1+x^2}}+C
Option D is correct because the integral simplifies to 21+1+x2+C2 \sqrt{1+\sqrt{1+x^2}}+C after a suitable substitution.
662 Easy
662 of 746
Analyzing +4 | -1
The value of the integral ∫01log⁡  sin⁡  (πx2)  dx\int \limits_0^1 \log \,\,\sin \,\,\left( {\frac{{\pi x}}{2}} \right)\,\,dx , is
View answer and explanation
Correct option: B
− log⁡  2- \,\log \,\,2
The correct answer is B (− log⁡  2- \,\log \,\,2) because after substitution, the integral can be solved using a known result.
663 Easy
663 of 746
Application +4 | -1
The value of ∫dx5+4cos⁡x\int \frac{\mathrm{d} x}{5+4 \cos x} is
View answer and explanation
Correct option: D
23tan⁡−1(13tan⁡(x2))+C\frac{2}{3} \tan ^{-1}\left(\frac{1}{3} \tan \left(\frac{x}{2}\right)\right)+C
Option D (23tan⁡−1(13tan⁡(x2))+C\frac{2}{3} \tan ^{-1}\left(\frac{1}{3} \tan \left(\frac{x}{2}\right)\right)+C) is correct because it is the result of integrating the given expression using the tangent half-angle substitution.
664 Easy
664 of 746
Application +4 | -1
∫x33+5x4dx=\int x^3 \sqrt{3+5 x^4} d x=
View answer and explanation
Correct option: C
130(3+5x4)3/2+c\frac{1}{30}\left(3+5 x^4\right)^{3 / 2}+c
Option C is correct because the integral evaluates to 130(3+5x4)3/2+c\frac{1}{30}(3 + 5x^4)^{3/2} + c after applying the substitution method.
665 Easy
665 of 746
Application +4 | -1
∫x−6(1+2x3)2/3dx\int x^{-6}\left(1+2 x^3\right)^{2 / 3} d x is equal to:
View answer and explanation
Correct option: A
−15(x−3+2)5/3+c-\frac{1}{5}\left(x^{-3}+2\right)^{5 / 3}+c
Option A (−15(x−3+2)5/3+c-\frac{1}{5}\left(x^{-3}+2\right)^{5 / 3}+c) is correct because it is the result of u-substitution and subsequent integration.
666 Easy
666 of 746
Application +4 | -1
The value of ∫  e5log⁡ex  −  e4log⁡exe3log⁡ex  −  e2log⁡ex    dx\int \,\,\frac{{{e^{5{{\log }_e}x}}\,\, - \,\,{e^{4{{\log }_e}x}}}}{{{e^{3{{\log }_e}x}}\,\, - \,\,{e^{2{{\log }_e}x}}}}\;\,\,dx is
View answer and explanation
Correct option: C
x33  +  c\frac{{{x^3}}}{3}\,\, + \,\,c
Option C (x33+c\frac{{{x^3}}}{3} + c) is correct because it is the result of simplifying the expression and then integrating.
667 Easy
667 of 746
Analyzing +4 | -1
∫  sec⁡  x  cosec  x2  cot⁡  x−  sec⁡x  cosec  x  dx\int \,\,\frac{{\sec \,\,x\,\,\mathrm{cosec}\,\,x}}{{2\,\,\cot \,\,x - \,\,\sec x\,\,\mathrm{cosec}\,\,x}}\,\,dx is equal to
View answer and explanation
Correct option: C
12  log⁡  ∣sec⁡  2x  +  tan⁡  2x∣+  c\frac{1}{2}\,\,\log \,\,|\sec \,\,2x\,\, + \,\,\tan \,\,2x| + \,\,c
Option C is correct because the integral simplifies to the integral of sec(2x), which integrates to (1/2)log|sec(2x) + tan(2x)| + c.
668 Easy
668 of 746
Application +4 | -1
∫  (tan⁡−1  x)31  +  x2    dx\int \,\,\frac{{{{({{\tan }^{ - 1}}\,\,x)}^3}}}{{1\,\, + \,\,{x^2}}}\;\,\,dx is equal to
View answer and explanation
Correct option: B
(tan⁡−1  x)44  +  c\frac{{{{({{\tan }^{ - 1}}\,\,x)}^4}}}{4}\,\, + \,\,c
Option B ((tan⁡−1x)44+c\frac{{{{({{\tan }^{ - 1}}\\ x)}^4}}}{4}\\ + \\ c) is correct because it is the result of integrating the given expression using u-substitution.
669 Easy
669 of 746
Application +4 | -1
∫sin⁡2xa2+b2sin⁡2xdx=\int \frac{\sin 2 x}{a^2+b^2 \sin ^2 x} d x=
View answer and explanation
Correct option: A
1b2log⁡(a2+b2sin⁡2x)+c\frac{1}{b^2} \log \left(a^2+b^2 \sin ^2 x\right)+c
Option A is correct because the integral can be solved using substitution.
670 Easy
670 of 746
Application +4 | -1
The value of ∫x31+x8dx\int {\frac{{{x^3}}}{{1 + {x^8}}}dx} is equal to
View answer and explanation
Correct option: A
14tan⁡−1x4+c\frac{1}{4}{\tan ^{ - 1}}{x^4} + c
Option A (14tan⁡−1x4+c\frac{1}{4}{\tan ^{ - 1}}{x^4} + c) is correct because after a simple substitution, the integral transforms into a standard arctangent integral.
671 Easy
671 of 746
Understanding +4 | -1
∫  (tan⁡−1  x)3(1  +  x2)  dx\int \,\,\frac{{{{\left( {{{\tan }^{ - 1}}\,\,x} \right)}^3}}}{{\left( {1\,\, + \,\,{x^2}} \right)}}\,\,dx is equal to
View answer and explanation
Correct option: B
(tan⁡−1x)44  +  c\frac{{{{\left( {{{\tan }^{ - 1}}x} \right)}^4}}}{4}\,\, + \,\,c
Option B ((((tan-1x)4)/4) + c) is correct because it is the result of a straightforward u-substitution where u = tan-1x.
672 Easy
672 of 746
Application +4 | -1
∫dx(x+1)(x+2)=\int \frac{d x}{(x+1)(x+2)}=
View answer and explanation
Correct option: C
log⁡x+1x+2+c\log \frac{x+1}{x+2}+c
Option C, log⁡x+1x+2+c\log \frac{x+1}{x+2}+c, is the correct answer because it results from partial fraction decomposition and integration of the given expression.
673 Easy
673 of 746
Application +4 | -1
If ∫1+x3x2/3 dx=2f(x)3/2+C\int \frac{\sqrt{1+\sqrt[3]{x}}}{x^{2 / 3}} \mathrm{~d} x=2 f(x)^{3 / 2}+C then f(x)f(x) is equal to
View answer and explanation
Correct option: B
1+x1/31+x^{1 / 3}
Option B (1+x1/31+x^{1 / 3}) is correct because after substituting t2=1+x1/3t^2 = 1 + x^{1/3}, the integral simplifies to 2(1+x1/3)3/2+C2(1+x^{1/3})^{3/2} + C, matching the given form.
674 Easy
674 of 746
Application +4 | -1
∫cos⁡3  xelog⁡(sin⁡x)  dx\int {\cos ^3}\,\,x{e^{\log \left( {\sin x} \right)}}\,\,dx is equal to
View answer and explanation
Correct option: B
−  cos⁡4  x4  +  C- \,\,\frac{{{{\cos }^4}\,\,x}}{4}\,\, + \,\,C
Option B ( −  cos⁡4 x4 + C\ - \,\,\frac{{{{\cos }^4}\,x}}{4}\, + \,C) is correct. Simplifying the integral using properties of logarithms and then integrating leads to the correct result.
675 Easy
675 of 746
Application +4 | -1
∫  x3  sin⁡  [tan⁡−1  (x4)]1  +  x8  dx\int \,\,\frac{{{x^3}\,\,\sin \,\,\left[ {{{\tan }^{ - 1}}\,\,\left( {{x^4}} \right)} \right]}}{{1\,\, + \,\,{x^8}}}\,\,dx is equal to
View answer and explanation
Correct option: C
−14  cos⁡  [tan⁡−1  (x4)]  +  c- \frac{1}{4}\,\,\cos \,\,\left[ {{{\tan }^{ - 1}}\,\,\left( {{x^4}} \right)} \right]\,\, + \,\,c
Option C (−14cos⁡[tan⁡−1(x4)] + c- \frac{1}{4}\cos \left[ {{{\tan }^{ - 1}}\left( {{x^4}} \right)} \right]\, + \,c) is correct because it is the result of the given integral after applying the correct substitutions and integration.
676 Easy
676 of 746
Application +4 | -1
∫dxsin⁡5xcos⁡5x\int \frac{d x}{\sin ^5 x \cos ^5 x} is equal to
View answer and explanation
Correct option: B
14(tan⁡4x−cot⁡4x)+2(tan⁡2x−cot⁡2x)+6log⁡∣tan⁡x∣\frac{1}{4}\left(\tan ^4 x-\cot ^4 x\right)+2\left(\tan ^2 x-\cot ^2 x\right)+6 \log |\tan x| +C+C
Option B is correct because the integral evaluates to 14(tan⁡4x−cot⁡4x)+2(tan⁡2x−cot⁡2x)+6log⁡∣tan⁡x∣+C\frac{1}{4}(\tan ^4 x-\cot ^4 x)+2(\tan ^2 x-\cot ^2 x)+6 \log |\tan x| +C after simplification.
677 Easy
677 of 746
Application +4 | -1
The value of ∫  dxx2(x4+1)3/4\int \,\,\frac{{dx}}{{{x^2}{{\left( {{x^4} + 1} \right)}^{3/4}}}} is
View answer and explanation
Correct option: A
−  (x4+1)1/4x  +  c- \,\,\frac{{{{\left( {{x^4} + 1} \right)}^{1/4}}}}{x}\,\, + \,\,c
Option A (−  (x4+1)1/4x + c- \,\,\frac{{{{\left( {{x^4} + 1} \right)}^{1/4}}}}{x}\, + \,c) is correct because the integral is solved using a substitution and simplification.
678 Easy
678 of 746
Application +4 | -1
The value of 2∫sin⁡xsin⁡(x−π4)dx\sqrt{2} \int \frac{\sin x}{\sin \left(x-\frac{\pi}{4}\right)} d x, is
View answer and explanation
Correct option: A
x+log⁡∣sin⁡(x−π4)∣+Cx+\log \left|\sin \left(x-\frac{\pi}{4}\right)\right|+C
Option A (x+log⁡∣sin⁡(x−π4)∣+Cx+\log \left|\sin \left(x-\frac{\pi}{4}\right)\right|+C) is correct because after applying trigonometric identities and integrating, the result matches this option.
679 Easy
679 of 746
Application +4 | -1
∫x2−1xx4+3x2+1dx=log⁡e(f(x))+c\int \frac{x^2-1}{x \sqrt{x^4+3 x^2+1}} d x=\log _e(f(x))+c where f(x)f (x) is given by
View answer and explanation
Correct option: D
1x(x2+1+x4+3x2+1)\frac{1}{x}\left(x^2+1+\sqrt{x^4+3 x^2+1}\right)
Option D (1x(x2+1+x4+3x2+1)\frac{1}{x}\left(x^2+1+\sqrt{x^4+3 x^2+1}\right)) is correct because after simplifying and integrating, the result matches the given form with this f(x).
680 Easy
680 of 746
Application +4 | -1
The value of ∫555x⋅55x⋅5xdx\int 5^{5^{5^x}} \cdot 5^{5^x} \cdot 5^x d x is equal to
View answer and explanation
Correct option: C
555x(ℓn5)3+C\frac{5^{5^{5^x}}}{(\ell n 5)^3}+C
Option C (555x(ℓn5)3+C\frac{5^{5^{5^x}}}{(\ell n 5)^3}+C) is correct because it is the result of repeated u-substitutions and integration of an exponential function.
681 Easy
681 of 746
Application +4 | -1
∫log⁡10xdx=\int \log _{10} x d x=
View answer and explanation
Correct option: D
x(log⁡10x−log⁡10e)+cx\left(\log _{10} x-\log _{10} e\right)+c
Option D (x(log⁡10x−log⁡10e)+cx(\log _{10} x-\log _{10} e)+c) is correct because it is the result of integrating log⁡10x\log_{10} x using integration by parts and the change of base formula.
682 Easy
682 of 746
Analyzing +4 | -1
∫sin⁡3x(cos⁡4x+3cos⁡2x+1)tan⁡−1(sec⁡x+cos⁡x)dx=\int \frac{\sin ^3 x}{\left(\cos ^4 x+3 \cos ^2 x+1\right) \tan ^{-1}(\sec x+\cos x)} d x=
View answer and explanation
Correct option: B
log⁡e∣tan⁡−1(sec⁡x+cos⁡x)∣+C\log _e\left|\tan ^{-1}(\sec x+\cos x)\right|+C
The correct answer is B (log⁡e∣tan⁡−1(sec⁡x+cos⁡x)∣+C\log _e\left|\tan ^{-1}(\sec x+\cos x)\right|+C) because the integral simplifies to a form where the derivative of the inner function is present, allowing for a direct integration.
683 Easy
683 of 746
Analyzing +4 | -1
If ∫dx(x2−2x+10)2=A(tan⁡−1(x−13)+f(x)x3−2x+10)+C,\int {\frac{{dx}}{{{{\left( {{x^2} - 2x + 10} \right)}^2}}}} = A\left( {{{\tan }^{ - 1}}\left( {\frac{{x - 1}}{3}} \right) + \frac{{f(x)}}{{{x^3} - 2x + 10}}} \right) + C, where, C is a constant of integration, then
View answer and explanation
Correct option: C
A=154    and   f(x)=3(x−1)A = \frac{1}{{54}}\;\,\,\mathrm{and}\,\;f(x) = 3(x - 1)
Option C (A=154A = \frac{1}{{54}} and f(x)=3(x−1)f(x) = 3(x - 1)) is correct because it matches the result obtained after integrating the given expression and comparing coefficients.
684 Easy
684 of 746
Analyzing +4 | -1
∫tan⁡xsin⁡4x+cos⁡4xdx\int \frac{\tan x}{\sqrt{\sin ^4 x+\cos ^4 x}} d x is equal to
View answer and explanation
Correct option: B
12log⁡e(tan⁡2x+1+tan⁡4x)+C\frac{1}{2} \log _e\left(\tan ^2 x+\sqrt{1+\tan ^4 x}\right)+C
The correct answer is B (12log⁡e(tan⁡2x+1+tan⁡4x)+C\frac{1}{2} \log _e\left(\tan ^2 x+\sqrt{1+\tan ^4 x}\right)+C) because after simplification and substitution, the integral matches the form of the integral of 1x2+1\frac{1}{\sqrt{x^2+1}}.
685 Easy
685 of 746
Application +4 | -1
∫{1+2tan⁡x(tan⁡x+sec⁡x)}12dx\int\{1+2 \tan x(\tan x+\sec x)\}^{\frac{1}{2}} d x is equal to
View answer and explanation
Correct option: C
log⁡∣sec⁡x(sec⁡x+tan⁡x)∣+C\log |\sec x(\sec x+\tan x)|+C
Option C (log⁡∣sec⁡x(sec⁡x+tan⁡x)∣+C\log |\sec x(\sec x+\tan x)|+C) is correct because the integral simplifies to ∫(sec⁡x+tan⁡x)dx\int (\sec x + \tan x) dx, which evaluates to log⁡∣sec⁡x(sec⁡x+tan⁡x)∣+C\log |\sec x(\sec x+\tan x)|+C.
686 Easy
686 of 746
Analyzing +4 | -1
If f(x)=∫5x8+7x6(x2+1+2x7)2dx,(x≥0)f(x) = \int {\frac{{5{x^8} + 7{x^6}}}{{{{({x^2} + 1 + 2{x^7})}^2}}}dx,(x \ge 0)}, and f(0)=0f(0) = 0, then the value of f(1)f (1) is
View answer and explanation
Correct option: C
14\frac{1}{4}
Option C (14\frac{1}{4}) is correct because after evaluating the integral and applying the initial condition f(0) = 0, we find that f(1) = 1/4.
687 Easy
687 of 746
Application +4 | -1
∫  dxsin⁡  x  cos⁡  x\int \,\,\frac{{dx}}{{\sin \,\,x\,\,\cos \,\,x}} is equal to
View answer and explanation
Correct option: B
log⁡  ∣tan⁡  x∣+ c\log \,\,|\tan \,\,x| + \,c
Option B (log⁡,∣tan⁡,x∣+,c\log \\,|\tan \\,x| + \\,c) is correct because the integral can be simplified using trigonometric identities and then solved by recognizing the derivative of tan⁡x\tan x in the numerator.
688 Easy
688 of 746
Application +4 | -1
∫1x−x3dx=\int \frac{1}{x-x^3} d x=
View answer and explanation
Correct option: D
12log⁡x2(1−x2)+c\frac{1}{2} \log \frac{x^2}{\left(1-x^2\right)}+c
Option D, 12log⁡x2(1−x2)+c\frac{1}{2} \log \frac{x^2}{\left(1-x^2\right)}+c, is the correct answer because it results from partial fraction decomposition and integration of the given expression.
689 Easy
689 of 746
Application +4 | -1
∫tan⁡4xdx=\int \tan ^4 x d x=
View answer and explanation
Correct option: B
13tan⁡3x−tan⁡x+x+c\frac{1}{3} \tan ^3 x-\tan x+x+c
Option B (13tan⁡3x−tan⁡x+x+c\frac{1}{3} \tan ^3 x-\tan x+x+c) is correct because the integral simplifies to this form after using trigonometric identities and integration.
690 Easy
690 of 746
Application +4 | -1
The integral of ∫(1ln⁡x−1(ln⁡x)2)dx=\int\left(\frac{1}{\ln x}-\frac{1}{(\ln x)^2}\right) d x=
View answer and explanation
Correct option: C
xln⁡x+c\frac{x}{\ln x}+c
Option C (xln⁡x+c\frac{x}{\ln x}+c) is correct because it is the result of integration by parts after a suitable substitution.
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