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JEE • MATHEMATICS • COMPLEX NUMBERS
Complex numbers practice · Medium
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 271-300 of 337 questions
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271
Medium
271 of 337
Application
+4 | -1
If and represent the vertices of a triangle whose circumcenter is at the origin, then the complex number representing the orthocenter of the triangle is
View answer and explanation
Correct option: B
Option B () is correct because the orthocenter of a triangle with circumcenter at the origin is represented by the sum of the complex numbers representing the vertices.
272
Medium
272 of 337
Application
+4 | -1
The locus of the point which satisfy the condition arg , is
View answer and explanation
Correct option: B
A circle
Option B (A circle) is correct because the locus of the point that satisfies the given condition is a circle.
273
Medium
273 of 337
Application
+4 | -1
If the area of the triangle on the complex plane formed by the points and is 200, then the value of must be equal to
View answer and explanation
Correct option: C
60
Option C (60) is correct because the area of the triangle is related to |z|^2, and given the area is 200, we can find |z| and then |3z|.
274
Medium
274 of 337
Application
+4 | -1
If the area of triangle on the argand place formed by the complex numbers is 600 sq. unit, then is equal to
View answer and explanation
Correct option: B
20
Option B (7) is correct because the number of oscillations per minute is proportional to the square root of the horizontal component of the Earth's magnetic field, which depends on the total intensity and the angle of dip.
275
Medium
275 of 337
Application
+4 | -1
If and are the roots of the equation then the least value of for which is
View answer and explanation
Correct option: C
4
Option C is correct because it accurately determines the least value of n for which the given condition is satisfied, using complex number properties.
276
Medium
276 of 337
Application
+4 | -1
If are real numbers and is a root of
(1)
then value of is
(1)
then value of is
View answer and explanation
Correct option: A
1
Option A (1) is correct because substituting the root into the polynomial and equating the real part to zero leads to the given expression being equal to -1, and taking the absolute value gives 1.
277
Medium
277 of 337
Application
+4 | -1
If and , then
View answer and explanation
Correct option: C
Option C () is correct because using the property when , we can simplify the expression to .
278
Medium
278 of 337
Analyzing
+4 | -1
and , then is equal to
View answer and explanation
Correct option: C
Option C () is the correct answer because after simplification and using the given equation, the expression reduces to .
279
Medium
279 of 337
Analyzing
+4 | -1
Let be two complex numbers such that and , then equals
View answer and explanation
Correct option: A
Option A () is correct because the given conditions lead to after substituting and simplifying the arguments.
280
Medium
280 of 337
Application
+4 | -1
For any complex number , the minimum value of is
View answer and explanation
Correct option: A
1
Option B () is correct because expanding and simplifying the given expression using properties of complex numbers leads to this result.
281
Medium
281 of 337
Understanding
+4 | -1
STATEMENT-I: Let be two natural numbers such that and for some , then there exist such that
STATEMENT-II: If , then if and only if
STATEMENT-II: If , then if and only if
View answer and explanation
Correct option: B
I is true, II is false
Option B (I is true, II is false) is correct because statement I is based on the property of complex number magnitudes, while statement II is only true when z1 and z2 have the same argument.
282
Medium
282 of 337
Application
+4 | -1
For all complex numbers of the form , if , then
View answer and explanation
Correct option: B
Option B (y2 + 4x - 4 = 0) is correct because substituting z = 1 + iα into z2 = x + iy and eliminating α results in the equation y2 + 4x - 4 = 0.
283
Medium
283 of 337
Application
+4 | -1
If , then is equal to
View answer and explanation
Correct option: A
5
Option A (5) is correct because simplifying the given equation leads to |z|^2 = 25, thus |z| = 5.
284
Medium
284 of 337
Application
+4 | -1
If is a complex cube root of unity, then is equal to
View answer and explanation
Correct option: C
16
Option C (16) is correct because by simplifying the expression using the properties of complex cube roots of unity, the result is 16.
285
Medium
285 of 337
Application
+4 | -1
If . Then the value of is equal to
View answer and explanation
Correct option: B
32
Option B (32) is correct because substituting x=i into the binomial expansion and taking the magnitude squared results in 32.
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286
Medium
286 of 337
Analyzing
+4 | -1
The equation not representing a circle is given by
View answer and explanation
Correct option: D
Option D is correct because represents a straight line, while the other options represent circles.
287
Medium
287 of 337
Application
+4 | -1
The value of the expression is
View answer and explanation
Correct option: A
Option A () is correct because it is the simplified form of the given expression using properties of complex cube roots of unity.
288
Medium
288 of 337
Application
+4 | -1
The complex number satisfying arg and simultaneously, is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the given conditions lead to contradictory requirements for x and y, indicating no solution exists for z.
289
Medium
289 of 337
Application
+4 | -1
Let and be real numbers. If and are complex numbers such that , then
View answer and explanation
Correct option: A
Option A (2) is correct because the minimum value is obtained when any two are zero and the third is a minimum magnitude integer i.e. 1.
290
Medium
290 of 337
Application
+4 | -1
A complex number is such that . The points representing this complex number will lie on
View answer and explanation
Correct option: C
A circle
Option C (A circle) is correct because the given condition leads to the equation of a circle when is expressed as .
291
Medium
291 of 337
Application
+4 | -1
The principal argument of the complex number is
View answer and explanation
Correct option: C
Option C () is correct because calculating the argument of each complex number and using the properties of arguments leads to the principal argument being .
292
Medium
292 of 337
Application
+4 | -1
If and , then satisfies
View answer and explanation
Correct option: B
Option B () is correct because it represents the locus of the complex number satisfying the given argument condition.
293
Medium
293 of 337
Application
+4 | -1
The value of is
View answer and explanation
Correct option: D
Option D () is correct because the sum is simplified using De Moivre's theorem and the properties of geometric progressions.
294
Medium
294 of 337
Analyzing
+4 | -1
Let be two non-zero real numbers. Then the number of elements in the set and is equal to
View answer and explanation
Correct option: A
0
Option A (0) is correct because the given equations lead to an impossible condition, indicating no solution for z.
295
Medium
295 of 337
Application
+4 | -1
Let be two distinct non-zero complex numbers such that the origin, and form an equilateral triangle, then is equal to
View answer and explanation
Correct option: A
0
Option A (0) is correct because the given condition implies that z_1/z_2 is a complex cube root of unity, which leads to the equation z_12 + z_22 - z_1z_2 = 0.
296
Medium
296 of 337
Application
+4 | -1
Suppose represent the vertices , and respectively of a with centroid at . If the mid point of is the origin, then
View answer and explanation
Correct option: D
Option D () is correct because the midpoint of AG being the origin leads to the given relationship between the complex numbers.
297
Medium
297 of 337
Application
+4 | -1
If and are the three cube roots of unity, then to factors is equal to
View answer and explanation
Correct option: A
1
Option A (1) is correct because the product simplifies to 1 using the properties of complex cube roots of unity.
298
Medium
298 of 337
Analyzing
+4 | -1
If and , then is equal to
View answer and explanation
Correct option: D
Option D () is correct because after substituting and and simplifying, the expression evaluates to -2.
299
Medium
299 of 337
Application
+4 | -1
If , then the principal value of arg is equal to
View answer and explanation
Correct option: B
or or
Option B ( or or ) is correct because it represents the possible values of the argument of when .
300
Medium
300 of 337
Application
+4 | -1
The centre of a square is at the origin and is one of its vertices. The extremities of its diagonals which does not pass through this vertex are
View answer and explanation
Correct option: A
Option A () is correct because these are the vertices obtained by rotating the given vertex by 90 and 270 degrees around the origin.
Revision notes and key takeaways
Review COMPLEX NUMBERS in your textbook or class notes, then use this set to check your understanding.
Showing 271-300 of 337 questions
