JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

x_1 \leq x_2

and

y_1 \leq y_2

for any two complex numbers

z_1=x_1+i y_1

and

z_2=x_2+i y_2

, then we say

z_1 \cap z_2.

Let

z

be a complex number with

1 \cap z

. Then

View answer and explanation

Correct option: C

\frac{1-z}{1+z} \cap 0

Option C (

\frac{{1-z}}{{1+z}} \cap 0

) is correct because given the condition 1 ∩ z, it follows that the real and imaginary parts of

\frac{{1-z}}{{1+z}}

are non-positive, implying it is \"less than or equal to\" 0.

More Questions from COMPLEX NUMBERS

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{\left| {1 - i} \right|^x} = {2^x}

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\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

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\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

{\left( {1 - {x^2} + x} \right)^6} - {\left( {1 - x + {x^2}} \right)^6}