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JEE • MATHEMATICS • COMPLEX NUMBERS
Complex numbers practice · Medium
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 301-330 of 337 questions
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301
Medium
301 of 337
Application
+4 | -1
If lies on the circle , then lies on a
View answer and explanation
Correct option: A
Circle
Option A (Circle) is correct because if , then also lies on a circle, specifically a circle with radius 2.
302
Medium
302 of 337
Analyzing
+4 | -1
Two conjugate complex numbers and represent two adjacent vertices of a polygon of sides, whose centre is origin. If then ratio of the areas of the circles inscribed and circumscribed the polygon is
View answer and explanation
Correct option: C
Option C () is correct because it represents the square of the cosine of , which is the ratio of the inscribed to circumscribed circle areas.
303
Medium
303 of 337
Application
+4 | -1
If is a complex number in the Argand plane, then the equation represents
View answer and explanation
Correct option: D
A circle
The correct answer is D (A circle) because the simplified equation results in the equation of a circle.
304
Medium
304 of 337
Application
+4 | -1
If , then is equal to:
View answer and explanation
Correct option: D
-1
Option D (-1) is correct because substituting into the expression and simplifying using properties of complex numbers and cube roots of unity leads to -1.
305
Medium
305 of 337
Application
+4 | -1
If , then is equal to
View answer and explanation
Correct option: C
, for some integer
Option C (, for some integer ) is correct because the argument of a product of complex numbers is the sum of their arguments.
306
Medium
306 of 337
Application
+4 | -1
For complex numbers , and , we write if and . Let be a complex number such that , then
View answer and explanation
Correct option: C
Option C () is correct because, given , the real and imaginary parts of are both non-positive.
307
Medium
307 of 337
Application
+4 | -1
If the roots of unity are then is equal to
View answer and explanation
Correct option: B
-1
Option B (-1) is correct because the sum of the squares of the non-real fifth roots of unity is -1.
308
Medium
308 of 337
Application
+4 | -1
Let and be th roots of unity which subtend a right angle at the origin. Then must be of the form
View answer and explanation
Correct option: D
Option D () is correct because the angle between the nth roots of unity must be a right angle, implying that n is a multiple of 4.
309
Medium
309 of 337
Application
+4 | -1
For any two complex numbers and and any real numbers and , is equal to
View answer and explanation
Correct option: B
Option B () is correct because expanding and simplifying the expression leads to this result.
310
Medium
310 of 337
Application
+4 | -1
Let then is equal to
View answer and explanation
Correct option: C
Option C () is correct because substituting and (where is a cube root of unity) and expanding the product leads to the given expression.
311
Medium
311 of 337
Application
+4 | -1
Locus of point so that , and are collinear, is
View answer and explanation
Correct option: B
a circle
Option B (a circle) is correct because the condition for collinearity leads to an equation that represents a circle in the complex plane.
312
Medium
312 of 337
Application
+4 | -1
Let be the roots of , then the equation whose roots are is
View answer and explanation
Correct option: B
Option B () is correct because the roots can be expressed using Euler's formula, and raising them to the power of n results in a new equation with coefficients involving cos(nφ).
313
Medium
313 of 337
Understanding
+4 | -1
If is a polynomial of degree with rational coefficients and and 5 are three roots of , then the least value of is
View answer and explanation
Correct option: A
5
Option A (5) is correct because complex and irrational roots occur in conjugate pairs, so we must include and as roots, along with 5, and , giving a minimum degree of 5.
314
Medium
314 of 337
Analyzing
+4 | -1
Let . Then is equal to
View answer and explanation
Correct option: B
4
The correct answer is B (4) because it is found by solving the given complex equation and summing the squared magnitudes of the solutions.
315
Medium
315 of 337
Application
+4 | -1
The greatest and the least value of if and are respectively
View answer and explanation
Correct option: A
Option A (31, 19) is correct because the greatest value is the sum of the magnitudes and the least value is the difference of the magnitudes.
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316
Medium
316 of 337
Application
+4 | -1
The modulus of is
View answer and explanation
Correct option: A
Option A () is correct because the modulus of a quotient is the quotient of the moduli, and the modulus of a product is the product of the moduli.
317
Medium
317 of 337
Analyzing
+4 | -1
If , then value of cannot exceed
View answer and explanation
Correct option: A
Option A () is correct because the argument of the given expression is bounded by and , and thus cannot exceed .
318
Medium
318 of 337
Application
+4 | -1
If and are the roots of , then
View answer and explanation
Correct option: B
Option B, , is correct because it is the simplified form of the expression where and are the roots of the given quadratic equation.
319
Medium
319 of 337
Application
+4 | -1
If , then the value of is
View answer and explanation
Correct option: A
1
Option A (1) is correct because by substituting and simplifying, the value of the expression is 1.
320
Medium
320 of 337
Application
+4 | -1
If one vertex of a square whose diagonals intersect at the origin is then the two adjacent vertices are
View answer and explanation
Correct option: A
Option A () is correct because rotating the given vertex by gives the adjacent vertices.
321
Medium
321 of 337
Application
+4 | -1
If for any complex number , then
View answer and explanation
Correct option: A
Option A () is correct because by letting and using the given argument condition, we derive the equation of a circle and find .
322
Medium
322 of 337
Application
+4 | -1
If , then is equal to
View answer and explanation
Correct option: C
Option B () is correct because simplifying the expression using and leads to , so x=0 and y=-2.
323
Medium
323 of 337
Application
+4 | -1
If and , the locus of is
View answer and explanation
Correct option: A
Option C () is correct because by using Vieta's formulas, we can express in terms of m and a, which simplifies to .
324
Medium
324 of 337
Understanding
+4 | -1
If and are two non- zero complex numbers such that , then is equal to
View answer and explanation
Correct option: C
0
Option C is correct because if |z1+z2| = |z1| + |z2|, then z1 and z2 are collinear and point in the same direction, meaning their arguments are equal, so arg(z1) - arg(z2) = 0.
325
Medium
325 of 337
Application
+4 | -1
If and then
View answer and explanation
Correct option: C
Option C () is correct because if the argument of the product of two complex numbers is zero and their magnitudes are equal to 1, then the two numbers are complex conjugates.
326
Medium
326 of 337
Application
+4 | -1
If then is represented by a point lying on
View answer and explanation
Correct option: C
A straight line
The correct answer is A (A straight line) because the real part condition leads to a linear equation in x and y, representing a straight line.
327
Medium
327 of 337
Analyzing
+4 | -1
If and are complex numbers representing the vertices of two triangles such that and where is a complex number, then the two triangles
View answer and explanation
Correct option: B
Are similar
Option B (Are similar) is correct because the given conditions imply that the two triangles have proportional sides and equal angles, thus they are similar.
328
Medium
328 of 337
Application
+4 | -1
If the points and 1 are collinear then lies on
View answer and explanation
Correct option: B
a circle
Option B (a circle) is correct because the collinearity condition leads to an equation of the form |z - c| = r, which represents a circle.
329
Medium
329 of 337
Understanding
+4 | -1
If , then
View answer and explanation
Correct option: B
Option A () is incorrect. The correct answer should be which represents . However, the provided option A is incorrect. The correct option should be B.
330
Medium
330 of 337
Application
+4 | -1
If , then value of cannot exceed
View answer and explanation
Correct option: C
9
Option C (9) is correct because the maximum value of the expression is obtained when the real part of the sum of complex conjugates is minimized, leading to a maximum value of 9.
Revision notes and key takeaways
Review COMPLEX NUMBERS in your textbook or class notes, then use this set to check your understanding.
Showing 301-330 of 337 questions
