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JEE • MATHEMATICS • COMBINATIONS
Combinations practice · Easy
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 181-210 of 236 questions
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181
Easy
181 of 236
Application
+4 | -1
If a polygon has 44 diagonals, then the number of its sides are
View answer and explanation
Correct option: A
11
The correct answer is A (11) because it is the number of sides of a polygon with 44 diagonals, calculated using the formula for the number of diagonals.
182
Easy
182 of 236
Application
+4 | -1
View answer and explanation
Correct option: B
Option B () is correct because it is the simplified form of the given expression after applying the identity multiple times.
183
Easy
183 of 236
Application
+4 | -1
Six points in a plane be joined in all possible ways by indefinite straight lines and if no two of them be coincident or parallel, and no three pass through the same point (with the exception of the original 6 points). The number of distinct points or intersection is equal to
View answer and explanation
Correct option: C
51
Option C (51) is correct because it accounts for the intersections of lines formed by joining the points, subtracting overcounted intersections at the original points, and adding back the original points.
184
Easy
184 of 236
Analyzing
+4 | -1
The value of is :
View answer and explanation
Correct option: A
Option A () is correct because the given expression can be transformed into a binomial coefficient sum, which simplifies to this value.
185
Easy
185 of 236
Application
+4 | -1
From 6 different novels and 3 different dictionaries, 4 novels and 1 dictionary are to be selected and arranged in a row on a shelf so that the dictionary is always in the middle. Then, the number of such arrangements is
View answer and explanation
Correct option: A
atleast 1000
Option A (atleast 1000) is correct because the total number of arrangements is 1080, which is greater than 1000.
186
Easy
186 of 236
Application
+4 | -1
There are 3 sections in a question paper and each section contains 5 questions. A candidate has to answer a total of 5 questions, choosing at least one question from each section. Then the number of ways, in which the candidate can choose the questions, is
View answer and explanation
Correct option: D
2250
Option D (2250) is correct because it correctly counts the number of ways to select 5 questions with at least one from each section, considering the possible distributions of questions across the three sections.
187
Easy
187 of 236
Application
+4 | -1
The number of integers which lie between 1 and and which have the sum of the digits equal to 12, is
View answer and explanation
Correct option: C
6062
Option C (6062) is correct because it is the coefficient of in the expansion of a generating function representing the sum of digits.
188
Easy
188 of 236
Application
+4 | -1
Consider three boxes, each containing 10 balls labelled 1, 2, …, 10. Suppose one ball is randomly drawn from each of the boxes. Denote by the label of the ball drawn from th box, (i = 1, 2, 3). Then, the number of ways in which the balls can be chosen such that is
View answer and explanation
Correct option: B
120
Option B (120) is correct because it's the number of ways to choose 3 distinct numbers from 1 to 10, which is a combination problem.
189
Easy
189 of 236
Application
+4 | -1
Find , if .
View answer and explanation
Correct option: A
1
Option A (1) is correct because given , we find , and .
190
Easy
190 of 236
Application
+4 | -1
The value of is
View answer and explanation
Correct option: A
Option A () is correct because the summation simplifies to a single combination using the identity .
191
Easy
191 of 236
Application
+4 | -1
The results of 21 football matches (win, lose or draw) are to be predicted. The number of forecasts that contain exactly 18 correct results is
View answer and explanation
Correct option: B
Option B () is correct because it calculates the number of ways to choose 18 correct results and then the number of ways to have the remaining 3 results be incorrect.
192
Easy
192 of 236
Application
+4 | -1
There are 10 points in a plane, out of these 6 are collinear. The number of triangles formed by joining these points is
View answer and explanation
Correct option: A
100
Option A (100) is correct because it is the result of subtracting the number of degenerate triangles (formed by collinear points) from the total possible number of triangles.
193
Easy
193 of 236
Application
+4 | -1
The total number of different combinations of letters which can be made from the letters of the word MISSISSIPPI is
View answer and explanation
Correct option: C
149
Option C (149) is correct because it accounts for all possible combinations of the letters in the word MISSISSIPPI, including the option of selecting no letters.
194
Easy
194 of 236
Application
+4 | -1
A person goes for an examination in which there are four papers with a maximum of m marks from each paper. The number of ways in which one can get marks, is
View answer and explanation
Correct option: C
Option C () is correct because it represents the number of ways to obtain 2m marks from four papers, each with a maximum of m marks.
195
Easy
195 of 236
Analyzing
+4 | -1
If the number of ways of selecting cards out of unlimited number of cards bearing the number , so that they cannot be used to write the number 903 is 93 , then is equal to
View answer and explanation
Correct option: C
5
The correct answer is C (5) because by analyzing the conditions under which the cards cannot be used to write the number 903, we find that n = 5.
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196
Easy
196 of 236
Application
+4 | -1
A lady gives a dinner party for six guests. The number of ways in which they may be selected from among ten friends, if two of the friends will not attent the party together, is
View answer and explanation
Correct option: B
140
Option B (140) is correct because it considers the cases where neither, or only one, of the two friends are invited.
197
Easy
197 of 236
Application
+4 | -1
In a cricket championship there are 36 matches. The number of terms, if each plays 1 match with other are
View answer and explanation
Correct option: A
9
Option A (9) is correct because solving the combination equation nC2 = 36 yields n = 9.
198
Easy
198 of 236
Application
+4 | -1
At an election, a voter may vote for any number of candidates, not greater than number to be elected. There are 10 candidates and 4 are to be selected. If a voter votes for atleast one candidate, then number of ways in which he can vote, is
View answer and explanation
Correct option: C
385
Option C (385) is correct because it sums the number of ways to vote for 1, 2, 3, or 4 candidates out of 10.
199
Easy
199 of 236
Application
+4 | -1
The number of ordered pairs of non-negative integers having sum 7596 without any carries is equal to
View answer and explanation
Correct option: B
3360
Option B (3360) is correct because it represents the number of ordered pairs that sum to 7596 without any carries.
200
Easy
200 of 236
Application
+4 | -1
The number of diagonals of a polygon of 20 sides is
View answer and explanation
Correct option: D
170
Option D (170) is correct because it uses the formula for calculating the number of diagonals in a polygon, which is .
201
Easy
201 of 236
Application
+4 | -1
In a club election the number of contestants is one more than the number of maximum candidates for which a voter can vote. If the total number of ways in which a voter can vote be 126, then the number of contestants is
View answer and explanation
Correct option: D
7
Option D (7) is correct because the equation simplifies to , which gives .
202
Easy
202 of 236
Application
+4 | -1
At an electron, a voter may vote for any number of candidates not greater than the number to be elected. There are 10 candidates and 4 are to be elected. If a voter votes for at least one candidate, then the number of ways in which he can vote, is
View answer and explanation
Correct option: B
385
Option B (385) is correct because it sums the number of ways to vote for 1, 2, 3, or 4 candidates out of 10.
203
Easy
203 of 236
Application
+4 | -1
Let be the set of 4 digit number then is equal to
View answer and explanation
Correct option: B
126
Option B (126) is correct because it calculates the number of ways to choose 4 distinct digits from the set {1, 2, 3, 4, 5, 6, 7, 8, 9} where the order is strictly increasing.
204
Easy
204 of 236
Application
+4 | -1
There are 10 points in a plane, out of these 6 are collinear. If is the number of triangles formed by joining these points, then
View answer and explanation
Correct option: B
Option B () is correct because the number of triangles formed is calculated by subtracting the number of collinear point combinations from the total possible combinations.
205
Easy
205 of 236
Application
+4 | -1
Given 6 different toys of green colour, 5 different toys of blue co- lour and 4 different toys of red colour. Combination of toys that can be chosen taking at least one green and one blue toys are
View answer and explanation
Correct option: B
31248
Option B (31248) is correct because it accurately calculates the number of combinations with at least one green and one blue toy.
206
Easy
206 of 236
Application
+4 | -1
There are 5 points on the side , excluding and , of a triangle . Similarly there are 6 points on the side and 7 points on the side of the triangle. The number of triangles, that can be formed using the points as vertices, is:
View answer and explanation
Correct option: B
751
Option B (751) is correct because it calculates the total number of possible triangles from 18 points, subtracting those formed only by points on the same side of the triangle.
207
Easy
207 of 236
Application
+4 | -1
points are chosen on each of the three coplanar lines. The maximum number of triangles formed with vertices at these points is
View answer and explanation
Correct option: D
Option D () is correct because it is the correct expression for the maximum number of triangles formed by the points.
208
Easy
208 of 236
Application
+4 | -1
The number of diagonals in a octagon will be
View answer and explanation
Correct option: B
20
Option A, , is correct because the sum of even-indexed binomial coefficients equals .
209
Easy
209 of 236
Analyzing
+4 | -1
If , then the value of is
View answer and explanation
Correct option: A
3
The correct answer is 3. The problem involves solving two equations derived from combinations and permutations, leading to n=3.
210
Easy
210 of 236
Application
+4 | -1
The number of ways in which a team of eleven players can be selected from 22 players including 2 of them and excluding 4 of them is
View answer and explanation
Correct option: C
Option C () is correct because after including 2 and excluding 4 players, 9 more players must be selected from the remaining 16.
Revision notes and key takeaways
Review COMBINATIONS in your textbook or class notes, then use this set to check your understanding.
Showing 181-210 of 236 questions
