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JEE • MATHEMATICS • COMBINATIONS
Combinations practice · Easy
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 151-180 of 236 questions
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151
Easy
151 of 236
Application
+4 | -1
If , then is equal to
View answer and explanation
Correct option: C
36
Option C (36) is correct because it uses the combination identity to find the value of x.
152
Easy
152 of 236
Application
+4 | -1
The total number of positive integral solutions such that is
View answer and explanation
Correct option: D
30
Option D (30) is correct because it correctly counts the number of positive integral solutions for the given equation.
153
Easy
153 of 236
Application
+4 | -1
Let the number of elements in sets and be five and two respectively. Then the number of subsets of each having at least 3 and at most 6 elements is
View answer and explanation
Correct option: C
792
The correct answer is 792 because it's the sum of the number of subsets of with 3, 4, 5, and 6 elements, calculated using combinations.
154
Easy
154 of 236
Application
+4 | -1
If and , then the value of is equal to
View answer and explanation
Correct option: C
3
Option C (3) is correct because by setting up ratios of consecutive combinations and solving the resulting system of equations, we find that r = 3.
155
Easy
155 of 236
Application
+4 | -1
In a college examination, a candidates is required to answer 6 out of 10 questions which are divided into two sections each containing 5 questions. Further the candidate is not permitted to attempt more than 4 questions from either of the section. The number of ways in which he can make up a choice of 6 questions, is
View answer and explanation
Correct option: A
200
Option A (200) is correct because it sums the ways to choose 4 questions from one section and 2 from the other, and vice versa, along with choosing 3 from each section.
156
Easy
156 of 236
Application
+4 | -1
A father with 8 children takes 3 at a time to the zoological garden, as often as he can without taking the same 3 children together more than once. The number of times he will go to the garden, is
View answer and explanation
Correct option: B
56
Option B (56) is correct because it calculates the number of ways to choose 3 children out of 8, which is a combination problem.
157
Easy
157 of 236
Application
+4 | -1
Consider 26 tangent lines to an ellipse. The lines separate the plane into several regions, some enclosed and others un- bounded. Then the number of unbounded regions is
View answer and explanation
Correct option: B
52
Option B (52) is correct because each tangent line creates two unbounded regions.
158
Easy
158 of 236
Application
+4 | -1
There are 20 lines numbered as . All the odd numbered lines intersect at a point and all the even numbered lines are parallel. Find the maximum number of point of intersections.
View answer and explanation
Correct option: A
101
Option A (101) is correct because with 10 parallel lines and 10 concurrent lines, the maximum number of intersection points is achieved when each parallel line intersects all concurrent lines, plus the single intersection point of the concurrent lines themselves.
159
Easy
159 of 236
Application
+4 | -1
If 7 points out of 12 are in the same straight line, then the number of triangles formed is
View answer and explanation
Correct option: C
185
Option C (185) is correct because we subtract the number of degenerate triangles formed by the collinear points from the total possible triangles.
160
Easy
160 of 236
Understanding
+4 | -1
Consider the following statements.
I. If there are different objects, then , .
II. If there are different objects, then
Choose the correct option.
I. If there are different objects, then , .
II. If there are different objects, then
Choose the correct option.
View answer and explanation
Correct option: B
Both are true
Option B (Both are true) is correct because both statements I and II represent fundamental properties of combinations.
161
Easy
161 of 236
Application
+4 | -1
The number of ways in which one can select three distinct integers between 1 and 30, both inclusive, whose sum is even, is
View answer and explanation
Correct option: D
2030
Option D (2030) is correct because we consider the cases where all three integers are even or one is even and the other two are odd.
162
Easy
162 of 236
Application
+4 | -1
In a Mathematics paper there are three sections containing 4, 5 and 6 questions respectively. From each section 3 questions are to be answered. In how many ways can be selection of questions be made?
View answer and explanation
Correct option: B
800
Option B (800) is correct because it calculates the product of the number of ways to choose 3 questions from each section.
163
Easy
163 of 236
Application
+4 | -1
A box contains two white balls, three black balls and four red balls. In how many ways can three balls be drawn from the box, if at least one black ball is to be included in the draw?
View answer and explanation
Correct option: A
64
Option A (64) is correct because we consider all possible combinations of 3 balls with at least one black ball.
164
Easy
164 of 236
Understanding
+4 | -1
There are 10 lamps in a hall. Each one of them can be switched on independently. The number of ways in which the hall can be illuminated, is
View answer and explanation
Correct option: C
1023
Option C is correct because each lamp has two states (on or off), and we subtract 1 to exclude the case where all lamps are off, resulting in 210 - 1 = 1023.
165
Easy
165 of 236
Application
+4 | -1
A lady given a dinner party for six guest. The number of ways in which they may be selected from among ten friends, if two of the friends will not, attends the party together is
View answer and explanation
Correct option: B
140
Option B (140) is correct because it accounts for the constraint that two friends will not attend the party together.
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166
Easy
166 of 236
Application
+4 | -1
The number of ways of selecting 10 balls from unlimited number of red, black, white and green balls is
View answer and explanation
Correct option: A
286
Option A (286) is correct because it represents the number of non-negative integer solutions to the equation x1 + x2 + x3 + x4 = 10.
167
Easy
167 of 236
Analyzing
+4 | -1
If then equals
View answer and explanation
Correct option: A
100
Option A (100) is correct because after simplifying the summation using combinatorial identities and the formula for the sum of cubes, we find that k = 100.
168
Easy
168 of 236
Application
+4 | -1
The number of ways in which thirty five apples can be distributed among 3 boys so that each can have any number of apples, is
View answer and explanation
Correct option: B
666
Option B (666) is correct because it uses the formula for distributing identical objects among distinct groups, which is .
169
Easy
169 of 236
Application
+4 | -1
The smallest value of satisfying the inequlity is
View answer and explanation
Correct option: D
8
Option D (8) is correct because it is the smallest integer value of x that satisfies the given inequality after simplifying the combination terms.
170
Easy
170 of 236
Application
+4 | -1
In the next world cup of cricket there will be 12 teams, divided equally in two groups. Teams of each group will play a match against each other. From each group 3 top teams will qualify for the next round. In this round each team will play against others once.
Four top teams of this round will qualify for the semi- final round, where each team will play against the others once. Two top teams of this round will go to the final round, where they will play the best of three matches. The minimum number of matches in the next world cup will be
Four top teams of this round will qualify for the semi- final round, where each team will play against the others once. Two top teams of this round will go to the final round, where they will play the best of three matches. The minimum number of matches in the next world cup will be
View answer and explanation
Correct option: B
53
Option B (53) is correct because it sums the matches in each round: group stage, second round, semi-final, and final.
171
Easy
171 of 236
Application
+4 | -1
The maximum number of points of intersection of 6 circles is
View answer and explanation
Correct option: D
30
Option D (30) is correct because each pair of circles can intersect at a maximum of two points, and we need to consider all possible pairs.
172
Easy
172 of 236
Application
+4 | -1
There are 15 points in a plane, no two of which are in a straight line except 4, all of which are in a straight line. The number of triangles that can be formed by using these 15 points is
View answer and explanation
Correct option: C
451
Option C (451) is correct because it calculates the total number of possible triangles minus the number of degenerate triangles formed by the 4 collinear points.
173
Easy
173 of 236
Application
+4 | -1
In a football championship, there were played 153 matches. Every team played one match with each other. The number of teams participating in the championship is
View answer and explanation
Correct option: B
18
Option B (18) is correct because the number of teams is found by solving the combination equation , which results in .
174
Easy
174 of 236
Application
+4 | -1
The total number of ways in which 5 balls of different colours can be distributed among 3 persons so that each person gets atleast one ball, is
View answer and explanation
Correct option: B
150
Option B (150) is correct because it represents the total number of ways to distribute the balls such that each person gets at least one ball, calculated using inclusion-exclusion principle.
175
Easy
175 of 236
Application
+4 | -1
The number of five digit numbers that contain 7 exactly once is
View answer and explanation
Correct option: A
Option A () is correct because it accounts for the placement of the digit 7 in different positions within the five-digit number.
176
Easy
176 of 236
Analyzing
+4 | -1
is a set containing elements. A subset of is chosen. The set is reconstructed by replacing the elements of . A subset of is again chosen, the number of ways of choosing so that is a proper subset of , is
View answer and explanation
Correct option: D
The correct answer is D () because by considering all possible combinations of elements in subsets P and Q and subtracting the cases where their union is not a proper subset of A, we find the number of ways is .
177
Easy
177 of 236
Application
+4 | -1
On the sides of a distinct points (excluding vertices A, B, C) are respectively chosen. The number of triangles that can be constructed using these chosen points as vertices are :
View answer and explanation
Correct option: B
205
Option B (205) is correct because the total number of triangles that can be formed is calculated by subtracting the number of collinear points from the total possible combinations.
178
Easy
178 of 236
Application
+4 | -1
The expression equals
View answer and explanation
Correct option: A
Option A () is correct because the given expression simplifies to this using the identity nCr + nCr-1 = n+1Cr repeatedly.
179
Easy
179 of 236
Application
+4 | -1
All possible two factors products are formed from numbers 1, 2, 3, 4,…,200. The number of factors out of the total obtained which are multiples of 5, is
View answer and explanation
Correct option: B
7180
Option B (7180) is correct because it subtracts the number of two-factor products not divisible by 5 from the total number of two-factor products.
180
Easy
180 of 236
Application
+4 | -1
A parallelogram is cut by two sets of lines parallel to its sides. The number of parallelograms thus formed is
View answer and explanation
Correct option: C
Option C () is correct because each parallelogram is formed by choosing two lines from each of the two sets of (m+2) parallel lines.
Revision notes and key takeaways
Review COMBINATIONS in your textbook or class notes, then use this set to check your understanding.
Showing 151-180 of 236 questions
