Skip to main content
Back to COMBINATIONS

Your Progress

0 / 5 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • COMBINATIONS

Combinations practice · Hard

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
1 Hard
1 of 5
Application +4 | -1
A rectangle of dimension m×nm \times n ( mm and nn being odd) is divided into square of unit length by drawing horizontal and vertical lines. The number of rectangles having side of odd unit length is
View answer and explanation
Correct option: B
((m+1)(n+1)4)2\left(\frac{(m+1)(n+1)}{4}\right)^{2}
Option B (((m+1)(n+1)4)2\left(\frac{(m+1)(n+1)}{4}\right)^{2}) is correct because it represents the number of rectangles with odd side lengths within the given rectangle.
2 Hard
2 of 5
Application +4 | -1
There are two bags each of which contains ' nn ' balls. A man has to select an equal number of balls from both the bags. The number of ways in which a man can choose at least one ball from each bag is
View answer and explanation
Correct option: D
2nCn−1{ }^{2 n} C_n-1
Option D (2nCn−1{}^{2 n} C_n-1) is correct because it represents the number of ways to select an equal number of balls from two bags, each containing 'n' balls, with at least one ball selected from each bag.
3 Hard
3 of 5
Application +4 | -1
The number of solutions of x1+x2+x3=51(x1,x2,x3x_{1}+x_{2}+x_{3}=51\left(x_{1}, x_{2}, x_{3}\right. being odd natural numbers) is
View answer and explanation
Correct option: B
325
Option B (325) is correct because it represents the number of solutions to the equation with odd natural numbers, transformed into a simpler equation.
4 Hard
4 of 5
Application +4 | -1
Number of positive unequal integral solutions of the equation x+y+z=12x+y+z=12 is
View answer and explanation
Correct option: B
42
Option B (42) is correct because it enumerates the unique sets of three unequal positive integers that sum to 12, and then accounts for the permutations of each set.
5 Hard
5 of 5
Analyzing +4 | -1
If ∑i=120(20Ci−120Ci+20Ci−1)3=k21\sum_{i=1}^{20}\left(\frac{{ }^{20} \mathrm{C}_{i-1}}{{ }^{20} \mathrm{C}_{i}+{ }^{20} \mathrm{C}_{i-1}}\right)^{3}=\frac{k}{21}, then kk equals:
View answer and explanation
Correct option: D
100
The correct answer is D (100) because after simplifying the expression inside the summation and using the formula for the sum of cubes of first n natural numbers, we get k = 100.
Revision notes and key takeaways

Review COMBINATIONS in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

  • ✓ This set contains 5 single-correct-answer MCQs on COMBINATIONS.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
0 /5
0✓ 0✗
0% Accuracy
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.