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JEE • CHEMISTRY • SOME BASIC CONCEPTS OF CHEMISTRY
Some basic concepts of chemistry practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 301-330 of 436 questions
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301
Easy
301 of 436
Remembering
+4 | -1
The net charge on ferrous ion is:
View answer and explanation
Correct option: A
Option A () is correct because the ferrous ion is , indicating a +2 charge.
302
Hard
302 of 436
Application
+4 | -1
1 mol each of and will neutralize of of and of and are in the ratio
View answer and explanation
Correct option: D
Option B () is correct because it is the concentration of CO3-2 calculated using the given pH, K1, and K2 values for carbonic acid.
303
Easy
303 of 436
Remembering
+4 | -1
Which represents per cent by weight?
View answer and explanation
Correct option: A
Option A is correct because percent by weight is defined as the weight of the solute divided by the weight of the solution, multiplied by 100.
304
Medium
304 of 436
Application
+4 | -1
If 65.5 g of a metal chloride contains 35.5 g chlorine, then equivalent mass of metal is
View answer and explanation
Correct option: A
30
Option A (30) is correct because the equivalent mass of the metal is calculated using the ratio of masses and equivalent masses of the metal and chlorine.
305
Medium
305 of 436
Application
+4 | -1
Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen according to the equation, under conditions where one mole of gas occupies 24 of solution of produces 3 of . Thus, is :
View answer and explanation
Correct option: A
2.5
Option A (2.5) is correct because the molarity X is calculated based on the volume of oxygen produced from the decomposition of hydrogen peroxide.
306
Medium
306 of 436
Application
+4 | -1
A transition metal forms a volatile chloride which has a vapour density of 94.8 . If it contains of chlorine the formula of the metal chloride will be
View answer and explanation
Correct option: C
Option C () is correct because the valency of the metal is calculated to be 4, leading to the formula .
307
Hard
307 of 436
Application
+4 | -1
The density of solution of sodium chloride is . The molality of the solution will be:
(molar mass, )
(molar mass, )
View answer and explanation
Correct option: C
Option C (2.79 m) is correct because it is calculated using the relationship between molarity, molality, and density.
308
Hard
308 of 436
Remembering
+4 | -1
In the given chemical reaction, colours of the ions, are respectively
View answer and explanation
Correct option: D
green, yellow
Option D (green, yellow) is correct because ions are typically green in solution, while ions are typically yellow.
309
Medium
309 of 436
Application
+4 | -1
50 mL of an aqueous solution of glucose contains molecules. The concentration of solution is:
View answer and explanation
Correct option: D
2.0 M
Option D (2.0 M) is correct because it is the concentration calculated using the number of molecules and volume of the solution.
310
Medium
310 of 436
Application
+4 | -1
Mass of one molecule of glucose is
View answer and explanation
Correct option: D
Option D () is correct because it is calculated by dividing the molar mass of glucose by Avogadro's number.
311
Medium
311 of 436
Analyzing
+4 | -1
For the reaction :
The correct statement(s) is/are
(a) The equivalent mass of is 41.
(b) is the acid salt
(c) is normal salt
(d) 1 mole of is completely neutralized by 1.5 moles of
The correct statement(s) is/are
(a) The equivalent mass of is 41.
(b) is the acid salt
(c) is normal salt
(d) 1 mole of is completely neutralized by 1.5 moles of
View answer and explanation
Correct option: D
a and c are correct
Options a and c are correct because the equivalent mass of is 41, and is a normal salt.
312
Hard
312 of 436
Application
+4 | -1
Chlorofluorocarbons such as and have been linked to ozone depletion in Antarctica. As of 2004, these gases were found in 275 and 605 parts per trillion by volume. What are the concentrations of these gases under conditions typical of Antarctica stratosphere and
View answer and explanation
Correct option: A
Option A () is correct because it correctly calculates the concentrations using the ideal gas law and the given parts per trillion values.
313
Medium
313 of 436
Application
+4 | -1
of will neutralize
View answer and explanation
Correct option: C
of
Option C ( of ) is correct because it is calculated by equating the equivalents of NaOH and H3BO3, considering the n-factor of H3BO3 is 1.
314
Medium
314 of 436
Analyzing
+4 | -1
25 mL of 0.50 solution is added to 50 mL of 0.20 M in acidic solution. Which of the following statements is true?
View answer and explanation
Correct option: B
0.005 mole of are left
The correct answer is B (0.005 mole of are left) because the milliequivalents of exceed those of , leaving excess .
315
Hard
315 of 436
Application
+4 | -1
The number of gram atoms of oxygen present in 0.3 gram mole of is
View answer and explanation
Correct option: B
1.8
Option B (1.8) is correct because it's the number of gram atoms of oxygen calculated from the given moles of the compound.
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316
Hard
316 of 436
Application
+4 | -1
The mineral haematite is . Haematite ore contains unwanted material called gangue in addition of . If of ore contains of , what per cent of ore is ?
View answer and explanation
Correct option: A
Option A (79.4 %) is correct because it accurately calculates the percentage of Fe2O3 in the ore based on the given mass of Fe.
317
Hard
317 of 436
Application
+4 | -1
If the weight of metal oxide is containing of oxygen, the equivalent weight of metal will be
View answer and explanation
Correct option: D
Option D () is correct because it represents the equivalent weight of the metal calculated from the ratio of the weight of the metal to the weight of oxygen multiplied by 8.
318
Medium
318 of 436
Application
+4 | -1
When of acetic acid (density ) is mixed with of water (density ) at a certain temperature, the final solution is found to have a density of The percent change in total volume on mixing is
View answer and explanation
Correct option: A
Option A () is correct because it is the percent change in volume calculated from the initial and final volumes after mixing.
319
Medium
319 of 436
Application
+4 | -1
At NTP 2.24L of a gas weight . The mole of the gas in is :-
View answer and explanation
Correct option: B
0.5
Option B (0.5) is correct because it is the number of moles calculated using the given volume and mass of the gas at NTP.
320
Hard
320 of 436
Application
+4 | -1
If gram of a metal displaces gram of another metal from its salt solution and if the equivalent weights are and respectively then equivalent weight of can be expressed as:
View answer and explanation
Correct option: A
Option A () is correct because it directly applies Faraday's laws of electrolysis, which state that the mass of a substance deposited or dissolved is proportional to its equivalent weight.
321
Hard
321 of 436
Application
+4 | -1
of oxalic acid dihydrate is shaken with active charcoal. The final concentration of the solution after adsorption is . What is the amount of oxalic acid adsorbed per gm of carbon?
View answer and explanation
Correct option: D
Option D () is correct because it is the amount of oxalic acid adsorbed per gram of carbon, calculated from the change in concentration.
322
Medium
322 of 436
Analyzing
+4 | -1
Assertion (A) : In the following half reaction:
Equivalent weight of
Reason (R) : Change in oxidation number of chromium is 3 per atom.
Equivalent weight of
Reason (R) : Change in oxidation number of chromium is 3 per atom.
View answer and explanation
Correct option: D
is false but is true.
Option D is correct because the assertion is false; the equivalent weight is molar mass divided by 6, not 3. The reason is true; the change in oxidation number of chromium is 3 per atom.
323
Medium
323 of 436
Application
+4 | -1
What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene
View answer and explanation
Correct option: C
9.6 kg
Option C (9.6 kg) is correct because it is the calculated mass of oxygen required for the complete combustion of 2.8 kg of ethylene based on stoichiometry.
324
Hard
324 of 436
Application
+4 | -1
What is the mass of molecules of ammonia?
View answer and explanation
Correct option: A
0.85 g
Option A (0.85 g) is correct because it is calculated using the mole concept and Avogadro's number to find the mass of the given number of ammonia molecules.
325
Easy
325 of 436
Analyzing
+4 | -1
An amount of 5 moles of 6 moles of and excess amount of are mixed to produce a final product , according to the following reactions.
What is the maximum moles of which can be produced assuming that the products formed can also be reused in the reactions?
What is the maximum moles of which can be produced assuming that the products formed can also be reused in the reactions?
View answer and explanation
Correct option: C
5 moles
Option C (A is true but R is false) is correct because HBF4 is a strong acid, but the given reaction of B(OH)3 with HF doesn't explain why HBF4 is a strong acid.
326
Medium
326 of 436
Analyzing
+4 | -1
In the following reaction, the equivalent weight of is related to its molecular weight by :
View answer and explanation
Correct option: D
Option D is correct because the n-factor is calculated based on the change in oxidation states of As and S, leading to M/28.
327
Medium
327 of 436
Analyzing
+4 | -1
Assertion (A) : 1 mole of is oxidised by 0.6 mole of in acidic medium.
Reason (R) : oxidises both as well as .
Reason (R) : oxidises both as well as .
View answer and explanation
Correct option: A
Both and are true and is the correct explanation of .
Option A is correct because both the assertion and the reason are true, and the reason correctly explains why 1 mole of requires 0.6 moles of for oxidation in acidic medium.
328
Hard
328 of 436
Analyzing
+4 | -1
Cupric ammonium sulphate was found to contain
water of crystallization by mass. Upon
strongly heating, it gave cupric oxide corresponding
to of starting mass. Find the empirical
formula of cupric ammonium sulphate.
water of crystallization by mass. Upon
strongly heating, it gave cupric oxide corresponding
to of starting mass. Find the empirical
formula of cupric ammonium sulphate.
View answer and explanation
Correct option: A
Option A is correct because the empirical formula is determined by calculating the moles of each component and finding the simplest whole number ratio, which corresponds to CuSO₄⋅(NH₄)₂SO₄⋅6H₂O.
329
Hard
329 of 436
Application
+4 | -1
Mole fraction of solute in an aqueous solution of is If the specific gravity of the solution is then the molarity of the solution is
View answer and explanation
Correct option: A
6.93
Option A (6.93) is correct because the molarity is calculated using the mole fraction, specific gravity, and molar masses of the solute and solvent.
330
Medium
330 of 436
Application
+4 | -1
The element has the following isotopic composition, and . The average atomic mass of the naturally occurring element is
View answer and explanation
Correct option: C
Option C (199 u) is correct because it's calculated as the weighted average of the isotopic masses based on their abundances.
Revision notes and key takeaways
Review SOME BASIC CONCEPTS OF CHEMISTRY in your textbook or class notes, then use this set to check your understanding.
Showing 301-330 of 436 questions
