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JEE • CHEMISTRY • SOLUTIONS

Solutions practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-265 of 265 questions
241 Medium
241 of 265
Remembering +4 | -1
Two solutions of different osmotic pressure. The solution of lower osmotic pressure is called
View answer and explanation
Correct option: C
Hypotonic
Option C (Hypotonic) is correct because a solution with lower osmotic pressure compared to another solution is termed hypotonic.
242 Medium
242 of 265
Application +4 | -1
pH of 0.1 M0.1 \mathrm{~M} monobasic acid solution is found to be 2. Thus its osmotic pressure at T.K\mathrm{T}.\mathrm{K} elvin is:
View answer and explanation
Correct option: B
0.11 ST0.11 \mathrm{~ST}
Option B (0.11 ST) is correct because it correctly calculates the osmotic pressure using the van't Hoff factor and the given concentration and temperature.
243 Medium
243 of 265
Application +4 | -1
The mass of KCl{KCl} required to depress the freezing point of 500 g500 \mathrm{~g} water by 2 K2 \mathrm{~K} is (Kf=1.86, K=39)\left(K_{\mathrm{f}}=1.86, \mathrm{~K}=39\right)
View answer and explanation
Correct option: D
20.03 g20.03 \mathrm{~g}
Option D (20.03 g20.03 \mathrm{~g}) is correct because it's the mass of KCl calculated using the freezing point depression formula, considering the van't Hoff factor.
244 Medium
244 of 265
Analyzing +4 | -1
Assertion (A): The water pouch of instant cold pack for treating athletic injuries breaks when squeezed and NH4NO3\mathrm{NH}_4 \mathrm{NO}_3 dissolves in water to lower the temperature.

Reason (R): Addition of non-volatile solute into solvent results into depression of freezing point of the solvent.
View answer and explanation
Correct option: A
Both A\mathrm{A} and R\mathrm{R} are correct, R\mathrm{R} is the correct explanation of A\mathrm{A}.
The correct answer is A because the dissolution of NH4NO3 is endothermic, lowering the temperature, and this is related to the depression of the freezing point of the solvent (water).
245 Medium
245 of 265
Understanding +4 | -1
A super saturated solution is a metastable state of solution in which solute concentration.
View answer and explanation
Correct option: B
Exceeds than its solubility
Option B (Exceeds than its solubility) is correct because a supersaturated solution contains more solute than it can normally dissolve at a given temperature.
246 Medium
246 of 265
Analyzing +4 | -1
0.1 M NaCl0.1 {~M} \mathrm{~NaCl} and 0.05 M BaCl20.05 {~M} \mathrm{~BaCl}_2 solutions are separated by a semi-permeable membrane in a container. For this system, choose the correct answer.
View answer and explanation
Correct option: B
Water flows from BaCl2\mathrm{BaCl}_2 solution towards NaCl\mathrm{NaCl} solution
Option B (Water flows from BaCl2\mathrm{BaCl}_2 solution towards NaCl\mathrm{NaCl} solution) is correct because the effective concentration of ions is higher in the NaCl solution, causing water to flow towards it.
247 Medium
247 of 265
Understanding +4 | -1
Osmosis of A into solution B will not take place if
View answer and explanation
Correct option: D
Either 1 or 3
Option D (Either 1 or 3) is correct. Osmosis will not occur if A is hypertonic (already has higher concentration) or isotonic (equal concentration) to B.
248 Medium
248 of 265
Application +4 | -1
The vapour pressure of benzene at 80∘C80^\circ C is lowered by 10 mm by dissolving 2g of a non-volatile substance in 78 g of benzene. The vapour pressure of pure benzene at 80∘C80^\circ C is 750 mm. The molecular weight of the substance will be :
View answer and explanation
Correct option: D
148
Option D (148) is correct because the molecular weight of the non-volatile substance is calculated using Raoult's law.
249 Medium
249 of 265
Analyzing +4 | -1
Molarity and molality of a solution of NaOH{NaOH} is calculated. If now temperature of the solution is increased then which of the following statement(s) is/are correct ?

(i) Molarity of solution decreases

(ii) Molality of the solution increases
View answer and explanation
Correct option: B
Statement (i) is correct only
Option B is correct. Molarity decreases with increasing temperature due to the volume expansion of the solution, while molality remains unaffected as it's based on the mass of the solvent.
250 Medium
250 of 265
Analyzing +4 | -1
Relative lowering of vapour pressure of an aqueous solution of 2 mole2 \,mole of binary solute (XY)(X Y) in 3  mol3 \,{~mol} of solvent is 0.5 then select the correct statement among the following
View answer and explanation
Correct option: C
50%50 \% solute is ionized
Option C (50%50 \% solute is ionized) is correct because the van't Hoff factor (i) is 1.5, indicating 50% ionization of the binary solute.
251 Medium
251 of 265
Application +4 | -1
Density of 2.05 M solution of acetic acid in water is 1.02 g/ml. The molality of the solution is:
View answer and explanation
Correct option: B
2.28 mol kg−12.28\,mol\,k{g^{ - 1}}
Option A (11) is correct because the pH is calculated from the concentration of OH−OH^- ions, which is derived from the mass of NaOH per liter.
252 Medium
252 of 265
Understanding +4 | -1
Assertion (A): Observed molecular mass of CaCl2{CaCl}_2 determined by any colligative property is less than ideal molecular mass.

Reason (R): CaCl2{CaCl}_2 gets ionised in water as it is a strong electrolyte.
View answer and explanation
Correct option: A
Both A & R are true, R is the correct explanation of A
Option A (Both A & R are true, R is the correct explanation of A) is correct because CaCl2 dissociates into ions in water, leading to a higher number of particles and a lower observed molecular mass.
253 Medium
253 of 265
Application +4 | -1
The vapour pressure of benzene at 90∘C90^\circ C is 1020 torr. A solution of 5 g of a solute in 58.5 g benzene has vapour pressure 990 torr. The molecular weight of the solute is :
View answer and explanation
Correct option: D
220220
Option D (220) is correct because the calculated molecular weight of the solute using Raoult's law is approximately 220.
254 Medium
254 of 265
Remembering +4 | -1
Enthalpy of solution is:
View answer and explanation
Correct option: C
positive for hydrated salts and negative for
anhydrous salts
Option D (negative for hydrated salts and positive for anhydrous salts) is correct because the enthalpy of solution is generally negative for anhydrous salts and positive for hydrated salts.
255 Medium
255 of 265
Application +4 | -1
For a solution in which CHCl3CHC{l_3} is dissolved in C6H6,{C_6}{H_6}, molality is 0.1 m. Then mole fraction of C6H6,{C_6}{H_6}, in the solution is
View answer and explanation
Correct option: D
0.9922
Option D (0.9922) is correct because it is calculated using the formula relating molality and mole fraction, given the molality of CHCl3 in C6H6.
256 Medium
256 of 265
Application +4 | -1
Vant Hoff’s factor (i) for acetic acid in benzene is (assuming 30%) dimerization of acetic acid in benzene)
View answer and explanation
Correct option: D
0.85
Option D (0.85) is correct because the Van't Hoff factor is calculated based on the degree of dimerization of acetic acid in benzene.
257 Medium
257 of 265
Application +4 | -1
Osmotic pressure of 0.1 M0.1 \,{M} solution of NaCl{NaCl} and Na2SO4{Na}_2 {SO}_4 will be
View answer and explanation
Correct option: C
Osmotic pressure of Na2SO4{Na}_2 {SO}_4 solution will be more than NaCl{NaCl}
Option C (Osmotic pressure of Na2SO4{Na}_2 {SO}_4 solution will be more than NaCl{NaCl}) is correct because Na2SO4{Na}_2 {SO}_4 dissociates into 3 ions, leading to a higher van't Hoff factor and thus greater osmotic pressure compared to NaCl{NaCl} which dissociates into 2 ions.
258 Medium
258 of 265
Analyzing +4 | -1
Assertion: Elevation in boiling point of 0.1MKCl0.1 \mathrm{M} \mathrm{KCl} and 0.1MCaCl20.1 \mathrm{M} \mathrm{CaCl}_2 is same.

Reason: Because colligative properties depends on molarity only.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because the elevation in boiling point depends on the van't Hoff factor (i) and molarity, and the reason incorrectly states that colligative properties depend only on molarity.
259 Medium
259 of 265
Application +4 | -1
The vapor pressure in mm\mathrm{mm} of Hg\mathrm{Hg} of an ideal solution of A\mathrm{A} and B\mathrm{B} at 25∘C25^{\circ} \mathrm{C} is given by pAB=33x+94,p_{\mathrm{AB}}=33 x+94, whereas that of an ideal solution of A\mathrm{A} and C\mathrm{C} at 25∘C25^{\circ} \mathrm{C} is given by pAC=81x+46;p_\text{AC}=81 x+46; xx being mole fraction of A\mathrm{A} in the solution. The vapor pressure of solution containing 2 mol A,3 mol B2 \mathrm{~mol} \mathrm{~A}, 3 \mathrm{~mol} \mathrm{~B} and 4 mol of C\text{4 mol of C} will be
View answer and explanation
Correct option: A
80
Option A (80) is correct because it is calculated using Raoult's Law and the mole fractions of each component in the solution.
260 Medium
260 of 265
Analyzing +4 | -1
Assertion: When two volatile liquids are mixed then vapour pressure of one increases and other decreases.

Reason: Vapour pressure of solution decreases.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option C (The pH of resultant solution becomes less than 6.0 and oxygen gas is liberated) is correct because chlorine reacts with hydrogen peroxide to produce HCl, which lowers the pH, and oxygen gas.
261 Medium
261 of 265
Understanding +4 | -1
Which of the following salts has the same value as of van't Hoff factor (i) as that of K3[Fe(CN)6]{K}_3\left[{Fe}({CN})_6\right] ?
View answer and explanation
Correct option: B
Al(NO3)3{Al}\left({NO}_3\right)_3
Option B (Al(NO3)3{Al}\left({NO}_3\right)_3) is correct because it dissociates into 4 ions, similar to K3[Fe(CN)6]{K}_3\left[{Fe}({CN})_6\right].
262 Medium
262 of 265
Understanding +4 | -1
Van't Hoff factors are x,yx, y and zz in case of association, ionisation and no change, respectively. Their increasing order is
View answer and explanation
Correct option: D
x<z<yx < z < y
Option D (x<z<yx < z < y) is correct because association decreases the Van't Hoff factor, ionization increases it, and no change leaves it at 1.
263 Medium
263 of 265
Analyzing +4 | -1
The freezing point depression of 0.1 molal solution of acetic acid in benzene is 0.256 K.kf0.256 \mathrm{~K} . k_f for benzene is 5.12 K kg mol−15.12 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}. What conclusion can you draw about the molecular state of acetic acid in benzene?
View answer and explanation
Correct option: A
Acetic acid is doubly associated
Option A (Acetic acid is doubly associated) is correct because the van't Hoff factor is 0.5, indicating dimerization of acetic acid in benzene.
264 Medium
264 of 265
Application +4 | -1
The vapour pressure of two liquids PP and QQ are 80 and 60 torr resp. The total vapour pressure of solution obtained by mixing 3 mole of PP and 2 mol of QQ would be
View answer and explanation
Correct option: D
72 torr
Option D (72 torr) is correct because the total vapor pressure is calculated using Raoult's law, considering the mole fractions and vapor pressures of both liquids.
265 Medium
265 of 265
Application +4 | -1
Essential quantity of ammonium sulphate taken for preparation of 1 molar solution in 2 litres is
View answer and explanation
Correct option: B
264 gm264 \,{gm}
Option B (264 gm264 \,{gm}) is correct because it's the mass calculated using the molarity, molecular weight, and volume of the solution.
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