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JEE • CHEMISTRY • SOLUTIONS

Solutions practice · Mixed difficulty

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421 Medium
421 of 460
Analyzing +4 | -1
Molarity and molality of a solution of NaOH{NaOH} is calculated. If now temperature of the solution is increased then which of the following statement(s) is/are correct ?

(i) Molarity of solution decreases

(ii) Molality of the solution increases
View answer and explanation
Correct option: B
Statement (i) is correct only
Option B is correct. Molarity decreases with increasing temperature due to the volume expansion of the solution, while molality remains unaffected as it's based on the mass of the solvent.
422 Medium
422 of 460
Analyzing +4 | -1
Relative lowering of vapour pressure of an aqueous solution of 2 mole2 \,mole of binary solute (XY)(X Y) in 3  mol3 \,{~mol} of solvent is 0.5 then select the correct statement among the following
View answer and explanation
Correct option: C
50%50 \% solute is ionized
Option C (50%50 \% solute is ionized) is correct because the van't Hoff factor (i) is 1.5, indicating 50% ionization of the binary solute.
423 Medium
423 of 460
Application +4 | -1
Density of 2.05 M solution of acetic acid in water is 1.02 g/ml. The molality of the solution is:
View answer and explanation
Correct option: B
2.28 mol kg−12.28\,mol\,k{g^{ - 1}}
Option A (11) is correct because the pH is calculated from the concentration of OH−OH^- ions, which is derived from the mass of NaOH per liter.
424 Medium
424 of 460
Understanding +4 | -1
Assertion (A): Observed molecular mass of CaCl2{CaCl}_2 determined by any colligative property is less than ideal molecular mass.

Reason (R): CaCl2{CaCl}_2 gets ionised in water as it is a strong electrolyte.
View answer and explanation
Correct option: A
Both A & R are true, R is the correct explanation of A
Option A (Both A & R are true, R is the correct explanation of A) is correct because CaCl2 dissociates into ions in water, leading to a higher number of particles and a lower observed molecular mass.
425 Medium
425 of 460
Application +4 | -1
The vapour pressure of benzene at 90∘C90^\circ C is 1020 torr. A solution of 5 g of a solute in 58.5 g benzene has vapour pressure 990 torr. The molecular weight of the solute is :
View answer and explanation
Correct option: D
220220
Option D (220) is correct because the calculated molecular weight of the solute using Raoult's law is approximately 220.
426 Easy
426 of 460
Analyzing +4 | -1
Assertion (A): Isotonic solutions must have same elevation in boiling point.

Reason (R): Osmotic pressure, π=iCRT\pi=i C R T
View answer and explanation
Correct option: D
A is false, R is true
Option D (A is false, R is true) is correct because isotonic solutions have the same osmotic pressure, not necessarily the same elevation in boiling point, and the reason correctly states the formula for osmotic pressure.
427 Medium
427 of 460
Remembering +4 | -1
Enthalpy of solution is:
View answer and explanation
Correct option: C
positive for hydrated salts and negative for
anhydrous salts
Option D (negative for hydrated salts and positive for anhydrous salts) is correct because the enthalpy of solution is generally negative for anhydrous salts and positive for hydrated salts.
428 Medium
428 of 460
Application +4 | -1
For a solution in which CHCl3CHC{l_3} is dissolved in C6H6,{C_6}{H_6}, molality is 0.1 m. Then mole fraction of C6H6,{C_6}{H_6}, in the solution is
View answer and explanation
Correct option: D
0.9922
Option D (0.9922) is correct because it is calculated using the formula relating molality and mole fraction, given the molality of CHCl3 in C6H6.
429 Hard
429 of 460
Analyzing +4 | -1
A 10%10 \% (mass/mass) solution of cane-sugar undergoes partial conversion into glucose and fructose to show inversion of cane-sugar as:
 Sucrose + Water ⟶ Glucose + Fructose. \text { Sucrose + Water } \longrightarrow \text { Glucose + Fructose. }

If the solution boils at 100.27∘C100.27^{\circ} {C} at this state, calculate the average mass of the dissolved material. What fraction of the sugar has inverted? Given Kb{K}_b for H2O{H}_2 {O} is 0.512 K mol−1 kg0.512 {~K} {~mol}^{-1} {~kg}.
View answer and explanation
Correct option: A
210.7
Option A (210.7) is correct because it is obtained by calculating the average mass of the dissolved material using the colligative properties formula and the degree of inversion.
430 Easy
430 of 460
Application +4 | -1
The vapour pressure of water at room temperature is lowered by 5%5 \% on dissolving a non-volatile solute in it. The molality of the solution is
View answer and explanation
Correct option: D
2.92
Option D (2.92) is correct because it is calculated using the relative lowering of vapor pressure formula and Raoult's law.
431 Medium
431 of 460
Application +4 | -1
Vant Hoff’s factor (i) for acetic acid in benzene is (assuming 30%) dimerization of acetic acid in benzene)
View answer and explanation
Correct option: D
0.85
Option D (0.85) is correct because the Van't Hoff factor is calculated based on the degree of dimerization of acetic acid in benzene.
432 Hard
432 of 460
Application +4 | -1
The vapour pressure of chloroform (CHCl3)\left(\mathrm{CHCl}_3\right) and dichloromethane (CH2Cl2)\left(\mathrm{CH}_2 \mathrm{Cl}_2\right) at 298 K298 \mathrm{~K} is 200 mmHg200 \mathrm{~mm} \mathrm{Hg} and 415 mmHg415 \mathrm{~mm} \mathrm{Hg}, respectively. If a solution is prepared by mixing 25.5 g25.5 \mathrm{~g} of CHCl3\mathrm{CHCl}_3 and 40 g40 \mathrm{~g} of CH2Cl2\mathrm{CH}_2 \mathrm{Cl}_2 at 298 K298 \mathrm{~K}, calculate the mole fractions of chloroform in vapour phase.
View answer and explanation
Correct option: A
0.180.18
Option A (0.18) is correct because it is calculated using Raoult's Law and Dalton's Law to find the mole fraction of chloroform in the vapor phase.
433 Medium
433 of 460
Application +4 | -1
Osmotic pressure of 0.1 M0.1 \,{M} solution of NaCl{NaCl} and Na2SO4{Na}_2 {SO}_4 will be
View answer and explanation
Correct option: C
Osmotic pressure of Na2SO4{Na}_2 {SO}_4 solution will be more than NaCl{NaCl}
Option C (Osmotic pressure of Na2SO4{Na}_2 {SO}_4 solution will be more than NaCl{NaCl}) is correct because Na2SO4{Na}_2 {SO}_4 dissociates into 3 ions, leading to a higher van't Hoff factor and thus greater osmotic pressure compared to NaCl{NaCl} which dissociates into 2 ions.
434 Hard
434 of 460
Application +4 | -1
The distribution coefficient of I2{\mathrm{I}_2} in between CCl4\mathrm{CC}{\mathrm{l}_4} and H2O{\mathrm{H}_2}\mathrm{O} is 85 in favour of CCl4\mathrm{CC}{\mathrm{l}_4} at 25∘C25^\circ \mathrm{C}. If solubility of I2{\mathrm{I}_2} in H2O{\mathrm{H}_2}\mathrm{O} at 25∘C25^\circ \mathrm{C} is 0.33 g litre−1,the  solubility  of I2\mathrm{litr}{\mathrm{e}^{ - 1}},\mathrm{the \;solubility\; of}\,{\mathrm{I}_2} in CCl4\mathrm{CC}{\mathrm{l}_4} is ……..g litre−1\mathrm{litr}{\mathrm{e}^{ - 1}}.
View answer and explanation
Correct option: A
28.05
Option A (28.05) is correct because, using the distribution coefficient formula, the solubility of I2 in CCl4 is calculated to be 28.05 g/L.
435 Hard
435 of 460
Analyzing +4 | -1
ΔTf/Kf\Delta T_f / K_f has the same value of 1 mol kg−11 \mathrm{~mol} \mathrm{~kg}^{-1} for 8%8 \% AB2A B_2 and 10%A2B10 \% A_2 B by mass of solvent, both AB2A B_2 and A2BA_2 B being non- electrolytes. Atomic masses of AA and BB will be respectively
View answer and explanation
Correct option: C
40,20
Option C (40,20) is correct because solving the simultaneous equations derived from the molality formula yields the atomic masses of A and B as 40 and 20 respectively.
436 Hard
436 of 460
Application +4 | -1
The distribution coefficient of I2{\mathrm{I}_2} in between CCl4\mathrm{CC}{\mathrm{l}_4} and H2O{\mathrm{H}_2}\mathrm{O} is 85 in favour of CCl4\mathrm{CC}{\mathrm{l}_4} at 25∘C25^\circ \mathrm{C}. If solubility of I2{\mathrm{I}_2} in H2O{\mathrm{H}_2}\mathrm{O} at 25∘C25^\circ \mathrm{C} is 0.33 g litre−1,the  solubility  of I2\mathrm{litr}{\mathrm{e}^{ - 1}},\mathrm{the \;solubility\; of}\,{\mathrm{I}_2} in CCl4\mathrm{CC}{\mathrm{l}_4} is ……..g litre−1\mathrm{litr}{\mathrm{e}^{ - 1}}.
View answer and explanation
Correct option: A
28.05
Option A (28.05) is correct because, using the distribution coefficient formula, the solubility of I2 in CCl4 is calculated to be 28.05 g/L.
437 Hard
437 of 460
Application +4 | -1
The elevation in boiling point of a solution of 13.44 g of CuCl2\mathrm{CuC}{\mathrm{l}_2} in 1 kg of water using the following information will be (molecular weight of CuCl2=134.4  and  kb=0.52  Km−1)\mathrm{CuC}{\mathrm{l}_2} = 134.4\;and\;{k_b} = 0.52\;K{m^{ - 1}})
View answer and explanation
Correct option: A
0.160.16
Option A (0.16) is correct because it is the elevation in boiling point calculated using the van't Hoff factor and molality.
438 Easy
438 of 460
Analyzing +4 | -1
Maximum freezing point will be for 1 molal solution, assuming equal ionization in each case:
View answer and explanation
Correct option: D
[Fe(H2O)3Cl3]⋅3H2O\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_3 \mathrm{Cl}_3\right] \cdot 3 \mathrm{H}_2 \mathrm{O}
The correct answer is D because [Fe(H2O)3Cl3]⋅3H2O\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_3 \mathrm{Cl}_3\right] \cdot 3 \mathrm{H}_2 \mathrm{O} will give the least number of ions in solution, resulting in the smallest depression in freezing point and thus the maximum freezing point.
439 Medium
439 of 460
Analyzing +4 | -1
Assertion: Elevation in boiling point of 0.1MKCl0.1 \mathrm{M} \mathrm{KCl} and 0.1MCaCl20.1 \mathrm{M} \mathrm{CaCl}_2 is same.

Reason: Because colligative properties depends on molarity only.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because the elevation in boiling point depends on the van't Hoff factor (i) and molarity, and the reason incorrectly states that colligative properties depend only on molarity.
440 Hard
440 of 460
Analyzing +4 | -1
Two components A and B form an ideal solution. The mole fractions of AA and BB in ideal solution are XAX_A and XBX_B, while that of in vapour phase, these components have their mole fractions as YA\mathrm{Y}_{\mathrm{A}} and YB\mathrm{Y}_{\mathrm{B}}. Then, the slope and intercept of plot of 1YA\frac{1}{\mathrm{Y}_{\mathrm{A}}} vs. 1XA\frac{1}{\mathrm{X}_{\mathrm{A}}} will be:
View answer and explanation
Correct option: B
PBoPAo,PAo−PBoPAo\frac{\mathrm{P}_{\mathrm{B}}^{\mathrm{o}}}{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}}, \frac{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}-\mathrm{P}_{\mathrm{B}}^{\mathrm{o}}}{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}}
The correct answer is B (PBoPAo,PAo−PBoPAo\frac{\mathrm{P}_{\mathrm{B}}^{\mathrm{o}}}{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}}, \frac{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}-\mathrm{P}_{\mathrm{B}}^{\mathrm{o}}}{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}}) because the equation derived from Raoult's law and Dalton's law of partial pressures gives these slope and intercept values.
441 Medium
441 of 460
Application +4 | -1
The vapor pressure in mm\mathrm{mm} of Hg\mathrm{Hg} of an ideal solution of A\mathrm{A} and B\mathrm{B} at 25∘C25^{\circ} \mathrm{C} is given by pAB=33x+94,p_{\mathrm{AB}}=33 x+94, whereas that of an ideal solution of A\mathrm{A} and C\mathrm{C} at 25∘C25^{\circ} \mathrm{C} is given by pAC=81x+46;p_\text{AC}=81 x+46; xx being mole fraction of A\mathrm{A} in the solution. The vapor pressure of solution containing 2 mol A,3 mol B2 \mathrm{~mol} \mathrm{~A}, 3 \mathrm{~mol} \mathrm{~B} and 4 mol of C\text{4 mol of C} will be
View answer and explanation
Correct option: A
80
Option A (80) is correct because it is calculated using Raoult's Law and the mole fractions of each component in the solution.
442 Medium
442 of 460
Analyzing +4 | -1
Assertion: When two volatile liquids are mixed then vapour pressure of one increases and other decreases.

Reason: Vapour pressure of solution decreases.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option C (The pH of resultant solution becomes less than 6.0 and oxygen gas is liberated) is correct because chlorine reacts with hydrogen peroxide to produce HCl, which lowers the pH, and oxygen gas.
443 Medium
443 of 460
Understanding +4 | -1
Which of the following salts has the same value as of van't Hoff factor (i) as that of K3[Fe(CN)6]{K}_3\left[{Fe}({CN})_6\right] ?
View answer and explanation
Correct option: B
Al(NO3)3{Al}\left({NO}_3\right)_3
Option B (Al(NO3)3{Al}\left({NO}_3\right)_3) is correct because it dissociates into 4 ions, similar to K3[Fe(CN)6]{K}_3\left[{Fe}({CN})_6\right].
444 Easy
444 of 460
Understanding +4 | -1
Which of the following is correct for a solution showing positive deviations from Raoult's law?
View answer and explanation
Correct option: A
ΔV=+ve,ΔH=+ve\Delta \mathrm{V}=+\mathrm{ve}, \Delta \mathrm{H}=+\mathrm{ve}
Option A (ΔV=+ve,ΔH=+ve\Delta \mathrm{V}=+\mathrm{ve}, \Delta \mathrm{H}=+\mathrm{ve}) is correct because for solutions showing positive deviations from Raoult's law, the volume and enthalpy changes upon mixing are positive, indicating weaker intermolecular forces in the solution compared to the pure components.
445 Easy
445 of 460
Understanding +4 | -1
Van’t Hoff factor more than unity indicates that the solute in solution has
View answer and explanation
Correct option: A
Dissociated
Option A (Dissociated) is correct because a Van't Hoff factor greater than 1 indicates that the number of particles in solution has increased due to dissociation of the solute.
446 Hard
446 of 460
Application +4 | -1
Osmotic pressure of 3%3 \% aqueous solution of a non-volatile, non-electrolyte solute AA at 298 K298 \mathrm{~K} is 3.632 atm3.632 \mathrm{~atm}. Thus, its vapour pressure is ( pH2O∘=23.7 mmp_{\mathrm{H}_2 \mathrm{O}}^{\circ}=23.7 \mathrm{~mm} at 298 K298 \mathrm{~K} )
View answer and explanation
Correct option: A
23.64 mm
Option A (23.64 mm) is correct because it is the vapor pressure calculated using Raoult's law and the osmotic pressure to find the molar mass of the solute.
447 Easy
447 of 460
Application +4 | -1
What is the total number of moles of H2SO4{H_2}S{O_4} needed to prepare 5.0  L5.0\;L of a 2.0  M2.0\;M solution of H2SO4{H_2}S{O_4} ?
View answer and explanation
Correct option: C
10
Option C (10) is correct because the number of moles is calculated by multiplying the molarity of the solution by its volume in liters: 2.0 M * 5.0 L = 10 moles.
448 Hard
448 of 460
Application +4 | -1
Partition coefficient of benzoic acid-ether-water in favour of ether is 2. A solution containing 8 g/litre benzoic acid in ether layer is shaken with 2 litre water. The concentration of acid in water layer is :
View answer and explanation
Correct option: B
2
Option B (2) is correct because the concentration of acid in the water layer is calculated using the partition coefficient formula.
449 Medium
449 of 460
Understanding +4 | -1
Van't Hoff factors are x,yx, y and zz in case of association, ionisation and no change, respectively. Their increasing order is
View answer and explanation
Correct option: D
x<z<yx < z < y
Option D (x<z<yx < z < y) is correct because association decreases the Van't Hoff factor, ionization increases it, and no change leaves it at 1.
450 Hard
450 of 460
Application +4 | -1
What is the mass ratio of ethylene glycol (C2H6O2\left(\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}_{2}\right., molar mass =62 g/mol=62 \, \mathrm{g} / \mathrm{mol} ) required for making 500 g500 \, \mathrm{g} of 0.25 molal aqueous solution and 250 mL250 \, \mathrm{mL} of 0.25 molal aqueous solution?
View answer and explanation
Correct option: A
2:12: 1
Option A (2:1) is correct because the mass ratio is determined by calculating the mass of ethylene glycol in each solution and then finding the ratio.
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