Solutions practice · Mixed difficulty

Two solvents '$A$' and '$B$' have $K_{\mathrm{f}}$ values $1.86$ and $2.79 \mathrm{~K} \mathrm{~mol}^{-1} \mathrm{~kg},$ respectively. A given amount of a substance when dissolved in $500 \mathrm{~g}$ of '$A$' completely dimerizes and when the same amount of the substance is dissolved in $500 \mathrm{~g}$ of '${B}$', the solute undergoes trimerization. The ratio of observed lowering of freezing point in two cases is

The amalgam of mercury in sodium is an example of

The increase in boiling point of a solution containing 0.6 g urea in 200 g water is $0.50^\circ \mathrm{C}$ .Find the molal elevation constant.

The reverse of fusion is freezing and it is :

What is the molality of a solution which contains $18 {~g}$ of glucose $\left({C}_6 {H}_{12} {O}_6\right)$ in $250 {~g}$ of water

Select the incorrect statement :

Boiling point of chloroform was raised by $0.323 \mathrm{~K}$, when $0.5143 \mathrm{~g}$ of anthracence was dissolved in its $35 \mathrm{~g}$. Molecular mass of anthracence is $\left({K}_{{b}}\right.$ for $\left.{CHCl}_3=3.9 \, \mathrm{k}-\mathrm{kg}-\mathrm{mol}^{-1}\right)$

An ideal solution was found to have a vapour pressure of 80 torr when the mole fraction of a non-volatile solute was $0.2.$ What would be the vapour pressure of the pure solvent at the same temperature?

The solution containing 4.0 g of PVC in 1 L of
dioxane was found to have osmotic pressure of
0.006 atm at 300 K. The molecular mass of the
polymer PVC is

Which of the following has minimum freezing point?

$1.0 \mathrm{~g}$ of a mono basic acid $\mathrm{HA}$ in $100 \mathrm{~gm}$ water lowers the freezing point by $0.155 \mathrm{~K}$. If 0.75 gm of same acid requires $25 \mathrm{ml}$ of $\mathrm{N} / 5 \mathrm{NaOH}$ solution for complete neutralization then % degree of ionization of acid is $\left(K_f\left(H_2 \mathrm{O}\right)=1.86 \mathrm{~kg} \mathrm{~mol}^{-1}\right)$

Which pair will not be isotonic

What will be the molarity of a $200 \mathrm{~mL}$ solution containing $1.2 \mathrm{~g}$ of urea?

If $0.1 \mathrm{~M}$ solution of ${NaCl}$ has same osmotic pressure as $0.1 \mathrm{~M}$ solution of ${CaCl}_2,$ then the degree of dissociation of ${CaCl}_2$ will be

The amount of solute (molar mass $60 \mathrm{~g} \mathrm{~mol}^{-1}$) that must be added to $180 \mathrm{~g}$ of water so that the vapour pressure of water is lowered by $10 \%$ is

Two solutions of different osmotic pressure. The solution of lower osmotic pressure is called

The vapour pressure $(VP)$ of a dilute solution of non-volatile solute is $P$ and the $VP$ of pure solvent is ${P_0}$, the lowering of the $VP$ is :

pH of $0.1 \mathrm{~M}$ monobasic acid solution is found to be 2. Thus its osmotic pressure at $\mathrm{T}.\mathrm{K}$ elvin is:

A thermometer which can be used only for accurate measurement of small differences in temperature is known as a:

The mass of ${KCl}$ required to depress the freezing point of $500 \mathrm{~g}$ water by $2 \mathrm{~K}$ is $\left(K_{\mathrm{f}}=1.86, \mathrm{~K}=39\right)$

Assertion (A): The water pouch of instant cold pack for treating athletic injuries breaks when squeezed and $\mathrm{NH}_4 \mathrm{NO}_3$ dissolves in water to lower the temperature.

Reason (R): Addition of non-volatile solute into solvent results into depression of freezing point of the solvent.

A super saturated solution is a metastable state of solution in which solute concentration.

An aqueous solution is 1.0 molal in KI. Which change will cause the vapour pressure of solution to increase :

$0.1 {~M} \mathrm{~NaCl}$ and $0.05 {~M} \mathrm{~BaCl}_2$ solutions are separated by a semi-permeable membrane in a container. For this system, choose the correct answer.

A solute is soluble in two immiscible liquids which are present in a mixture. The concentration of the solute in the upper layer will be :

Osmosis of A into solution B will not take place if

Which has the minimum freezing point?

The vapour pressure of benzene at $80^\circ C$ is lowered by 10 mm by dissolving 2g of a non-volatile substance in 78 g of benzene. The vapour pressure of pure benzene at $80^\circ C$ is 750 mm. The molecular weight of the substance will be :

The solubility of a solid in a liquid depends on :

A dry air is passed through the solution, containing the $10 \mathrm{~g}$ of solute and $90 \mathrm{~g}$ of water and then it is passed through pure water. There is the depression in weight of solution by $2.5 \mathrm{~g}$ and in weight of pure solution by $0.05 \mathrm{~g}$. Calculate the molecular weight of solute.