Skip to main content
Back to SOLID STATE

Your Progress

0 / 199 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • CHEMISTRY • SOLID STATE

Solid state practice · Mixed difficulty

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 181-199 of 199 questions
181 Easy
181 of 199
Understanding +4 | -1
Which of the following statements is not true?
View answer and explanation
Correct option: C
In calcium fluoride structure, coordination number of Ca2+Ca^{2+} is 4
Option C (In calcium fluoride structure, coordination number of Ca2+Ca^{2+} is 4) is correct because the coordination number of Ca2+Ca^{2+} in CaF2CaF_2 is 8, not 4.
182 Easy
182 of 199
Understanding +4 | -1
Ionic solids are characterised by :
View answer and explanation
Correct option: D
Solubility in polar solvents
Option D (Solubility in polar solvents) is correct because ionic solids dissolve in polar solvents due to ion-dipole interactions.
183 Medium
183 of 199
Analyzing +4 | -1
Which of the following statements is/are not true?
View answer and explanation
Correct option: D
Non – stoichiometric defects do not alter the density of the solid
Option D (Non – stoichiometric defects do not alter the density of the solid) is not true because non-stoichiometric defects involve either excess metal ions or metal deficiencies, which *do* alter the density of the solid.
184 Medium
184 of 199
Application +4 | -1
In a solid ′AB′'AB' having the NaCl structure ′A′'A' atoms occupy the corners of the cubic unit cell. If all the face centred atoms along one of the axes are removed then the resultant stoichiometry of the solid is
View answer and explanation
Correct option: C
A3B4{A_3}{B_4}
The correct answer is A (13.15 M13.15 \mathrm{~M}) because it is calculated using the density, percentage strength, and molar mass of HCl.
185 Medium
185 of 199
Remembering +4 | -1
The percentages of void space for simple cubic, body centered cubic and hexagonal close packed arrangement respectively are
View answer and explanation
Correct option: A
48,32,26
Option A (48,32,26) is correct because the percentages of void space for simple cubic, body-centered cubic, and hexagonal close-packed arrangements are approximately 48%, 32%, and 26%, respectively.
186 Easy
186 of 199
Understanding +4 | -1
Among the following which is the best description of water in the solid phase?
View answer and explanation
Correct option: B
Molecular solid
Option B (Molecular solid) is correct because ice (solid water) consists of individual water molecules held together by intermolecular forces (hydrogen bonds), which is characteristic of molecular solids.
187 Easy
187 of 199
Remembering +4 | -1
Which of the following is not a crystalline solid?
View answer and explanation
Correct option: C
Glass
Option C (Glass) is correct because glass lacks a long-range ordered structure and is therefore an amorphous solid, unlike the other crystalline options.
188 Medium
188 of 199
Understanding +4 | -1
What is the coordination number of sodium in Na2ON{a_2}O ?
View answer and explanation
Correct option: B
4
Option B (4) is correct because in Na2ON{a_2}O, each Na+N{a^+} ion is coordinated to 4 oxide ions (O2−O^{2-}).
189 Medium
189 of 199
Understanding +4 | -1
Assertion (A): Stoichiometric compounds obey the law of constant composition.

Reason (R): Schottky and Frenkel defects are observed in stoichiometric compounds.
View answer and explanation
Correct option: B
Both (A) and (R) are correct but (R) is not the correct explanation of (A)
Option B is correct because both the assertion and reason are true, but the reason doesn't explain the assertion. Stoichiometric compounds maintain a fixed ratio of elements, and Schottky/Frenkel defects don't change this ratio, but they are not the *reason* for the law of constant composition.
190 Easy
190 of 199
Remembering +4 | -1
For orthorhombic system axial ratios are a≠b≠ca \ne b \ne c and the axial angles are
View answer and explanation
Correct option: B
α=β=γ=900\alpha = \beta = \gamma = {90^0}
Option B (α=β=γ=900\alpha = \beta = \gamma = {90^0}) is correct because the orthorhombic crystal system has axial ratios a≠b≠ca \ne b \ne c and all axial angles are equal to 90 degrees.
191 Medium
191 of 199
Application +4 | -1
If NaCl\mathrm{NaCl} is doped with 10−3{10^{ - 3}} mol % SrCl2\mathrm{SrC}{\mathrm{l}_2}, then the concentration of cation vacancies will be
View answer and explanation
Correct option: A
1×10−3mol%1 \times {10^{ - 3}}mol\%
Option A (1×10−3mol%1 \times {10^{ - 3}}mol\%) is correct because each SrCl2 introduces one cation vacancy.
192 Easy
192 of 199
Remembering +4 | -1
Which one of the following is a covalent crystal?
View answer and explanation
Correct option: C
Quartz
Option C (Quartz) is correct because Quartz (SiO2\mathrm{SiO}_2) forms a giant network of covalently bonded atoms, making it a covalent crystal.
193 Hard
193 of 199
Analyzing +4 | -1
Assertion (A): If the length of the unit cell of LiClLiCl having NaCl{NaCl} structure is 5.14  A∘,5.14\,\,\mathop {\text{A}}\limits^ \circ , the ionic radius of ion is 4.82  A∘.4.82 \,\,\mathop {\text{A}}\limits^ \circ.

Reason (R): Action-anion contact is retained in LiCl{LiCl} structure because anions constitute the lattice.
View answer and explanation
Correct option: A
Both (A) and (R) are correct and (R) is the correct explanation of (A)
Option A (Both (A) and (R) are correct and (R) is the correct explanation of (A)) is correct because the assertion is derived from the anion-anion contact in the LiCl structure.
194 Easy
194 of 199
Remembering +4 | -1
The resistance of mercury becomes almost zero at :
View answer and explanation
Correct option: A
4K4\mathrm{ }K
Option A (4K4\mathrm{ }K) is correct because mercury becomes a superconductor at approximately 4K, meaning its resistance drops to almost zero.
195 Medium
195 of 199
Analyzing +4 | -1
(Ag+Pb)alloy  →Zinc     is     addedMelt     and\left( {Ag + Pb} \right)\mathrm{alloy}\,\,\xrightarrow[{\mathrm{Zinc}\,\,\,\,\,\mathrm{is}\,\,\,\,\,\mathrm{added}}]{{\mathrm{Melt}\,\,\,\,\,\mathrm{and}}} ; (Ag+Pb+Zn)melt→Cool       →Layer    YLayer    X\left( {Ag + Pb + Zn} \right)\mathrm{melt}\xrightarrow[{}]{{\mathrm{Cool}}}\,\,\,\,\,\,\,\xrightarrow[{\mathrm{Layer}\,\,\,\,\mathrm{Y}}]{{\mathrm{Layer}\,\,\,\,\mathrm{X}}}
Select correct statement based on above scheme.
View answer and explanation
Correct option: D
All are correct answer.
Option D (All are correct answer.) is correct because zinc and lead are immiscible in the molten state, forming separate layers, and silver is soluble in both zinc and lead.
196 Medium
196 of 199
Remembering +4 | -1
The co – ordination number for the simple, FCC and BCC lattices are respectively
View answer and explanation
Correct option: D
6, 12, 2008
Option D (6, 12, 8) is correct because the coordination numbers for simple cubic, FCC (face-centered cubic), and BCC (body-centered cubic) lattices are 6, 12, and 8, respectively.
197 Easy
197 of 199
Remembering +4 | -1
The structure of CsCl\mathrm{CsCl} crystal is :
View answer and explanation
Correct option: A
Body centred cubic lattice
Option A (Body centred cubic lattice) is correct because the CsCl crystal structure is a body-centered cubic lattice.
198 Medium
198 of 199
Analyzing +4 | -1
Assertion (A): Covalent crystal have the higher melting point.

Reason (R): Covalent bonds are stronger than ionic bonds.
View answer and explanation
Correct option: C
(A) is correct but (R) is not correct
Option C is correct. Covalent crystals have high melting points, but the reason that covalent bonds are stronger than ionic bonds is incorrect. The network structure is the main reason.
199 Medium
199 of 199
Application +4 | -1
A compound CuCl\mathrm{CuCl} has face centred cubic structure. Its density is 3.4  g  cm−3\mathrm{3}\mathrm{.4}\;\mathrm{g}\;\mathrm{c}{\mathrm{m}^{ - 3}}. The length of unit cell is :
View answer and explanation
Correct option: A
5.783A∘5.783\mathop \mathrm{A}\limits^ \circ
Option A (5.783A∘5.783\mathop \mathrm{A}\limits^ \circ) is correct because it is calculated using the density formula for a face-centered cubic structure.
Revision notes and key takeaways

Review SOLID STATE in your textbook or class notes, then use this set to check your understanding.

Showing 181-199 of 199 questions
0 /199
0✓ 0✗
0% Accuracy
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.