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JEE • CHEMISTRY • SOLID STATE

Solid state practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-180 of 199 questions
151 Medium
151 of 199
Remembering +4 | -1
In a monoclinic unit cell the relation of sides and
angles are respectively:
View answer and explanation
Correct option: C
a≠b≠c   and   α=γ=90∘≠βa \ne b \ne c\,\,\,{\text{and}}\,\,\,\alpha = \gamma = 90^\circ \ne \beta
Option C is correct because in a monoclinic unit cell, the sides are unequal (a≠b≠ca \ne b \ne c) and two angles are 90 degrees (α=γ=90∘\alpha = \gamma = 90^\circ) while the third angle is not (β≠90∘\beta \ne 90^\circ).
152 Easy
152 of 199
Understanding +4 | -1
Which one is correct about ferrites?
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because ferrites possess the formula AB2O4, have a spinel structure, and MgAl2O4 is an example of a ferrite.
153 Easy
153 of 199
Remembering +4 | -1
The co-ordination number of Ca2+\mathrm{C}{\mathrm{a}^{2 + }} ion in fluorite crystal is :
View answer and explanation
Correct option: B
8
Option B (8) is correct because in the fluorite structure (CaF₂), each Ca²⁺ ion is surrounded by 8 F⁻ ions, giving it a coordination number of 8.
154 Easy
154 of 199
Remembering +4 | -1
TiO2\mathrm{Ti}{\mathrm{O}_2} is well known example of :
View answer and explanation
Correct option: B
Tetragonal system
Option B (Tetragonal system) is correct because TiO2\mathrm{Ti}{\mathrm{O}_2} (Titanium dioxide) has a tetragonal crystal structure.
155 Easy
155 of 199
Understanding +4 | -1
The number of octahedral void(s) per atom present in a cubic close-packed structure is :
View answer and explanation
Correct option: C
1
Option C (1) is correct because in a cubic close-packed structure, the number of octahedral voids is equal to the number of atoms.
156 Medium
156 of 199
Application +4 | -1
A compound of ‘A’ and ‘B’ crystallises in a cubic lattice in which ‘A’ atoms occupy the lattice points at the corners of the cube. The ‘B’ atoms occupy the centre of each face of the cube. The probable empirical formula of the compound is
View answer and explanation
Correct option: D
AB3A{B_3}
Option D (AB3A{B_3}) is correct because the number of A atoms is 1 and the number of B atoms is 3 in the unit cell.
157 Easy
157 of 199
Remembering +4 | -1
The unit cell with crystallographic dimensions a=b≠c;α=β=γ=90∘a = b \ne c;\alpha = \beta = \gamma = 90^\circ is :
View answer and explanation
Correct option: B
Tetragonal
Option B (Tetragonal) is correct because the tetragonal crystal system is defined by a=b≠ca = b \ne c and α=β=γ=90∘\alpha = \beta = \gamma = 90^\circ.
158 Easy
158 of 199
Understanding +4 | -1
Which arrangement of electrons leads to anti-ferromagnetism?
View answer and explanation
Correct option: B
↑↓↑↓\uparrow \mathrm{ } \downarrow \mathrm{ } \uparrow \mathrm{ } \downarrow
Option B (↑↓↑↓\uparrow \mathrm{ } \downarrow \mathrm{ } \uparrow \mathrm{ } \downarrow) is correct because anti-ferromagnetism arises from the alignment of magnetic moments in opposite directions, resulting in a net magnetic moment of zero.
159 Medium
159 of 199
Understanding +4 | -1
The number of equidistance oppositely charged ions in a sodium chloride crystal is
View answer and explanation
Correct option: C
6
Option C (6) is correct because in a sodium chloride (NaCl) crystal, each Na+Na^+ ion is surrounded by 6 equidistant Cl−Cl^- ions, and vice versa.
160 Easy
160 of 199
Remembering +4 | -1
A cubic crystal possesses in all ……elements of symmetry.
View answer and explanation
Correct option: D
23
Option D (23) is correct because a cubic crystal possesses 23 elements of symmetry.
161 Easy
161 of 199
Remembering +4 | -1
ZnSZnS is:
View answer and explanation
Correct option: A
Ionic crystal
Option A (Ionic crystal) is correct because Zinc Sulfide (ZnS) is a compound formed by ionic bonding between zinc and sulfur ions, resulting in an ionic crystal structure.
162 Medium
162 of 199
Understanding +4 | -1
Among the following species, the one which become paramagnetic on heating at 850 K850 {~K} is
View answer and explanation
Correct option: D
Both (1) and (3)
Option D (Both (1) and (3)) is correct because ferrimagnetic substances like Fe3O4 and ZnFe2O4 lose their ferrimagnetism and become paramagnetic upon heating above their Curie temperature.
163 Easy
163 of 199
Understanding +4 | -1
Which of the following arrangement correctly shows the magnetic moment of anti-ferromagnetic substance?
View answer and explanation
Correct option: D
↑,↓,↑,↓,↑,↓\uparrow , \downarrow , \uparrow , \downarrow , \uparrow , \downarrow
Option D (↑,↓,↑,↓,↑,↓\uparrow , \downarrow , \uparrow , \downarrow , \uparrow , \downarrow) is correct because in antiferromagnetic substances, the magnetic moments are aligned in an antiparallel manner, resulting in a net magnetic moment of zero.
164 Easy
164 of 199
Understanding +4 | -1
The tetrahedral voids formed by ccp arrangement of Cl−{Cl^-} ions in rock salt structure are:
View answer and explanation
Correct option: D
Neither occupied by Na+{Na}^{+} nor Cl−{Cl^-}
Option D is correct because in the rock salt structure, Na+ ions occupy the octahedral voids, and Cl- ions form the ccp lattice; tetrahedral voids are not occupied by either.
165 Medium
165 of 199
Application +4 | -1
The pyknometric density of sodium chloride crystal is 2.165×103  kg  m−32.165 \times {10^3}\;\mathrm{kg}\;{\mathrm{m}^{ - 3}} while is X-ray density is 2.178×103  kg  m−32.178 \times {10^3}\;\mathrm{kg}\;{\mathrm{m}^{ - 3}}. The fraction of the unoccupied sites in sodium chloride crystal is :
View answer and explanation
Correct option: D
5.96×10−35.96 \times {10^{ - 3}}
Option D (5.96×10−35.96 \times {10^{ - 3}}) is correct because it accurately calculates the fraction of unoccupied sites based on the difference between pyknometric and X-ray densities.
166 Medium
166 of 199
Understanding +4 | -1
Assertion : Stability of a crystal is reflected in the magnitude of its melting point.

Reason : The stability of a crystal depends upon the strength of the interparticle attractive force.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.
Option A is correct because the stability of a crystal is directly related to its melting point, which depends on the strength of interparticle attractive forces.
167 Medium
167 of 199
Analyzing +4 | -1
Assertion (A) Both Frenkel and Schottky defects are stoichiometric defects.

Reason (R) Both defects change the density of the crystalline solid.
View answer and explanation
Correct option: C
If Assertion is true but Reason is false.
Option C is correct because both Frenkel and Schottky defects are stoichiometric, but only Schottky defects affect the density of the crystal.
168 Easy
168 of 199
Understanding +4 | -1
The number of carbon atoms per unit cell of diamond unit cell is
View answer and explanation
Correct option: D
8
Option D (8) is correct because in a diamond structure, carbon atoms occupy FCC lattice points and half of the tetrahedral voids, resulting in a total of 8 carbon atoms per unit cell.
169 Easy
169 of 199
Understanding +4 | -1
The number of atoms contained in a fcc unit cell of a monoatomic substance is
View answer and explanation
Correct option: C
4
Option C is correct because a face-centered cubic (fcc) unit cell contains 4 atoms: 1 from the corners (8 corners x 1/8 atom per corner) and 3 from the faces (6 faces x 1/2 atom per face).
170 Medium
170 of 199
Remembering +4 | -1
Order of packing efficiency is
View answer and explanation
Correct option: D
HCP ≈\approx FCC > BCC > Simple cubic
Option D (HCP ≈\approx FCC > BCC > Simple cubic) is correct because it represents the correct order of packing efficiency for the given crystal structures.
171 Easy
171 of 199
Remembering +4 | -1
The appearance of colour in solid state of alkali metal halides is due to
View answer and explanation
Correct option: C
F-centre
Option C (F-centre) is correct because the appearance of color in solid state of alkali metal halides is due to F-centers, which are electrons trapped in anion vacancies.
172 Medium
172 of 199
Remembering +4 | -1
Structure similar to zinc blende is found in
View answer and explanation
Correct option: C
CuCl\mathrm{CuCl}
Option C (CuCl\mathrm{CuCl}) is correct because CuCl has a structure similar to zinc blende.
173 Medium
173 of 199
Application +4 | -1
How many number of atoms are there in a cube based unit cell having one atom on each corner and two atoms on each body diagonal of cube
View answer and explanation
Correct option: D
9
Option D (9) is correct because it correctly accounts for the contribution of atoms at the corners and along the body diagonals of the cube.
174 Medium
174 of 199
Remembering +4 | -1
In zinc blende structure, the coordination number of Zn2+\mathrm{Z}{\mathrm{n}^{2 + }} ion is
View answer and explanation
Correct option: B
4
Option B (4) is correct because in the zinc blende (ZnS) structure, each Zn2+Zn^{2+} ion is tetrahedrally coordinated to four S2−S^{2-} ions, and vice versa.
175 Easy
175 of 199
Analyzing +4 | -1
Which is the incorrect statement?
View answer and explanation
Correct option: B
FeO0.98\mathrm{Fe}{\mathrm{O}_{0.98}} has non stoichiometric metal deficiency defect
Option A is the incorrect statement because Frenkel defects are favored when there is a significant size difference between cations and anions, not when they are almost equal.
176 Easy
176 of 199
Understanding +4 | -1
The number of octahedral void(s) per atom present in a cubic close-packed structure is :
View answer and explanation
Correct option: C
1
Option C (1) is correct because in a cubic close-packed (ccp) structure, the number of octahedral voids is equal to the number of atoms.
177 Medium
177 of 199
Application +4 | -1
The number of unit cells in the Ca atom lies on the surface of a cubic crystal that is 1.0 cm1.0 \mathrm{~cm} in length is
View answer and explanation
Correct option: B
9.17×10229.17 \times 10^{22}
Option B (9.17×10229.17 \times 10^{22}) is correct because it calculates the number of unit cells by dividing the volume of the crystal by the volume of a single unit cell.
178 Hard
178 of 199
Remembering +4 | -1
In diamond, the coordination number of carbon is
View answer and explanation
Correct option: A
four and its unit cell has eight carbon atoms
Option A (four and its unit cell has eight carbon atoms) is correct because in a diamond structure, each carbon atom is tetrahedrally bonded to four other carbon atoms, and the unit cell contains eight carbon atoms.
179 Hard
179 of 199
Application +4 | -1
A metallic element exists as simple cubic lattice. Each edge of the unit cell is 3Å. The density of the metal is 9 g cm−39 \mathrm{~g} \mathrm{~cm}^{-3}. How many number of unit cells will be present in 100 g100 \mathrm{~g} of the metal :-
View answer and explanation
Correct option: B
4.12×10234.12 \times 10^{23}
Option B (4.12×10234.12 \times 10^{23}) is correct because it correctly calculates the number of unit cells using the density, edge length, and the fact that it's a simple cubic lattice.
180 Medium
180 of 199
Understanding +4 | -1
The ratio of cationic radius to anionic radius in an ionic crystal is greater than 0.732. Its coordination number is
View answer and explanation
Correct option: D
8
Option D (8) is correct because a radius ratio greater than 0.732 indicates a coordination number of 8, corresponding to a body-centered cubic structure.
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