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JEE • CHEMISTRY • SOLID STATE

Solid state practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 199 questions
61 Hard
61 of 199
Application +4 | -1
For a given crystal, the lattice parameter ‘aa’ is 318 pm. The dd-spacing for a (III) plane is
View answer and explanation
Correct option: B
184pm184\mathrm{ }pm
Option B (184 pm) is correct because it is calculated using the formula for d-spacing in a cubic crystal system, given the lattice parameter and Miller indices.
62 Medium
62 of 199
Remembering +4 | -1
The number of octahedral sites per sphere in a fcc structure is
View answer and explanation
Correct option: A
1
Option A (1) is correct because in a face-centered cubic (fcc) structure, there is one octahedral site per sphere (atom).
63 Medium
63 of 199
Understanding +4 | -1
Structure of a compound of the formula A2B{A}_2 {B} in which each B2−{B}^{2-} ions is co- ordinated by eight A+{A}^{+}ions and each A+{A}^{+}ion by four B−{B}^{-}ions is called
View answer and explanation
Correct option: B
anti - fluorite structure
Option B (anti - fluorite structure) is correct because in an anti-fluorite structure, the cation to anion ratio is 2:1, and the coordination numbers are 4 for the cation and 8 for the anion.
64 Medium
64 of 199
Application +4 | -1
A compound consists of atoms AA and BB crystalizes in a cubic closed packed structure. Atoms of AA are located at all the corners and atoms of BB are at 14\frac{1}{4}th of octahedral voids. The simplest formula of the compound will be
View answer and explanation
Correct option: A
AB{AB}
Answer A (AB) is correct because the ratio of atoms A and B in the compound is 1:1, based on their positions in the cubic closed packed structure.
65 Easy
65 of 199
Remembering +4 | -1
What is the number of tetrahedral voids per atom in a crystal?
View answer and explanation
Correct option: B
2
Option B (2) is correct because there are 2 tetrahedral voids per atom in a crystal.
66 Hard
66 of 199
Application +4 | -1
How many unit cells are present in a cube shaped ideal crystal of NaCl\mathrm{NaCl} of mass 1.00g?

[Atomic  masses:Na=23,  Cl=35.5]\left[ {\mathrm{Atomic}\;\mathrm{ masses}:\mathrm{Na} = 23,\;\mathrm{Cl} = 35.5} \right]
View answer and explanation
Correct option: A
2.57×10212.57 \times {10^{21}}
Option A (2.57×10212.57 \times {10^{21}}) is correct because it is calculated by dividing the total mass by the mass of one unit cell.
67 Easy
67 of 199
Remembering +4 | -1
Which of the following is a covalent solid
View answer and explanation
Correct option: D
All
Correct Answer + Core Reason: Option D (All) is correct because Fe2O3Fe_2O_3, NaClNaCl, and CO2CO_2 all exhibit covalent bonding.
68 Easy
68 of 199
Remembering +4 | -1
Which substance shows antiferromagnetism?
View answer and explanation
Correct option: D
Mn2O3\mathrm{M}{\mathrm{n}_2}{\mathrm{O}_3}
Option D (Mn2O3\mathrm{M}{\mathrm{n}_2}{\mathrm{O}_3}) is correct because it exhibits antiferromagnetism due to the alignment of magnetic moments in opposite directions, resulting in a net magnetic moment of zero.
69 Easy
69 of 199
Analyzing +4 | -1
Which is the incorrect statement
View answer and explanation
Correct option: D
FeO0.98Fe{O_{0.98}} has non-stoichiometric metal deficiency defect
The correct answer is FeO0.98Fe{O_{0.98}} has non-stoichiometric metal deficiency defect because it actually exhibits a metal deficiency defect, not a metal excess defect.
70 Hard
70 of 199
Application +4 | -1
An element (atomic mass 100 g/mol100 {~g} / {mol} ) having bccb c c structure has unit cell edge 400pm400 {pm}. The density of element is (no. of atoms in bcc,Z=2b c c, Z=2 )
View answer and explanation
Correct option: C
5.188 g/cm35.188 {~g} / {cm}^3
Option C (5.188 g/cm35.188 {~g} / {cm}^3) is correct because the density is calculated using the formula ρ=Z×MNA×a3\rho = \frac{{Z \times M}}{{N_A \times a^3}}, where Z=2 for bcc, M is the molar mass, NAN_A is Avogadro's number, and a is the edge length.
71 Easy
71 of 199
Remembering +4 | -1
Cation and anion combines in a crystal to form following type of compound
View answer and explanation
Correct option: A
Ionic
Option A (Ionic) is correct because cations and anions combine through electrostatic attraction to form ionic compounds in a crystal lattice.
72 Medium
72 of 199
Application +4 | -1
Structure of a mixed oxide is cubic close-packed (c.c.p). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal AA and the octahedral voids are occupied by a monovalent metal BB. The formula of the oxide is :
View answer and explanation
Correct option: D
AB2O2A{B_2}{O_2}
Option D (AB2O2AB_2O_2) is correct because it correctly calculates the ratio of A, B, and O atoms based on their occupancy in the ccp lattice, tetrahedral voids, and octahedral voids, respectively.
73 Medium
73 of 199
Remembering +4 | -1
Which among the following is an antiferromagnetic substance?
View answer and explanation
Correct option: A
MnO\mathrm{MnO}
Option A (MnO\mathrm{MnO}) is correct because MnO\mathrm{MnO} (Manganese(II) oxide) is a classic example of an antiferromagnetic substance where the magnetic moments of adjacent ions are aligned in an antiparallel manner, resulting in zero net magnetic moment.
74 Hard
74 of 199
Application +4 | -1
Silver (atomic weight =108  g  mol−1= 108\;\mathrm{g}\;\mathrm{mo}{\mathrm{l}^{ - 1}}) has a density of 10.5  g  cm−3.10.5\;g\;\mathrm{c}{\mathrm{m}^{ - 3}}. The number of silver atoms on a surface of area 10−12  m2{10^{ - 12}}\;{\mathrm{m}^2} can be expressed in scientific notation as y×10x.y \times {10^x}. The value of xx is
View answer and explanation
Correct option: C
7
Option C is correct because the calculation involves finding the volume of a silver atom, then its area, and finally dividing the given surface area by the area of each silver atom.
75 Easy
75 of 199
Remembering +4 | -1
What is the coordination number of body centred cube?
View answer and explanation
Correct option: A
8
Option A (8) is correct because in a body-centered cubic structure, each atom is surrounded by 8 nearest neighbors.
76 Medium
76 of 199
Understanding +4 | -1
The incorrect statement about the imperfections in solids is:
View answer and explanation
Correct option: D
Vacancy defect increases the density of the substance.
Option D (Vacancy defect increases the density of the substance) is correct because vacancy defects decrease the density of the substance, not increase it.
77 Medium
77 of 199
Understanding +4 | -1
Potassium fluoride has NaClNaCl type structure. What is the distance between K+{K^ + } and F−{F^ - } ions if cell edge is aa cm?
View answer and explanation
Correct option: A
a2cm\frac{a}{2}\mathrm{cm}
Option A (a2cm\frac{a}{2}\mathrm{cm}) is correct because in an NaCl type structure, the distance between cation and anion is half the cell edge length.
78 Medium
78 of 199
Analyzing +4 | -1
Distance between nearest cation and anion in an ionic solid is 3a4\frac{\sqrt{3} a}{4} then ionic solid may be:
View answer and explanation
Correct option: D
All
Option D (All) is correct because in ZnS, Na2ONa_2O, and CaF2CaF_2 structures, the distance between the nearest cation and anion can be 3a4\frac{\sqrt{3} a}{4} when the cation occupies a tetrahedral void.
79 Medium
79 of 199
Analyzing +4 | -1
Analysis shows that an oxide ore of nickel has formula Ni0.98O1.00\mathrm{N}{\mathrm{i}_{0.98}}{\mathrm{O}_{1.00}}. The percentage of nickel as Ni3+\mathrm{N}{\mathrm{i}^{3 + }} ions is nearly
View answer and explanation
Correct option: C
4
Option D (phenylacetic acid dimerizes in benzene) is correct because the van't Hoff factor (i) is approximately 0.5, indicating dimerization.
80 Medium
80 of 199
Application +4 | -1
A binary solid (A+B−)\left( {{A^ + }{B^ - }} \right) has a rock salt structure. If the edge length is 400 pm and radius of cation is 75 pm the radius of anion is :
View answer and explanation
Correct option: B
125 pm
Option B (125 pm) is correct because the radius of the anion is calculated using the rock salt structure relationship with the edge length and cation radius.
81 Medium
81 of 199
Understanding +4 | -1
Statement I: Schottky defect involving stoichiometric cation and anion vacancies are likely for compounds and ions of comparable size.

Statement II: Schottky defect minimise mechanical distortions and charge displacement.
View answer and explanation
Correct option: A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I
Option A is correct because Schottky defects occur in compounds with ions of comparable size to minimize mechanical distortions and charge displacement.
82 Medium
82 of 199
Application +4 | -1
The radius of Ag+\mathrm{A}{\mathrm{g}^ + } ion is 126 pm while that of I−{\mathrm{I}^ - } ion is 216 pm. The co-ordination number of Ag\mathrm{Ag} in AgI\mathrm{AgI} is :
View answer and explanation
Correct option: C
6
Option C (6) is correct because the radius ratio falls within the range that corresponds to an octahedral coordination number of 6.
83 Medium
83 of 199
Understanding +4 | -1
Statement I: The electrical conductivity of a metal decreases as temperature increases.

Statement II: This impedes the flow of electrons, when an electric field is applied.
View answer and explanation
Correct option: B
Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I
Option B (Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I) is correct because both statements are true, but the impeding of electron flow is a general property, not the direct cause of decreased conductivity with increased temperature.
84 Medium
84 of 199
Remembering +4 | -1
Frenkel defect is caused due to
View answer and explanation
Correct option: A
The shift of a positive ion from its normal lattice site to an interstitial site
Option A (The shift of a positive ion from its normal lattice site to an interstitial site) is correct because the Frenkel defect involves the displacement of an ion (typically a cation) from its lattice site to an interstitial site.
85 Easy
85 of 199
Remembering +4 | -1
In a cubic close packing of spheres in three dimensions, the co-ordination number of each sphere is :
View answer and explanation
Correct option: D
12
Option D (12) is correct because in a cubic close-packed structure, each sphere is surrounded by 12 other spheres, giving it a coordination number of 12.
86 Easy
86 of 199
Remembering +4 | -1
The one that is extensively used as a piezoelectric material is
View answer and explanation
Correct option: A
Quartz
Correct Answer + Core Reason: Option A (Quartz) is correct because quartz is a well-known piezoelectric material.
87 Easy
87 of 199
Remembering +4 | -1
Which of the following solid is non-crystalline solid
View answer and explanation
Correct option: D
Glass
Option D (Glass) is correct because glass is an amorphous solid, lacking long-range order, and is therefore non-crystalline.
88 Medium
88 of 199
Analyzing +4 | -1
Analysis shows that an oxide ore of nickel has formula Ni0.98O1.00\mathrm{N}{\mathrm{i}_{0.98}}{\mathrm{O}_{1.00}}. The percentage of nickel as Ni3+\mathrm{N}{\mathrm{i}^{3 + }} ions is nearly
View answer and explanation
Correct option: C
4
Option C (4) is correct because the percentage of Ni as Ni3+^{3+} is calculated based on charge balance to maintain neutrality of the compound.
89 Hard
89 of 199
Analyzing +4 | -1
In a fcc lattice A,B,CA, B, C and DD atoms are arranged at corners, face centres octahedral voids and half of tetrahedral voids respectively and if the crystal deposited is defected such that all the particles at one body diagonal of each unit cell are missing, correspondingly then what is the resulted formula of the compound?
View answer and explanation
Correct option: B
AB4C4D4{AB}_4 {C}_4 {D}_4
Option B is correct. After removing atoms along the body diagonal, the formula becomes AB₄C₄D₄, calculated by considering the contributions of atoms at corners, faces, octahedral voids, and tetrahedral voids.
90 Easy
90 of 199
Remembering +4 | -1
The substance which possesses zero resistance as 0 K :
View answer and explanation
Correct option: B
Super conductor
Option B (Super conductor) is correct because superconductors exhibit zero electrical resistance below a critical temperature, approaching 0 K.
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