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JEE CHEMISTRY MCQ: SOLID STATE

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An element XX (Atomic weight =96 u=96 \,{u} ) having FCCFCC structure. The number of unit cells in 9.6  g9.6 \,{~g} of XX is
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Correct option: D
0.025  NA0.025 \,{~N}_{A}
Option D (0.025 NA0.025 {~N}_{{A}}) is correct because it is the number of unit cells in 9.6 g of element X with FCC structure, calculated by determining the number of moles and dividing by the number of atoms per unit cell in FCC.

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