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JEE • CHEMISTRY • S-BLOCK ELEMENTS

S-block elements practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 121-150 of 303 questions

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121 Medium
121 of 303
Understanding +4 | -1
Thermal decomposition of which compound yields a basic and acidic oxide simultaneously?
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Correct option: D
CaCO3\mathrm{CaC}{\mathrm{O}_3}
Option D is correct. Calcium carbonate (CaCO3) decomposes to form calcium oxide (CaO), a basic oxide, and carbon dioxide (CO2), an acidic oxide.
122 Easy
122 of 303
Remembering +4 | -1
In the manufacture of sodium hydroxide, byproduct obtained is:
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Correct option: B
Cl2\mathrm{C}{\mathrm{l}_2}
Option B (Cl2\mathrm{C}{\mathrm{l}_2}) is correct because in the manufacture of sodium hydroxide by electrolysis of brine, chlorine gas is produced as a byproduct at the anode.
123 Medium
123 of 303
Understanding +4 | -1
The carbonate that will not decompose on heating is
View answer and explanation
Correct option: A
Na2CO3\mathrm{N}{\mathrm{a}_2}\mathrm{C}{\mathrm{O}_3}
Option A is correct because alkali metal carbonates are stable to heat except for lithium carbonate.
124 Easy
124 of 303
Remembering +4 | -1
Which one of the following is a peroxide
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Correct option: B
BaO2Ba{O_2}
Option B (BaO2Ba{O_2}) is correct because barium peroxide is a known peroxide compound.
125 Easy
125 of 303
Remembering +4 | -1
In the hardening stage of plaster of Paris, the compound formed is
View answer and explanation
Correct option: D
Monoclinic CaSO4.2H2O\mathrm{CaS}{\mathrm{O}_4}.2{\mathrm{H}_2}\mathrm{O}
Option D (Monoclinic CaSO4.2H2O\mathrm{CaS}{\mathrm{O}_4}.2{\mathrm{H}_2}\mathrm{O}) is correct because Plaster of Paris hardens by absorbing water and forming monoclinic gypsum.
126 Easy
126 of 303
Remembering +4 | -1
Slaked lime is:
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Correct option: C
Ca(OH)2\mathrm{Ca}{\left( {\mathrm{OH}} \right)_2}
Option C (Ca(OH)2\mathrm{Ca}{\left( {\mathrm{OH}} \right)_2}) is correct because slaked lime is the common name for calcium hydroxide.
127 Easy
127 of 303
Remembering +4 | -1
The suspension of slaked lime in water is known as
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Correct option: D
Milk of lime
Option D (Milk of lime) is correct because the suspension of slaked lime in water is known as milk of lime.
128 Medium
128 of 303
Understanding +4 | -1
Tin dissolves in boiling caustic soda solution because of the formation of soluble:
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Correct option: C
Na2SnO3\mathrm{N}{\mathrm{a}_2}\mathrm{Sn}{\mathrm{O}_3}
Option C (Na2SnO3\mathrm{N}{\mathrm{a}_2}\mathrm{Sn}{\mathrm{O}_3}) is correct because tin reacts with boiling caustic soda to form sodium stannate, which is soluble.
129 Medium
129 of 303
Analyzing +4 | -1
Which of the following statements about Na2O2\mathrm{Na}_2 \mathrm{O}_2 is not correct?
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Correct option: D
It is the super oxide of sodium
Option D (It is the super oxide of sodium) is not correct because Na2O2\mathrm{Na}_2 \mathrm{O}_2 is the peroxide of sodium, not the superoxide.
130 Hard
130 of 303
Remembering +4 | -1
Microcosmic salt is
View answer and explanation
Correct option: B
Na(NH4)HPO4\mathrm{Na}\left( {\mathrm{N}{\mathrm{H}_4}} \right)\mathrm{HP}{\mathrm{O}_4}
Option B (Na(NH4)HPO4\mathrm{Na}\left( {\mathrm{N}{\mathrm{H}_4}} \right)\mathrm{HP}{\mathrm{O}_4}) is the correct formula for microcosmic salt, a white crystalline solid.
131 Easy
131 of 303
Remembering +4 | -1
Calcium does not combine directly with:
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Correct option: D
Carbon
Option D (Carbon) is correct because Calcium does not directly combine with carbon under normal conditions to form a stable binary compound.
132 Easy
132 of 303
Remembering +4 | -1
Calcium is obtained by
View answer and explanation
Correct option: A
Electrolysis of molten CaCl2\mathrm{CaC}{\mathrm{l}_2}
Option A is correct because calcium is obtained by the electrolysis of molten calcium chloride (CaCl2), where calcium ions are reduced at the cathode to form metallic calcium.
133 Medium
133 of 303
Understanding +4 | -1
When sodium metal is dissolved in liquid ammonia, a blue solution is formed. The blue colour is due to:
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Correct option: B
Solvated electrons
The correct answer is B. The blue color of the solution is due to solvated electrons, which absorb energy and impart the blue color.
134 Easy
134 of 303
Analyzing +4 | -1
A chloride dissolves appreciably in cold water. When placed on a platinum wire in Bunsen flame, no distinctive colour is noticed. Which one is cation?
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Correct option: A
Mg2+\mathrm{M}{\mathrm{g}^{2 + }}
The correct answer is A (Mg2+\mathrm{M}{\mathrm{g}^{2 + }}) because magnesium chloride is soluble in cold water and does not impart a distinctive color to the Bunsen flame.
135 Medium
135 of 303
Remembering +4 | -1
In the wet tests for detection of various cations by precipitation, Ba2+\mathrm{Ba}^{2+} cations are detected by obtaining precipitate of
View answer and explanation
Correct option: B
BaCO3\mathrm{BaCO}_{3}
Option B (BaCO3\mathrm{BaCO}_{3}) is correct because barium ions (Ba2+Ba^{2+}) are typically precipitated as barium carbonate (BaCO3BaCO_3) in qualitative analysis.
136 Medium
136 of 303
Remembering +4 | -1
The metal, which is lighter than water at 25∘C25^{\circ} \mathrm{C} is
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Correct option: A
K\mathrm{K}
Option A (K\mathrm{K}) is correct because Potassium (K) is an alkali metal with a density less than that of water at 25∘C25^{\circ} \mathrm{C}.
137 Easy
137 of 303
Analyzing +4 | -1
Which substance gives a different flame colouration from the others?
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Correct option: D
Table salt
Option D (Table salt) is correct because table salt is NaCl, which gives a yellow flame, while the others are potassium salts, which give a lilac flame.
138 Easy
138 of 303
Remembering +4 | -1
Bleaching powder is obtained by treating chlorine with
View answer and explanation
Correct option: B
Ca(OH)2\mathrm{Ca}{\left( {\mathrm{OH}} \right)_2}
Option B (Ca(OH)2) is correct because bleaching powder is produced by reacting chlorine gas with calcium hydroxide (slaked lime).
139 Medium
139 of 303
Understanding +4 | -1
Solution of sodium metal in liquid ammonia is good conductor of electricity due to presence of
View answer and explanation
Correct option: D
Both (1) and (3)
Option D (Both (1) and (3)) is correct because the solution contains both solvated sodium ions and solvated electrons, which contribute to its electrical conductivity.
140 Easy
140 of 303
Understanding +4 | -1
The cation which forms a yellow precipitate with potassium chromate in acetic acid is:
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Correct option: B
Ba2+\mathrm{B}{\mathrm{a}^{2 + }}
Option B (Ba2+\mathrm{B}{\mathrm{a}^{2 + }}) is correct because BaCrO4\mathrm{BaCr}{\mathrm{O}_4} is a yellow solid that is insoluble in acetic acid.
141 Medium
141 of 303
Analyzing +4 | -1
Which pair cannot exist together in solution?
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Correct option: C
NaHCO3andNa2CO3\mathrm{NaHC}{\mathrm{O}_3}\mathrm{and N}{\mathrm{a}_2}\mathrm{C}{\mathrm{O}_3}
The correct answer is A (NaHCO3 and NaOH) because NaOH will react with NaHCO3 to form Na2CO3 and H2O, thus they cannot coexist in solution.
142 Easy
142 of 303
Remembering +4 | -1
Causticisation process is used for the preparation of:
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Correct option: A
Caustic soda
Option A (Caustic soda) is correct because the causticization process is used to produce sodium hydroxide (caustic soda) from sodium carbonate.
143 Easy
143 of 303
Understanding +4 | -1
Alkali metals react with water vigorously to form hydroxides and dihydrogen. Which of the following alkali metals reacts with water least vigorously?
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Correct option: A
LiLi
Option A (LiLi) is correct because lithium reacts least vigorously with water among alkali metals due to its small size and high ionization enthalpy.
144 Easy
144 of 303
Remembering +4 | -1
The only element which is radioactive among alkali metals is:
View answer and explanation
Correct option: B
Fr\mathrm{Fr}
Option B (Fr) is correct because Francium is the only radioactive alkali metal.
145 Medium
145 of 303
Analyzing +4 | -1
A: BeCl2{BeCl}_2 and AlCl3{AlCl}_3 are useful as catalysts in Friedel-Crafts reaction.

R: BeCl2{BeCl}_2 and AlCl3{AlCl}_3 provide Cl+{Cl}^{+} easily.
View answer and explanation
Correct option: A
Both A and R are true and R is the correct explanation of A
Option A (Both A and R are true and R is the correct explanation of A) is correct because both BeCl2{BeCl}_2 and AlCl3{AlCl}_3 act as Lewis acids in Friedel-Crafts reactions by providing Cl+{Cl}^{+}.
146 Medium
146 of 303
Understanding +4 | -1
Which of the following statement is wrong for solvey process?
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Correct option: D
Na2CO3Na_2CO_3 is partially converted into bi-carbonate.
Option D (Na2CO3Na_2CO_3 is partially converted into bi-carbonate) is the wrong statement because NaHCO3NaHCO_3 converts into Na2CO3Na_2CO_3 mainly, and the reverse does not happen.
147 Easy
147 of 303
Understanding +4 | -1
Which metal dissolves in NaOH\mathrm{NaOH} with the evolution of H2{\mathrm{H}_2} ?
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Correct option: A
Be\mathrm{Be}
Option A (Be) is correct because beryllium reacts with NaOH to produce sodium beryllate and hydrogen gas.
148 Medium
148 of 303
Analyzing +4 | -1
Which of the following statement is not correct?
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Correct option: D
Hydrated MgCl2{MgCl}_2 gives anhydrous MgCl2{MgCl}_2 on heating in dry air.
Option D (Hydrated MgCl2{MgCl}_2 gives anhydrous MgCl2{MgCl}_2 on heating in dry air.) is incorrect because hydrated MgCl2 on heating gives MgO, not anhydrous MgCl2.
149 Easy
149 of 303
Understanding +4 | -1
Which of the following hydride conducts electricity in molten state
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Correct option: D
KH
Option D (KH) is correct because KH is an ionic hydride, and in the molten state, it dissociates into ions (K+K^+ and H−H^-) which conduct electricity.
150 Medium
150 of 303
Remembering +4 | -1
When kept open in air, the crystals of washing soda lose 9 molecules of water to form a monohydrate.

Na2CO3⋅10H2O→to  airexposedNa2CO3⋅H2O+9H2ON{a_2}C{O_3} \cdot 10{H_2}O\xrightarrow[{{\text{to}}\,\,{\text{air}}}]{{{\text{exposed}}}}N{a_2}C{O_3} \cdot {H_2}O + 9{H_2}O

This process is called
View answer and explanation
Correct option: A
efflorescence
Option A (efflorescence) is correct because efflorescence is the process where a hydrated salt loses water molecules to the atmosphere.
Revision notes and key takeaways

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