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JEE • CHEMISTRY • S-BLOCK ELEMENTS

S-block elements practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 151 questions
1 Medium
1 of 151
Analyzing +4 | -1
Assertion (A): Among the alkali metals, lithium salts exhibit the least electrical condutance in aqueous solutions.
Reason (R): Smaller the radius of the hydrated cation, lower is the electrical conductance in aqueous solutions.
View answer and explanation
Correct option: C
A\mathbf{A} is true but R\mathbf{R} is false.
Option C is correct because Assertion (A) is true, lithium salts have the least electrical conductance, but Reason (R) is false, as smaller hydrated radius implies higher conductance.
2 Medium
2 of 151
Analyzing +4 | -1
(A)(A) is a ternary salt with divalent cation. (A)(A) gives yellow ppt. with K2CrO4\mathrm{K}_2 \mathrm{CrO}_4 as well as with AgNO3\mathrm{AgNO}_3. (A) is precipitated by H2 S\mathrm{H}_2 \mathrm{~S} neither in acidic nor ammoniacal medium, but addition of (NH4)2CO3\left(\mathrm{NH}_4\right)_2 \mathrm{CO}_3 in NH4OH\mathrm{NH}_4 \mathrm{OH} gave white ppt. (B). 0.297 g0.297 \mathrm{~g} of (A)(A) gave 0.197 g0.197 \mathrm{~g} of (B)(B). Identify (A)(A).
View answer and explanation
Correct option: A
BaBr2\mathrm{BaBr}_2
The correct answer is A (BaBr2\mathrm{BaBr}_2) because it satisfies the given conditions of forming yellow precipitates with K2CrO4\mathrm{K}_2 \mathrm{CrO}_4 and AgNO3\mathrm{AgNO}_3, and forming a white precipitate with (NH4)2CO3(\mathrm{NH}_4)_2 \mathrm{CO}_3 in NH4OH\mathrm{NH}_4 \mathrm{OH}.
3 Medium
3 of 151
Remembering +4 | -1
Which of the alkali metal is having least melting point?
View answer and explanation
Correct option: D
Cs
Option D (Cs) is correct because melting point decreases down the group in alkali metals due to increasing atomic size and weaker metallic bonding.
4 Medium
4 of 151
Analyzing +4 | -1
Statement 1: LiCl{LiCl} is predominatly a covalent compound.

Statement 2: Electronegativity difference between Li{Li} and Cl{Cl} is too small.
View answer and explanation
Correct option: A
Statement 1 is true but statement 2 is false
The correct answer is A (Statement 1 is true but statement 2 is false) because LiCl has significant covalent character due to the high polarizing power of Li+ ion, despite the electronegativity difference.
5 Medium
5 of 151
Analyzing +4 | -1
Metal (M)+({M})+ air →Δ(A)⟶H2O(B)⟶HCl\stackrel{\Delta}{\rightarrow}({A}) \stackrel{{H}_2 {O}}{\longrightarrow}({B}) \stackrel{{HCl}}{\longrightarrow} white fumes. Metal M{M} can be
View answer and explanation
Correct option: A
Li,Mg{Li}, {Mg} or Al{Al}
Option A (Li,Mg{Li}, {Mg} or Al{Al}) is correct because these metals can form nitrides that hydrolyze to produce ammonia, which reacts with HCl to form white fumes of ammonium chloride.
6 Medium
6 of 151
Understanding +4 | -1
Among the alkali metals caesium is the most reactive because
View answer and explanation
Correct option: D
The outermost electron is more loosely bound than the outermost electron of the other alkali metals.
Option D is correct because caesium's outermost electron is the most loosely bound due to its large atomic size, making it the most reactive alkali metal.
7 Medium
7 of 151
Understanding +4 | -1
Nitrates of which of the following alkali metals decomposes on heating to give corresponding oxide?
View answer and explanation
Correct option: A
Li{Li}
Option A (Li{Li}) is correct because lithium nitrate decomposes to give lithium oxide, while other alkali metal nitrates decompose to give nitrites.
8 Medium
8 of 151
Understanding +4 | -1
Which of the following is not correct?
View answer and explanation
Correct option: A
2Li2O⟶ heat 673 KLi2O2+2Li2Li_2O \underset{673 \mathrm{~K}}{\stackrel{\text { heat }}{\longrightarrow}}Li_2O_2+2Li
Option A (2Li2O⟶ heat 673 KLi2O2+2Li2Li_2O \underset{673 \mathrm{~K}}{\stackrel{\text { heat }}{\longrightarrow}}Li_2O_2+2Li) is not correct because Lithium primarily forms the monoxide (Li2OLi_2O) and does not readily form the peroxide (Li2O2Li_2O_2).
9 Medium
9 of 151
Remembering +4 | -1
Which alkaline earth metal shows some anomalous behaviour and has the same electronegativity as aluminium?
View answer and explanation
Correct option: D
Be\mathrm{Be}
Option D (Be\mathrm{Be}) is correct because Beryllium (Be) shows anomalous behavior due to its small size and high polarizing power, and it has a similar electronegativity to aluminium.
10 Medium
10 of 151
Understanding +4 | -1
The addition of dilute NaOHNaOH to Cr3+C{r^{3 + }} salt solution will give
View answer and explanation
Correct option: B
Precipitate of Cr2O3(H2O)nC{r_2}{O_3}{({H_2}O)_n}
Option B (Precipitate of Cr2O3(H2O)nC{r_2}{O_3}{({H_2}O)_n}) is correct because the addition of dilute NaOH to a Cr3+ salt solution results in the precipitation of hydrated chromium(III) oxide.
11 Medium
11 of 151
Understanding +4 | -1
Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) Lithium salts are hydrated.
Reason (R) Lithium has higher polarising power than other alkali metal group members.
In the light of the above statements, choose the most appropriate answer from the options given below.
View answer and explanation
Correct option: A
Both (A) and (R) are true but (R) is not the correct explanation of (A).
Option A (Both (A) and (R) are true but (R) is not the correct explanation of (A)) is correct because while both the assertion and reason are true, the reason doesn't directly explain why lithium salts are hydrated.
12 Medium
12 of 151
Remembering +4 | -1
Choose the correct order of density of the alkali metals.
View answer and explanation
Correct option: A
Li<K<Na<Rb<Cs\mathrm{Li}<\mathrm{K}<\mathrm{Na}<\mathrm{Rb}<\mathrm{Cs}
Option A (Li<K<Na<Rb<Cs\mathrm{Li}<\mathrm{K}<\mathrm{Na}<\mathrm{Rb}<\mathrm{Cs}) is the correct order of density for alkali metals, considering the anomaly between Na and K.
13 Medium
13 of 151
Remembering +4 | -1
Portland cement does not contain:
View answer and explanation
Correct option: D
Ca3(PO4)2C{a_3}{(P{O_4})_2}
Option D (Ca3(PO4)2Ca_3(PO_4)_2) is correct because Portland cement primarily consists of calcium silicates and aluminates, and does not contain calcium phosphate.
14 Medium
14 of 151
Analyzing +4 | -1
(Mily Cloud) C⟵CO2A+Na2CO3→B+C\text{(Mily Cloud) } {C} \stackrel{{CO}_2}{\longleftarrow} {A}+{Na}_2 {CO}_3 \rightarrow {B}+{C}

The chemical formulae of A{A} and B{B} are
View answer and explanation
Correct option: B
Ca(OH)2{Ca}({OH})_2 and NaOH{NaOH}
Option B (Ca(OH)2{Ca}({OH})_2 and NaOH{NaOH}) is correct because calcium hydroxide reacts with carbon dioxide to form calcium carbonate (milky cloud) and with sodium carbonate to form calcium carbonate and sodium hydroxide.
15 Medium
15 of 151
Understanding +4 | -1
Select the correct statements

(i) Cs+\mathrm{Cs}^{+}is more highly hydrated that the other alkali metal ions

(ii) Among the alkali metals Li,Na,K\mathrm{Li}, \mathrm{Na}, \mathrm{K} and Rb\mathrm{Rb}, lithium has the highest melting point

(iii) Among the alkali metals only lithium forms a stable nitride by direct combination with nitrogen
View answer and explanation
Correct option: D
(ii) and (iii)
Option D ((ii) and (iii)) is correct because Li+ is more hydrated, Li has the highest melting point among alkali metals, and only Li forms a stable nitride.
16 Medium
16 of 151
Analyzing +4 | -1
Which of the following is not correct as indicated?
View answer and explanation
Correct option: C
Li  and  NaLi\mathrm{ \,\,and }\,\,Na do not impart colour in oxidizing flame
Option C is correct because ethylene undergoes Sabatier and Senderen's reaction (catalytic hydrogenation) but does not react with ammoniacal silver nitrate.
17 Medium
17 of 151
Remembering +4 | -1
Alkali metals when dissolved in liquid NH3{NH}_3 at very high concentration gives which of the following coloured solution?
View answer and explanation
Correct option: C
Bronze
Option C (Bronze) is correct because at high concentrations, alkali metals dissolved in liquid ammonia form metal clusters, leading to a bronze-colored solution.
18 Medium
18 of 151
Analyzing +4 | -1
An inorganic compound first melts then resolidifies and then liberates a gas. It may be:
View answer and explanation
Correct option: A
KClO3KCl{O_3}
KClO3 first melts upon heating, then decomposes into KCl (a solid) and O2 (a gas).
19 Medium
19 of 151
Remembering +4 | -1
Baryta is:
View answer and explanation
Correct option: A
BaO\mathrm{BaO}
Option A (BaO\mathrm{BaO}) is correct because Baryta is the common name for barium oxide, which has the chemical formula BaO\mathrm{BaO}.
20 Medium
20 of 151
Understanding +4 | -1
Magnesium wire burns in the atmosphere of CO2\mathrm{C}{\mathrm{O}_2} because:
View answer and explanation
Correct option: C
Magnesium acts as a reducing agent and removes oxygen from CO2\mathrm{C}{\mathrm{O}_2}
Option C is correct because magnesium acts as a reducing agent, removing oxygen from CO2\mathrm{C}{\mathrm{O}_2} due to its higher reducing power than carbon.
21 Medium
21 of 151
Understanding +4 | -1
Which of the following statement is false?
View answer and explanation
Correct option: D
Na+\mathrm{Na}^{+}ions are the most abundant cations within cell fluids
Option D is the false statement. K+\mathrm{K}^+ ions, not Na+\mathrm{Na}^+ ions, are the most abundant cations within cell fluids.
22 Medium
22 of 151
Understanding +4 | -1
Sodium thiosulphate is formed when:
View answer and explanation
Correct option: C
Na2SO3\mathrm{N}{\mathrm{a}_2}\mathrm{S}{\mathrm{O}_3} is boiled with Na2S\mathrm{N}{\mathrm{a}_2}\mathrm{S} and I2{\mathrm{I}_2}
Option C (Na2SO3\mathrm{N}{\mathrm{a}_2}\mathrm{S}{\mathrm{O}_3} is boiled with Na2S\mathrm{N}{\mathrm{a}_2}\mathrm{S} and I2{\mathrm{I}_2}) is correct because sodium thiosulphate is formed by the reaction of sodium sulfite with sodium sulfide in the presence of iodine.
23 Medium
23 of 151
Analyzing +4 | -1
A: Among alkali metals, Lithium is the strongest reducing agent.

R: Li+\mathrm{Li}^{+}ions are heavily hydrated in water and large amount of hydration energy helps in the release of electrons from Li\mathrm{Li} atoms.
View answer and explanation
Correct option: A
Both (A) and (R) are correct and (R) is the correct explanation of (A)
Option A is correct because Lithium is indeed the strongest reducing agent among alkali metals, and this is due to the high hydration energy of Li+ ions.
24 Medium
24 of 151
Analyzing +4 | -1
A: BeSO4{BeSO}_4 and MgSO4{MgSO}_4 decompose on heating.

R: Lattice structures are not stable when anions and cations are not of comparable size.
View answer and explanation
Correct option: A
Both A and R are true and R is the correct explanation of A
Option A is correct because BeSO4 and MgSO4 decompose due to the large difference in size between the cation and anion, leading to lower lattice energy.
25 Medium
25 of 151
Analyzing +4 | -1
Statement 1: Lithium is the weakest reducing agent among alkali metals.

Statement 2: In alkali metals I.P. decreases down the group.
View answer and explanation
Correct option: B
Statement 1 is false but statement 2 is true
Option B (Statement 1 is false but statement 2 is true) is correct because Lithium is the strongest reducing agent in aqueous solution due to its high hydration energy, and ionization energy decreases down the group.
26 Medium
26 of 151
Analyzing +4 | -1
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : LiF is sparingly soluble in water.
Reason R : The ionic radius of Li+L{i^ + } ion is smallest
among its group members, hence has least
hydration enthalpy.
In the light of the above statements, choose the
most appropriate answer from the options given
below.
View answer and explanation
Correct option: C
A is true but R is false.
Option C (A is true but R is false) is correct because LiF is sparingly soluble due to high lattice enthalpy, and Li+Li^+ has high hydration enthalpy due to its small size.
27 Medium
27 of 151
Understanding +4 | -1
The compound insoluble in acetic acid is:
View answer and explanation
Correct option: D
Calcium oxalate
Option D (Calcium oxalate) is correct because calcium oxalate is known to be insoluble in acetic acid.
28 Medium
28 of 151
Understanding +4 | -1
Al2 O3 A{l_2}\,{O_3}\, was leached with alkali to get X.X. the solution of XX on passing of gas Y,Y, forms Z.Z. X,  YX,\,\,Y and ZZ respectively are
View answer and explanation
Correct option: D
X=Na[Al(OH)4],Y=CO2,    Z=Al2O3⋅xH2O  X = Na\left[ {Al{{\left( {OH} \right)}_4}} \right],Y = C{O_2},\,\,\,\,Z = A{l_2}{O_3} \cdot x{H_2}O\,\,
Option D (X=Na[Al(OH)4],Y=CO2,Z=Al2O3⋅xH2OX = Na[Al(OH)_4], Y = CO_2, Z = Al_2O_3 \cdot xH_2O) is correct because aluminum oxide reacts with alkali to form sodium aluminate, which then reacts with carbon dioxide to form hydrated aluminum oxide.
29 Medium
29 of 151
Understanding +4 | -1
Calgon is used for water treatment. Which of the following statement is not true about Calgon?
View answer and explanation
Correct option: A
Calgon contains the 2nd most abundant element by weight in the Earth’s crust.
Option A is the correct answer because Calgon is a compound, not an element, and therefore cannot *contain* the 2nd most abundant element. The 2nd most abundant element in Earth's crust is Silicon.
30 Medium
30 of 151
Analyzing +4 | -1
Assertion (A): Group 1 elements are the largest in their horizontal periods in the periodic table (exclude noble gases).

Reason (R): The melting and boiling points of group 1 elements increases on moving down from LiLi to CsCs.
View answer and explanation
Correct option: C
Assertion (A) is true, and Reason (R) is false.
Option C (Assertion (A) is true, and Reason (R) is false) is correct because Group 1 elements are indeed the largest in their respective periods (excluding noble gases), but the melting and boiling points of Group 1 elements decrease, not increase, down the group from Li to Cs.
Revision notes and key takeaways

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Key Takeaways

  • ✓ This set contains 151 single-correct-answer MCQs on S-BLOCK ELEMENTS.
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