Skip to main content
Back to REDOX REACTIONS

Your Progress

0 / 171 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • CHEMISTRY • REDOX REACTIONS

Redox reactions practice · Medium

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 91-120 of 171 questions

Preparing practice and saved progress…

91 Medium
91 of 171
Application +4 | -1
C2H6(g)+NO2(g)→CO2(g)+H2O(l){C}_2 {H}_6(g)+{NO}_2(g) \rightarrow {CO}_2(g)+{H}_2 {O}(l)

In this equation, the ratio of the coefficients of CO2{CO}_2 and H2O{H}_2 {O} is
View answer and explanation
Correct option: B
2:32: 3
Option B (2:32: 3) is correct because the balanced equation is 2C2H6+7O2→4CO2+6H2O2 {C}_2 {H}_6+7 {O}_2 \rightarrow 4 {CO}_2+6 {H}_2 {O}, and the ratio of the coefficients of CO2{CO}_2 and H2O{H}_2 {O} is 4:64: 6 or 2:32: 3.
92 Medium
92 of 171
Application +4 | -1
The oxidation number of Ni\mathrm{Ni} in K4[Ni(CN)4]{\mathrm{K}_4}\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right] is :
View answer and explanation
Correct option: D
0
Option D (0) is correct because the overall charge of the complex ion is -4, and considering the charges of K and CN, the oxidation number of Ni must be 0.
93 Medium
93 of 171
Application +4 | -1
Chlorine undergoes disproportionation in alkaline medium as shown below :
aCl2(g)+bOH(aq)−→cClO(aq)−+dCl(aq)−+eH2O(l)a \mathrm{Cl}_{2(g)}+b O H_{(a q)}^{-} \rightarrow \mathrm{cClO}_{(a q)}^{-}+d \mathrm{Cl}_{(a q)}^{-}+\mathrm{eH}_2 \mathrm{O}_{(l)}

The values of a,b,c\mathrm{a}, \mathrm{b}, \mathrm{c} and d\mathrm{d} in a balanced redox reaction are respectively:
View answer and explanation
Correct option: B
1, 2, 1 and 1
Option B (1, 2, 1 and 1) is correct because it represents the coefficients that balance the disproportionation reaction of chlorine in an alkaline medium.
94 Medium
94 of 171
Analyzing +4 | -1
In the reactions;As2S3+HNO3→H3AsO4+H2SO4+NO\mathrm{A}{\mathrm{s}_2}{\mathrm{S}_3} + \mathrm{HN}{\mathrm{O}_3} \to {\mathrm{H}_3}\mathrm{As}{\mathrm{O}_4} + {\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} + \mathrm{NO}, the element oxidized is/ are :
View answer and explanation
Correct option: D
As and S both
Option D is correct. In the given reaction, both Arsenic (As) and Sulfur (S) are oxidized.
95 Medium
95 of 171
Application +4 | -1
In which compound, oxygen has an oxidation state of +2+ 2 ?
View answer and explanation
Correct option: C
OF2\mathrm{O}{\mathrm{F}_2}
Option C (OF2OF_2) is correct because fluorine is more electronegative than oxygen, giving oxygen a +2 oxidation state.
96 Medium
96 of 171
Application +4 | -1
Oxidation state of P\mathrm{P} in H4P2O5,H4P2O6\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_5, \mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_6 and H4P2O7\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_7 are respectively :
View answer and explanation
Correct option: A
+3,+4,+5+3,+4,+5
Option A (+3,+4,+5) is correct because it represents the correct oxidation states of P in the given compounds.
97 Medium
97 of 171
Understanding +4 | -1
Among the properties given below, the set of properties shown by CN−\mathrm{C}{\mathrm{N}^ - } ion towards metal species is :1. Reducing; 2. Oxidising ; 3. Complexation
View answer and explanation
Correct option: A
1,3
Option A (1,3) is correct because cyanide ions can act as reducing agents and form complexes with metal species.
98 Medium
98 of 171
Analyzing +4 | -1
In the reaction, NaH+H2O→NaOH+H2\mathrm{NaH} + {\mathrm{H}_2}\mathrm{O} \to \mathrm{NaOH} + {\mathrm{H}_2}:
View answer and explanation
Correct option: A
H−{H^ - } is oxidised
The correct answer is A. In the reaction NaH + H2O -> NaOH + H2, H- in NaH is oxidized to H2.
99 Medium
99 of 171
Analyzing +4 | -1
Statement-I: H2SO4\mathrm{H}_2 \mathrm{SO}_4 can act as reducing agent and oxidising agent.

Statement-II: Sulphur can not increase its oxidation number beyond +6.
View answer and explanation
Correct option: D
Statement-I is incorrect but statement-II is correct
Option D is correct because H2SO4 can only act as an oxidizing agent, and sulfur cannot increase its oxidation number beyond +6.
100 Medium
100 of 171
Understanding +4 | -1
Which of the following is not a redox reaction?
View answer and explanation
Correct option: B
NaOH+HCl⟶NaCl+H2O{NaOH}+{HCl} \longrightarrow {NaCl}+{H}_2 {O}
Option B (NaOH+HCl⟶NaCl+H2O\mathrm{NaOH}+{HCl} \longrightarrow {NaCl}+{H}_2 {O}) is correct because it is a neutralization reaction, which involves the combination of an acid and a base to form salt and water, without any change in oxidation states.
101 Medium
101 of 171
Application +4 | -1
Number of moles of MnO4−\mathrm{MnO}_4^ - required to oxidise one mole of ferrous oxalate completely in acidic medium will be :
View answer and explanation
Correct option: D
0.6 mole
Option D (0.6 mole) is correct because 3 moles of MnO4- are required to oxidize 5 moles of ferrous oxalate, thus 0.6 moles are needed for 1 mole.
102 Medium
102 of 171
Understanding +4 | -1
For reducing one mole of Fe2+\mathrm{F}{\mathrm{e}^{2 + }}ion to FeFe, the number of faraday of electricity is :
View answer and explanation
Correct option: A
2
Option A (2) is correct because reducing one mole of Fe2+\mathrm{F}{\mathrm{e}^{2 + }} to FeFe requires 2 moles of electrons, which corresponds to 2 Faradays of electricity.
103 Medium
103 of 171
Analyzing +4 | -1
Assertion: Among Br−,O22−,H−\mathrm{Br}^-, \mathrm{O}_2^{2-}, \mathrm{H}^- and NO3−,\mathrm{NO}_3^-, the ions that could not act as oxidising agents are Br−\mathrm{Br}^{-}and H−.\mathrm{H}^{-}.

Reason: Br⊖\mathrm{Br}^{\ominus} and H−\mathrm{H}^{-} could not be reduced.
View answer and explanation
Correct option: A
Assertion is true, Reason is true and Reason is correct explanation for Assertion
Option A (Assertion is true, Reason is true and Reason is correct explanation for Assertion) is correct because Br- and H- are in their lowest oxidation states and cannot be further reduced, thus cannot act as oxidizing agents.
104 Medium
104 of 171
Analyzing +4 | -1
The reaction; H2S+H2O2→2H2O+S{\mathrm{H}_2}\mathrm{S} + {\mathrm{H}_2}{\mathrm{O}_2} \to 2{\mathrm{H}_2}\mathrm{O} + \mathrm{S} shows :
View answer and explanation
Correct option: C
Oxidising action of H2O2{\mathrm{H}_2}{\mathrm{O}_2}
Option C (Oxidising action of H2O2{\mathrm{H}_2}{\mathrm{O}_2}) is correct because hydrogen peroxide oxidizes H2SH_2S to sulfur.
105 Medium
105 of 171
Analyzing +4 | -1
Statement-I: KClO3→KClO4+KCl{KClO}_3 \rightarrow {KClO}_4+{KCl}. This is a disproportionation reaction.
Statement-II: The reaction in which one substance gets oxidised and reduced is known as disproportionation reaction.
View answer and explanation
Correct option: A
Both the statements are correct
Option A (Both the statements are correct) is correct because in the given reaction, chlorine undergoes both oxidation and reduction, which defines a disproportionation reaction.
106 Medium
106 of 171
Application +4 | -1
Oxidation number of carbon in carbon sub oxide (C3O2)\left( {{\mathbf{C}_\mathbf{3}}{\mathbf{O}_\mathbf{2}}} \right)
View answer and explanation
Correct option: B
+43+ \frac{4}{3}
Option B (+43+ \frac{4}{3}) is correct because the average oxidation number of carbon in carbon suboxide is calculated to be +4/3.
107 Medium
107 of 171
Understanding +4 | -1
Cr2O72−\mathrm{Cr}_2 \mathrm{O}_7^{2-} is not a self indicator but
View answer and explanation
Correct option: B
oxidises the indicator substance
Option B (oxidises the indicator substance) is correct because Cr2O72−\mathrm{Cr}_2 \mathrm{O}_7^{2-} acts as an oxidizing agent and oxidizes the indicator substance.
108 Medium
108 of 171
Remembering +4 | -1
The maximum oxidation state of oxygen is
View answer and explanation
Correct option: C
+2+2
Option C (+2) is correct because the maximum oxidation state of oxygen is +2, which occurs when it is bonded to fluorine in OF2OF_2.
109 Medium
109 of 171
Understanding +4 | -1
A solution of sulphur dioxide in water reacts with H2S{H}_2 {S} precipitating sulphur. Here sulphur dioxide acts as
View answer and explanation
Correct option: A
As oxidising agent
The correct answer is A (As oxidising agent) because sulphur dioxide gains electrons from hydrogen sulfide, thus reducing itself and oxidizing hydrogen sulfide to sulphur.
110 Medium
110 of 171
Analyzing +4 | -1
Assertion: KCl/NaCl/NH4Cl{KCl} / {NaCl} / {NH}_4 {Cl} etc. cannot be used in the salt bridge of a cell containing silver.

Reason: A salt bridge contains concentrated solution of an inert electrolyte like KCl,KNO3,NH4NO3{KCl}, {KNO}_3, {NH}_4 {NO}_3 etc. or solidified solution of such as electrolyte in agar-agar and gelatine.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
The correct answer is B (If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion) because while the reason correctly describes the composition of a salt bridge, it doesn't explain why certain salts cannot be used with silver.
111 Medium
111 of 171
Application +4 | -1
Consider the following reaction, xMnO4−+yC2O42−+zH+→xMn2++2yCO2+z2H2OxMnO_4^ - + y{C_2}O_4^{2 - } + z{H^ + } \to xM{n^{2 + }} + 2yC{O_2} + \frac{z}{2}{H_2}O The values of xx, yy and zz in the reaction are respectively
View answer and explanation
Correct option: C
2, 5 and 16
Option C (2, 5 and 16) is correct because balancing the redox reaction using the half-reaction method yields these stoichiometric coefficients.
112 Medium
112 of 171
Understanding +4 | -1
In which reaction is hydrogen acting as an oxidising agent?
View answer and explanation
Correct option: B
With lithium to give lithium hydride
Option B (With lithium to give lithium hydride) is correct because hydrogen gains an electron (reduction) to form H−1H^{-1}, thus acting as an oxidizing agent.
113 Medium
113 of 171
Analyzing +4 | -1
Which of the following involves transfer of five electrons?
View answer and explanation
Correct option: A
MnO4−→Mn2+{MnO}_4^{-} \rightarrow {Mn}^{2+}
Option A (MnO4−→Mn2+{MnO}_4^{-} \rightarrow {Mn}^{2+}) is correct because the oxidation state of Mn changes from +7 to +2, involving a transfer of 5 electrons.
114 Medium
114 of 171
Understanding +4 | -1
Given below are two statements.
One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) Aluminium is extracted from bauxite by the electrolysis of molten mixture of Al2O3A{l_2}{O_3} with cryolite.
Reason (R) The oxidation state of AlAl in cryolite is +3.
In the light of the above statements, choose the most appropriate answer from the options given below.
View answer and explanation
Correct option: D
Both (A) and (R) are true but (R) is not the correct explanation of (A)
The correct answer is D (Both (A) and (R) are true but (R) is not the correct explanation of (A)) because both the assertion and reason are true, but the reason doesn't explain the assertion.
115 Medium
115 of 171
Analyzing +4 | -1
Which of the following is not a redox reaction?
View answer and explanation
Correct option: B
CaCO3(s)→ heat CaO(s)+CO2(g)\mathrm{CaCO}_3\text{(s)}\xrightarrow{\text { heat }} \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g})
Option B (CaCO3(s)→ heat CaO(s)+CO2(g)\mathrm{CaCO}_3\text{(s)}\xrightarrow{\text { heat }} \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g})) is the correct answer because there is no change in oxidation states of any element during the reaction, indicating it is not a redox reaction.
116 Medium
116 of 171
Analyzing +4 | -1
Which of the following is not an intramolecular redox reaction?
View answer and explanation
Correct option: D
2H2O2+2H2O+O22 \mathrm{H}_2 \mathrm{O}_2+2 \mathrm{H}_2 \mathrm{O}+\mathrm{O}_2
Option D (2H2O2+2H2O+O22 \mathrm{H}_2 \mathrm{O}_2+2 \mathrm{H}_2 \mathrm{O}+\mathrm{O}_2) is correct because it is an intermolecular redox reaction, not intramolecular.
117 Medium
117 of 171
Understanding +4 | -1
Oxalic acid on reacting with acidified KMnO4\mathrm{KMn}{\mathrm{O}_4} is oxidised to :
View answer and explanation
Correct option: C
CO2 and H2O\mathrm{C}{\mathrm{O}_2}\,and\,{\mathrm{H}_2}\mathrm{O}
Option C (CO2 and H2O\mathrm{C}{\mathrm{O}_2}\,and\,{\mathrm{H}_2}\mathrm{O}) is correct because oxalic acid is oxidized to carbon dioxide and water by acidified potassium permanganate.
118 Medium
118 of 171
Application +4 | -1
In the balanced reaction, IO3−+SO2+4H2O→I2+SO4−2+8H+IO_3^ - + S{O_2} + 4{H_2}O \to {I_2} + SO_4^{ - 2} + 8{H^ + } the coefficient of SO2S{O_2} is
View answer and explanation
Correct option: C
5
Option C (5) is correct because the balanced equation shows that 5 moles of SO2SO_2 are required.
119 Medium
119 of 171
Application +4 | -1
Oxidation number of carbon inKCN\mathrm{KCN} is :
View answer and explanation
Correct option: A
+2+ 2
Option A (+2+2) is correct because the oxidation number of carbon in KCN is calculated based on the known oxidation states of K and N.
120 Medium
120 of 171
Application +4 | -1
The value of 'n' in the reaction Cr2O72−+14H++nFe2+→2Cr3++nFe3++7H2O\mathrm{C}{\mathrm{r}_2}\mathrm{O}_7^{2 - } + 14{\mathrm{H}^ + } + n\mathrm{F}{\mathrm{e}^{2 + }} \to 2\mathrm{C}{\mathrm{r}^{3 + }} + n\mathrm{F}{\mathrm{e}^{3 + }} + 7{\mathrm{H}^2}\mathrm{O} will be
View answer and explanation
Correct option: C
6
Option C (6) is correct because balancing the redox reaction shows that 6 moles of Fe2+ are required to react with 1 mole of dichromate.
Revision notes and key takeaways

Review REDOX REACTIONS in your textbook or class notes, then use this set to check your understanding.

Showing 91-120 of 171 questions

Your practice

0 / 171 answered · 171 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Answer feedback and difficulty

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.